{"id":377,"date":"2023-07-04T01:01:00","date_gmt":"2023-07-04T01:01:00","guid":{"rendered":"https:\/\/mathority.org\/pt\/assintota-horizontal\/"},"modified":"2023-07-04T01:01:00","modified_gmt":"2023-07-04T01:01:00","slug":"assintota-horizontal","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/assintota-horizontal\/","title":{"rendered":"Ass\u00edntota horizontal"},"content":{"rendered":"<p>Neste artigo explicamos o que s\u00e3o as ass\u00edntotas horizontais de uma fun\u00e7\u00e3o e como s\u00e3o calculadas. Al\u00e9m disso, voc\u00ea encontrar\u00e1 v\u00e1rios exemplos deste tipo de ass\u00edntotas para compreender totalmente o conceito e, al\u00e9m disso, poder\u00e1 praticar com exerc\u00edcios resolvidos de ass\u00edntotas horizontais. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-una-asintota-horizontal\"><\/span> O que \u00e9 uma ass\u00edntota horizontal?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Uma ass\u00edntota horizontal de uma fun\u00e7\u00e3o \u00e9 uma linha horizontal da qual seu gr\u00e1fico se aproxima indefinidamente sem nunca cruz\u00e1-la.<\/strong> Portanto, a equa\u00e7\u00e3o para uma ass\u00edntota horizontal \u00e9 <em>y=k<\/em> , onde <em>k<\/em> \u00e9 o valor da ass\u00edntota horizontal.<\/p>\n<p> Ou seja, <strong><em>k<\/em> \u00e9 uma ass\u00edntota horizontal se o limite da fun\u00e7\u00e3o quando <em>x<\/em> se aproxima do infinito for igual a <em>k<\/em> .<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/asymptote-horizontale-dune-fonction.webp\" alt=\"ass\u00edntota horizontal de uma fun\u00e7\u00e3o\" class=\"wp-image-1350\" width=\"401\" height=\"269\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> A fun\u00e7\u00e3o acima possui uma ass\u00edntota horizontal em ambos os lados do gr\u00e1fico, mas uma fun\u00e7\u00e3o s\u00f3 pode ter uma ass\u00edntota horizontal em um lado:<\/p>\n<ul>\n<li> A fun\u00e7\u00e3o tem uma <strong>ass\u00edntota horizontal \u00e0 esquerda<\/strong> se o limite pelo menos ao infinito fornecer um n\u00famero real.<\/li>\n<li> A fun\u00e7\u00e3o tem uma <strong>ass\u00edntota horizontal \u00e0 direita<\/strong> se o limite mais infinito fornecer um n\u00famero real. <\/li>\n<\/ul>\n<div class=\"wp-block-columns are-vertically-aligned-center is-layout-flex wp-container-111\">\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/asymptote-horizontale-dune-fonction-a-partir-de-la-gauche.webp\" alt=\"ass\u00edntota horizontal de uma fun\u00e7\u00e3o da esquerda\" class=\"wp-image-1352\" width=\"227\" height=\"239\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<\/div>\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/asymptote-horizontale-vers-la-droite.webp\" alt=\"ass\u00edntota horizontal \u00e0 direita\" class=\"wp-image-1328\" width=\"268\" height=\"239\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"como-calcular-la-asintota-horizontal-de-una-funcion\"><\/span> Como calcular a ass\u00edntota horizontal de uma fun\u00e7\u00e3o<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Para calcular a ass\u00edntota horizontal de uma fun\u00e7\u00e3o, devem ser seguidos os seguintes passos:<\/p>\n<ol style=\"color:#FF8A05; font-weight: bold;border:\">\n<li style=\"margin-bottom:12px\"> <span style=\"color:#101010;font-weight: normal;\">Calcule o limite da fun\u00e7\u00e3o ao infinito (+\u221e e -\u221e).<\/span><\/li>\n<li style=\"margin-bottom:12px\"> <span style=\"color:#101010;font-weight: normal;\">Se um limite ao infinito d\u00e1 um n\u00famero real (k), a reta y=k \u00e9 uma ass\u00edntota horizontal da fun\u00e7\u00e3o.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">Se nenhum dos limites corresponder a um n\u00famero real, a fun\u00e7\u00e3o n\u00e3o possui ass\u00edntotas horizontais.