{"id":375,"date":"2023-07-04T03:00:17","date_gmt":"2023-07-04T03:00:17","guid":{"rendered":"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/"},"modified":"2023-07-04T03:00:17","modified_gmt":"2023-07-04T03:00:17","slug":"indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/","title":{"rendered":"Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e)"},"content":{"rendered":"<p>Neste artigo explicamos como calcular o infinito da indetermina\u00e7\u00e3o entre o infinito (\u221e\/\u221e). Voc\u00ea encontrar\u00e1 exemplos desta indetermina\u00e7\u00e3o com todos os tipos de fun\u00e7\u00f5es: fun\u00e7\u00f5es polinomiais, radicais, exponenciais, etc. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo de limites que d\u00e3o infinitas indetermina\u00e7\u00f5es entre infinitos. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"como-resolver-la-indeterminacion-infinito-entre-infinito\"><\/span> Como resolver a indetermina\u00e7\u00e3o infinita entre infinito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Quando o limite de uma fun\u00e7\u00e3o d\u00e1 infinito dividido por infinito, significa que se trata de uma indetermina\u00e7\u00e3o (ou forma indeterminada). Para <strong>resolver o limite de uma fun\u00e7\u00e3o que d\u00e1 infinito de indetermina\u00e7\u00e3o entre o infinito,<\/strong> o grau do polin\u00f4mio do numerador deve ser comparado ao grau do polin\u00f4mio do denominador.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-77419fd05960300c6e2cd6158cd04e69_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to +\\infty}\\frac{a_nx^r+a_{n-1}x^{r-1}+a_{n-2}x^{r-2}+\\dots}{b_nx^s+b_{n-1}x^{s-1}+b_{n-2}x^{s-2}+\\dots}=\\frac{+\\infty}{+\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"375\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<p> O resultado da indetermina\u00e7\u00e3o infinito dividido pelo infinito depende do grau do numerador e do grau do denominador da fra\u00e7\u00e3o:<\/p>\n<ol style=\"color:#FF8A05; font-weight: bold;border:\">\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\">Se o grau do polin\u00f4mio do numerador for menor que o grau do polin\u00f4mio do denominador, o infinito da indetermina\u00e7\u00e3o dividido pelo infinito <strong><u style=\"text-decoration-color:#FF9B28;\">\u00e9 igual a zero.<\/u><\/strong><\/span><\/li>\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\">Se o grau do polin\u00f4mio do numerador for equivalente ao grau do polin\u00f4mio do denominador, a indetermina\u00e7\u00e3o infinita sobre o infinito \u00e9 o <strong><u style=\"text-decoration-color:#FF9B28;\">quociente dos coeficientes principais dos dois polin\u00f4mios.<\/u><\/strong><\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">Se o grau do polin\u00f4mio do numerador for maior que o grau do polin\u00f4mio do denominador, o infinito da indetermina\u00e7\u00e3o entre o infinito d\u00e1 <strong><u style=\"text-decoration-color:#FF9B28;\">mais ou menos infinito<\/u><\/strong> (o sinal depende dos termos principais dos dois polin\u00f4mios).<\/span> <\/li>\n<\/ol>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2c969e4b99985b44006e57d554ff0247_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to \\pm \\infty}}\\frac{a_nx^r+a_{n-1}x^{r-1}+a_{n-2}x^{r-2}+\\dots}{b_nx^s+b_{n-1}x^{s-1}+b_{n-2}x^{s-2}+\\dots}=\\left\\{ \\begin{array}{lcl} 0 &amp; \\text{si} &amp; r<s \\\\[3ex]=&quot;&quot; \\cfrac{a_n}{b_n}=&quot;&quot; &amp;=&quot;&quot; \\text{si}=&quot;&quot; r=&quot;s&quot; \\\\[5ex]=&quot;&quot; \\pm=&quot;&quot; \\infty=&quot;&quot;>s \\end{array}\\right.&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;139&#8243; width=&#8221;767&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplos-de-indeterminaciones-infinito-entre-infinito\"><\/span> Exemplos de indetermina\u00e7\u00f5es infinitas entre o infinito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Vamos ver como a forma indeterminada infinito entre infinito \u00e9 resolvida observando v\u00e1rios exemplos de cada caso:<\/p>\n<h3 class=\"wp-block-heading\"> grau do numerador menor que o grau do denominador<\/h3>\n<p> Como vimos acima, quando o grau do polin\u00f4mio do numerador \u00e9 menor que o grau do polin\u00f4mio do denominador, o limite infinito indeterminado entre o infinito sempre d\u00e1 0.