{"id":19,"date":"2023-09-17T11:08:30","date_gmt":"2023-09-17T11:08:30","guid":{"rendered":"https:\/\/mathority.org\/pt\/limites-trigonometricos\/"},"modified":"2023-09-17T11:08:30","modified_gmt":"2023-09-17T11:08:30","slug":"limites-trigonometricos","status":"publish","type":"post","link":"https:\/\/mathority.org\/pt\/limites-trigonometricos\/","title":{"rendered":"Limites trigonom\u00e9tricos"},"content":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como resolver limites trigonom\u00e9tricos. Voc\u00ea poder\u00e1 ver diversos exemplos de limites de fun\u00e7\u00f5es trigonom\u00e9tricas e at\u00e9 praticar com passo a passo resolvidos exerc\u00edcios sobre limites trigonom\u00e9tricos. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-son-los-limites-trigonometricos\"><\/span> O que s\u00e3o limites trigonom\u00e9tricos?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Limites trigonom\u00e9tricos s\u00e3o limites calculados em fun\u00e7\u00f5es trigonom\u00e9tricas.<\/strong> Para resolver limites trigonom\u00e9tricos, deve-se aplicar um procedimento preliminar, pois geralmente d\u00e3o origem a indetermina\u00e7\u00f5es.<\/p>\n<p> Al\u00e9m disso, n\u00e3o existem limites infinitos de fun\u00e7\u00f5es trigonom\u00e9tricas, porque s\u00e3o fun\u00e7\u00f5es peri\u00f3dicas. Ou seja, seus gr\u00e1ficos s\u00e3o repetidos continuamente e periodicamente sem tender a um valor espec\u00edfico. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"formulas-de-los-limites-trigonometricos\"><\/span> F\u00f3rmulas de limite trigonom\u00e9trico<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Todos os limites trigonom\u00e9tricos s\u00e3o calculados a partir das duas f\u00f3rmulas a seguir: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-14300dcf4010d732b8568b9b4460b5e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"116\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Demonstra\u00e7\u00e3o de f\u00f3rmula<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Se tentarmos calcular o limite por substitui\u00e7\u00e3o, obtemos a indetermina\u00e7\u00e3o zero entre zero:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0ba13ab3640b429e546e97da2a0ab155_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}=\\frac{\\text{sen}(0)}{0}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"193\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Mas esta f\u00f3rmula trigonom\u00e9trica pode ser demonstrada calculando valores da fun\u00e7\u00e3o mais pr\u00f3xima e mais pr\u00f3xima de x=0 (\u00e2ngulos em radianos). <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2a7ed3df9110a97c224bde10980f2682_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)=\\frac{\\text{sen}(x)}{x}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"142\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-columns is-layout-flex wp-container-123\">\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccd668acef73b9140a0cbbb9c1d53ad3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}\\begin{array}{l}f(-1)=\\cfrac{\\text{sen}(-1)}{-1}=0,84147\\\\[3ex]f(-0,1)=\\cfrac{\\text{sen}(-0,1)}{-0,1}=0,99833\\\\[3ex]f(-0,01)=\\cfrac{\\text{sen}(-0,01)}{-0,01}=0,99998\\\\[3ex]f(-0,001)=\\cfrac{\\text{sen}(-0,001)}{-0,001}=0,99999\\end{array}\\\\[14ex]\\vdots\\\\[2ex]\\displaystyle\\lim_{x\\to 0^-}\\frac{\\text{sen}(x)}{x}=1\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"312\" width=\"288\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66152efc3ce1fa761186a65db677af27_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}\\begin{array}{l}f(1)=\\cfrac{\\text{sen}(1)}{1}=0,84147\\\\[3ex]f(0,1)=\\cfrac{\\text{sen}(0,1)}{0,1}=0,99833\\\\[3ex]f(0,01)=\\cfrac{\\text{sen}(0,01)}{0,01}=0,99998\\\\[3ex]f(0,001)=\\cfrac{\\text{sen}(0,001)}{0,001}=0,99999\\end{array}\\\\[14ex]\\vdots\\\\[2ex]\\displaystyle\\lim_{x\\to 0^+}\\frac{\\text{sen}(x)}{x}=1\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"312\" width=\"261\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Os dois limites laterais da fun\u00e7\u00e3o trigonom\u00e9trica d\u00e3o 1, ent\u00e3o o limite no ponto x=0 \u00e9 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8af649189957b154866097e315f7cb92_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c}\\displaystyle\\lim_{x\\to 0^-}\\frac{\\text{sen}(x)}{x}=\\lim_{x\\to 0^+}\\frac{\\text{sen}(x)}{x}=1\\\\[3ex]\\color{orange}\\bm{\\downarrow}\\\\[2ex]\\lim_{x\\to 0}\\displaystyle\\frac{\\text{sen}(x)}{x}=1\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"130\" width=\"243\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, o limite trigonom\u00e9trico do seno de x dividido por x quando x tende a 0 \u00e9 igual a 1.