{"id":245,"date":"2023-07-10T13:40:44","date_gmt":"2023-07-10T13:40:44","guid":{"rendered":"https:\/\/mathority.org\/pt\/ponto-simetrico-respeitando-outro-ponto-em-uma-linha-e-em-um-plano-de-formula\/"},"modified":"2023-07-10T13:40:44","modified_gmt":"2023-07-10T13:40:44","slug":"ponto-simetrico-respeitando-outro-ponto-em-uma-linha-e-em-um-plano-de-formula","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/ponto-simetrico-respeitando-outro-ponto-em-uma-linha-e-em-um-plano-de-formula\/","title":{"rendered":"Ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto, uma reta e um plano"},"content":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como calcular o ponto de simetria em rela\u00e7\u00e3o a outro ponto, em rela\u00e7\u00e3o a uma reta e em rela\u00e7\u00e3o a um plano. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos e exerc\u00edcios resolvidos passo a passo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"punto-simetrico-respecto-a-otro-punto\"><\/span> Ponto sim\u00e9trico a outro ponto<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Antes de vermos como o ponto sim\u00e9trico \u00e9 calculado, vamos revisar o que exatamente \u00e9 um ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto:<\/p>\n<p> <strong>O ponto A&#8217; \u00e9 o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o a outro ponto M se o ponto A&#8217; estiver localizado simetricamente \u00e0 mesma dist\u00e2ncia do ponto M que a dist\u00e2ncia entre os pontos A e M. Portanto, M \u00e9 o ponto m\u00e9dio do segmento formado por pontos A e A&#8217;.<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/point-symetrique-par-respect-dun-autre-point.webp\" alt=\"ponto sim\u00e9trico a outro ponto\" class=\"wp-image-2568\" width=\"224\" height=\"224\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b245228198e894b500e680fba0da85a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"d(A,M) = d(A',M )\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"154\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Por outro lado, dizemos tamb\u00e9m que o ponto M \u00e9 o centro de simetria.<\/p>\n<p> Assim, para calcular as coordenadas do ponto de simetria, utilizaremos a <a href=\"https:\/\/mathority.org\/pt\/formula-para-o-ponto-medio-de-um-vetor-de-segmento\/\">f\u00f3rmula do ponto m\u00e9dio de um segmento<\/a> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-89899129b0d44c4cd976ad3e49613dc3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{A+A'}{2}=M\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"95\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Desta equa\u00e7\u00e3o extra\u00edmos o ponto desconhecido A&#8217; e obtemos a <strong>f\u00f3rmula para o ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto:<\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7f086fbd1244c016821d618224d85d1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\color{orange} \\boxed{ \\color{black} \\quad A' = 2M - A \\quad \\vphantom{\\Bigl)}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"246\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-como-hallar-el-punto-simetrico-respecto-a-otro-punto\"><\/span> Exemplo de encontrar o ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Como exemplo, calcularemos o ponto de simetria do ponto A em rela\u00e7\u00e3o ao ponto M. Considere os dois pontos:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-da59d3cf0aad36a3cc97ba45f400fcf0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(1,3,0) \\qquad \\qquad M(-1,4,2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"229\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Para determinar o ponto de simetria entre esses dois pontos, aplicamos a f\u00f3rmula do ponto de simetria em rela\u00e7\u00e3o a outro:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd271153fefe3118d9443db8d7e2bafc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A' = 2M - A\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"104\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Agora substitu\u00edmos os pontos na f\u00f3rmula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fa87525f5b34bdcef7b82eb336078a8a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A' = 2(-1,4,2) -(1,3,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"197\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> E operamos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0c48dd83cd17af141e618108f5a84ce0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A' = (-2,8,4) -(1,3,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"188\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-409d4dd835ed4cfa11e51b615bf6d6df_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A'=(-3,5,4)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"111\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"punto-simetrico-respecto-a-una-recta\"><\/span> ponto sim\u00e9trico a uma linha reta<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Acabamos de ver a no\u00e7\u00e3o de um ponto que \u00e9 sim\u00e9trico em rela\u00e7\u00e3o a outro ponto. Bem, o ponto sim\u00e9trico de um ponto em rela\u00e7\u00e3o a uma reta \u00e9 muito semelhante:<\/p>\n<p> <strong>O ponto A&#8217; \u00e9 o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o a uma reta se os dois pontos A&#8217; e A est\u00e3o na mesma reta perpendicular \u00e0 reta e, al\u00e9m disso, a dist\u00e2ncia entre o ponto A&#8217; e a reta \u00e9 igual \u00e0 dist\u00e2ncia entre o ponto A e a reta.