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 1:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b4e5e0058ab08d743a6dc18587912a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{6x^2-5}{x^3+1} = \\cfrac{6(+\\infty)^2}{(+\\infty)^3} = \\cfrac{+\\infty}{+\\infty}= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"293\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> O polin\u00f4mio do numerador \u00e9 de segundo grau, enquanto o do denominador \u00e9 de terceiro grau, ent\u00e3o a solu\u00e7\u00e3o do limite \u00e9 0.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 2:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7b7cb8798b808542e53a1caa8fcb9ee5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\frac{-7x}{2x^4+3x^2}=\\frac{-7\\cdot (-\\infty)}{2(-\\infty)^4}=\\frac{+\\infty}{+\\infty}= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"328\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> A fun\u00e7\u00e3o polinomial do numerador \u00e9 de primeiro grau, mas a fun\u00e7\u00e3o do denominador \u00e9 de quarto grau, ent\u00e3o o limite ao infinito negativo \u00e9 0.<\/p>\n<h3 class=\"wp-block-heading\"> grau do numerador igual ao grau do denominador<\/h3>\n<p> Quando o grau do polin\u00f4mio do numerador \u00e9 igual ao grau do polin\u00f4mio do denominador, o limite indeterminado infinito por infinito \u00e9 calculado dividindo os coeficientes l\u00edderes (coeficiente do termo de grau superior) dos dois polin\u00f4mios.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 3:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c21a5f7720fd6be40b043d30f904941_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{4x^2+1}{2x^2-5} = \\cfrac{4(+\\infty)^2}{2(+\\infty)^2}= \\cfrac{+\\infty}{+\\infty} =\\cfrac{4}{2} = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"327\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Neste caso, os dois polin\u00f4mios s\u00e3o de segundo grau, portanto \u00e9 necess\u00e1rio dividir os coeficientes dos termos de grau superior para encontrar o limite no infinito positivo.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 4:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6e019743989a25f2cfa1c1dd1aa718b3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{2x+1}{5x+3} = \\cfrac{2(-\\infty)}{5(-\\infty)}= \\cfrac{-\\infty}{-\\infty} =\\cfrac{\\bm{2}}{\\bm{5}}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"280\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Embora o limite seja quando x tende a menos infinito, a indetermina\u00e7\u00e3o infinita entre o infinito se resolve da mesma maneira.<\/p>\n<h3 class=\"wp-block-heading\"> Grau do numerador maior que o grau do denominador<\/h3>\n<p> Quando o grau do polin\u00f4mio do numerador \u00e9 maior que o grau do polin\u00f4mio do denominador, a forma indeterminada do infinito entre o infinito sempre dar\u00e1 o infinito, e o sinal do infinito \u00e9 determinado pelos termos de grau superior dos dois polin\u00f4mios.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 5:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36bee41554444ea88e0bc4f6d0dbf75a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{x^2+7}{x-2} = \\cfrac{(+\\infty)^2}{+\\infty} = \\cfrac{+\\infty}{+\\infty} = \\bm{+\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"297\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> A fun\u00e7\u00e3o do numerador tem um grau superior ao do denominador, ent\u00e3o a indetermina\u00e7\u00e3o infinito sobre infinito d\u00e1 infinito. Al\u00e9m disso, neste caso tanto o numerador quanto o denominador obt\u00eam infinito positivo, ent\u00e3o o resultado do limite tamb\u00e9m deve ser positivo.<\/p>\n<h4 class=\"wp-block-heading\"> Exemplo 6:<\/h4>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-de6d4de74f4fe69e45ce1a55fcb8c7d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{3x^2+2x-5}{7x+1} = \\cfrac{3(-\\infty)^2}{7(-\\infty)}=\\cfrac{3(+\\infty)}{-\\infty}}= \\cfrac{+\\infty}{-\\infty}= \\bm{-\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"436\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Neste problema, um infinito positivo \u00e9 obtido do numerador porque qualquer termo quadrado \u00e9 positivo, por outro lado, um infinito negativo \u00e9 obtido do denominador. Portanto, o limite resultante \u00e9 negativo porque positivo dividido por negativo \u00e9 igual a negativo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"indeterminacion-infinito-entre-infinito-con-raices\"><\/span> Indetermina\u00e7\u00e3o infinita entre o infinito com ra\u00edzes<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Acabamos de ver como calcular a indetermina\u00e7\u00e3o infinita entre o infinito quando temos fun\u00e7\u00f5es polinomiais. Mas\u2026 quanto \u00e9 o infinito dividido pelo infinito se tivermos ra\u00edzes?