{"id":288,"date":"2023-07-06T19:13:46","date_gmt":"2023-07-06T19:13:46","guid":{"rendered":"https:\/\/mathority.org\/pt\/exemplos-de-adjuntos-menores-de-matrizes-e-adjuntos-complementares-e-exercicios-resolvidos\/"},"modified":"2023-07-06T19:13:46","modified_gmt":"2023-07-06T19:13:46","slug":"exemplos-de-adjuntos-menores-de-matrizes-e-adjuntos-complementares-e-exercicios-resolvidos","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/exemplos-de-adjuntos-menores-de-matrizes-e-adjuntos-complementares-e-exercicios-resolvidos\/","title":{"rendered":"Menor, assistente e auxiliar matricial complementar"},"content":{"rendered":"<p>Nesta se\u00e7\u00e3o veremos o que s\u00e3o e como calcular uma <strong>matriz complementar menor, uma adjunta e a matriz adjunta<\/strong> . Al\u00e9m disso, voc\u00ea encontrar\u00e1 exemplos, para que voc\u00ea entenda perfeitamente, e exerc\u00edcios resolvidos passo a passo, para que voc\u00ea possa praticar.<\/p>\n<h2 class=\"wp-block-heading\"> Qual \u00e9 o menor complementar?<\/h2>\n<p class=\"has-background\" style=\"background-color:#dff6ff\"> \u00c9 chamado <strong>de complemento menor<\/strong> de um elemento.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> ao determinante obtido excluindo a linha<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> e a coluna<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> de uma matriz.<\/p>\n<h2 class=\"wp-block-heading\"> Como calcular o complementar menor de um elemento?<\/h2>\n<p> Vamos ver como o menor complementar de um elemento \u00e9 calculado usando alguns exemplos:<\/p>\n<h3 style=\"color:#00B0FF\"> Exemplo 1:<\/h3>\n<p> Calcule o <strong>complemento menor de 1<\/strong> da seguinte matriz quadrada 3 \u00d7 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0a9db280911827ab5d64507cfe71aed4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\left( \\begin{array}{ccc} 6 &amp; 1 &amp; 7 \\\\[1.1ex] 3 &amp; 2 &amp; 0 \\\\[1.1ex] 5 &amp; 8 &amp; 4 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> O <strong>complementar menor de 1<\/strong> \u00e9 o determinante da matriz que permanece ao eliminar a linha e coluna onde est\u00e1 localizado o 1. Ou seja, removendo a primeira linha e a segunda coluna:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cb0021e61d4a3779378734771071bdfa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{tabular}{ccc} \\cellcolor[HTML]{F5B7B1}6 &amp; \\cellcolor[HTML]{F5B7B1}1 &amp; \\cellcolor[HTML]{F5B7B1}7 \\\\ &amp; \\cellcolor[HTML]{F5B7B1} &amp; \\\\[-2ex] 3 &amp; \\cellcolor[HTML]{F5B7B1}2 &amp; 0 \\\\ &amp; \\cellcolor[HTML]{F5B7B1} &amp; \\\\[-2ex] 5 &amp;  \\cellcolor[HTML]{F5B7B1}8 &amp; 4                    \\end{tabular} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"486\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7a38c134fa8e592ff15956701ce4521c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Menor complementario de 1} =  \\begin{vmatrix} 3 &amp; 0 \\\\[1.1ex] 5 &amp; 4 \\end{vmatrix} = \\bm{12}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"331\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h3 style=\"color:#00B0FF\"> Exemplo 2:<\/h3>\n<p> Desta vez calcularemos o <strong>complementar menor de 0<\/strong> da mesma matriz de antes:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0a9db280911827ab5d64507cfe71aed4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\left( \\begin{array}{ccc} 6 &amp; 1 &amp; 7 \\\\[1.1ex] 3 &amp; 2 &amp; 0 \\\\[1.1ex] 5 &amp; 8 &amp; 4 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> O <strong>complementar menor de 0<\/strong> \u00e9 o determinante da matriz removendo a linha e a coluna onde o 0 est\u00e1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eeeb42496216ad8689d1a70807b56644_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{tabular}{ccc} 6 &amp; 1 &amp; \\cellcolor[HTML]{F5B7B1}7 \\\\ &amp;  &amp; \\cellcolor[HTML]{F5B7B1} \\\\[-2ex] \\cellcolor[HTML]{F5B7B1} 3 &amp; \\cellcolor[HTML]{F5B7B1}2 &amp; \\cellcolor[HTML]{F5B7B1}0 \\\\ &amp; &amp;\\cellcolor[HTML]{F5B7B1} \\\\[-2ex] 5 &amp;  8 &amp; \\cellcolor[HTML]{F5B7B1}4                    \\end{tabular} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"492\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bd1eff11f2081d56b20c97203fc053c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Menor complementario de 0} =  \\begin{vmatrix} 6 &amp; 1 \\\\[1.1ex] 5 &amp; 8 \\end{vmatrix} = \\bm{43}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"332\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"> Exerc\u00edcios resolvidos para menores complementares<\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule o menor complemento de 3 da seguinte matriz 3\u00d73: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-16dac836fa9d63465e46dd35e2f36249_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 5 &amp; 1 &amp; 2 \\\\[1.1ex] 3 &amp; 4 &amp; 7 \\\\[1.1ex] -1 &amp; 6 &amp; 7 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"94\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O complementar menor de 3 \u00e9 o determinante da matriz que permanece ap\u00f3s a remo\u00e7\u00e3o da linha e coluna onde est\u00e1 o 3: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23b957e07aa004db36332997e906169f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Menor complementario de 