<\/p>\n<p class=\"has-text-align-left\"> Esta f\u00f3rmula tamb\u00e9m pode ser aplicada para v\u00e1rios \u00e2ngulos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8b276a8e0f8bf93f3ea2b7d0158adbe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(kx)}{kx}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51835176b411ca1ec4f37835a83685fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"146\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Demonstra\u00e7\u00e3o de f\u00f3rmula<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Se tentarmos encontrar o limite por substitui\u00e7\u00e3o direta, obteremos a forma indeterminada zero entre zero:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3e50a5f25f1ca148a4e0107e75e62c43_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{x}=}\\frac{1-\\text{cos}(0)}{0}=\\frac{1-1}{0}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"319\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Mas podemos verificar a igualdade na f\u00f3rmula acima. Para fazer isso, primeiro voc\u00ea deve multiplicar o numerador e o denominador da fra\u00e7\u00e3o por 1 mais o cosseno de x:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-40196b4f425393970ff11577ef645dba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\bigl(1-\\text{cos}(x)\\bigr)\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}{x\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}\" title=\"Rendered by QuickLaTeX.com\" height=\"48\" width=\"235\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora temos uma identidade not\u00e1vel no numerador da fra\u00e7\u00e3o, ent\u00e3o podemos simplific\u00e1-la: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-052fdb01d818c3baa3293d4e1927d37c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1^2-\\text{cos}^2(x)}{x\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"151\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b7f2f3a29d5eaebb5f226607e80dbb9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}^2(x)}{x\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"151\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Partindo da identidade trigonom\u00e9trica fundamental, reescrevemos o numerador: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ff23bded6a6a479ee358e635c74ef2fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}^2(x)+\\text{cos}^2(x)=1 \\ \\longrightarrow \\ \\text{sen}^2(x)=1-\\text{cos}^2(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"381\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-df11237bdbf1c1ef5f607f08db54ca91_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}^2(x)}{x\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}\" title=\"Rendered by QuickLaTeX.com\" height=\"47\" width=\"151\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Podemos, portanto, transformar a fra\u00e7\u00e3o em um produto de fra\u00e7\u00f5es: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cff26553bbe1117d69b5a11e0371b996_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)\\cdot \\text{sen}(x)}{x\\cdot \\bigl(1+\\text{cos}(x)\\bigr)}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"151\" style=\"vertical-align: -20px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ac46678f2030eed0dc15696613ec60ee_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot \\frac{\\text{sen}(x)}{1+\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"178\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Usando as propriedades dos limites, podemos converter a express\u00e3o acima em um produto de limites:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-94b986a7b575a61eeba306ce22a6a01e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot \\lim_{x\\to 0}\\frac{\\text{sen}(x)}{1+\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"209\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Usando a f\u00f3rmula demonstrada acima, podemos simplificar facilmente o limite trigonom\u00e9trico: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-14300dcf4010d732b8568b9b4460b5e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"116\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c46c6322634327f17aa601618460fd3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1\\cdot \\lim_{x\\to 0}\\frac{\\text{sen}(x)}{1+\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"133\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b446be13fe115291c38a7c34c192d571_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x\\to 0}\\frac{\\text{sen}(x)}{1+\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"112\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente, calculamos o limite resultante:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bee04c527b0609fc39a7729ec6677874_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x\\to 0}\\frac{\\text{sen}(0)}{1+\\text{cos}(0)}=\\frac{0}{1+1}=\\frac{0}{2}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"248\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, a f\u00f3rmula do limite trigonom\u00e9trico \u00e9 verificada:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51835176b411ca1ec4f37835a83685fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"146\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tal como acontece com a outra f\u00f3rmula, tamb\u00e9m pode ser usada para v\u00e1rios \u00e2ngulos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-afd4adcffaaad5d5b5c7063ec3542b5e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(kx)}{kx}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"156\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<p> Portanto, <strong>para resolver limites trigonom\u00e9tricos, devemos utilizar a aritm\u00e9tica para transformar as fun\u00e7\u00f5es e obter express\u00f5es semelhantes a estas.