{"id":30,"date":"2023-09-17T11:02:59","date_gmt":"2023-09-17T11:02:59","guid":{"rendered":"https:\/\/mathority.org\/pt\/deriva-do-cosseno\/"},"modified":"2023-09-17T11:02:59","modified_gmt":"2023-09-17T11:02:59","slug":"deriva-do-cosseno","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/deriva-do-cosseno\/","title":{"rendered":"Derivada de cosseno"},"content":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como derivar a fun\u00e7\u00e3o cosseno (f\u00f3rmula). Voc\u00ea poder\u00e1 ver exemplos de derivadas de fun\u00e7\u00f5es cosseno e praticar exerc\u00edcios passo a passo. Al\u00e9m disso, mostramos a prova da f\u00f3rmula, qual \u00e9 a segunda derivada do cosseno e at\u00e9 mesmo a derivada do cosseno inverso. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfcual-es-la-derivada-del-coseno\"><\/span> Qual \u00e9 a derivada do cosseno?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>A derivada da fun\u00e7\u00e3o cosseno \u00e9 a fun\u00e7\u00e3o seno com sinal modificado. Em outras palavras, a derivada do cosseno de x \u00e9 igual a menos o seno de x.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-72551067d650b8d3797bc37497ec609d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"389\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Se houver uma fun\u00e7\u00e3o no argumento do cosseno, a derivada do cosseno \u00e9 o produto de menos o seno dessa fun\u00e7\u00e3o vezes a derivada da fun\u00e7\u00e3o.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccc4f6fce30c027f8782a296a44b84b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"416\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> A segunda f\u00f3rmula \u00e9 equivalente \u00e0 primeira f\u00f3rmula, mas aplicando a regra da cadeia. Ent\u00e3o, em resumo, a f\u00f3rmula da derivada do cosseno \u00e9 a seguinte: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/derivee-du-cosinus.webp\" alt=\"derivada de cosseno\" class=\"wp-image-1902\" width=\"428\" height=\"292\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplos-de-la-derivada-del-coseno\"><\/span> Exemplos de derivadas de cosseno<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Agora que sabemos o que \u00e9 a f\u00f3rmula do cosseno, explicaremos v\u00e1rios exemplos desse tipo de derivadas trigonom\u00e9tricas para que voc\u00ea n\u00e3o tenha d\u00favidas sobre como derivar a fun\u00e7\u00e3o cosseno. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-1-derivada-del-coseno-de-2x\"><\/span> Exemplo 1: Derivada do cosseno de 2x<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-87c696135df266b2d8498b353bf03c36_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(2x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"114\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> No argumento do cosseno n\u00e3o temos um \u00fanico x, mas sim uma fun\u00e7\u00e3o mais complexa. Portanto, precisamos usar a seguinte f\u00f3rmula para derivar o cosseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccc4f6fce30c027f8782a296a44b84b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"416\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Como a derivada de 2x \u00e9 2, a derivada do cosseno de 2x ser\u00e1 menos o seno de 2x multiplicado por 2. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ba75c906f1694fe3fbd16fa61e0d288e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(2x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(2x)\\cdot 2=-2\\text{sen}(2x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"532\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-2-derivada-del-coseno-de-x-al-cuadrado\"><\/span> Exemplo 2: Derivada do cosseno de x ao quadrado<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-89f1a1fc3f2d5e95aafbd2a37282f88c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(x^2)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"113\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Como no exemplo anterior, no argumento do cosseno temos uma fun\u00e7\u00e3o diferente de x, ent\u00e3o usaremos a regra da cadeia para derivar o cosseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccc4f6fce30c027f8782a296a44b84b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"416\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Ent\u00e3o, a derivada de x <sup>2<\/sup> \u00e9 2x, portanto, a derivada do cosseno de x elevado \u00e0 pot\u00eancia de 2 \u00e9: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a410f3316194c86b97a987b0ec7e9e6a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(x^2) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(x^2)\\cdot 