{"id":429,"date":"2023-07-03T15:44:25","date_gmt":"2023-07-03T15:44:25","guid":{"rendered":"https:\/\/mathority.org\/nl\/hyperbolische-sinusderivaat\/"},"modified":"2023-07-03T15:44:25","modified_gmt":"2023-07-03T15:44:25","slug":"hyperbolische-sinusderivaat","status":"publish","type":"post","link":"https:\/\/mathority.org\/nl\/hyperbolische-sinusderivaat\/","title":{"rendered":"Afgeleide van de hyperbolische sinus"},"content":{"rendered":"<p>Hier vindt u hoe u de hyperbolische sinus (formule) kunt afleiden. Bovendien ziet u verschillende opgeloste voorbeelden van de hyperbolische sinusderivaat. En ten slotte bewijzen we de formule voor de afgeleide van dit type trigonometrische functie. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"formula-de-la-derivada-del-seno-hiperbolico\"><\/span> Formule afgeleid van hyperbolische sinus<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>De afgeleide van de hyperbolische sinus van x is de hyperbolische cosinus van x.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5824c2bfe983f8a9b725fab69a97ecca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"394\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Daarom is de <strong>afgeleide van de hyperbolische sinus van een functie<\/strong> gelijk aan het product van de hyperbolische cosinus van de functie en de afgeleide van die functie.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d49318fdfae22c716e856e18e7440db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"422\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Eigenlijk zijn de bovenstaande twee formules hetzelfde, het enige verschil is dat we in de tweede formule de kettingregel toepassen. En aangezien de afgeleide van x 1 is, verandert dit niets aan de functie. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/derivee-du-sinus-hyperbolique.webp\" alt=\"afgeleide van de hyperbolische sinus\" class=\"wp-image-2021\" width=\"423\" height=\"286\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Zoals je kunt zien, lijkt de formule voor de hyperbolische sinusderivaat sterk op de <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/nl\/sinusderivaat\/\">formule voor de sinusderivaat<\/a><\/span> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplos-de-la-derivada-del-seno-hiperbolico\"><\/span> Voorbeelden van de hyperbolische sinusderivaat<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Nadat we al hebben gezien wat de formule van de hyperbolische sinusderivaat is, gaan we nu verder met het oplossen van verschillende voorbeelden van de hyperbolische sinusderivaat. U twijfelt dus zeker niet aan de manier waarop dit wordt gedaan. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-1-derivada-del-seno-hiperbolico-de-2x\"><\/span> Voorbeeld 1: Afgeleide van de hyperbolische sinus van 2x<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-11e5d630f508c66d1be884d9a6454d30_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(2x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"125\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> In dit geval hebben we in het hyperbolische sinusargument een andere functie dan x. Daarom moeten we de hyperbolische sinusafgeleide formule met de kettingregel gebruiken om de afgeleide te vinden:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d49318fdfae22c716e856e18e7440db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"422\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> De afgeleide van 2x is 2, dus de afgeleide van de hyperbolische sinus van 2x is de hyperbolische cosinus van 2x maal 2. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4e763d6973e52217ac14f6f6b3344737_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(2x) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(2x)\\cdot 2=2\\text{cosh}(2x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"533\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-2-derivada-del-seno-hiperbolico-de-x-al-cuadrado\"><\/span> Voorbeeld 2: Afgeleide van de hyperbolische sinus van x kwadraat<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-432b20159f3f131533249e4ee44702e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(x^2)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"123\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> De formule voor de afgeleide van de hyperbolische sinusfunctie is:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d49318fdfae22c716e856e18e7440db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(u) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(u)\\cdot u'\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"422\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Aan de andere kant is de afgeleide van de kwadratische functie x <sup>2<\/sup> 2x. De afgeleide van de gehele functie is daarom: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-56db45ee5a51f7ed624f7e88ce4cf906_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=\\text{senh}(x^2) \\quad\\color{orange}\\bm{\\longrightarrow}\\quad\\color{black} f'(x)=\\text{cosh}(x^2)\\cdot 2x\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"443\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"demostracion-de-la-formula-de-la-derivada-del-seno-hiperbolico\"><\/span> Bewijs van de formule voor de afgeleide van de hyperbolische sinus<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Ten slotte zullen we de formule voor de hyperbolische sinusderivaat demonstreren. Om dit te doen, zullen we uitgaan van de wiskundige definitie van de hyperbolische sinus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef003e8f8367d5cacacb4d67fb8dbd01_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{senh}(x)=\\cfrac{e^x-e^{-x}}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"150\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> We leiden nu de twee kanten van de gelijkheid af:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-39aa6ef096997dc19e3850036a95b0d2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\bigl(\\text{senh}(x)\\bigr)'=\\left(\\frac{e^x-e^{-x}}{2}\\right)'\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"201\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Om de rechterkant van de vergelijking af te leiden, gebruiken we de formule voor de afgeleide van deling:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c11def15692e1374b5f75743bfc04b40_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\text{senh}'(x)=\\frac{(e^x+e^{-x})\\cdot 2}{2^2}=\\frac{e^x+e^{-x}}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"284\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Zie:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/nl\/afgeleide-van-de-exponentiele-functie\/\">afgeleide van de exponenti\u00eble functie met grondtal e<\/a><\/span><\/p>\n<p> En precies zijn we aangekomen bij de uitdrukking die de hyperbolische cosinus definieert. Zodat de afgeleide van de hyperbolische sinus bewezen is:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fb3756efaf241b9435c36856a5dad2b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\text{senh}'(x)=\\text{cosh}(x)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"143\" style=\"vertical-align: -5px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hier vindt u hoe u de hyperbolische sinus (formule) kunt afleiden. Bovendien ziet u verschillende opgeloste voorbeelden van de hyperbolische sinusderivaat. En ten slotte bewijzen we de formule voor de afgeleide van dit type trigonometrische functie. Formule afgeleid van hyperbolische sinus De afgeleide van de hyperbolische sinus van x is de hyperbolische cosinus van x. &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/nl\/hyperbolische-sinusderivaat\/\"> <span class=\"screen-reader-text\">Afgeleide van de hyperbolische sinus<\/span> Lees meer &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[38],"tags":[],"class_list":["post-429","post","type-post","status-publish","format-standard","hentry","category-derivaten"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Afgeleide van de hyperbolische sinus - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/nl\/hyperbolische-sinusderivaat\/\" \/>\n<meta property=\"og:locale\" content=\"nl_NL\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Afgeleide van de hyperbolische sinus - Mathority\" \/>\n<meta property=\"og:description\" content=\"Hier vindt u hoe u de hyperbolische sinus (formule) kunt afleiden. 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