<\/strong> Desta forma podemos utilizar uma das duas f\u00f3rmulas e encontrar o valor do limite.<\/p>\n<p> Por outro lado, \u00e0s vezes podemos precisar aplicar certas identidades trigonom\u00e9tricas, por isso deixamos todas as f\u00f3rmulas abaixo para voc\u00ea <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Identidades trigonom\u00e9tricas<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> F\u00f3rmula que liga as tr\u00eas principais raz\u00f5es trigonom\u00e9tricas:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dbf6d65fa67f0a2161bd99ee7431f015_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x)=\\cfrac{\\text{sen}(x)}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"124\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Identidade trigonom\u00e9trica fundamental:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-92d80771f891319379b2e756c5524aaf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}^2(x)+\\text{cos}^2(x)=1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"165\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Rela\u00e7\u00f5es trigonom\u00e9tricas derivadas do fundamental: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-983ec3f9bdead575a110ab13a3149351_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1+\\text{tan}^2 (x)=\\cfrac{1}{\\text{cos}^2(x)}=\\text{sec}^2(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"245\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7b04254cbdd6156ce5fd5449f5234a9e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1+\\text{cot}^2 (x)=\\cfrac{1}{\\text{sen}2(x)}=\\text{cosec}^2(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"262\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00c2ngulos opostos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a0a5345d1ad85390cacfc38e99beb548_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}(-x)=-\\text{sen}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"148\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b7ef3e0d227838cf04c0f7413d1e07f2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(-x)=\\text{cos}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"132\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-507f1aa7df63922130ea766d03aaf91a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(-x)=-\\text{tan}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"149\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Soma de dois \u00e2ngulos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-58668a0aaa63a0e4c39b859619d2444a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}(x+y)=\\text{sen}(x)\\text{cos}(y)+\\text{cos}(x)\\text{sen}(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"315\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-46aaa0aea1219b24ef354afcc8a15953_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(x+y)=\\text{cos}(x)\\text{cos}(y)-\\text{sen}(x)\\text{sen}(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"314\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c5c001a17b792285beacf6cf91f93033_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x+y)=\\cfrac{\\text{tan}(x)+\\text{tan}(y)}{1-\\text{tan}(x)\\text{tan}(y)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"235\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Diferen\u00e7a de dois \u00e2ngulos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02420c87f520da509e0193dab4798f55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}(x-y) = \\text{sen}(x)\\text{cos}(y)-\\text{cos}(x)\\text{sen}(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"315\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9d5d84d5fa7db15e90131596953bedb9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(x-y) = \\text{cos}(x)\\text{cos}(y)+ \\text{sen}(x) sen(y)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"317\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5d01deaacd8e294bcfd6b6284231fa2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x-y)=\\cfrac{\\text{tan}(x)-\\text{tan}(y)}{1+\\text{tan}(x)\\text{tan}(y)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"235\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00c2ngulo duplo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c135a8fb824883a8b8f9ff27a737a9d2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}(2x) = 2\\text{sen}(x)\\text{cos}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"185\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-91843029bf168eab0615f3bb849f2dd1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(2x) =\\text{cos}^2(x)-\\text{sen}^2(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"213\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0cc8aed863858c3052e1dae8bdcdb377_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(2x) =\\cfrac{2\\text{tan}(x)}{1-\\text{tan}^2(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"172\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Meio \u00e2ngulo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ccae2dc8b2bc812d68f9361538ebaf4d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{sen}\\left(\\frac{x}{2}\\right) = \\pm \\sqrt{\\frac{1-\\text{cos}(x)}{2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"201\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f87b3d54e5b0d7527bf38b2a7a71928_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{cos}\\left(\\frac{x}{2}\\right) = \\pm \\sqrt{\\frac{1+\\text{cos}(x)}{2}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"200\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1126d8d443e0285d4ecc510a119b393d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\text{tan}\\left(\\frac{x}{2}\\right) = \\pm \\sqrt{\\frac{1-\\text{cos}(x)}{1+\\text{cos}(x)}}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"202\" style=\"vertical-align: -21px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Adi\u00e7\u00e3o e subtra\u00e7\u00e3o de seno e cosseno: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-457b2949084f43244b619fd965e403f2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{sen}(x)+\\text{sen}(y)=2\\text{sen}\\left(\\frac{x+y}{2} \\right)\\text{cos}\\left(\\frac{x-y}{2} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"347\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4ff2373c8559ef4bebc00a31c7c8f2ef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{sen}(x)-\\text{sen}(y)=2\\text{cos}\\left(\\frac{x+y}{2} \\right)\\text{sen}\\left(\\frac{x-y}{2} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"347\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-625d75c4be2e5bbaca73e2a3f1e1980b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{cos}(x)+\\text{cos}(y)=2\\text{cos}\\left(\\frac{x+y}{2} \\right)\\text{cos}\\left(\\frac{x-y}{2} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"344\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b0a498d3701c9c87123c269c81d266d2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{cos}(x)-\\text{cos}(y)=-2\\text{sen}\\left(\\frac{x+y}{2} \\right)\\text{sen}\\left(\\frac{x-y}{2} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"360\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Produto de senos e cossenos: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-78ab2bb9d2bc291a1f7e4c9e329d893e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{sen}(x)\\cdot \\text{sen}(y)=\\frac{1}{2}\\Bigl[\\text{cos}(x-y)-\\text{cos}(x+y)\\Bigr]\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"338\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-40daecfe989acfa36adb6772d193d027_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{cos}(x)\\cdot \\text{cos}(y)=\\frac{1}{2}\\Bigl[\\text{cos}(x+y)+\\text{cos}(x-y)\\Bigr]\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"336\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b01d45ae9c7b57d25e2bd1bdfea9dba9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{sen}(x)\\cdot \\text{cos}(y)=\\frac{1}{2}\\Bigl[\\text{sen}(x+y)+\\text{sen}(x-y)\\Bigr]\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"339\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<p> Para que voc\u00ea possa ver exatamente como os limites trigonom\u00e9tricos s\u00e3o calculados, reunimos abaixo um exemplo passo a passo.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-limite-trigonometrico\"><\/span> Exemplo de limite trigonom\u00e9trico<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Vamos ver como um limite trigonom\u00e9trico \u00e9 resolvido usando o seguinte exemplo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-83fe05cfbae51406227f863405374405_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{tan}(x)}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"83\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Tentando calcular o limite trigonom\u00e9trico, obtemos a indetermina\u00e7\u00e3o de zero entre zero:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-29fd7943ebb7d7c4ecc7886207c4a1cb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{tan}(x)}{x}=\\frac{\\text{tan}(0)}{0}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"195\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/pt\/zero-entre-zero-0-0-indeterminacao\/\">limites de zero entre zero<\/a><\/span><\/p>\n<p> \u00c9 portanto necess\u00e1rio transformar a fun\u00e7\u00e3o trigonom\u00e9trica para resolver o limite. A fun\u00e7\u00e3o tangente \u00e9 igual ao seno dividido pelo cosseno, ent\u00e3o:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dbf6d65fa67f0a2161bd99ee7431f015_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x)=\\cfrac{\\text{sen}(x)}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"124\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-24793b3f48b399e9fd64b2eb6758f0c8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{tan}(x)}{x}=\\lim_{x\\to 0}\\frac{\\displaystyle\\frac{\\text{sen}(x)}{\\text{cos}(x)}}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"61\" width=\"195\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Podemos agora expressar a fun\u00e7\u00e3o como um produto aplicando as propriedades das fra\u00e7\u00f5es:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fe877e223e062371ef4aa551372cfa69_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\frac{\\displaystyle\\frac{a}{b}}{\\displaystyle\\frac{c}{d}}=\\frac{a\\cdot