<\/span> <\/li>\n<\/ol>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-asintota-horizontal\"><\/span> Exemplo de ass\u00edntota horizontal<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Para que voc\u00ea possa ver um exemplo de como isso \u00e9 feito, removeremos todas as ass\u00edntotas horizontais da seguinte fun\u00e7\u00e3o racional:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6b695ac0a1f175a1522a0c606da9458_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\cfrac{x+1}{x-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"101\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Para determinar as ass\u00edntotas horizontais, \u00e9 necess\u00e1rio calcular o limite em menos infinito e em mais infinito da fun\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c437f7aa8aec16519f5ff4bfd2666a32_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{x+1}{x-1} = \\cfrac{+\\infty}{+\\infty}= \\cfrac{1}{1} = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"223\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6a04dd749f028409b7c952eb01d5adde_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{x+1}{x-1} = \\cfrac{-\\infty}{-\\infty}= \\cfrac{1}{1} = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"223\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\">como resolver a indetermina\u00e7\u00e3o infinita entre infinitos<\/a><\/span><\/p>\n<p> Os dois limites no infinito d\u00e3o 1, ent\u00e3o <strong>y=1 \u00e9 a \u00fanica ass\u00edntota horizontal da fun\u00e7\u00e3o.<\/strong><\/p>\n<p> Abaixo est\u00e1 a fun\u00e7\u00e3o representada graficamente. Como voc\u00ea pode ver, a fun\u00e7\u00e3o chega muito perto de y=1 (tanto em mais infinito quanto em menos infinito), mas nunca a toca porque \u00e9 uma ass\u00edntota horizontal. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exemple-dasymptote-horizontale.webp\" alt=\"exemplo de ass\u00edntota horizontal\" class=\"wp-image-1333\" width=\"525\" height=\"414\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> <strong>Nota:<\/strong> em alguns casos especiais, a fun\u00e7\u00e3o intercepta a ass\u00edntota horizontal em um ou mais pontos, mas em geral o gr\u00e1fico de uma fun\u00e7\u00e3o nunca cruza as suas ass\u00edntotas.<\/p>\n<p> Por outro lado, esta fun\u00e7\u00e3o tamb\u00e9m possui uma ass\u00edntota vertical em x=1. Porque, como voc\u00ea pode ver no gr\u00e1fico, ele chega muito perto da reta x=1, mas nunca atinge esse valor. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-asintotas-horizontales\"><\/span> Problemas resolvidos de ass\u00edntotas horizontais<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Encontre a ass\u00edntota horizontal, se houver, da seguinte fun\u00e7\u00e3o fracion\u00e1ria: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-717c0b45bca578809a5e633a960e72c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\frac{4x+3}{2x-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"110\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para determinar as ass\u00edntotas horizontais da fun\u00e7\u00e3o racional, \u00e9 necess\u00e1rio calcular os limites no infinito da fun\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-27d982077c31fd0cd8f75cab15b6aafc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\frac{4x+3}{2x-1} = \\frac{4(+\\infty)}{2(+\\infty)} = \\frac{+\\infty}{+\\infty} = \\frac{4}{2} = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"311\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-137e1fdfcb79e76bfaaae3f42466a16e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\frac{4x+3}{2x-1} = \\frac{4(-\\infty)}{2(-\\infty)} = \\frac{-\\infty}{-\\infty} = \\frac{4}{2} = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"311\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Neste caso, o resultado da forma indeterminada \u221e\/\u221e \u00e9 a divis\u00e3o dos coeficientes do x de maior grau, pois o numerador e o denominador s\u00e3o da mesma ordem.<\/p>\n<p class=\"has-text-align-left\"> Os limites em mais infinito e menos infinito da fun\u00e7\u00e3o d\u00e3o 2, ent\u00e3o <strong>y=2 \u00e9 uma ass\u00edntota horizontal<\/strong> e \u00e9 a \u00fanica que a fun\u00e7\u00e3o possui.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 2<\/h3>\n<p> Encontre todas as ass\u00edntotas horizontais da seguinte fun\u00e7\u00e3o racional com raiz: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c605d3e2ddf02895534060c0d965daaf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\frac{3x}{\\sqrt{x^2+2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"124\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para encontrar as ass\u00edntotas horizontais da fun\u00e7\u00e3o, primeiro calculamos o limite no infinito positivo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36b52bec09032cfd322340c6f979d5f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty}\\frac{3x}{\\sqrt{x^2+2}}= \\frac{+\\infty}{+\\infty} = \\frac{3}{\\sqrt{1}} = \\bm{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"259\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E