3} = \\begin{vmatrix} 1 &amp; 2 \\\\[1.1ex] 6 &amp; 7 \\end{vmatrix} = \\bm{-5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"328\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Encontre o complementar menor de 5 da seguinte matriz de ordem 3: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-870e864969258f55a07ecd82c68c3132_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} -2 &amp; 4 &amp; -2 \\\\[1.1ex] 1 &amp; 3 &amp; 4 \\\\[1.1ex] 5 &amp; 8 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"108\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O complementar menor de 5 \u00e9 o determinante da matriz que obtemos excluindo a linha e a coluna onde est\u00e1 o 5: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f9fc980c8adf2b46e6bcfea0ef69737a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Menor complementario de 5} = \\begin{vmatrix} 4 &amp; -2 \\\\[1.1ex] 3 &amp; 4 \\end{vmatrix} = \\bm{22}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"344\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Calcule o complemento menor de 6 da seguinte matriz 4\u00d74: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c61e20d710e35ab2b27c94ca720e01a9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 1 &amp; 1 &amp; 3 &amp; 4 \\\\[1.1ex] 2 &amp; 6 &amp; -1 &amp; 8 \\\\[1.1ex] 3 &amp; 9 &amp; -1 &amp; 4 \\\\[1.1ex] 5 &amp; 4 &amp; 1 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"119\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O complementar menor de 6 \u00e9 o determinante da matriz que permanece ap\u00f3s a remo\u00e7\u00e3o da linha e coluna onde est\u00e1 o 6:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-60150a09c3023b5f1e147bf437df719c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Menor complementario de 6} = \\begin{vmatrix} 1 &amp; 3 &amp; 4 \\\\[1.1ex] 3 &amp; -1 &amp; 4 \\\\[1.1ex] 5&amp; 1 &amp; 3 \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"325\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Resolvemos o determinante com a regra de Sarrus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f331c9c3723df34235d8f172f5f41750_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix} 1 &amp; 3 &amp; 4 \\\\[1.1ex] 3 &amp; -1 &amp; 4 \\\\[1.1ex] 5 &amp; 1 &amp; 3 \\end{vmatrix}=-3+60+12+20-4-27 = \\bm{58}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"359\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\">Qual \u00e9 o adjunto de um elemento de array? <\/h2>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> O <strong>deputado<\/strong> de<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> , ou seja, item de linha<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> e a coluna<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> , \u00e9 obtido com a seguinte f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dcce4b79a3549da03df7c78b678add31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } a_{ij} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"430\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<\/div>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<h2 class=\"wp-block-heading\"> Como obter o adjunto de um elemento do array?<\/h2>\n<p> Vamos ver como o adjunto de um elemento \u00e9 calculado atrav\u00e9s de v\u00e1rios exemplos:<\/p>\n<h3 style=\"color:#00B0FF\"> Exemplo 1:<\/h3>\n<p> Calcule o <strong>adjunto de 4<\/strong> da seguinte matriz de ordem 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0acdd22355294e7c19583b1538c9070d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\begin{pmatrix} 1 &amp; 2 &amp; 3 \\\\[1.1ex] 4 &amp; 5 &amp; 6 \\\\[1.1ex] 7 &amp; 8 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-32a95816558c4ad5b48cb3e6b06eb8c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 4 = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } 4\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"406\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> O 4 est\u00e1 na <strong>linha 2<\/strong> e <strong>na coluna 1<\/strong> , ent\u00e3o neste caso<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-16ec1d81dc1a7d422c1985f813b6603b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i = 2\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"38\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb4d87f6d5922c8ff5cf03f1ea28faaf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j = 1 :\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"51\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aea771762912a2598233c359dabc88e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 4 = \\displaystyle (-1)^{2+1} \\bm{\\cdot} \\text{Menor complementario de } 4\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"409\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> E, como vimos anteriormente, o <strong>complemento menor de 4<\/strong> \u00e9 o determinante da matriz, eliminando a linha e a coluna onde est\u00e1 localizado o 4. Portanto:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b1cdd0dac0607a955fcfb19849c05276_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de} 4 = \\displaystyle(-1)^{2+1} \\bm{\\cdot}  \\begin{vmatrix}  2 &amp; 3  \\\\[1.1ex]  8 &amp; 9 \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"241\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Agora resolvemos o determinante e <strong>encontramos o adjunto de 4:<\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d9522581f22ca9b6b750bb9e3e7b0a60_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 4 = (-1)^{3} \\bm{\\cdot}  (-5) = -1 \\cdot (-6) = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"339\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div style=\"background-color:#fffde7;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> <strong>Lembre-se<\/strong> de que um n\u00famero negativo elevado a um expoente par \u00e9 positivo. Portanto, se o -1 for elevado a um n\u00famero par, ele se tornar\u00e1 positivo.