2x\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"437\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-3-derivada-del-coseno-al-cubo\"><\/span> Exemplo 3: Derivada do cosseno ao cubo<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dfa2e76d23ef3aeb2ab3ff8e20e2aa07_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}^3(2x^6-5x^3)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"178\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> A fun\u00e7\u00e3o cosseno neste exemplo \u00e9 composta por outra fun\u00e7\u00e3o, portanto precisamos aplicar a seguinte f\u00f3rmula para resolver a derivada:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccc4f6fce30c027f8782a296a44b84b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\text{sen}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"416\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Assim, aplicando a f\u00f3rmula, chegamos \u00e0 derivada da fun\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-73284bcfb1d5647b2304e323e7fbaedf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}f'(x)&amp;=3\\text{cos}^2(2x^6-5x^3)\\cdot \\bigl(-\\text{sen}(2x^6-5x^3)\\bigr)\\cdot (12x^5-15x^2)\\\\[2ex]&amp;=-3\\text{cos}^2(2x^6-5x^3)\\cdot \\text{sen}(2x^6-5x^3)\\cdot (12x^5-15x^2)\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"467\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <u style=\"text-decoration-color:#ff951b;\">Para derivar esta fun\u00e7\u00e3o, voc\u00ea tamb\u00e9m deve usar a f\u00f3rmula da<\/u> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/derivada-de-uma-funcao-potencial-de-potencia\/\">derivada de uma fun\u00e7\u00e3o potencial<\/a><\/span> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"segunda-derivada-del-coseno\"><\/span> Segunda derivada do cosseno<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A seguir veremos que a segunda derivada do seno pode ser facilmente calculada, gra\u00e7as \u00e0s caracter\u00edsticas das fun\u00e7\u00f5es trigonom\u00e9tricas.<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <u style=\"text-decoration-color:#ff951b;\"><strong>Nota:<\/strong> Para entender o seguinte, voc\u00ea precisa saber<\/u> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/derivada-sinusal\/\">qual \u00e9 a derivada do seno<\/a><\/span> .<\/p>\n<p> <strong>A segunda derivada do cosseno de x \u00e9 menos o cosseno de x.<\/strong> Isto pode parecer estranho, mas matematicamente \u00e9 assim. Na verdade, a derivada do seno \u00e9 o cosseno e, portanto, diferenciando duas vezes o cosseno de x, o cosseno \u00e9 novamente obtido, mas com um sinal modificado.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d0d9dda8a4031c367120b1f950da4391_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}f(x)=\\text{cos}(x)\\\\[1.5ex] \\quad\\color{orange}\\bm{\\downarrow}\\quad\\color{black} \\\\[1.5ex] f'(x)=-\\text{sen}(x)\\\\[2ex] \\quad\\color{orange}\\bm{\\downarrow}\\quad\\color{black} \\\\[1.5ex] f''(x)=-\\text{cos}(x)\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"157\" width=\"132\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Esta propriedade muda se o argumento do cosseno n\u00e3o for x, pois neste caso arrastamos o termo da regra da cadeia: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-83d86bd6508f06b0723153b3b9254c1f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}f(x)=\\text{cos}(u)\\\\[1.5ex] \\quad\\color{orange}\\bm{\\downarrow}\\quad\\color{black} \\\\[1.5ex] f'(x)=-\\text{sen}(u)\\cdot u' \\\\[1.5ex] \\quad\\color{orange}\\bm{\\downarrow}\\quad\\color{black} \\\\[1.5ex] f''(x)=-\\text{cos}(u)\\cdot u'^2 -\\text{sen}(u)\\cdot u'' \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"153\" width=\"263\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"derivada-del-coseno-inverso\"><\/span> Derivada do cosseno inverso<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Todas as fun\u00e7\u00f5es trigonom\u00e9tricas t\u00eam uma fun\u00e7\u00e3o inversa e, como tal, a fun\u00e7\u00e3o cosseno tamb\u00e9m pode ser invertida. Da mesma forma, o cosseno inverso \u00e9 diferenci\u00e1vel.<\/p>\n<p> A <strong>derivada do cosseno inverso<\/strong> de uma fun\u00e7\u00e3o \u00e9 menos a derivada da fun\u00e7\u00e3o dividida pela raiz quadrada de um menos o quadrado da referida fun\u00e7\u00e3o.