{"id":373,"date":"2023-07-04T05:10:26","date_gmt":"2023-07-04T05:10:26","guid":{"rendered":"https:\/\/mathority.org\/pt\/limites-laterais\/"},"modified":"2023-07-04T05:10:26","modified_gmt":"2023-07-04T05:10:26","slug":"limites-laterais","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/limites-laterais\/","title":{"rendered":"Limites laterais"},"content":{"rendered":"<p>Neste artigo explicamos o que \u00e9 o limite lateral de uma fun\u00e7\u00e3o (com exemplos). Tamb\u00e9m ensinamos como calcular os limites laterais esquerdo e direito de uma fun\u00e7\u00e3o, tanto gr\u00e1fica quanto numericamente. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo dos limites laterais. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-son-los-limites-laterales\"><\/span> Quais s\u00e3o os limites laterais?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Os limites laterais de uma fun\u00e7\u00e3o<\/strong> num ponto estudam o comportamento da fun\u00e7\u00e3o em torno desse ponto. Existe o limite lateral esquerdo e o limite lateral direito, que analisa o valor da fun\u00e7\u00e3o \u00e0 esquerda e \u00e0 direita do ponto considerado respectivamente. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"limites-laterales-por-la-izquierda-y-por-la-derecha\"><\/span> Limites laterais esquerdo e direito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Como vimos na defini\u00e7\u00e3o dos limites laterais, existem dois tipos: limites laterais esquerdos e limites laterais direitos.<\/p>\n<p> O limite esquerdo da fun\u00e7\u00e3o \u00e9 expresso por um sinal de menos no ponto onde o limite \u00e9 analisado e, por outro lado, o limite direito \u00e9 indicado pelo sinal de mais. <\/p>\n<div class=\"wp-block-columns are-vertically-aligned-center is-layout-flex wp-container-129\">\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<p class=\"has-text-align-center\"> <strong><u style=\"text-decoration-color:#FF9B28;\">Limite lateral \u00e0 esquerda<\/u><\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3224554094b2418a485786bfbe4db5f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to a^{\\color{orange}\\bm{-}\\color{black}}}f(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"141\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<\/div>\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<p class=\"has-text-align-center\"> <strong><u style=\"text-decoration-color:#FF9B28;\">Limite lateral \u00e0 direita<\/u><\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e2e49ad15a0b5fd2db93797689ea1b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to a^{\\color{orange}\\bm{+}\\color{black}}}f(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"141\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<\/div>\n<\/div>\n<p> Veja o exemplo a seguir para entender melhor o significado dos limites laterais: <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/limites-laterales.webp\" alt=\"limites laterais\" class=\"wp-image-823\" width=\"299\" height=\"314\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<p> Como voc\u00ea pode ver na representa\u00e7\u00e3o gr\u00e1fica desta fun\u00e7\u00e3o por partes, os limites laterais dependem do lado em que s\u00e3o calculados.<\/p>\n<p> Nesse caso, a fun\u00e7\u00e3o se aproxima de 3 quando x se aproxima de 2 pela esquerda, j\u00e1 que a fun\u00e7\u00e3o assume valores mais pr\u00f3ximos de 3 quando <em>x<\/em> se aproxima de x=2 pela sua esquerda.<\/p>\n<p> Por outro lado, o limite lateral da fun\u00e7\u00e3o em x=2 pela reta vale 6. Porque se nos aproximarmos do ponto x=2 pela sua reta, a fun\u00e7\u00e3o assume valores cada vez mais pr\u00f3ximos de f(x)= 6.<\/p>\n<p> Por outro lado, voc\u00ea deve saber que os limites laterais t\u00eam as mesmas propriedades dos limites normais. No link a seguir voc\u00ea pode ver quais s\u00e3o as propriedades dos limites:<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/propriedades-leis-de-limites\/\">propriedades de limite<\/a><\/span><\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"limites-laterales-iguales\"><\/span>limites laterais iguais<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Acabamos de ver um exemplo onde os limites laterais de uma fun\u00e7\u00e3o s\u00e3o diferentes, mas&#8230; o que acontece se os limites laterais forem iguais?<\/p>\n<p> <strong>Se ambos os limites laterais de uma fun\u00e7\u00e3o num ponto existem e s\u00e3o iguais<\/strong> , o limite da fun\u00e7\u00e3o existe nesse ponto e o resultado do limite \u00e9 o valor dos limites laterais.