{"id":262,"date":"2023-07-10T05:22:42","date_gmt":"2023-07-10T05:22:42","guid":{"rendered":"https:\/\/mathority.org\/pt\/equacao-canonica-segmentar-ou-simetrica-de-uma-formula-de-linha-exemplos-resolvidos-exercicios\/"},"modified":"2023-07-10T05:22:42","modified_gmt":"2023-07-10T05:22:42","slug":"equacao-canonica-segmentar-ou-simetrica-de-uma-formula-de-linha-exemplos-resolvidos-exercicios","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/equacao-canonica-segmentar-ou-simetrica-de-uma-formula-de-linha-exemplos-resolvidos-exercicios\/","title":{"rendered":"Equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta"},"content":{"rendered":"<p>Aqui voc\u00ea encontrar\u00e1 a explica\u00e7\u00e3o do que \u00e9 a f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta, tamb\u00e9m chamada de equa\u00e7\u00e3o sim\u00e9trica. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos e praticar com exerc\u00edcios resolvidos. E, ainda, voc\u00ea descobrir\u00e1 como a equa\u00e7\u00e3o can\u00f4nica \u00e9 calculada a partir da equa\u00e7\u00e3o geral (ou impl\u00edcita) da reta. <\/p>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-104\"><\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-la-ecuacion-canonica-o-segmentaria-de-la-recta\"><\/span> Qual \u00e9 a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta? <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-105\"><\/div>\n<\/div>\n<p> Lembre-se de que a defini\u00e7\u00e3o matem\u00e1tica de uma reta \u00e9 um conjunto de pontos consecutivos representados na mesma dire\u00e7\u00e3o, sem curvas ou \u00e2ngulos.<\/p>\n<p> Assim, a <strong>equa\u00e7\u00e3o can\u00f4nica da reta<\/strong> , tamb\u00e9m chamada <strong>de equa\u00e7\u00e3o segmentar da reta<\/strong> , \u00e9 uma forma de expressar matematicamente qualquer reta. Para isso, basta conhecer os pontos de intersec\u00e7\u00e3o com os eixos coordenados da referida reta.<\/p>\n<p> Por outro lado, em geometria anal\u00edtica, a equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta tamb\u00e9m \u00e9 chamada <strong>de equa\u00e7\u00e3o sim\u00e9trica da reta<\/strong> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"formula-de-la-ecuacion-canonica-o-segmentaria-de-la-recta\"><\/span> F\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-106\"><\/div>\n<\/div>\n<p> A equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta \u00e9 a express\u00e3o alg\u00e9brica da reta que pode ser determinada conhecendo os valores onde a reta intercepta o eixo x e o eixo y. <\/p>\n<div style=\"background-color:#FFCC8080;padding-top: 20px; padding-bottom: 0.5px; padding-right: 30px; padding-left: 30px; border: 2px solid #FFB74D; border-radius:20px;\">\n<p style=\"text-align:left\"> Se uma linha intercepta os eixos cartesianos nos seguintes pontos:<\/p>\n<p style=\"text-align:center\"> Ponto de intersec\u00e7\u00e3o com o eixo X:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-73f7f9618f43f69c0d8a68ff9b47ffef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(a,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"text-align:center\"> Ponto de intersec\u00e7\u00e3o com o eixo Y:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aee2e1bda5b37d0b02db636b7d6a73e7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(0,b)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"37\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> A <strong>f\u00f3rmula para a equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta<\/strong> \u00e9: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1f779ba21479453dc5020b38c2222700_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{a}+ \\cfrac{y}{b}= 1\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"75\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<\/div>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/equation-canonique-segmentaire-ou-symetrique-d-une-ligne.webp\" alt=\"equa\u00e7\u00e3o can\u00f4nica segmentar ou sim\u00e9trica da reta no espa\u00e7o\" class=\"wp-image-3261\" width=\"293\" height=\"294\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Deve-se notar que n\u00e3o existe equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta em nenhum dos tr\u00eas casos a seguir:<\/p>\n<ol>\n<li> Quando a linha \u00e9 vertical, ou seja, paralela ao eixo OY. Como a equa\u00e7\u00e3o de uma reta vertical \u00e9\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9c28d78386332247b427523e1e946b18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=k.\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"48\" style=\"vertical-align: 0px;\"><\/p>\n<\/li>\n<li> Quando a linha \u00e9 horizontal, ou seja, paralela ao eixo OX. Como a equa\u00e7\u00e3o de uma reta horizontal \u00e9\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-afa765d3f555400c4f5b69f3a3d3d4a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y=k.\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"47\" style=\"vertical-align: -4px;\"><\/p>\n<\/li>\n<li> Quando a linha passa pela origem da coordenada (ponto\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9cf2000c782cfe94be6df5f499cd3e24_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(0,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<p> ), pois ter\u00edamos ent\u00e3o duas indetermina\u00e7\u00f5es na equa\u00e7\u00e3o da reta. <\/li>\n<\/ol>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-como-hallar-la-ecuacion-canonica-o-segmentaria-de-la-recta\"><\/span> Exemplo de como encontrar a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-109\"><\/div>\n<\/div>\n<p> Para que voc\u00ea entenda melhor o conceito, resolveremos um problema de equa\u00e7\u00e3o segmental (ou can\u00f4nica) da reta:<\/p>\n<ul>\n<li> Encontre a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta que passa pelos dois pontos a seguir:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0f784463d818c3536bb37e53cf52004c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(0,4) \\qquad \\qquad B(-2,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"190\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Neste caso, a declara\u00e7\u00e3o n\u00e3o nos d\u00e1 2 pontos, mas sim os dois pontos de intersec\u00e7\u00e3o com os eixos.