<\/p>\n<p> O <strong>grau de uma fun\u00e7\u00e3o irracional<\/strong> (fun\u00e7\u00e3o com ra\u00edzes) \u00e9 o quociente entre o grau do termo principal e o \u00edndice do radical.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ffc00917d2cc316211a57feafdddd0d2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sqrt[\\color{red}\\bm{m}\\color{black}]{a_nx^{\\color{blue}\\bm{n}\\color{black}}+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+\\dots} \\ \\longrightarrow \\ \\text{grado}=\\cfrac{\\color{blue}\\bm{n}\\color{black}}{\\color{red}\\bm{m}\\color{black}}\" title=\"Rendered by QuickLaTeX.com\" height=\"64\" width=\"580\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Portanto, se <strong>o limite de uma fun\u00e7\u00e3o com ra\u00edzes d\u00e1 a indetermina\u00e7\u00e3o entre o infinito<\/strong> , devemos aplicar as mesmas regras explicadas acima para os graus do numerador e do denominador, mas levando em considera\u00e7\u00e3o que o grau de um polin\u00f4mio com ra\u00edzes \u00e9 calculado de forma diferente.<\/p>\n<p> Veja o seguinte exemplo do limite ao infinito de uma fun\u00e7\u00e3o com radicais:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b93ef0d623e6904538b361f5d6f1ef9d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to +\\infty}\\frac{4x^2+11}{\\sqrt{x^8-3x^2-5}}=\\frac{4(+\\infty)^2}{\\sqrt{(+\\infty)^8}}=\\frac{+\\infty}{+\\infty}=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"354\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p> O grau do numerador \u00e9 2 e o grau do denominador \u00e9 4 (8\/2=4), portanto o limite \u00e9 0 porque o grau do numerador \u00e9 menor que o grau do denominador.<\/p>\n<p> Por outro lado, se o grau do numerador e do denominador forem iguais, para calcular o limite indeterminado devemos tomar o coeficiente principal com o radical: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-130d73020be7d3969b22ecd4381ccf8c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to +\\infty}\\frac{6x-5}{\\sqrt{9x^2+2x}}=\\frac{6(+\\infty)}{\\sqrt{9(+\\infty)^2}}=\\frac{+\\infty}{+\\infty}=\\frac{6}{\\sqrt{9}}=\\frac{6}{3}=\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"420\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"indeterminacion-infinito-entre-infinito-con-funciones-exponenciales\"><\/span> Indetermina\u00e7\u00e3o infinita entre o infinito com fun\u00e7\u00f5es exponenciais<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Por fim, s\u00f3 nos resta estudar um caso de quociente de indetermina\u00e7\u00e3o de infinitos: quanto \u00e9 a indetermina\u00e7\u00e3o infinita entre infinito e fun\u00e7\u00f5es exponenciais.<\/p>\n<p> O crescimento de uma fun\u00e7\u00e3o exponencial \u00e9 muito maior que o crescimento de uma fun\u00e7\u00e3o polinomial, <strong>portanto devemos considerar que o grau de uma fun\u00e7\u00e3o exponencial \u00e9 maior que o grau de uma fun\u00e7\u00e3o polinomial.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-49d708f83c6876b3cdb6d884ab7b6a23_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{exponencial}>\\text{polinomio}&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;16&#8243; width=&#8221;192&#8243; style=&#8221;vertical-align: -4px;&#8221;><\/p>\n<\/p>\n<p> Portanto, se a indetermina\u00e7\u00e3o infinita dividida pelo infinito resulta de um limite com fun\u00e7\u00f5es exponenciais, basta aplicar as mesmas regras explicadas para os graus do numerador e do denominador, mas levando em considera\u00e7\u00e3o que uma fun\u00e7\u00e3o exponencial \u00e9 de ordem superior a um polin\u00f4mio. .<\/p>\n<p> Al\u00e9m disso, se tivermos fun\u00e7\u00f5es exponenciais no numerador e no denominador da divis\u00e3o, a fun\u00e7\u00e3o exponencial com base maior ser\u00e1 de ordem superior.