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d5044fab01a117e78360f8982b1d37d5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{\\longrightarrow}(-1)^2=\\bm{+1}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"117\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p align=\"LEFT\"> Por outro lado, se um n\u00famero negativo for elevado a um expoente \u00edmpar, ele ser\u00e1 negativo. Portanto, se o -1 for elevado a um n\u00famero \u00edmpar, ser\u00e1 sempre negativo.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b51896f8d21b327891018914418bf6f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{\\longrightarrow}(-1)^3=\\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"117\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<\/div>\n<h3 style=\"color:#00B0FF\"> Exemplo 2:<\/h3>\n<p> Encontraremos o <strong>deputado de 5<\/strong> da mesma matriz anterior: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0acdd22355294e7c19583b1538c9070d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\begin{pmatrix} 1 &amp; 2 &amp; 3 \\\\[1.1ex] 4 &amp; 5 &amp; 6 \\\\[1.1ex] 7 &amp; 8 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-330e8801d4047cb9970efea37bb1eb8f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 5 = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } 5\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"405\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f3e47d30b12e053b3f5950033640b662_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de} 5 = \\displaystyle(-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 3  \\\\[1.1ex]  7 &amp; 9 \\end{vmatrix} = 1 \\cdot (-12) = \\bm{-12}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"388\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h3 style=\"color:#00B0FF\"> Exemplo 3:<\/h3>\n<p> Vamos fazer o <strong>deputado de 3<\/strong> da mesma matriz: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0acdd22355294e7c19583b1538c9070d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\begin{pmatrix} 1 &amp; 2 &amp; 3 \\\\[1.1ex] 4 &amp; 5 &amp; 6 \\\\[1.1ex] 7 &amp; 8 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bb298a5166e562f6a168addd0d1450a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 3 = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } 3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"406\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-954d6137c753a58e91682334addc5345_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de} 3 \\displaystyle =  (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} 4 &amp; 5  \\\\[1.1ex]  7 &amp; 8 \\end{vmatrix} = 1 \\cdot (-3) = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"370\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> O adjunto de um elemento \u00e9 utilizado para calcular determinantes, como veremos mais adiante, e para calcular a matriz adjunta, que \u00e9 o que veremos agora.<\/p>\n<h2 class=\"wp-block-heading\"> Exerc\u00edcios resolvidos para assistentes<\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule o adjunto de 2 da seguinte matriz 3\u00d73: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-340d5ef9265b33c7a6ad4ac7d72633f5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 2 &amp; 3 &amp; 1 \\\\[1.1ex] -1 &amp; -3 &amp; 5 \\\\[1.1ex] 5 &amp; 3 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"108\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para obter o resultado do adjunto de 2, basta aplicar a f\u00f3rmula do adjunto de um elemento: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-27e737fcb3ffe43ab7b1ee30a091bfb4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de 2}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"405\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-74e69b36278f7b0518a20be2e02aea4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} \\displaystyle = (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} -3 &amp; 5 \\\\[1.1ex] 3 &amp; 1 \\end{vmatrix} = 1 \\cdot (-18) = \\bm{-18}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"402\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Encontre o adjunto de 4 da seguinte matriz de ordem 3: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e21733cd834cdbeed5ca8fc433068ccf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 3 &amp; 1 &amp; -1 \\\\[1.1ex] 2 &amp; 9 &amp; 4 \\\\[1.1ex] 6 &amp; 5 &amp; -3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"94\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para obter o deputado de 4, devemos utilizar a f\u00f3rmula do deputado de um elemento: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-58a3653b2ec21f65f85689ffbe978079_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de 