<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o da linha com o eixo X:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c03b999207a9ba4c2b91b508225efdf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(-2,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o da linha com o eixo Y:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a71f6efcd7309620d3fe2f4944127b08_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(0,4)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Assim, como j\u00e1 conhecemos os dois pontos de intersec\u00e7\u00e3o com os eixos, basta aplicar a f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1f779ba21479453dc5020b38c2222700_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{a}+ \\cfrac{y}{b}= 1\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"75\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> E por fim, substitu\u00edmos o valor dos par\u00e2metros<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c53d6ebabdbcfa4e107550ea60b1b19_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f56d50c26583f9a035ff6b4e3c0ca5c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"b\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> na f\u00f3rmula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0ece0e8770ed189c1665264e68eb29ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{\\bm{x}}{\\bm{-2}}\\bm{+} \\cfrac{\\bm{y}}{\\bm{4}}\\bm{= 1}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"74\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Agora voc\u00ea sabe qual \u00e9 a equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta. Por\u00e9m, voc\u00ea deve saber que existem outras formas de expressar uma reta, e dentre elas se destaca a <a href=\"https:\/\/mathority.org\/pt\/equacao-explicita-de-uma-reta\/\">equa\u00e7\u00e3o expl\u00edcita<\/a> . Este tipo de equa\u00e7\u00e3o linear \u00e9 dif\u00edcil de entender completamente, por isso explicamos tudo sobre ela em detalhes na p\u00e1gina do link. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"calcular-la-ecuacion-canonica-o-segmentaria-de-la-recta-a-partir-de-su-ecuacion-general\"><\/span> Calcule a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta a partir de sua equa\u00e7\u00e3o geral<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Acabamos de ver uma maneira de determinar a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta, mas tamb\u00e9m existem outros m\u00e9todos:<\/p>\n<p> A equa\u00e7\u00e3o can\u00f4nica ou segmentar de uma reta pode ser obtida a partir da <a href=\"https:\/\/mathority.org\/pt\/equacao-cartesiana-geral-ou-implicita-de-uma-reta\/\">equa\u00e7\u00e3o geral (ou impl\u00edcita)<\/a> desta mesma reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02f4d03229cc8bd79a81b676a8132f37_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"Ax+By+C=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"137\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Primeiro, mudamos de lado no coeficiente C:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b1489afd0358ec59084c6b1b1115db78_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"Ax+By=-C\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"120\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> A seguir, dividimos a equa\u00e7\u00e3o inteira pelo valor do par\u00e2metro C com sinal alterado:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7cb0d2f6fd79c7598a67c1c4d4109252_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{Ax+By}{-C}=\\cfrac{-C}{-C}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"130\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f06bd2a7c60d6965a0513cc80d690de5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{Ax}{-C}+\\cfrac{By}{-C}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"111\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> E, atrav\u00e9s das propriedades das fra\u00e7\u00f5es, chegamos \u00e0 f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ada21ad618cf0132a303b70558e74088_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{-\\frac{C}{A}}+\\cfrac{y}{-\\frac{C}{B}}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"112\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p> Portanto, segue-se desta f\u00f3rmula que os termos<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c53d6ebabdbcfa4e107550ea60b1b19_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f56d50c26583f9a035ff6b4e3c0ca5c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"b\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> da equa\u00e7\u00e3o can\u00f4nica de uma reta s\u00e3o equivalentes \u00e0s seguintes express\u00f5es: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-90927645767d583d31f8b62b16df5eb8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=  -\\cfrac{C}{A} \\qquad \\qquad b= -\\cfrac{C}{B}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"196\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-ecuacion-canonica-o-segmentaria-de-la-recta\"><\/span> Problemas resolvidos da equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Quais s\u00e3o os pontos de intersec\u00e7\u00e3o com os eixos coordenados da linha a seguir? <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-10e387260c9dc85e2b17e527d4e5d63f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{3}+ \\cfrac{y}{-1}= 1\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"88\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A reta do exerc\u00edcio \u00e9 expressa na forma de uma equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta, cuja