d}{b\\cdot c}\" title=\"Rendered by QuickLaTeX.com\" height=\"69\" width=\"73\" style=\"vertical-align: -30px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dd10c321c3b7dc40698b318c7187a3c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}\\displaystyle\\lim_{x\\to 0}\\frac{\\displaystyle\\frac{\\text{sen}(x)}{\\text{cos}(x)}}{\\displaystyle\\frac{x}{1}}=\\lim_{x\\to 0}{\\frac{\\text{sen}(x)\\cdot 1}{\\text{cos}(x) \\cdot x}=\\\\[6ex]\\displaystyle =\\lim_{x\\to 0}{\\frac{\\text{sen}(x)}{x\\text{cos}(x)}=\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot \\frac{1}{\\text{cos}(x)}\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"145\" width=\"282\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Usando as propriedades dos limites, podemos converter o limite de duas fun\u00e7\u00f5es multiplicadas no produto de dois limites:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-38f278cf96ac97997db5ffe530037582_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot\\frac{1}{\\text{cos}(x)}=\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot\\lim_{x\\to 0}\\frac{1}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"350\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Como mostramos acima, o primeiro limite trigonom\u00e9trico d\u00e1 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-14300dcf4010d732b8568b9b4460b5e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"116\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ac5a01bca48ac7a961a99be694dcd8c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot\\lim_{x\\to 0}\\frac{1}{\\text{cos}(x)}=1\\cdot\\lim_{x\\to 0}\\frac{1}{\\text{cos}(x)}=\\lim_{x\\to 0}\\frac{1}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"413\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Ent\u00e3o basta fazer o seguinte c\u00e1lculo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-24b950800435e32f07649e25afd6d68e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lim_{x\\to 0}\\frac{1}{\\text{cos}(x)}=\\frac{1}{\\text{cos}(0)}=\\frac{1}{1}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"225\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-limites-trigonometricos\"><\/span> Exerc\u00edcios resolvidos sobre limites trigonom\u00e9tricos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Resolva o seguinte limite trigonom\u00e9trico: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-730128e3fffaf36349ed1c2db19d8796_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{2x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"91\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Primeiro, tentamos calcular o limite trigonom\u00e9trico por avalia\u00e7\u00e3o direta:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b46144b4ff38b63a3c428b5aa60ffb5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{2x}=\\frac{\\text{sen}(4\\cdot 0)}{2\\cdot 0}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"224\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Mas obtemos zero sobre zero indetermina\u00e7\u00e3o. Portanto, precisamos aplicar transforma\u00e7\u00f5es \u00e0 fun\u00e7\u00e3o.<\/p>\n<p class=\"has-text-align-left\"> Primeiro, deixaremos o x no denominador fazendo o seguinte:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66cfa67d319a268be5ac3c6eaf733240_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{2x}=\\lim_{x\\to 0}\\frac{1}{2}\\cdot\\frac{\\text{sen}(4x)}{x}=\\frac{1}{2}\\cdot\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"375\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora multiplicamos e dividimos a fra\u00e7\u00e3o por 4 para obter uma express\u00e3o com a qual a primeira f\u00f3rmula para limites trigonom\u00e9tricos pode ser aplicada:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-caa05571515d0dbc716d6e8cb6b0be0b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\frac{1}{2}\\lim_{x\\to 0}\\frac{\\text{sen}(4x)\\cdot 4}{x\\cdot 4}=\\frac{1}{2}\\cdot 4 \\cdot \\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{4x}=2\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{4x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"418\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por fim, aplicamos a f\u00f3rmula vista no in\u00edcio e resolvemos o limite trigonom\u00e9trico: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8b276a8e0f8bf93f3ea2b7d0158adbe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(kx)}{kx}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e21a4ad74086fda398299e2d83c9a052_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 2\\lim_{x\\to 0}\\frac{\\text{sen}(4x)}{4x}=2\\cdot 1=\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"190\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Calcule o seguinte limite trigonom\u00e9trico: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b6eb2bc6fa65e96cfe55e695b93b2cd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)+\\text{tan}(x)}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"153\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Primeiro, tentamos encontrar o limite trigonom\u00e9trico:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2e4a361830bf074dfb37219d1288c315_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)+\\text{tan}(x)}{x}=\\frac{\\text{sen}(0)+\\text{tan}(0)}{0}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"334\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Mas a forma indeterminada zero corresponde a zero \u00e9 alcan\u00e7ada.