<\/p>\n<p> Em outras palavras, para que o limite de uma fun\u00e7\u00e3o exista em um ponto, a seguinte condi\u00e7\u00e3o deve ser atendida:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1d596fffab33786b9af4466210642acf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to a^-}f(x)=\\lim_{x\\to a^+}f(x)=L \\ \\iff \\ \\lim_{x\\to a}f(x)=L\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"378\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Portanto, se os limites laterais de uma fun\u00e7\u00e3o num ponto forem diferentes, o limite da fun\u00e7\u00e3o nesse ponto n\u00e3o existe.<\/p>\n<p> Al\u00e9m disso, que exista o limite de uma fun\u00e7\u00e3o em um ponto \u00e9 uma condi\u00e7\u00e3o essencial para que ela seja uma <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/continuidade-de-funcao-continua-de-uma-funcao\/\">fun\u00e7\u00e3o cont\u00ednua em um ponto<\/a><\/span> .<\/p>\n<p> Vamos resolver um exemplo para finalizar o entendimento do conceito de limites laterais: <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/continuite-dune-fonction-definie-par-morceaux.webp\" alt=\"\" class=\"wp-image-201\" width=\"429\" height=\"299\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<p> Os limites laterais no ponto x=-2 da fun\u00e7\u00e3o representada graficamente coincidem, pois o valor da fun\u00e7\u00e3o tende para 3 quer nos aproximemos de x=-2 pela esquerda ou pela direita. Portanto, o limite da fun\u00e7\u00e3o em x=-2 \u00e9 igual a 3.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b7e7a7ee82b827ba469558c38fc81a45_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to -2^-}f(x)=\\lim_{x\\to -2^+}f(x)=3 \\ \\longrightarrow \\ \\lim_{x\\to -2}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"389\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Por outro lado, no ponto x=4 os limites laterais s\u00e3o diferentes, pois pela esquerda a fun\u00e7\u00e3o se aproxima de f(x)=3 mas pela direita a fun\u00e7\u00e3o se aproxima de f(x)=2. O limite da fun\u00e7\u00e3o neste ponto, portanto, n\u00e3o existe. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3a52e97ba4cff3c4cd84977fb27db89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 4^-}f(x)=3 \\neq \\lim_{x\\to 4^+}f(x)=2 \\ \\longrightarrow \\ \\cancel{\\exists} \\ \\lim_{x\\to 4}f(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"374\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"calculo-de-limites-laterales\"><\/span> C\u00e1lculo dos limites laterais<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dada a defini\u00e7\u00e3o dos limites laterais, veremos como eles s\u00e3o calculados numericamente resolvendo o seguinte exemplo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42104fdcfcbc6e35486c13774c7288ac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2}\\frac{3}{x-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"74\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Se calcularmos o limite normalmente, obteremos a indetermina\u00e7\u00e3o de um n\u00famero real dividido por 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d98b33a08f3017676e2271bdb0b325d5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2}\\frac{3}{x-2}=\\frac{3}{2-2}=\\frac{3}{0}=\\infty\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"220\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Por\u00e9m, ao calcular os limites laterais, n\u00e3o obtemos nenhuma indetermina\u00e7\u00e3o.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-df0f7477f84abd22a805c7cf70300f16_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}\\frac{3}{x-2}=\\ \\color{red}\\bm{?}\\color{black} \\qquad \\lim_{x\\to 2^+}\\frac{3}{x-2}=\\ \\color{red}\\bm{?}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"378\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Para calcular o limite lateral da fun\u00e7\u00e3o \u00e0 esquerda em x=2, voc\u00ea deve pegar um n\u00famero menor que x=2, mas muito pr\u00f3ximo dele, por exemplo x=1,999.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e3cc43d40eb552932818635f1abcd310_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}\\frac{3}{x-2}=\\frac{3}{\\color{red}\\bm{1,999}\\color{black}-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"252\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> Neste caso o denominador ser\u00e1 um n\u00famero negativo com um valor muito pequeno mas nem sequer zero, e \u00e9 geralmente representado por um zero e um sinal de menos na frente dele:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-32da1df64469d97474fd1b9e25efcd31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}\\frac{3}{x-2}=\\frac{3}{1,999-2}=\\frac{3}{\\color{red}\\bm{-0}\\color{black}}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"302\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> Portanto, o resultado do limite lateral \u00e9 menos infinito, pois qualquer n\u00famero dividido por 0 d\u00e1 infinito, e positivo dividido por negativo d\u00e1 negativo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-44072ab37d2d34b0a1cf8655d4b576c7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}\\frac{3}{x-2}=\\frac{3}{1,999-2}=\\frac{3}{-0}=\\color{red}\\bm{-\\infty}\\color{black}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"358\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> Podemos verificar que a fun\u00e7\u00e3o se aproxima de menos infinito computando imagens da fun\u00e7\u00e3o com valores mais pr\u00f3ximos de x=2 a partir da esquerda.