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50f9e93066ce9e76b76ef6c7a72a9fad_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to +\\infty}\\frac{7x^5+6x^3-4x}{4^x}=\\frac{7(+\\infty)^5}{4^{+\\infty}}=\\frac{+\\infty}{+\\infty}=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"350\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Neste caso, o denominador \u00e9 formado por uma fun\u00e7\u00e3o exponencial, portanto \u00e9 de ordem superior ao numerador. Portanto, a forma indeterminada infinito entre o infinito desaparece. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-indeterminacion-infinito-entre-infinito\"><\/span> Exerc\u00edcios resolvidos de indetermina\u00e7\u00e3o infinita entre o infinito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule o limite da seguinte fun\u00e7\u00e3o racional: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cf1cd4bc84c0a321db33330a58a89ae4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x \\to +\\infty} \\cfrac{6x-5}{x^2-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"101\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Ao calcular o limite, obtemos a indetermina\u00e7\u00e3o infinita entre o infinito, mas como o grau do numerador \u00e9 menor que o grau do denominador, o limite indeterminado \u00e9 igual a zero. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-08cb59f29e9be213c6cf5f22f796b132_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{6x-5}{x^2-1} = \\cfrac{6(+\\infty)}{(+\\infty)^2} = \\cfrac{+\\infty}{+\\infty}= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"278\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Resolva o seguinte limite indeterminado: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02dd4897e57603625223d03f893f78c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x \\to +\\infty} \\cfrac{x^3+4x-1}{5x^2-3x+4}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"149\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Ao tentar calcular o limite, obt\u00e9m-se a indetermina\u00e7\u00e3o \u221e\/\u221e. Neste caso, o grau do polin\u00f4mio do numerador \u00e9 maior que o grau do polin\u00f4mio do denominador, portanto o limite indeterminado \u00e9 igual a mais infinito. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-72be3fb247787c715fa772abbf1df242_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{x^3+4x-1}{5x^2-3x+4} = \\cfrac{(+\\infty)^3}{5(+\\infty)^2} = \\cfrac{+\\infty}{+\\infty}= \\bm{+\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"356\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Resolva o seguinte limite no infinito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2459122cc1d9e723b3f78d858c48fe1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{-4x^2+3}{3x+1}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"130\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O limite d\u00e1 indetermina\u00e7\u00e3o menos infinito entre mais infinito. O grau do numerador \u00e9 maior que o grau do denominador, ent\u00e3o o limite indeterminado \u00e9 igual a mais infinito. Por\u00e9m, como a divis\u00e3o \u00e9 infinito negativo por infinito positivo, o resultado \u00e9 menos infinito. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a446d2cb568ab87f57eb43614c7727e3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{-4x^2+3}{3x+1} = \\cfrac{-4(+\\infty)^2}{3(+\\infty)} =\\cfrac{-4(+\\infty)}{+\\infty}= \\cfrac{-\\infty}{+\\infty}= \\bm{-\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"460\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 4<\/h3>\n<p> Resolva o seguinte limite indeterminado: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-08b74c12124842886ef576ef8c4eeb1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{5x+8}{-5x+2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"115\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste problema, a forma infinita indeterminada sobre o infinito \u00e9 obtida a partir do quociente de dois polin\u00f4mios de mesmo grau, portanto, o resultado do limite indeterminado \u00e9 a divis\u00e3o de seus coeficientes principais: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc2fb0ed175e50d56e670681c136cd17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{5x+8}{-5x+2} = \\cfrac{5(+\\infty)}{-5(+\\infty)} = \\cfrac{+\\infty}{-\\infty}=\\cfrac{5}{-5}= \\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"367\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 