{"id":32,"date":"2023-09-17T11:02:19","date_gmt":"2023-09-17T11:02:19","guid":{"rendered":"https:\/\/mathority.org\/pt\/derivada-do-arco-tangente-1\/"},"modified":"2023-09-17T11:02:19","modified_gmt":"2023-09-17T11:02:19","slug":"derivada-do-arco-tangente-1","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/derivada-do-arco-tangente-1\/","title":{"rendered":"Derivada do arco tangente"},"content":{"rendered":"<p>Neste artigo, voc\u00ea aprender\u00e1 como derivar o arco tangente de uma fun\u00e7\u00e3o. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos desse tipo de derivada e at\u00e9 praticar com exerc\u00edcios resolvidos sobre a derivada do arco tangente. Por fim, mostramos tamb\u00e9m a prova da f\u00f3rmula da derivada do arco tangente. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfcual-es-la-derivada-del-arcotangente\"><\/span> Qual \u00e9 a derivada do arco tangente?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>A derivada do arco tangente de x \u00e9 um sobre um mais x ao quadrado.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cdeb5e29b862b8b9d5bc9f4c2c747106_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{1}{1+x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"404\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Portanto, a <strong>derivada do arco tangente de uma fun\u00e7\u00e3o<\/strong> \u00e9 igual ao quociente da derivada dessa fun\u00e7\u00e3o dividido por um mais a referida fun\u00e7\u00e3o ao quadrado.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c6546edbf0ff2d0ccba20a7fac11b89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{u'}{1+u^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"404\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Neste caso, a fun\u00e7\u00e3o foi representada por au, ent\u00e3o esta seria a f\u00f3rmula da derivada do arco tangente da fun\u00e7\u00e3o u. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/derivee-arctangente.webp\" alt=\"derivado do arco tangente\" class=\"wp-image-1997\" width=\"389\" height=\"296\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Como voc\u00ea pode ver, a f\u00f3rmula da derivada da tangente inversa \u00e9 muito semelhante \u00e0s f\u00f3rmulas das derivadas do arco seno e do arco cosseno. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplos-de-la-derivada-del-arcotangente\"><\/span> Exemplos de derivada do arco tangente<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Uma vez conhecida a f\u00f3rmula da derivada do arco tangente, explicaremos a deriva\u00e7\u00e3o de v\u00e1rios exemplos deste tipo de derivadas trigonom\u00e9tricas. Dessa forma, ser\u00e1 mais f\u00e1cil entender como o arco tangente de uma fun\u00e7\u00e3o \u00e9 derivado. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-1-derivada-del-arcotangente-de-2x\"><\/span> Exemplo 1: Derivada do arco tangente de 2x<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3c8877ac889f77baa22f66d4b2568418_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(2x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"139\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Aplicamos a f\u00f3rmula para resolver a derivada:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c6546edbf0ff2d0ccba20a7fac11b89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{u'}{1+u^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"404\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> A derivada de 2x \u00e9 2, ent\u00e3o a derivada arco tangente de 2x \u00e9 2 sobre um mais 2x ao quadrado: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2a5ff151a4471bb769c46ac896ee0ca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(2x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{2}{1+(2x)^2}}=\\cfrac{2}{1+ 4x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"518\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-2-derivada-del-arcotangente-de-x-al-cuadrado\"><\/span> Exemplo 2: Derivada do arco tangente de x ao quadrado<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3f62897c299972bd734ffe87b6d28e84_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(x^2)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"138\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Para encontrar o resultado da derivada deste exemplo, precisamos usar a f\u00f3rmula da derivada do arco tangente, que \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c6546edbf0ff2d0ccba20a7fac11b89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{u'}{1+u^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"404\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Assim, a derivada da fun\u00e7\u00e3o x <sup>2<\/sup> \u00e9 2x, ent\u00e3o a derivada do arco tangente de x elevado \u00e0 pot\u00eancia de 2 \u00e9: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4518d6b8df16464b2a763eb7d736504d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(x^2) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{2x}{1+\\left(x^2\\right)^2}=\\cfrac{2x}{1+x^4}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"507\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-3-derivada-del-arcotangente-del-seno-de-x\"><\/span> Exemplo 3: Derivada do arco tangente do seno de x<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-72df0a729eefc917694a84ecccd4a959_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}\\bigl(\\text{sen}(x)\\bigr)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"170\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Logicamente, para calcular a derivada deve-se aplicar a f\u00f3rmula correspondente:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c6546edbf0ff2d0ccba20a7fac11b89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{u'}{1+u^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"404\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Neste caso temos uma fun\u00e7\u00e3o composta, portanto devemos aplicar a regra da cadeia para calcular a derivada do arco tangente: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f3897b362bb6b4681404918f45e91565_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{arctan}\\bigl(\\text{sen}(x)\\bigr) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\cfrac{\\text{cos}(x)}{1+\\text{sen}^2(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"482\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-derivada-del-arcotangente\"><\/span> Exerc\u00edcios resolvidos sobre a derivada do arco tangente<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Derive as seguintes fun\u00e7\u00f5es arco tangente: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23cb449bba097b71c6154e6bfd755940_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{A) } f(x)=\\text{arctan}(x^3)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"164\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ec295f2cfb72911775d2bc47d379e11_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{B) } f(x)=\\cfrac{\\text{arctan}(3x^4)}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"175\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5e54c5dc5ee8464186009da410740df5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{C) } f(x)=\\text{arctan}(x^5-3x^3+10)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"252\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b63b4e04e749c7b7d4cfecca4391eee7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{D) }f(x)=\\text{arctan}^3(4x^2)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"181\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c72a415d8c2e54870c4dc2e92344cef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{E) }f(x)=\\text{arctan}\\bigl(\\ln(x)\\bigr)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"185\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4fad4c5f97c1492b8ad5df06b165d2c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{F) } f(x)=\\text{arctan}\\left(\\sqrt{x^2+2x}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"32\" width=\"227\" style=\"vertical-align: -11px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong> <\/div>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-effa4065c7c98ae655b2cc5bdf14ca07_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{A) } f'(x)=\\cfrac{3x^2}{1+\\left(x^3\\right)^2}=\\cfrac{3x^2}{1+x^6}\" title=\"Rendered by QuickLaTeX.com\" height=\"49\" width=\"235\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2de05c8d708d379982abc8461f5d8706_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{B) } f'(x)=\\cfrac{12x^3}{2\\left(1+\\left(3x^4\\right)^2\\right)}=\\cfrac{6x^3}{1+9x^8}\" title=\"Rendered by QuickLaTeX.com\" height=\"59\" width=\"285\" style=\"vertical-align: -30px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d72faae19f9b5cd7a8d53364bcf9817a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{C) } f'(x)=\\cfrac{5x^4-9x^2}{1+\\left(x^5-3x^3+10\\right)^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"49\" width=\"248\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ea7d5ff105b7432c2756cdcbf44e311b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{D) } f'(x)=3\\text{arctan}^2(4x^2)\\cdot \\cfrac{8x}{1+\\left(4x^2\\right)^2}=\\cfrac{24x\\cdot\\text{arctan}^2(4x^2)}{1+16x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"49\" width=\"453\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6eefb865fce5124f8326d122437c3124_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{E) } f'(x)=\\cfrac{\\cfrac{1}{x}}{1+\\bigl(\\ln(x)\\bigr)^2}=\\cfrac{1}{x\\left(1+\\ln^2(x)\\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"68\" width=\"315\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6faff8aba659922b2cfc784a4f3dae4f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{F) } f'(x)=\\cfrac{1}{1+\\left(\\sqrt{x^2+2x}\\right)^2}\\cdot \\cfrac{2x+2}{2\\sqrt{x^2+2x}}=\\cfrac{x+1}{\\left(1+x^2+2x\\right)\\sqrt{x^2+2x}}\" title=\"Rendered by QuickLaTeX.com\" height=\"59\" width=\"524\" style=\"vertical-align: -33px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"demostracion-de-la-formula-de-la-derivada-del-arcotangente\"><\/span>Demonstra\u00e7\u00e3o da f\u00f3rmula da derivada do arco tangente<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A seguir, provaremos a f\u00f3rmula da derivada do arco tangente.