f\u00f3rmula \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1f779ba21479453dc5020b38c2222700_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{a}+ \\cfrac{y}{b}= 1\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"75\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, os pontos onde a linha cruza os eixos coordenados s\u00e3o:<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o com o eixo X:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b7456e9e3fa0dd6b686d7de7e625a50c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(3,0)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o com o eixo Y: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-737e35e6d1698a9e89986af90d34722e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(0,-1)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"52\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Qual \u00e9 a equa\u00e7\u00e3o can\u00f4nica ou segmentar da linha representada graficamente? <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/equation-canonique-symetrique-segmentaire-dans-le-plan.webp\" alt=\"equa\u00e7\u00e3o can\u00f4nica segmentar ou sim\u00e9trica no plano\" class=\"wp-image-3364\" width=\"305\" height=\"278\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A partir do gr\u00e1fico podemos saber os pontos onde a reta cruza os eixos coordenados:<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o da linha com o eixo X:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66d157e60ba32a840b2e593e20fa0fd8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(5,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> Ponto de intersec\u00e7\u00e3o da linha com o eixo Y:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b00c0ef29f378fc09b68112ef3dd8311_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(0,3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"38\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, uma vez que j\u00e1 conhecemos os 2 pontos de intersec\u00e7\u00e3o com os eixos, basta utilizar a f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1f779ba21479453dc5020b38c2222700_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{a}+ \\cfrac{y}{b}= 1\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"75\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E por fim, substitu\u00edmos o valor dos par\u00e2metros<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c53d6ebabdbcfa4e107550ea60b1b19_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f56d50c26583f9a035ff6b4e3c0ca5c0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"b\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> na f\u00f3rmula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3e0b25723a1e16d5ab74faa9323a7faa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{\\bm{x}}{\\bm{5}}\\bm{+} \\cfrac{\\bm{y}}{\\bm{3}}\\bm{= 1}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"62\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Calcule a equa\u00e7\u00e3o can\u00f4nica ou segmentar da reta determinada pela seguinte equa\u00e7\u00e3o geral (ou impl\u00edcita): <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3e8c85f08a9721767b635d1e302df175_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"3x-2y+6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"122\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para passar de uma equa\u00e7\u00e3o geral para uma equa\u00e7\u00e3o segmental, devemos primeiro isolar o termo independente da equa\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3e8c85f08a9721767b635d1e302df175_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"3x-2y+6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"122\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4f821b1d54ce7c347bd6c6db2e5a1d91_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"3x-2y=-6\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"105\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Segundo, dividimos a equa\u00e7\u00e3o inteira pelo coeficiente do lado direito da equa\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-671e28b3249f507bbe0915cb02aa6357_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{3x-2y}{-6}=\\cfrac{-6}{-6}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"115\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-28a99bf95110cc21e96868b1631685fa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{3x}{-6}+\\cfrac{-2y}{-6}=\\cfrac{-6}{-6}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"143\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A express\u00e3o acima \u00e9 equivalente ao seguinte:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a7d3f91347ac743f153ec1a0d5f490d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{\\frac{-6}{3}}+\\cfrac{y}{\\frac{-6}{-2}}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"98\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Para que a equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta seja: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2323019e7dc7df3e790241c38a815dc0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{\\bm{x}}{\\bm{-2}}\\bm{+} \\cfrac{\\bm{y}}{\\bm{3}}\\bm{= 1}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"74\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 4<\/h3>\n<p> Determine a equa\u00e7\u00e3o can\u00f4nica ou segmentar cujo vetor de dire\u00e7\u00e3o \u00e9<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eddc36bb0af0be28b6aee682b4d0620d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{v}}=(4,-3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"86\" style=\"vertical-align: -5px;\"><\/p>\n<p> e passa pelo ponto <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-950aa8893c81e9d03ae829fdbff65170_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(-1,5).