4}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"406\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c4a2228588aeef08594e7f3cc93c53ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} \\displaystyle = (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 3 &amp; 1 \\\\[1.1ex] 6 &amp; 5 \\end{vmatrix} = -1 \\cdot 9 = \\bm{-9}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"356\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-118\"><\/div>\n<\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Encontre o deputado de 7 da seguinte matriz 4\u00d74: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-64b3cf6b9f34fce5f66d24502f2434a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 1 &amp; 2 &amp; 5 &amp; -2 \\\\[1.1ex] 3 &amp; 1 &amp; -3 &amp; 3 \\\\[1.1ex] 2 &amp; -1 &amp; 4 &amp; 0 \\\\[1.1ex] 2 &amp; 7 &amp; 9 &amp; -4 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"108\" width=\"147\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para fazer o adjunto de 7 aplicamos a f\u00f3rmula do adjunto de um elemento: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b62c0cebb18f5b2ae6d01078babc00b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 7}=(-1)^{4+2} \\bm{\\cdot} \\text{Menor complementario de 7}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"409\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-54f5200bb9a57df8b0aa73271ec26c7f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 7} \\displaystyle = (-1)^{4+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 5 &amp; -2 \\\\[1.1ex] 3 &amp; -3 &amp; 3 \\\\[1.1ex] 2 &amp; 4 &amp; 0\\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"293\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Aplicamos a regra de Sarrus para resolver o determinante de terceira ordem: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-34d456bf805c4a6d8673d00febc983dc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle = (-1)^{6} \\bm{\\cdot} \\bigl[0+30-24-12-12-0\\bigr]\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"276\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b228f8cd5f96cfdbd7e80138cb109e3b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle = 1 \\bm{\\cdot} \\bigl[-18 \\bigr] = \\bm{-18}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"134\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\">Qual \u00e9 a matriz anexa?<\/h2>\n<p> A <strong>matriz anexada<\/strong> \u00e9 uma matriz na qual todos os seus elementos foram substitu\u00eddos por seus substitutos.<\/p>\n<h2 class=\"wp-block-heading\"> Como calcular a matriz adjunta?<\/h2>\n<p class=\"has-background\" style=\"background-color:#dff6ff\"> Para calcular a <strong>matriz de deputados<\/strong> , precisamos substituir todos os elementos da matriz pelos seus deputados.<\/p>\n<p> Vamos ver como \u00e9 feita a matriz unida atrav\u00e9s de um exemplo: <\/p>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-119\"><\/div>\n<\/div>\n<h3 style=\"color:#00B0FF\"> Exemplo:<\/h3>\n<p> Calcule a matriz adjunta da seguinte matriz quadrada de dimens\u00e3o 2\u00d72:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e1d84d025062b24cb6a7ef021cb55de1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A  =  \\begin{pmatrix} 4 &amp; -1 \\\\[1.1ex] 3 &amp; 2  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Para calcular a matriz adjunta, devemos <strong>calcular o adjunto de cada elemento da matriz<\/strong> . Portanto, primeiro resolveremos as conjun\u00e7\u00f5es de todos os elementos com a f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dcce4b79a3549da03df7c78b678add31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } a_{ij} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"430\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-30683bf4304e3072c4fcf46610e06e05_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 4 =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 2 \\end{vmatrix} = 1 \\cdot 2 = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"302\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-04af89fae8a9060940f892f5d1e0c51d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -1} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"336\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-042a24b0f0896742500d7455e8f944ab_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 3 =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -1 \\end{vmatrix} = -1 \\cdot (-1) = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a0d3e6017c878bc47df1c509936fbcf7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } 2 =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 4 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"303\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Agora s\u00f3 precisamos substituir cada elemento do array<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> pelo seu substituto para encontrar a <strong>matriz suplente de<\/strong><\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1372441aae26d85aebdcbe3baf70cf56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A} :\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"22\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4c4c2583218c84e184a1911972dca72b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj} (A)  =  \\begin{pmatrix} \\bm{2} &amp; \\bm{-3} \\\\[1.1ex] \\bm{1} &amp; \\bm{4}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"159\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> E assim se encontra o deputado de uma matriz. Mas voc\u00ea provavelmente est\u00e1 se perguntando para que servem todos esses c\u00e1lculos? Bem, uma das utilidades da jun\u00e7\u00e3o de matrizes \u00e9 calcular o <a href=\"https:\/\/mathority.org\/pt\/matriz-inversa\/\">inverso de uma matriz<\/a> . Na verdade, o m\u00e9todo mais comum para encontrar a matriz inversa \u00e9 o m\u00e9todo da matriz adjunta.