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-97d799f09c2e0890cf3a856bf9c711a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}\\begin{array}{l}f(1,9)=\\cfrac{3}{1,9-2}=-30\\\\[2ex]f(1,99)=\\cfrac{3}{1,99-2}=-300\\\\[2ex]f(1,999)=\\cfrac{3}{1,999-2}=-3000\\\\[2ex]f(1,9999)=\\cfrac{3}{1,9999-2}=-30000\\\\[2ex]f(1,99999)=\\cfrac{3}{1,99999-2}=-300000\\end{array}\\\\[16ex]\\vdots\\\\[1.5ex] f(2^-)=-\\infty\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"317\" width=\"294\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Da mesma forma, para encontrar o limite da fun\u00e7\u00e3o no ponto x=2 \u00e0 direita, podemos aplicar o mesmo racioc\u00ednio: tomamos um valor maior que 2 mas muito pr\u00f3ximo, como 2001.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21cbd07eef353c53bdfa09eaceb6bd25_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^+}\\frac{3}{x-2}=\\frac{3}{2,001-2}=\\frac{3}{+0}=+\\infty\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"292\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> Da mesma forma, podemos verificar que a fun\u00e7\u00e3o tende ao infinito calculando imagens da fun\u00e7\u00e3o com valores cada vez mais pr\u00f3ximos de x=2 \u00e0 direita.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e6d448cdad3ac6ba82e749b30d2bcc11_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}\\begin{array}{l}f(2,1)=\\cfrac{3}{2,1-2}=30\\\\[2ex]f(2,01)=\\cfrac{3}{2,01-2}=300\\\\[2ex]f(2,001)=\\cfrac{3}{2,001-2}=3000\\\\[2ex]f(2,0001)=\\cfrac{3}{2,0001-2}=30000\\\\[2ex]f(2,00001)=\\cfrac{3}{2,00001-2}=300000\\end{array}\\\\[16ex]\\vdots\\\\[1.5ex] f(2^+)=+\\infty\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"317\" width=\"280\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> No gr\u00e1fico a seguir voc\u00ea pode ver representada a fun\u00e7\u00e3o analisada. Como voc\u00ea pode ver, o limite lateral da fun\u00e7\u00e3o no ponto x=2 \u00e0 esquerda \u00e9 menos infinito, e o limite lateral da fun\u00e7\u00e3o no ponto x=2 \u00e0 direita \u00e9 mais infinito. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/representation-graphique-dune-fonction-de-proportionnalite-inverse.webp\" alt=\"\" class=\"wp-image-166\" width=\"508\" height=\"514\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-limites-laterales\"><\/span> Problemas de limite lateral corrigidos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Encontre os limites laterais da seguinte fun\u00e7\u00e3o definida por partes nos pontos onde a defini\u00e7\u00e3o muda (x=-2 ex=4). <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercices-resolus-de-fonctions-definies-par-parties.webp\" alt=\"\" class=\"wp-image-209\" width=\"395\" height=\"307\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Os limites laterais n\u00e3o coincidem no ponto x=-2, \u00e0 esquerda a fun\u00e7\u00e3o tende para f(x)=5 e, por outro lado, \u00e0 direita a fun\u00e7\u00e3o \u00e9 constante e vale 3. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36fbddc8f36db5a92d77dd9e9b3b81ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to -2^-}f(x)=5\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"118\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8e153627ce1a29511f502c30bd599a6e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to -2^+}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"119\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Os limites laterais tamb\u00e9m s\u00e3o diferentes \u00e0 medida que x se aproxima de 4. A fun\u00e7\u00e3o por partes se aproxima de 3 pela esquerda, mas se aproxima de -2 pela direita. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c590b4da48c82d7a43ef65e89b3e9977_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 4^-}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"109\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a4d4c175b4f2e5ecfe44fb41fe420820_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 4^+}f(x)=-2\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"121\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Determine se o limite existe quando x se aproxima de 3 da seguinte fun\u00e7\u00e3o por partes e, em caso afirmativo, qual \u00e9 o seu valor. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/limites-laterales-dune-fonction-par-morceaux.webp\" alt=\"Limites laterais de uma fun\u00e7\u00e3o por partes\" class=\"wp-image-866\" width=\"337\" height=\"303\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste problema, os limites laterais no ponto x=3 \u00e0 esquerda e \u00e0 direita s\u00e3o id\u00eanticos, pois a fun\u00e7\u00e3o tende para o mesmo valor (f(x)=3) quer seja abordada pela esquerda ou pela direita . seu lado direito: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d8f2aea7db3ddf52e74f09960dd15629_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 3^-}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"109\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ee9606c4d6e820e4ac3bb5fa5aa3575_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 3^+}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"108\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, de acordo com a defini\u00e7\u00e3o matem\u00e1tica do limite, o limite da fun\u00e7\u00e3o quando x tende a 3 \u00e9 igual a 3, porque os dois limites laterais neste mesmo ponto coincidem neste valor:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f82de582de8671680e14cfbf92001010_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 3^-}f(x)=\\lim_{x\\to 3^+}f(x)=3 \\ \\longrightarrow \\ \\lim_{x\\to 3}f(x)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"357\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Embora o limite da fun\u00e7\u00e3o em x=3 seja 3, deve-se levar em conta que a fun\u00e7\u00e3o neste ponto n\u00e3o \u00e9 3, mas sim que f(3)=7. Como veremos mais tarde, isto significa que a fun\u00e7\u00e3o n\u00e3o \u00e9 cont\u00ednua em x=3, mas sim tem uma descontinuidade evit\u00e1vel.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Calcule os limites laterais da seguinte fun\u00e7\u00e3o racional no ponto x=4. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5eff7e2ff1b4df8ee2ec49b7db80a18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\cfrac{-2x+3}{x-4}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"132\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para calcular o limite quando x tende para 4 pela esquerda, tomamos um valor menor que 4, mas muito pr\u00f3ximo dele, por exemplo 3.999:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-845fc23ff2883308a9b535c84cd69d83_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 4^-}\\frac{-2x+3}{x-4}=\\frac{-2\\cdot 3,999+3}{3,999-4}=\\frac{-4,998}{-0}=+\\infty\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"385\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, o limite lateral quando x se aproxima de 4 pela esquerda \u00e9 mais infinito.<\/p>\n<p class=\"has-text-align-left\"> E para resolver o limite quando x tende para 4 pela direita, avaliamos a fun\u00e7\u00e3o em um valor maior que 4 mas muito pr\u00f3ximo dele, por exemplo 4.001:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef680d721aae4b9b993bbc65542d5d2b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 4^+}\\frac{-2x+3}{x-4}=\\frac{-2\\cdot 4,001+3}{4,001-4}=\\frac{-5,002}{+0}=-\\infty\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"385\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, o limite lateral quando x se aproxima de 4 pela direita \u00e9 menos infinito.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 4<\/h3>\n<p> Encontre o limite, se existir, da seguinte fun\u00e7\u00e3o por partes definida no ponto x=2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-40d5632016e70b9d9ab8e46e76e0102b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\left\\{ \\begin{array}{lcl} x^2-3 &amp; \\text{si} &amp;  x \\leq 2 \\\\[2ex]\\displaystyle \\frac{-3x+5}{x-3} &amp; \\text{si} &amp; x>2 \\end{array} \\right.&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;75&#8243; width=&#8221;235&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste caso, a defini\u00e7\u00e3o do problema pede-nos para determinar o limite onde a fun\u00e7\u00e3o por partes muda de express\u00e3o, por isso precisamos de determinar o limite no lado esquerdo utilizando a primeira express\u00e3o e o limite no lado direito utilizando a segunda express\u00e3o. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-312aa6dc645115b9d1a680ef3cc5fb9b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}f(x)=\\lim_{x\\to 2^-}(x^2-3)=2^2-3=1\" title=\"Rendered by QuickLaTeX.com\" height=\"30\" width=\"303\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cad9d8ff045408344a1435ec6441aa73_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^+}f(x)=\\lim_{x\\to 2^+}\\frac{-3x+5}{x-3}=\\frac{-3\\cdot 2+5}{2-3}=\\frac{-1}{-1}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"392\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> O limite da fun\u00e7\u00e3o em x=2 \u00e0 esquerda coincide com o limite da fun\u00e7\u00e3o \u00e0 direita, ent\u00e3o o limite da fun\u00e7\u00e3o existe e \u00e9 igual a 1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fe286d19fdb8b3f5859e8073869660ae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 2^-}f(x)=\\lim_{x\\to 2^+}f(x)=1 \\ \\longrightarrow \\ \\lim_{x\\to 2}f(x)=1\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"356\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo explicamos o que \u00e9 o limite lateral de uma fun\u00e7\u00e3o (com exemplos). Tamb\u00e9m ensinamos como calcular os limites laterais esquerdo e direito de uma fun\u00e7\u00e3o, tanto gr\u00e1fica quanto numericamente. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo dos limites laterais. Quais s\u00e3o os limites laterais? Os limites laterais de uma &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/limites-laterais\/\"> <span class=\"screen-reader-text\">Limites laterais<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[16],"tags":[],"class_list":["post-373","post","type-post","status-publish","format-standard","hentry","category-limites-de-funcao"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Limites laterais - Matoridade<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/limites-laterais\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Limites laterais - Matoridade\" \/>\n<meta property=\"og:description\" content=\"Neste artigo explicamos o que \u00e9 o limite lateral de uma fun\u00e7\u00e3o (com exemplos). Tamb\u00e9m ensinamos como calcular os limites laterais esquerdo e direito de uma fun\u00e7\u00e3o, tanto gr\u00e1fica quanto numericamente. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo dos limites laterais. Quais s\u00e3o os limites laterais? Os limites laterais de uma &hellip; Limites laterais Leia mais &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/pt\/limites-laterais\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-04T05:10:26+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3224554094b2418a485786bfbe4db5f1_l3.png\" \/>\n<meta name=\"author\" content=\"Equipe Mathoridade\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Equipe Mathoridade\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/\"},\"author\":{\"name\":\"Equipe Mathoridade\",\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/person\/26defeb7b79f5baaedafa33a1ac6ac00\"},\"headline\":\"Limites laterais\",\"datePublished\":\"2023-07-04T05:10:26+00:00\",\"dateModified\":\"2023-07-04T05:10:26+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/\"},\"wordCount\":1231,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/mathority.org\/pt\/#organization\"},\"articleSection\":[\"Limites de fun\u00e7\u00e3o\"],\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/mathority.org\/pt\/limites-laterais\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/\",\"url\":\"https:\/\/mathority.org\/pt\/limites-laterais\/\",\"name\":\"Limites laterais - Matoridade\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/pt\/#website\"},\"datePublished\":\"2023-07-04T05:10:26+00:00\",\"dateModified\":\"2023-07-04T05:10:26+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/#breadcrumb\"},\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mathority.org\/pt\/limites-laterais\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mathority.org\/pt\/limites-laterais\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mathority.org\/pt\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Limites laterais\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mathority.org\/pt\/#website\",\"url\":\"https:\/\/mathority.org\/pt\/\",\"name\":\"Mathority\",\"description\":\"Onde a curiosidade encontra o c\u00e1lculo!