5<\/h3>\n<p> Calcule o seguinte limite pelo menos at\u00e9 o infinito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c0431a362c02fce505f4567e28f21fa3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{x^2+3x+5}{x^4-x-6}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"141\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O grau da express\u00e3o alg\u00e9brica do numerador \u00e9 menor que o grau da express\u00e3o do denominador, ent\u00e3o a indetermina\u00e7\u00e3o +\u221e\/+\u221e d\u00e1 0: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-405fbcd016c064f414b043abe04fa768_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{x^2+3x+5}{x^4-x-6} = \\cfrac{(-\\infty)^2}{(-\\infty)^4} = \\cfrac{+\\infty}{+\\infty}= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"316\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 6<\/h3>\n<p> Resolva o seguinte limite indeterminado de uma fun\u00e7\u00e3o com ra\u00edzes: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-159a0cb8cc6c1e4551195c4bb03eacd7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to +\\infty}\\frac{\\sqrt[3]{x^7-4x^3}}{x^2+5x}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"134\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A express\u00e3o para o numerador est\u00e1 sob um radical, ent\u00e3o seu grau \u00e9 7\/3. Por outro lado, o polin\u00f4mio no denominador \u00e9 quadr\u00e1tico. E como 7\/3&gt;2, o limite d\u00e1 mais infinito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-912b218cb8aa2c4bbc93df147bfb4af6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty}\\frac{\\sqrt[3]{x^7-4x^3}}{x^2+5x}=\\frac{\\sqrt[3]{(+\\infty)^7}}{(+\\infty)^2}=\\frac{+\\infty}{+\\infty}=+\\infty\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"348\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 7<\/h3>\n<p> Determine o limite ao infinito da seguinte fun\u00e7\u00e3o com fra\u00e7\u00f5es: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ffef148096d3aa64a2eb5d63e00d2f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x \\to +\\infty} \\cfrac{-2x^2}{5-4x}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"101\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste exerc\u00edcio, a indetermina\u00e7\u00e3o menos infinito dividido por menos infinito \u00e9 obtida com o grau do numerador maior que o grau do denominador, portanto: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0b2dfa8a24dd69065fc8ddcf223321d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{-2x^2}{5-4x} = \\cfrac{-2(+\\infty)^2}{-4(+\\infty)} = \\cfrac{-2(+\\infty)}{-\\infty}= \\cfrac{-\\infty}{-\\infty} =\\bm{+\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"431\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 8<\/h3>\n<p> Encontre o limite pelo menos ao infinito da seguinte fun\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-68566303139abd794f304c979271a058_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{9x}{4-x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"100\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O polin\u00f4mio denominador \u00e9 quadr\u00e1tico, enquanto o polin\u00f4mio numerador \u00e9 linear. Portanto, o infinito da indetermina\u00e7\u00e3o dividido pelo infinito d\u00e1 0. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c5e09be0ae49504103eb4cb5bc2bff7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{9x}{4-x^2} = \\cfrac{9(-\\infty)}{-(-\\infty)^2} = \\cfrac{-\\infty}{-(+\\infty)}=\\cfrac{-\\infty}{-\\infty}= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"374\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 9<\/h3>\n<p> Resolva o limite pelo menos infinito da seguinte fun\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-550b7d336f11ad3346cc238a9f5719db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{-2x^3-3x}{-3x^2+4x-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"163\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O numerador \u00e9 de grau maior que o denominador, ent\u00e3o o resultado da forma indeterminada \u221e\/\u221e ser\u00e1 infinito. Al\u00e9m disso, o sinal do infinito ser\u00e1 negativo porque o positivo dividido pelo negativo d\u00e1 o