<\/p>\n<h2 class=\"wp-block-heading\"> Problemas de matriz adjunta resolvidos<\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule a matriz adjunta da seguinte matriz quadrada 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5fbfc1c22345724f35d7208214f8592_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 2 &amp; 3  \\\\[1.1ex] -4 &amp; 1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"68\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para calcular a matriz adjunta, devemos calcular o adjunto de cada elemento da matriz. Portanto, primeiro resolveremos as conjun\u00e7\u00f5es de todos os elementos com a f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-86e59cf1a404062a425e15fde85090cb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 1 \\end{vmatrix} = 1 \\cdot 1 = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"302\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-74a9e31be5bf93b62a51c1bf23200f48_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} -4 \\end{vmatrix} = -1 \\cdot (-4) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"358\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25393a1a057c92d2eea1f57ac2ae914f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -4} =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"336\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f05aa937b693794438cf7c04b75fc924_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 2 \\end{vmatrix} = 1 \\cdot 2 = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"302\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora s\u00f3 precisamos substituir cada elemento do array<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> pelo seu substituto para encontrar a matriz suplente de <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ed7f99fecb7719c7108eaecc0a21dad2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A :\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"22\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5d3fdee2506136365c141a81596f1d22_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj} (A)  =  \\begin{pmatrix} \\bm{1} &amp; \\bm{4} \\\\[1.1ex] \\bm{-3} &amp; \\bm{2}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"159\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Encontre a matriz adjunta da seguinte matriz de segunda ordem: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b95133fbf999cb6585b3a32f4b1b906b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 6 &amp; -2  \\\\[1.1ex] 3 &amp; -7  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"68\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para calcular a matriz adjunta, devemos calcular o adjunto de cada elemento da matriz. Portanto, primeiro resolveremos as conjun\u00e7\u00f5es de todos os elementos com a f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-35b5b261848474e8eb940bee9147c21b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 6} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} -7 \\end{vmatrix} = 1 \\cdot (-7) = \\bm{-7}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"358\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0f1e6a5a5c504b3b6d06e5d3d8e0862e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"336\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-05a49201adc9cef4d1e9903157860e4b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -2 \\end{vmatrix} = -1 \\cdot (-2) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e936a7e026d5fc05b60e032170c85c1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -7} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 6 \\end{vmatrix} = 1 \\cdot 6 = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"309\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora s\u00f3 precisamos substituir cada elemento do array<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> pelo seu substituto para encontrar a matriz suplente de <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ed7f99fecb7719c7108eaecc0a21dad2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A :\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"22\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-604112d6e7d95ca76dd5266dc2eceb86_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj} (A)  =  \\begin{pmatrix} \\bm{-7} &amp; \\bm{-3} \\\\[1.1ex] \\bm{2} &amp; \\bm{6}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Calcule a matriz adjunta da seguinte matriz 3\u00d73: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0072b68810f2662ae9f4ec3d11902f97_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 1 &amp; 3 &amp; -1 \\\\[1.1ex] 2 &amp; 4 &amp; 0 \\\\[1.1ex] 5 &amp; 0 &amp; -2  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"94\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para calcular a matriz adjunta, devemos calcular o adjunto de cada elemento da