<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/point-symetrique-par-rapport-a-une-droite.webp\" alt=\"ponto sim\u00e9trico de um ponto em rela\u00e7\u00e3o a uma reta\" class=\"wp-image-2586\" width=\"470\" height=\"362\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-82482dab7ac516792922108f81d4b657_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"d(A,r)= d(A',r)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"133\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Portanto, a reta <em>r<\/em> tamb\u00e9m \u00e9 um eixo de simetria entre os pontos.<\/p>\n<p> Assim, para determinar o ponto de simetria do ponto A em rela\u00e7\u00e3o \u00e0 reta <em>r<\/em> , devemos seguir o seguinte procedimento:<\/p>\n<ol style=\"color:#ff6f00; font-weight: bold;>\n<li><span style=\" color:#262626;font-weight:=\"\" normal;\"=\"\">\n<li style=\"margin-bottom:18px\"><span style=\"color:#000000;font-weight: normal;\">Encontramos o plano perpendicular \u00e0 reta <em>r<\/em> que passa pelo ponto A (plano \u03c0 da representa\u00e7\u00e3o gr\u00e1fica anterior). Para isso, devemos utilizar o vetor dire\u00e7\u00e3o da reta, que ser\u00e1 o vetor normal do plano.<\/span><\/li>\n<li style=\"margin-bottom:18px\"> <span style=\"color:#000000;font-weight: normal;\">Calculamos o <a href=\"https:\/\/mathority.org\/pt\">ponto de intersec\u00e7\u00e3o<\/a> entre o plano encontrado e a reta (ponto M na imagem anterior).<\/span><\/li>\n<li> <span style=\"color:#000000;font-weight: normal;\">Usamos a f\u00f3rmula ponto sobre ponto sim\u00e9trico (vista na se\u00e7\u00e3o acima) para encontrar o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o ao ponto M. O resultado \u00e9 o ponto sim\u00e9trico que procur\u00e1vamos.<\/span> <\/li>\n<\/ol>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-como-calcular-el-punto-simetrico-respecto-a-una-recta\"><\/span> Exemplo de c\u00e1lculo do ponto de simetria em rela\u00e7\u00e3o a uma reta<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Assim que soubermos calcular o ponto de simetria de outro ponto em rela\u00e7\u00e3o a uma reta, veremos um exerc\u00edcio resolvido como exemplo:<\/p>\n<ul>\n<li> Encontre o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o \u00e0 linha r. Sendo dito ponto e linha:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e5906f8f5fce95109f9f19d93d1f41cd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A(4,0,-1) \\qquad \\qquad r: \\ \\begin{cases}x=1 + t \\\\[1.7ex] y=5 +4t\\\\[1.7ex] z=-4-3t \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"291\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Primeiro, precisamos calcular o plano perpendicular \u00e0 reta r que passa pelo ponto A. O vetor normal a este plano ser\u00e1 o vetor diretor da reta, cujos componentes s\u00e3o os termos na frente do par\u00e2metro<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4e3cbf5d4c5c6d9b702dd139f14c147_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> porque \u00e9 expresso na forma de equa\u00e7\u00f5es param\u00e9tricas:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2fd3ff01a978525adb880475d0a0d304_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{n}=(1,4,-3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"104\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> E os coeficientes A, B e C da equa\u00e7\u00e3o de um plano coincidem com as coordenadas do seu vetor normal, portanto:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b2278392c74541903e84c40636e7f639_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{n}=(1,4,-3) \\quad \\longrightarrow \\quad \\pi : \\ 1x+4y-3z+D=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"377\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> O ponto A deve estar neste plano, ent\u00e3o podemos agora substituir o ponto A na equa\u00e7\u00e3o do plano para encontrar o coeficiente D: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-10ddfecdcccda04ffbed3050c6ce5f8e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(4,0,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"83\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8659ebec73b4b105c79e577a0a7727ac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"4+4\\cdot 0-3\\cdot (-1)+D=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"210\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a74808d2c61fe33db5d803d5c2b4749c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"4+3+D=0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"109\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-959115729e795b196c018c3e5fe0d5b7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"7+D=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"78\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ad9cd621146368bea5d81d84aa5d1b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"D=-7\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"62\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Portanto, a equa\u00e7\u00e3o do plano perpendicular \u00e0 reta ry que passa pelo ponto A \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e36d9c18276dad2d9ada0417be32c1d0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\pi : \\ x+4y-3z-7=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"184\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Depois de conhecermos a equa\u00e7\u00e3o do plano, precisamos calcular o ponto de intersec\u00e7\u00e3o do plano e da reta. Para fazer isso, substitu\u00edmos as coordenadas da reta na equa\u00e7\u00e3o do plano e resolvemos a equa\u00e7\u00e3o resultante: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fd611c8a6c7e516dbb67583b49f0b8e6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases}x=1 + t \\\\[1.7ex] y=5 +4t\\\\[1.7ex] z=-4-3t \\end{cases} \\qquad \\qquad \\pi : \\ x+4y-3z-7=0\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"415\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7852fbe82935cb80948392ece78525bc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(1+t)+4(5+4t)-3(-4-3t)-7=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"307\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-03bf61d8e06f77dcb88707b3825a8f05_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1+t+20+16t+12+9t-7=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"261\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-94ed39e3d685ae2b03f269a9da7dd0a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"26t+26=0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"96\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5e99205a6c41b2ae65c560013b9aa1f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"26t=-26\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"80\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5d5cd7fed91a3e59d8059cb486d7fdb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t=\\cfrac{-26}{26}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"72\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-35d11e298e261d1ee0e702c094322281_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t=-1\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"52\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Agora substitu\u00edmos o valor de<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4e3cbf5d4c5c6d9b702dd139f14c147_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> obtido na equa\u00e7\u00e3o da reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9b0c515e3969169679e810db65a99e3f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle t=-1 \\ \\longrightarrow \\ \\begin{cases}x=1 -1=0 \\\\[1.7ex] y=5 +4\\cdot (-1)=1\\\\[1.7ex] z=-4-3\\cdot (-1)=-1 \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"299\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Portanto, o ponto de intersec\u00e7\u00e3o entre a reta r e o plano perpendicular a ela \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d3c3451c553224af2b93bf9e49ba1ed6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M(0,1,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"89\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Finalmente, basta encontrar o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o ao ponto M; para isso, podemos utilizar a f\u00f3rmula vista no in\u00edcio desta p\u00e1gina: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c4b39555d71f045dd42e9422dd077679_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned} A' &amp; = 2M - A \\\\[2ex] &amp;= 2(0,1,-1) - (4,0,-1) \\\\[2ex] &amp; = (0,2,-2)-(4,0,-1)\\\\[2ex] &amp; = \\bm{(-4,2,-1)} \\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"147\" width=\"211\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"punto-simetrico-respecto-a-un-plano\"><\/span> ponto sim\u00e9trico a um plano<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Antes de vermos o m\u00e9todo de determina\u00e7\u00e3o do ponto de simetria de outro ponto em rela\u00e7\u00e3o a um plano, vejamos qual \u00e9 a sua defini\u00e7\u00e3o:<\/p>\n<p> <strong>O ponto A&#8217; \u00e9 o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o a um plano se os dois pontos A&#8217; e A est\u00e3o na mesma linha perpendicular ao plano e, al\u00e9m disso, a dist\u00e2ncia entre o ponto A&#8217; e o plano \u00e9 equivalente \u00e0 dist\u00e2ncia entre o ponto A e o plano.<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/point-symetrique-d-un-autre-point-par-respect-d-un-plan.webp\" alt=\"ponto sim\u00e9trico a outro ponto relativo a um plano\" class=\"wp-image-2611\" width=\"402\" height=\"465\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-843280748c244e7f9c83ceda57c4c33e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"d(A,\\pi)= d(A',\\pi)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"137\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Portanto, o plano tamb\u00e9m \u00e9 um plano de simetria entre os dois pontos.<\/p>\n<p> Assim, para conhecer as coordenadas cartesianas do ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o ao plano \u03c0, deve-se seguir os seguintes passos:<\/p>\n<ol style=\"color:#ff6f00; font-weight: bold;>\n<li><span style=\" color:#262626;font-weight:=\"\" normal;\"=\"\">\n<li style=\"margin-bottom:18px\"><span style=\"color:#000000;font-weight: normal;\">Encontramos a equa\u00e7\u00e3o da reta perpendicular ao plano que passa pelo ponto A. Para isso usaremos o vetor normal ao plano como vetor diretor da reta.<\/span><\/li>\n<li style=\"margin-bottom:18px\"> <span style=\"color:#000000;font-weight: normal;\">Calculamos o ponto de intersec\u00e7\u00e3o entre o plano e a reta encontrada (ponto M da imagem anterior).<\/span><\/li>\n<li> <span style=\"color:#000000;font-weight: normal;\">Usamos a f\u00f3rmula ponto sobre ponto sim\u00e9trico (vista na se\u00e7\u00e3o inicial) para encontrar o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o ao ponto M. O resultado \u00e9 o ponto sim\u00e9trico que procur\u00e1vamos.