\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"71\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Primeiro encontramos facilmente a equa\u00e7\u00e3o cont\u00ednua da reta a partir de seu vetor dire\u00e7\u00e3o e um ponto que pertence \u00e0 reta: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ae68ef371c0e47a191b39c7dd91b8d74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x-P_1}{\\text{v}_1} = \\cfrac{y-P_2}{\\text{v}_2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"127\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d5b3f6927c514d04ea06e2aa009f60e6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x-(-1)}{4} = \\cfrac{y-5}{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"134\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd68671f2588fd33c149ff55a34f1e0c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x+1}{4} = \\cfrac{y-5}{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"106\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora vamos calcular a equa\u00e7\u00e3o geral da reta multiplicando as fra\u00e7\u00f5es transversalmente e agrupando os termos resultantes: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fc458b66d50df3770633bcbf97f8d3d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3(x+1) = 4(y-5)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"161\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b6443bb2976d046405c02e5803284ec2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3x-3 = 4y-20\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"144\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b8531fe9e8e2b451c0ea756ab0b6b875_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3x-3 - 4y+20 =0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"174\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-634adbfe51f6b1253f7eca15f143524a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3x - 4y+17 =0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"144\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00c9, portanto, suficiente converter a equa\u00e7\u00e3o geral da reta em uma equa\u00e7\u00e3o can\u00f4nica. Para fazer isso, primeiro exclu\u00edmos o termo independente da equa\u00e7\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1369da6585734499e838193b4ba83689_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3x - 4y=-17\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"127\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A seguir, dividimos a equa\u00e7\u00e3o inteira pelo coeficiente do lado direito da equa\u00e7\u00e3o: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4ae05d00e91badb1444cdc9125c6bd76_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{-3x - 4y}{-17}=\\cfrac{-17}{-17}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"146\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42c48c859ffa1f3d5e663040bc86c995_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{-3x}{-17}+\\cfrac{-4y}{-17}=\\cfrac{-17}{-17}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"170\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A express\u00e3o acima \u00e9 equivalente ao seguinte:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-70d6bd2ab7bd685ff390129d995fe2b1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{\\frac{-17}{-3}}+\\cfrac{y}{\\frac{-17}{-4}}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"112\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Negativo dividido por negativo \u00e9 igual a positivo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8f41be687aab214e112403e3937ecb89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{x}{\\frac{17}{3}}+\\cfrac{y}{\\frac{17}{4}}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"90\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> As fra\u00e7\u00f5es n\u00e3o podem ser mais simplificadas, portanto, a equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta \u00e9: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8a945a5a562df95e1bda59e43fe11ffb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{\\bm{x}}{\\mathbf{\\frac{17}{3}}}\\bm{+} \\cfrac{\\bm{y}}{\\mathbf{\\frac{17}{4}}}\\bm{= 1}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"82\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Aqui voc\u00ea encontrar\u00e1 a explica\u00e7\u00e3o do que \u00e9 a f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta, tamb\u00e9m chamada de equa\u00e7\u00e3o sim\u00e9trica. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos e praticar com exerc\u00edcios resolvidos. E, ainda, voc\u00ea descobrir\u00e1 como a equa\u00e7\u00e3o can\u00f4nica \u00e9 calculada a partir da equa\u00e7\u00e3o geral (ou impl\u00edcita) da reta. Qual \u00e9 a &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/equacao-canonica-segmentar-ou-simetrica-de-uma-formula-de-linha-exemplos-resolvidos-exercicios\/\"> <span class=\"screen-reader-text\">Equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[20],"tags":[],"class_list":["post-262","post","type-post","status-publish","format-standard","hentry","category-pontos-retas-e-planos"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/equacao-canonica-segmentar-ou-simetrica-de-uma-formula-de-linha-exemplos-resolvidos-exercicios\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Equa\u00e7\u00e3o can\u00f4nica, segmentar ou sim\u00e9trica da reta - Mathority\" \/>\n<meta property=\"og:description\" content=\"Aqui voc\u00ea encontrar\u00e1 a explica\u00e7\u00e3o do que \u00e9 a f\u00f3rmula da equa\u00e7\u00e3o can\u00f4nica (ou segmentar) da reta, tamb\u00e9m chamada de equa\u00e7\u00e3o sim\u00e9trica. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos e praticar com exerc\u00edcios resolvidos. E, ainda, voc\u00ea descobrir\u00e1 como a equa\u00e7\u00e3o can\u00f4nica \u00e9 calculada a partir da equa\u00e7\u00e3o geral (ou impl\u00edcita) da reta. 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