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-307f91156ee9c404e9c1a1c0de56b102_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}^{-1}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\cfrac{u'}{\\sqrt{1-u^2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"425\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> Lembre-se de que o cosseno inverso tamb\u00e9m \u00e9 chamado de arco cosseno.<\/p>\n<p> Por exemplo, a derivada do cosseno inverso de 3x \u00e9: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7ce426dcd95d21e43b182ef593520c16_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{cos}^{-1}(3x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=-\\cfrac{3}{\\sqrt{1-(3x)^2}}=-\\cfrac{3}{\\sqrt{1-9x^2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"571\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-derivada-del-coseno\"><\/span> Exerc\u00edcios resolvidos sobre a derivada do cosseno<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Calcule a derivada das seguintes fun\u00e7\u00f5es cosseno: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c1caebbb3b9acfa8cd25721299f9a22e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{A) } f(x)=\\text{cos}(4x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"140\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a89d6e415addae7423aa75362416686b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{B) } f(x)=\\text{cos}(2x^3-5x+1)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"218\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dad34285ad7ac07f34ef408c65cbb96c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{C) } \\displaystyle f(x)=9\\text{cos}\\left(\\frac{x}{3}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"33\" width=\"152\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-752bff297c20cdf69d6fcb45290be935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{D) } f(x)=\\text{cos}^5(x^2+3x)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"187\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-939dee8bcafba3f55812c5a13f27a309_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{E) } f(x)=\\text{cos}\\left(e^{5x}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"148\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6c7c3c5786d010b99f4e65b692dfe1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{F) } \\displaystyle f(x)=9\\text{cos}\\left(\\frac{e^x}{5x}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"164\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong> <\/div>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8a3e1b1b2fe486d1c432a075c0028b62_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{A) } f'(x)=-\\text{sen}(4x)\\cdot 4 =-4\\text{sen}(4x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"285\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8bc2f2e1676bb5f0d4ca231bd35b2b12_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{B) } f'(x)=-\\text{sen}(2x^3-5x+1)\\cdot (6x^2-5)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"321\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cc5cf86d30b34d4cd1a794a4d2ee6a5e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{C) } \\displaystyle f'(x)=-9\\text{sen}\\left(\\frac{x}{3}\\right)\\cdot \\frac{1}{3} =-3\\text{sen}\\left(\\frac{x}{3}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"306\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f168f2e897b18c662f567a25ff09e881_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{D) } f'(x)=-5\\text{cos}^4(x^2+3x)\\cdot \\text{sen}(x^2+3x)\\cdot (2x+3)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"401\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fe49736d7a1ce1736679e8c25bc4a66b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{E) } f'(x)=-\\text{sen}\\left(e^{5x}\\right)\\cdot e^{5x}\\cdot 5=-5\\text{sen}\\left(e^{5x}\\right)\\cdot e^{5x}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"377\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9f4645fb77435daec6f696cffbd54884_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}\\text{F) }\\displaystyle f'(x)&amp;=-9\\text{sen}\\left(\\frac{e^x}{5x}\\right)\\cdot \\frac{e^x\\cdot 5x-e^x\\cdot 5}{(5x)^2}\\\\[2ex]&amp;=-9\\text{sen}\\left(\\frac{e^x}{5x}\\right)\\cdot \\frac{5e^x(x-1)}{25x^2}\\\\[2ex]&amp;=-9\\text{sen}\\left(\\frac{e^x}{5x}\\right)\\cdot \\frac{e^x(x-1)}{5x^2}\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"172\" width=\"310\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"demostracion-de-la-derivada-del-coseno\"><\/span> Prova da derivada do cosseno<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Por fim, demonstraremos matematicamente a f\u00f3rmula da derivada do cosseno de x. Para isso, utilizaremos a defini\u00e7\u00e3o