<\/span> <\/li>\n<\/ol>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-como-determinar-el-punto-simetrico-respecto-a-un-plano\"><\/span> Exemplo de determina\u00e7\u00e3o do ponto de simetria em rela\u00e7\u00e3o a um plano<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Abaixo voc\u00ea pode ver um problema resolvido referente ao ponto de simetria de outro ponto em rela\u00e7\u00e3o a um plano:<\/p>\n<ul>\n<li> Determine o ponto de simetria de A em rela\u00e7\u00e3o ao plano \u03c0. Tendo dito ponto e plano:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-764c77ab01ff5f982839f6bc69b91162_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A(3,-4,2) \\qquad \\qquad \\pi: \\ 2x+y-z-6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"329\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> A primeira coisa que precisamos fazer \u00e9 encontrar a equa\u00e7\u00e3o da reta perpendicular ao plano e que passa pelo ponto A. Para isso, podemos usar o vetor normal ao plano como vetor diretor da reta, cujas componentes X, Y, Z s\u00e3o os coeficientes dos termos A, B e C respectivamente da equa\u00e7\u00e3o do plano:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-343ad7603e2777441731b82b5870295d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\pi: \\ 2x+y-z-6=0 \\quad \\longrightarrow \\quad \\vv{n} = (2,1,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"353\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Podemos agora construir as equa\u00e7\u00f5es param\u00e9tricas da reta ortogonal ao plano com o vetor diretor encontrado e um de seus pontos (ponto A):<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7ec51a68802f626dcd5cf7a3bc1dda59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases}x=3 + 2t \\\\[1.7ex] y=-4 +t\\\\[1.7ex] z=2-t \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"128\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Uma vez conhecida a reta perpendicular, calculamos o ponto de intersec\u00e7\u00e3o do plano e da reta substituindo as coordenadas da reta na equa\u00e7\u00e3o do plano: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb4ee2c7f6742eec2e1fa11cac3c5635_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases}x=3 + 2t \\\\[1.7ex] y=-4 +t\\\\[1.7ex] z=2-t \\end{cases} \\qquad \\qquad \\pi : \\ 2x+y-z-6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"397\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fbd71a4094da61137e01c53f34de7058_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2(3+2t)+(-4+t)-(2-t)-6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"290\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a6f4c7a9c5c5277b866385627b521bb0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"6+4t-4+t-2+t-6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"226\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b1360d3226af716e09f10a17743771dc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"6t-6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"78\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8a6bdb4ce652ce19b9ce2304834e1cb8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"6t=6\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"48\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-90ecb612afe8f2bc45dd7111119b07a0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t=\\cfrac{6}{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"41\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-abf8f2abfdf1913d009a51ad64786690_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t=1\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"38\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Agora substitu\u00edmos o valor de<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4e3cbf5d4c5c6d9b702dd139f14c147_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> obtido na equa\u00e7\u00e3o da reta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0a9373141f2f699971d5789e1cb0ed0d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle t=1 \\ \\longrightarrow \\ \\begin{cases}x=3 + 2\\cdot 1 =5\\\\[1.7ex] y=-4 +1=-3\\\\[1.7ex] z=2-1=1 \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"238\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Portanto, o ponto de intersec\u00e7\u00e3o entre o plano e a reta perpendicular \u00e9:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1c91141b9bba6d3ffa4c81fc2d1ef446_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M(5,-3,1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"88\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Por fim, s\u00f3 precisamos encontrar o ponto sim\u00e9trico do ponto A em rela\u00e7\u00e3o ao ponto M. E, para isso, podemos usar a f\u00f3rmula vista no in\u00edcio desta p\u00e1gina:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8199cf83bc3bdfbf0a7b2adb65a97af_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned} A' &amp; = 2M - A \\\\[2ex] &amp;= 2(5,-3,1) - (3,-4,2) \\\\[2ex] &amp; = (10,-6,2)-(3,-4,2)\\\\[2ex] &amp; = \\bm{(7,-2,0)} \\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"147\" width=\"211\" style=\"vertical-align: 0px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como calcular o ponto de simetria em rela\u00e7\u00e3o a outro ponto, em rela\u00e7\u00e3o a uma reta e em rela\u00e7\u00e3o a um plano. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos e exerc\u00edcios resolvidos passo a passo. Ponto sim\u00e9trico a outro ponto Antes de vermos como o ponto sim\u00e9trico \u00e9 calculado, vamos revisar o que &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/ponto-simetrico-respeitando-outro-ponto-em-uma-linha-e-em-um-plano-de-formula\/\"> <span class=\"screen-reader-text\">Ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto, uma reta e um plano<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[20],"tags":[],"class_list":["post-245","post","type-post","status-publish","format-standard","hentry","category-pontos-retas-e-planos"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto, a uma reta e a um plano - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/ponto-simetrico-respeitando-outro-ponto-em-uma-linha-e-em-um-plano-de-formula\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ponto sim\u00e9trico em rela\u00e7\u00e3o a outro ponto, a uma reta e a um plano - Mathority\" \/>\n<meta property=\"og:description\" content=\"Aqui voc\u00ea descobrir\u00e1 como calcular o ponto de simetria em rela\u00e7\u00e3o a outro ponto, em rela\u00e7\u00e3o a uma reta e em rela\u00e7\u00e3o a um plano. 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