\",\"publisher\":{\"@id\":\"https:\/\/mathority.org\/pt\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mathority.org\/pt\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/mathority.org\/pt\/#organization\",\"name\":\"Mathority\",\"url\":\"https:\/\/mathority.org\/pt\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/mathority.org\/pt\/wp-content\/uploads\/2023\/10\/mathority-logo.png\",\"contentUrl\":\"https:\/\/mathority.org\/pt\/wp-content\/uploads\/2023\/10\/mathority-logo.png\",\"width\":703,\"height\":151,\"caption\":\"Mathority\"},\"image\":{\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/person\/26defeb7b79f5baaedafa33a1ac6ac00\",\"name\":\"Equipe Mathoridade\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/mathority.org\/pt\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"caption\":\"Equipe Mathoridade\"},\"sameAs\":[\"http:\/\/mathority.org\/pt\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Limites laterais - Matoridade","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mathority.org\/pt\/limites-laterais\/","og_locale":"pt_BR","og_type":"article","og_title":"Limites laterais - Matoridade","og_description":"Neste artigo explicamos o que \u00e9 o limite lateral de uma fun\u00e7\u00e3o (com exemplos). Tamb\u00e9m ensinamos como calcular os limites laterais esquerdo e direito de uma fun\u00e7\u00e3o, tanto gr\u00e1fica quanto numericamente. Al\u00e9m disso, voc\u00ea poder\u00e1 treinar com exerc\u00edcios resolvidos passo a passo dos limites laterais. Quais s\u00e3o os limites laterais? Os limites laterais de uma &hellip; Limites laterais Leia mais &raquo;","og_url":"https:\/\/mathority.org\/pt\/limites-laterais\/","article_published_time":"2023-07-04T05:10:26+00:00","og_image":[{"url":"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3224554094b2418a485786bfbe4db5f1_l3.png"}],"author":"Equipe Mathoridade","twitter_card":"summary_large_image","twitter_misc":{"Escrito por":"Equipe Mathoridade","Est. tempo de leitura":"6 minutos"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/mathority.org\/pt\/limites-laterais\/#article","isPartOf":{"@id":"https:\/\/mathority.org\/pt\/limites-laterais\/"},"author":{"name":"Equipe Mathoridade","@id":"https:\/\/mathority.org\/pt\/#\/schema\/person\/26defeb7b79f5baaedafa33a1ac6ac00"},"headline":"Limites laterais","datePublished":"2023-07-04T05:10:26+00:00","dateModified":"2023-07-04T05:10:26+00:00","mainEntityOfPage":{"@id":"https:\/\/mathority.org\/pt\/limites-laterais\/"},"wordCount":1231,"commentCount":0,"publisher":{"@id":"https:\/\/mathority.org\/pt\/#organization"},"articleSection":["Limites de fun\u00e7\u00e3o"],"inLanguage":"pt-BR","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/mathority.org\/pt\/limites-laterais\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/mathority.org\/pt\/limites-laterais\/","url":"https:\/\/mathority.org\/pt\/limites-laterais\/","name":"Limites laterais - Matoridade","isPartOf":{"@id":"https:\/\/mathority.org\/pt\/#website"},"datePublished":"2023-07-04T05:10:26+00:00","dateModified":"2023-07-04T05:10:26+00:00","breadcrumb":{"@id":"https:\/\/mathority.org\/pt\/limites-laterais\/#breadcrumb"},"inLanguage":"pt-BR","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mathority.org\/pt\/limites-laterais\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/mathority.org\/pt\/limites-laterais\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mathority.org\/pt\/"},{"@type":"ListItem","position":2,"name":"Limites laterais"}]},{"@type":"WebSite","@id":"https:\/\/mathority.org\/pt\/#website","url":"https:\/\/mathority.org\/pt\/","name":"Mathority","description":"Onde a curiosidade encontra o c\u00e1lculo!","publisher":{"@id":"https:\/\/mathority.org\/pt\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mathority.org\/pt\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"pt-BR"},{"@type":"Organization","@id":"https:\/\/mathority.org\/pt\/#organization","name":"Mathority","url":"https:\/\/mathority.org\/pt\/","logo":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/mathority.org\/pt\/#\/schema\/logo\/image\/","url":"https:\/\/mathority.org\/pt\/wp-content\/uploads\/2023\/10\/mathority-logo.png","contentUrl":"https:\/\/mathority.org\/pt\/wp-content\/uploads\/2023\/10\/mathority-logo.png","width":703,"height":151,"caption":"Mathority"},"image":{"@id":"https:\/\/mathority.org\/pt\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/mathority.org\/pt\/#\/schema\/person\/26defeb7b79f5baaedafa33a1ac6ac00","name":"Equipe Mathoridade","image":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/mathority.org\/pt\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","caption":"Equipe Mathoridade"},"sameAs":["http:\/\/mathority.org\/pt"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/posts\/373","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/comments?post=373"}],"version-history":[{"count":0,"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/posts\/373\/revisions"}],"wp:attachment":[{"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/media?parent=373"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/categories?post=373"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mathority.org\/pt\/wp-json\/wp\/v2\/tags?post=373"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}