matriz. Portanto, primeiro resolveremos as conjun\u00e7\u00f5es de todos os elementos com a f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-68e2bee7e07b5749033cdf67d90684a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 4 &amp; 0 \\\\[1.1ex] 0 &amp; -2\\end{vmatrix} = 1 \\cdot (-8) = \\bm{-8}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"385\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-88120e3a6fa0e6ba43c654ce7884eb41_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} = \\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix}  2 &amp; 0 \\\\[1.1ex] 5 &amp; -2\\end{vmatrix} = -1 \\cdot (-4) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"385\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-49c170f202956d9571fcce88cd389889_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -1} = \\displaystyle (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} 2 &amp; 4 \\\\[1.1ex] 5 &amp; 0\\end{vmatrix} = 1 \\cdot (-20) = \\bm{-20}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"395\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9dd9f81ddb6bd58f2a4e1241c3fbfdb3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} = \\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3 &amp; -1 \\\\[1.1ex] 0 &amp; -2\\end{vmatrix} = -1 \\cdot (-6) = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"385\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ee11d10a5ef1719e3eee0d1de8e2fd1e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} = \\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; -1 \\\\[1.1ex] 5 &amp; -2\\end{vmatrix} = 1 \\cdot 3 = \\bm{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"343\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-327cba2dd78055703b66b887083d3a50_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 0} = \\displaystyle (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 3  \\\\[1.1ex] 5 &amp; 0 \\end{vmatrix} = -1 \\cdot (-15) = \\bm{15}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"388\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d5df97c790e24f1257c7d1073c4e2af8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 5} = \\displaystyle (-1)^{3+1} \\bm{\\cdot} \\begin{vmatrix} 3 &amp; -1 \\\\[1.1ex] 4 &amp; 0 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"343\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0d0cd9b3ea07312942362d52f07c04bc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 0} = \\displaystyle (-1)^{3+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; -1 \\\\[1.1ex] 2 &amp; 0\\end{vmatrix} = -1 \\cdot 2 = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"370\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-00f3983f64257be282584209b8f2d842_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} = \\displaystyle (-1)^{3+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 4 \\end{vmatrix} = 1 \\cdot (-2) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"376\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora s\u00f3 precisamos substituir cada elemento do array<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> pelo seu substituto para encontrar a matriz suplente de <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ed7f99fecb7719c7108eaecc0a21dad2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A :\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"22\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-01e49ffda72034d74b18ecdd37d1e3b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj} (A)  =  \\begin{pmatrix} \\bm{-8} &amp; \\bm{4} &amp; \\bm{-20} \\\\[1.1ex] \\bm{6} &amp; \\bm{3} &amp; \\bm{15} \\\\[1.1ex] \\bm{4} &amp; \\bm{-2} &amp; \\bm{-2}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"223\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Nesta se\u00e7\u00e3o veremos o que s\u00e3o e como calcular uma matriz complementar menor, uma adjunta e a matriz adjunta . Al\u00e9m disso, voc\u00ea encontrar\u00e1 exemplos, para que voc\u00ea entenda perfeitamente, e exerc\u00edcios resolvidos passo a passo, para que voc\u00ea possa praticar. Qual \u00e9 o menor complementar? \u00c9 chamado de complemento menor de um elemento. ao &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/exemplos-de-adjuntos-menores-de-matrizes-e-adjuntos-complementares-e-exercicios-resolvidos\/\"> <span class=\"screen-reader-text\">Menor, assistente e auxiliar matricial complementar<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[36],"tags":[],"class_list":["post-288","post","type-post","status-publish","format-standard","hentry","category-matriz-inversa"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Menor, auxiliar e auxiliar matricial complementar - Matoridade<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/exemplos-de-adjuntos-menores-de-matrizes-e-adjuntos-complementares-e-exercicios-resolvidos\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Menor, auxiliar e auxiliar matricial complementar - Matoridade\" \/>\n<meta property=\"og:description\" content=\"Nesta se\u00e7\u00e3o veremos o que s\u00e3o e como calcular uma matriz complementar menor, uma adjunta e a matriz adjunta . Al\u00e9m disso, voc\u00ea encontrar\u00e1 exemplos, para que voc\u00ea entenda perfeitamente, e exerc\u00edcios resolvidos passo a passo, para que voc\u00ea possa praticar. 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