negativo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9820c6575934eac4bea0f71a98db09b3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{-2x^3-3x}{-3x^2+4x-1} = \\cfrac{-2(-\\infty)^3}{-3(-\\infty)^2} =\\cfrac{-2(-\\infty)}{-3(+\\infty)}= \\cfrac{+\\infty}{-\\infty}= \\bm{-\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"493\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 10<\/h3>\n<p> Resolva o seguinte limite com indetermina\u00e7\u00e3o infinita entre o infinito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5ebe0714beba2eea5d7ab668eb8c75de_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x \\to +\\infty}\\cfrac{2^x-4}{-2x^6+x^4}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"131\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A fun\u00e7\u00e3o exponencial \u00e9 de ordem superior \u00e0 fun\u00e7\u00e3o polinomial, ent\u00e3o o limite dar\u00e1 infinito. Por\u00e9m, dividindo o positivo pelo negativo, o sinal do infinito ser\u00e1 negativo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7917d9ddbc8ccb39774511497bdefb5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x \\to +\\infty}\\frac{2^x-4}{-2x^6+x^4}=\\frac{2^{+\\infty}}{-2(+\\infty)^6}=\\frac{+\\infty}{-\\infty}=\\bm{-\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"350\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 11<\/h3>\n<p> Calcule o seguinte limite: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1aaa5294b445d8033648f190609987c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{x^3-5x}{-x^3-5x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"131\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste problema, a indetermina\u00e7\u00e3o infinito no infinito \u00e9 resolvida dividindo os coeficientes dominantes dos dois polin\u00f4mios, uma vez que s\u00e3o do mesmo grau: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2c768688b8251d2b4313af43af4f746_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to -\\infty} \\cfrac{x^3-5x}{-x^3-5x^2} = \\cfrac{(-\\infty)^3}{-(-\\infty)^3} = \\cfrac{-\\infty}{-(-\\infty)}= \\cfrac{-\\infty}{+\\infty}=\\cfrac{1}{-1}=\\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"467\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 12<\/h3>\n<p> Resolva o limite da seguinte fun\u00e7\u00e3o quando x se aproxima do infinito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1cce696dca9dec8cf7f859d792996b89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{(x+3)^2}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"114\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Embora a inc\u00f3gnita no numerador n\u00e3o seja diretamente elevada ao quadrado, ao resolver a identidade not\u00e1vel podemos ver claramente que o grau do numerador \u00e9 maior que o grau do denominador. Ainda: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b93b4ad05b7c3a78f61fe5af296c8055_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{(x+3)^2}{x}=\\lim_{x \\to +\\infty} \\cfrac{x^2+9+6x}{x} = \\cfrac{(+\\infty)^2}{+\\infty} = \\cfrac{+\\infty}{+\\infty} = \\bm{+\\infty}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"475\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 13<\/h3>\n<p> Calcule o limite ao infinito da seguinte fun\u00e7\u00e3o com raiz c\u00fabica: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f29e7741e7378d96ef63a5da902d185d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[3]{8x^3+1}}{-4x}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"125\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O numerador \u00e9 formado por uma raiz c\u00fabica, ent\u00e3o seu grau \u00e9 3\/3=1. Ent\u00e3o, o grau do numerador \u00e9 igual ao do denominador, ent\u00e3o a indetermina\u00e7\u00e3o infinita entre o infinito \u00e9 resolvida da seguinte forma: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-72958d733b74a32ee99322f4adfefb4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[3]{8x^3+1}}{-4x}= \\cfrac{\\sqrt[3]{8(+\\infty)^3}}{-4(\\infty)}= \\cfrac{+\\infty}{-\\infty}  = \\cfrac{\\sqrt[3]{8}}{-4}=\\cfrac{2}{-4}=\\bm{-}\\mathbf{\\cfrac{1}{2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"444\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 14<\/h3>\n<p> Resolva o limite ao infinito da seguinte fun\u00e7\u00e3o com dois radicais: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66a62b591cedd9d53e14613fc16bca97_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[3]{6x^7+2x^3}}{\\sqrt{x^5-3x^4+2x}}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"173\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O