ent\u00e3o resolvemos o limite da fun\u00e7\u00e3o at\u00e9 menos infinito:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fb11630356a1314b3785cc90980b419b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty}\\frac{3x}{\\sqrt{x^2+2}}= \\frac{-\\infty}{+\\infty} = \\frac{-3}{\\sqrt{1}} = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"273\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <u style=\"text-decoration-color:#FF9B28;\">\u27a4 Se voc\u00ea tiver alguma d\u00favida sobre como foram resolvidos os limites ao infinito, recomendamos conferir no link acima <em>como resolver a indetermina\u00e7\u00e3o infinita entre o infinito.<\/em><\/u><\/p>\n<p class=\"has-text-align-left\"> Neste caso, obtivemos dois valores diferentes dos limites no infinito. A fun\u00e7\u00e3o, portanto, tem duas ass\u00edntotas horizontais: y=3 \u00e9 uma ass\u00edntota horizontal da fun\u00e7\u00e3o \u00e0 direita e, por outro lado, y=-3 \u00e9 uma ass\u00edntota horizontal da fun\u00e7\u00e3o \u00e0 esquerda.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Calcule as ass\u00edntotas horizontais da seguinte fun\u00e7\u00e3o definida por partes: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa168db8e7d068a6d331e40401a90da6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)=\\left\\{ \\begin{array}{lcl}\\displaystyle\\frac{3x-1}{x^2}&amp; \\text{si} &amp; x<4\\\\[4ex]\\displaystyle\\frac{x^3-2x+5}{2x^3-9} &amp; \\text{si} &amp; x\\geq 4 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"262\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para calcular as ass\u00edntotas horizontais da fun\u00e7\u00e3o, n\u00e3o existe f\u00f3rmula, mas \u00e9 necess\u00e1rio calcular os limites para mais e menos infinito.<\/p>\n<p class=\"has-text-align-left\"> Assim, para encontrar o limite pelo menos infinito, tomamos a fun\u00e7\u00e3o definida na primeira se\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50c7440eb78bb31e6b0e2b4663d892bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty}\\frac{3x-1}{x^2}= \\frac{-\\infty}{+\\infty}=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"194\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, a linha y=0 \u00e9 uma ass\u00edntota horizontal \u00e0 esquerda da fun\u00e7\u00e3o.<\/p>\n<p class=\"has-text-align-left\"> E agora calculamos o limite em mais infinito tomando a fun\u00e7\u00e3o definida na segunda se\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ba01137442f320e04e824b4963a3383b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty}\\frac{x^3-2x+5}{2x^3-9}= \\frac{+\\infty}{+\\infty}=\\mathbf{\\frac{1}{2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"237\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, a reta y=1\/2 \u00e9 uma ass\u00edntota horizontal \u00e0 direita da fun\u00e7\u00e3o.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo explicamos o que s\u00e3o as ass\u00edntotas horizontais de uma fun\u00e7\u00e3o e como s\u00e3o calculadas. Al\u00e9m disso, voc\u00ea encontrar\u00e1 v\u00e1rios exemplos deste tipo de ass\u00edntotas para compreender totalmente o conceito e, al\u00e9m disso, poder\u00e1 praticar com exerc\u00edcios resolvidos de ass\u00edntotas horizontais. O que \u00e9 uma ass\u00edntota horizontal? Uma ass\u00edntota horizontal de uma fun\u00e7\u00e3o \u00e9 &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/assintota-horizontal\/\"> <span class=\"screen-reader-text\">Ass\u00edntota horizontal<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[16],"tags":[],"class_list":["post-377","post","type-post","status-publish","format-standard","hentry","category-limites-de-funcao"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Ass\u00edntota horizontal - Matoridade<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/assintota-horizontal\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ass\u00edntota horizontal - Matoridade\" \/>\n<meta property=\"og:description\" content=\"Neste artigo explicamos o que s\u00e3o as ass\u00edntotas horizontais de uma fun\u00e7\u00e3o e como s\u00e3o calculadas. Al\u00e9m disso, voc\u00ea encontrar\u00e1 v\u00e1rios exemplos deste tipo de ass\u00edntotas para compreender totalmente o conceito e, al\u00e9m disso, poder\u00e1 praticar com exerc\u00edcios resolvidos de ass\u00edntotas horizontais. O que \u00e9 uma ass\u00edntota horizontal? 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