da derivada, que corresponde ao seguinte limite:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc1699622d128f888c1f20599aeccf60_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\lim_{h \\to 0}\\frac{f(x+h)-f(x)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"219\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Vamos provar o cosseno, ent\u00e3o a fun\u00e7\u00e3o \u00e9 cos(x):<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a00c11698e4b4f5caf0f227e18be8656_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\lim_{h \\to 0}\\frac{\\text{cos}(x+h)-\\text{cos}(x)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"245\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> N\u00e3o podemos resolver este limite por substitui\u00e7\u00e3o, porque terminar\u00edamos na indetermina\u00e7\u00e3o. No entanto, podemos expressar o cosseno de uma soma de outra forma, aplicando a seguinte identidade trigonom\u00e9trica:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5e06f1728cce31fb5650ba149b8e5b9a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(a+b)=\\text{cos}(a)\\text{cos}(b)-\\text{sen}(a)\\text{sen}(b)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"307\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-db64449e24b11a613417ebce4c7c7a85_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\lim_{h \\to 0}\\frac{\\text{cos}(x)\\text{cos}(h)-\\text{sen}(x)\\text{sen}(h)-\\text{cos}(x)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"380\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> O pr\u00f3ximo passo \u00e9 separar a fra\u00e7\u00e3o em duas fra\u00e7\u00f5es e pegar o fator comum do cosseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c7c1cd89cf290b01d7d72fc8084f6529_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\lim_{h \\to 0}\\left[\\frac{\\text{cos}(x)\\bigl(\\text{cos}(h)-1\\bigr)}{h}-\\frac{\\text{sen}(x)\\text{sen}(h)}{h}\\right]\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"380\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p> O limite de uma subtra\u00e7\u00e3o \u00e9 igual \u00e0 subtra\u00e7\u00e3o dos limites, portanto:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-739fc9a2280c7da1bf2ea830ee5ec88c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\lim_{h \\to 0}\\frac{\\text{cos}(x)\\bigl(\\text{cos}(h)-1\\bigr)}{h}-\\lim_{h \\to 0}\\frac{\\text{sen}(x)\\text{sen}(h)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"393\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> O cosseno de x e o seno de x n\u00e3o dependem de h, ent\u00e3o podemos extra\u00ed-los fora dos limites:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bfbc83e5a84d91a0f6d98418a4f0041c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\text{cos}(x)\\lim_{h \\to 0}\\frac{\\text{cos}(h)-1}{h}-\\text{sen}(x)\\lim_{h \\to 0}\\frac{\\text{sen}(h)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"383\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Utilizando o c\u00e1lculo dos limites por equivalentes infinitesimais, conclu\u00edmos que o primeiro limite \u00e9 0 e o segundo limite \u00e9 1. Portanto:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f0c2ed1188b80356d05d6188fab5ca47_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=\\text{cos}(x)\\cdot 0-\\text{sen}(x)\\cdot 1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"223\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9f33ae6c9b18e01ba654772f22cab6d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)=-\\text{sen}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"124\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> E j\u00e1 chegamos \u00e0 f\u00f3rmula da derivada da fun\u00e7\u00e3o cosseno, ent\u00e3o a igualdade est\u00e1 provada.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como derivar a fun\u00e7\u00e3o cosseno (f\u00f3rmula). Voc\u00ea poder\u00e1 ver exemplos de derivadas de fun\u00e7\u00f5es cosseno e praticar exerc\u00edcios passo a passo. Al\u00e9m disso, mostramos a prova da f\u00f3rmula, qual \u00e9 a segunda derivada do cosseno e at\u00e9 mesmo a derivada do cosseno inverso. Qual \u00e9 a derivada do cosseno? A derivada da &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/deriva-do-cosseno\/\"> <span class=\"screen-reader-text\">Derivada de cosseno<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[11],"tags":[],"class_list":["post-30","post","type-post","status-publish","format-standard","hentry","category-derivados"],"yoast_head":"<!-- This site is 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