<\/p>\n<p class=\"has-text-align-left\"> Ent\u00e3o, convertemos a tangente em um quociente do seno e do cosseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8dbbefdca880d5806977d6b13b473b7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)+\\text{tan}(x)}{x}=\\lim_{x\\to 0}\\frac{\\displaystyle\\text{sen}(x)+\\frac{\\text{sen}(x)}{\\text{cos}(x)}}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"61\" width=\"335\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Multiplicamos e dividimos pelo cosseno de x:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-53452abaa54f3c7e46b75965500221ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\left(\\displaystyle\\text{sen}(x)+\\frac{\\text{sen}(x)}{\\text{cos}(x)}\\right)\\cdot\\text{cos}(x)}{x\\cdot\\text{cos}(x)}=\\lim_{x\\to 0}\\frac{\\text{sen}(x)\\text{cos}(x)+\\text{sen}(x)}{x\\cdot\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"67\" width=\"469\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pegamos um fator comum no numerador e separamos o limite trigonom\u00e9trico em dois:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eeaa601256f134072260480b64210950_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)(\\text{cos}(x)+1)}{x\\cdot\\text{cos}(x)}=\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot\\lim_{x\\to 0}\\frac{\\text{cos}(x)+1}{\\text{cos}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"408\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente, encontramos o resultado do limite trigonom\u00e9trico: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7259ba5ebcb847c0953947ca2fb1d219_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(x)}{x}\\cdot\\lim_{x\\to 0}\\frac{\\text{cos}(x)+1}{\\text{cos}(x)}=1\\cdot\\frac{\\text{cos}(0)+1}{\\text{cos}(0)} =\\frac{1+1}{1}=\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"435\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Resolva o limite da seguinte fun\u00e7\u00e3o trigonom\u00e9trica quando x se aproxima de zero: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f9da1c65931e93b840821e76bc20d629_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\text{tan}(x)-\\text{sen}{(x)}}{3x\\cdot\\text{tan}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"153\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Fazendo o c\u00e1lculo direto obtemos o limite indeterminado 0 entre 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-67e20b7fd699b38122cab6a801cc5655_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}}\\frac{\\text{tan}(x)-\\text{sen}(x)}{3x\\cdot\\text{tan}(x)}=\\frac{\\text{tan}(0)-\\text{sen}(0)}{3\\cdot 0\\cdot\\text{tan}(0)}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"334\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, simplificaremos o limite dividindo cada termo pela tangente de x:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d9036c709f0cf05a0e1d3e53a1f81af8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\displaystyle\\frac{\\text{tan}(x)}{\\text{tan}(x)}-\\frac{\\text{sen}(x)}{\\text{tan}(x)}}{\\displaystyle\\frac{3x\\cdot\\text{tan}(x)}{\\text{tan}(x)}}=\\lim_{x\\to 0}\\frac{\\displaystyle 1-\\frac{\\text{sen}(x)}{\\text{tan}(x)}}{3x}\" title=\"Rendered by QuickLaTeX.com\" height=\"89\" width=\"305\" style=\"vertical-align: -40px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Segundo, podemos deduzir da identidade trigonom\u00e9trica fundamental que a fra\u00e7\u00e3o do numerador \u00e9 equivalente ao cosseno de x: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2c4733e791e3ea6006f69e25c3db9f99_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{tan}(x)=\\cfrac{\\text{sen}(x)}{\\text{cos}(x)}\\ \\longrightarrow \\ \\text{cos}(x)=\\cfrac{\\text{sen}(x)}{\\text{tan}(x)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"297\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-061c6b3972071af7e6227fad37ec4019_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{\\displaystyle 1-\\frac{\\text{sen}(x)}{\\text{tan}(x)}}{3x}=\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{3x}\" title=\"Rendered by QuickLaTeX.com\" height=\"61\" width=\"255\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E aplicando a segunda f\u00f3rmula demonstrada na teoria dos limites trigonom\u00e9tricos, podemos facilmente resolver o limite: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51835176b411ca1ec4f37835a83685fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"146\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b1ee20bc86ad7559fcda3d6bad3c9b27_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}\\displaystyle\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{3x}=\\lim_{x\\to 0}\\frac{1}{3}\\cdot \\frac{1-\\text{cos}(x)}{x}=\\\\[4ex]\\displaystyle =\\frac{1}{3}\\lim_{x\\to 0}\\frac{1-\\text{cos}(x)}{x}=\\frac{1}{3}\\cdot 