grau do numerador \u00e9 7\/3 = 2,33 e o grau do denominador \u00e9 5\/2 = 2,5. Portanto, como o grau do numerador \u00e9 menor que o grau do denominador, o limite infinito indeterminado entre o infinito \u00e9 0: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-681401701d7d7f3fad1879db26659942_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[3]{6x^7+2x^3}}{\\sqrt{x^5-3x^4+2x}}=\\cfrac{\\sqrt[3]{6(+\\infty)^7}}{\\sqrt{(+\\infty)^5}}=\\cfrac{+\\infty}{+\\infty}=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"50\" width=\"376\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 15<\/h3>\n<p> Calcule o seguinte limite: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fe6ecfeb0afd1ce82003504bdd2222a3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[5]{x^7-2x^5-1}}{4^{x-2}+3x}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"164\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Independentemente do grau do numerador, como temos uma fun\u00e7\u00e3o exponencial no denominador, o resultado da forma indeterminada infinito sobre infinito \u00e9 0: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cc9e15968203ed8d39e04b1f2239b9b5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x \\to +\\infty} \\cfrac{\\sqrt[5]{x^7-2x^5-1}}{4^{x-2}+3x}=\\cfrac{\\sqrt[5]{(+\\infty)^7}}{4^{+\\infty-2}}=\\cfrac{+\\infty}{+\\infty}=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"358\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo explicamos como calcular o infinito da indetermina\u00e7\u00e3o entre o infinito (\u221e\/\u221e). Voc\u00ea encontrar\u00e1 exemplos desta indetermina\u00e7\u00e3o com todos os tipos de fun\u00e7\u00f5es: fun\u00e7\u00f5es polinomiais, radicais, exponenciais, etc. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo de limites que d\u00e3o infinitas indetermina\u00e7\u00f5es entre infinitos. Como resolver a indetermina\u00e7\u00e3o infinita entre infinito &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\"> <span class=\"screen-reader-text\">Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e)<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[16],"tags":[],"class_list":["post-375","post","type-post","status-publish","format-standard","hentry","category-limites-de-funcao"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e) - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-\u221e-\u221e\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e) - Mathority\" \/>\n<meta property=\"og:description\" content=\"Neste artigo explicamos como calcular o infinito da indetermina\u00e7\u00e3o entre o infinito (\u221e\/\u221e). Voc\u00ea encontrar\u00e1 exemplos desta indetermina\u00e7\u00e3o com todos os tipos de fun\u00e7\u00f5es: fun\u00e7\u00f5es polinomiais, radicais, exponenciais, etc. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo de limites que d\u00e3o infinitas indetermina\u00e7\u00f5es entre infinitos. Como resolver a indetermina\u00e7\u00e3o infinita entre infinito &hellip; Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e) Leia mais &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-\u221e-\u221e\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-04T03:00:17+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-77419fd05960300c6e2cd6158cd04e69_l3.png\" \/>\n<meta name=\"author\" content=\"Equipe Mathoridade\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Equipe Mathoridade\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\"},\"author\":{\"name\":\"Equipe Mathoridade\",\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/person\/26defeb7b79f5baaedafa33a1ac6ac00\"},\"headline\":\"Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e)\",\"datePublished\":\"2023-07-04T03:00:17+00:00\",\"dateModified\":\"2023-07-04T03:00:17+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\"},\"wordCount\":1624,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/mathority.org\/pt\/#organization\"},\"articleSection\":[\"Limites de fun\u00e7\u00e3o\"],\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\",\"url\":\"https:\/\/mathority.org\/pt\/indeterminacao-infinita-entre-infinito-%e2%88%9e-%e2%88%9e\/\",\"name\":\"Indetermina\u00e7\u00e3o infinita entre o infinito (\u221e\/\u221e) - 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