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-88c05a50eddb183a57270676d6ebc5cb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y=\\text{arctan}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"105\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Primeiro convertemos o arco tangente em tangente aproveitando o fato de que o arco tangente \u00e9 a fun\u00e7\u00e3o inversa da tangente:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e806041dd9dbc7cf01bb34014aa18d59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\text{tan}(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Diferenciamos os dois lados da equa\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ca9f080338b9ab014e272f81395146ca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1=\\cfrac{1}{\\text{cos}^2(y)}\\cdot y'\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"114\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> N\u00f3s apagamos e&#8217;:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-05c04d0ce365d8bd7848d4923038778c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\text{cos}^2(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"91\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Por outro lado, gra\u00e7as \u00e0 identidade trigonom\u00e9trica fundamental sabemos que a soma dos quadrados do seno e do cosseno \u00e9 igual a 1. Podemos portanto transformar a express\u00e3o anterior numa fra\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-34f7d2ec2a5836c843db8adea73d021f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}^2(y)+\\text{cos}^2(y)=1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"163\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d5314e15fe7e8ff7c9155906e7725483_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\cfrac{\\text{cos}^2(y)}{1}=\\cfrac{\\text{cos}^2(y)}{\\text{sen}^2(y)+\\text{cos}^2(y)}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"252\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Dividimos todos os termos pelo quadrado do cosseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-39e03a87b9a62ab2db6a56192e44f531_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\cfrac{\\cfrac{\\text{cos}^2(y)}{\\text{cos}^2(y)}}{\\cfrac{\\text{sen}^2(y)}{\\text{cos}^2(y)}+\\cfrac{\\text{cos}^2(y)}{\\text{cos}^2(y)}}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"176\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cf88afedfff6a5c53ffb31df510b4ed_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\cfrac{1}{\\cfrac{\\text{sen}^2(y)}{\\text{cos}^2(y)}+1}\" title=\"Rendered by QuickLaTeX.com\" height=\"70\" width=\"128\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p> O seno dividido pelo cosseno \u00e9 igual \u00e0 tangente, ent\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dbf6d65fa67f0a2161bd99ee7431f015_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x)=\\cfrac{\\text{sen}(x)}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"124\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-db914ed4a068a6dff2598b981b1682d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\cfrac{1}{\\text{tan}^2(y)+1}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"126\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Como vimos acima, a tangente equivale \u00e0 vari\u00e1vel x, podemos portanto substituir a express\u00e3o para chegar \u00e0 f\u00f3rmula da derivada do arco tangente:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-61292316edd6cef99a6135989713cd22_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y'=\\cfrac{1}{x^2+1}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"88\" style=\"vertical-align: -14px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo, voc\u00ea aprender\u00e1 como derivar o arco tangente de uma fun\u00e7\u00e3o. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos desse tipo de derivada e at\u00e9 praticar com exerc\u00edcios resolvidos sobre a derivada do arco tangente. Por fim, mostramos tamb\u00e9m a prova da f\u00f3rmula da derivada do arco tangente. Qual \u00e9 a derivada do arco tangente? A &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/derivada-do-arco-tangente-1\/\"> <span class=\"screen-reader-text\">Derivada do arco tangente<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[11],"tags":[],"class_list":["post-32","post","type-post","status-publish","format-standard","hentry","category-derivados"],"yoast_head":"<!-- This site is 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