0=\\bm{0}\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"101\" width=\"294\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 4<\/h3>\n<p> Determine a solu\u00e7\u00e3o do seguinte limite trigonom\u00e9trico no ponto x=0: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a7cbd12a8e0f0416e55baa4799395661_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{2\\text{sen}(x)\\text{cos}(x)\\text{sen}(5x)}{x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"196\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Se tentarmos resolver o limite, encontraremos a forma indeterminada 0\/0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0d1052ddde97caedf5e563febc26fad7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{2\\text{sen}(x)\\text{cos}(x)\\text{sen}(5x)}{x^2}=\\frac{2\\text{sen}(0)\\text{cos}(0)\\text{sen}(5\\cdot 0)}{0^2}=\\frac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"432\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A express\u00e3o alg\u00e9brica para o numerador pode ser reescrita usando a identidade trigonom\u00e9trica do seno de um \u00e2ngulo duplo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2a7acdc1773c3d7fd430328604cee7d3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sen}(2x)=2\\text{sen}(x)\\text{cos}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"185\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4426a183bebf1739384bda14bcd59dc7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\lim_{x\\to 0}\\frac{2\\text{sen}(x)\\text{cos}(x)\\text{sen}(5x)}{x^2}=\\lim_{x\\to 0}\\frac{\\text{sen}(2x)\\text{sen}(5x)}{x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"371\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora vamos separar o limite da fun\u00e7\u00e3o trigonom\u00e9trica em um produto:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fc650634075435b782f1e7b921b77c02_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(2x)\\cdot \\text{sen}(5x)}{x\\cdot x}=\\\\[4ex]\\displaystyle =\\lim_{x\\to 0}\\frac{\\text{sen}(2x)}{x}\\cdot\\frac{\\text{sen}(5x)}{x}=\\\\[4ex]\\displaystyle =\\lim_{x\\to 0}\\frac{\\text{sen}(2x)}{x}\\cdot\\lim_{x\\to 0}\\frac{\\text{sen}(5x)}{x}\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"163\" width=\"216\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E, finalmente, resolvemos o limite trigonom\u00e9trico aplicando as propriedades dos limites: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7c26ba3032828541e69e4bd976ac4f96_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}\\displaystyle\\lim_{x\\to 0}\\frac{\\text{sen}(2x)}{x}\\cdot\\lim_{x\\to 0}\\frac{\\text{sen}(5x)}{x}=\\\\[4ex]\\displaystyle =2\\cdot \\lim_{x\\to 0}\\frac{\\text{sen}(2x)}{2x}\\cdot 5\\cdot \\lim_{x\\to 0}\\frac{\\text{sen}(5x)}{5x}=\\\\[4ex]\\displaystyle =2\\cdot 1\\cdot 5\\cdot 1=\\bm{10}\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"141\" width=\"278\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Aqui voc\u00ea descobrir\u00e1 como resolver limites trigonom\u00e9tricos. Voc\u00ea poder\u00e1 ver diversos exemplos de limites de fun\u00e7\u00f5es trigonom\u00e9tricas e at\u00e9 praticar com passo a passo resolvidos exerc\u00edcios sobre limites trigonom\u00e9tricos. O que s\u00e3o limites trigonom\u00e9tricos? Limites trigonom\u00e9tricos s\u00e3o limites calculados em fun\u00e7\u00f5es trigonom\u00e9tricas. Para resolver limites trigonom\u00e9tricos, deve-se aplicar um procedimento preliminar, pois geralmente d\u00e3o origem &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/pt\/limites-trigonometricos\/\"> <span class=\"screen-reader-text\">Limites trigonom\u00e9tricos<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[34],"tags":[],"class_list":["post-19","post","type-post","status-publish","format-standard","hentry","category-trigonometria"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Limites trigonom\u00e9tricos -<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/pt\/limites-trigonometricos\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Limites trigonom\u00e9tricos -\" \/>\n<meta property=\"og:description\" content=\"Aqui voc\u00ea descobrir\u00e1 como resolver limites trigonom\u00e9tricos. Voc\u00ea poder\u00e1 ver diversos exemplos de limites de fun\u00e7\u00f5es trigonom\u00e9tricas e at\u00e9 praticar com passo a passo resolvidos exerc\u00edcios sobre limites trigonom\u00e9tricos. O que s\u00e3o limites trigonom\u00e9tricos? Limites trigonom\u00e9tricos s\u00e3o limites calculados em fun\u00e7\u00f5es trigonom\u00e9tricas. Para resolver limites trigonom\u00e9tricos, deve-se aplicar um procedimento preliminar, pois geralmente d\u00e3o origem &hellip; Limites trigonom\u00e9tricos Leia mais &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/pt\/limites-trigonometricos\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-17T11:08:30+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-14300dcf4010d732b8568b9b4460b5e0_l3.png\" \/>\n<meta name=\"author\" content=\"Equipe Mathoridade\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Equipe Mathoridade\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"5 minutos\" \/>\n<script type=\"application\/ld+json\" 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