{"id":70,"date":"2023-09-17T05:59:45","date_gmt":"2023-09-17T05:59:45","guid":{"rendered":"https:\/\/mathority.org\/it\/matrice-inversa\/"},"modified":"2023-09-17T05:59:45","modified_gmt":"2023-09-17T05:59:45","slug":"matrice-inversa","status":"publish","type":"post","link":"https:\/\/mathority.org\/it\/matrice-inversa\/","title":{"rendered":"Come calcolare la matrice inversa"},"content":{"rendered":"<p>In questa pagina imparerai cos&#8217;\u00e8 e come calcolare l&#8217;inversa di una matrice con il metodo dei determinanti (o matrice aggiunta) e con il metodo di Gauss. Vedrai anche tutte le propriet\u00e0 della matrice inversa e troverai anche esempi ed esercizi risolti passo dopo passo per ciascun metodo in modo da comprenderli completamente. Infine, spieghiamo una formula per invertire rapidamente una matrice 2&#215;2 e anche la pi\u00f9 grande utilit\u00e0 di questa operazione di matrice: risolvere un sistema di equazioni lineari.<\/p>\n<h2 class=\"wp-block-heading\"> Qual \u00e8 l&#8217;inverso di una matrice? <\/h2>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Essere<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> una matrice quadrata. La <strong>matrice inversa<\/strong> di<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 scritto<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2b32875906f7ed9c10ffd1b09a6ed5e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"30\" style=\"vertical-align: 0px;\"><\/p>\n<p> , ed \u00e8 questa matrice che soddisfa:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fd42c364eee57f5eada44b8ef06f254a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A \\cdot A^{-1} = I\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a003e1fd3042f8cd7ec7d3fe7f286f5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}\\cdot A  = I\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p align=\"LEFT\"> Oro<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-18b5e45cb4a1ee02e81b9a980f828db8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 la matrice Identit\u00e0.<\/p>\n<\/div>\n<h2 class=\"wp-block-heading\"> Quando puoi invertire una matrice e quando no?<\/h2>\n<p> Il modo pi\u00f9 semplice per determinare l&#8217;invertibilit\u00e0 di una matrice \u00e8 utilizzare il suo determinante:<\/p>\n<ul>\n<li> Se il determinante della matrice in questione \u00e8 diverso da 0 significa che la matrice \u00e8 invertibile. In questo caso si dice che \u00e8 una matrice regolare. Inoltre, ci\u00f2 implica che la matrice sia di rango massimo.<\/li>\n<\/ul>\n<ul>\n<li> Se invece il determinante della matrice \u00e8 uguale a 0, la matrice non pu\u00f2 essere invertita. E, in questo caso, diciamo che si tratta di una matrice singolare o degenere.<\/li>\n<\/ul>\n<p> Principalmente esistono due metodi per invertire qualsiasi matrice: il metodo dei determinanti o matrice aggiunta e il metodo di Gauss. Di seguito hai la spiegazione del primo, ma puoi anche consultare di seguito come invertire una matrice con il metodo di Gauss.<\/p>\n<h2 class=\"wp-block-heading\"> Invertire una matrice utilizzando il metodo del determinante (o utilizzando la matrice adiacente) <\/h2>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Per calcolare l&#8217; <strong>inversa di una matrice<\/strong> ,<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3017946e4911f6188e04dfdca6f050ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"30\" style=\"vertical-align: 0px;\"><\/p>\n<p> , deve essere applicata la seguente formula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p align=\"LEFT\" style=\"margin-bottom:8px\"> Oro:<\/p>\n<ul>\n<li style=\"margin-bottom:12px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a80d0312d139244060532c8c78fe6140_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix} A \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"21\" style=\"vertical-align: -7px;\"><\/p>\n<p> \u00e8 il determinante della matrice<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<\/li>\n<li style=\"margin-bottom:12px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e87ef954487ce9371eac7dc25f234613_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj}(A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"55\" style=\"vertical-align: -5px;\"><\/p>\n<p> \u00e8 la matrice aggiunta di<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<\/li>\n<li> L&#8217;espositore\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50d6971192a73f12b183dbddd7c75197_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> indica la trasposizione della matrice, ovvero la matrice allegata deve essere trasposta.<\/li>\n<\/ul>\n<\/div>\n<p> <strong>Commento:<\/strong> alcuni libri utilizzano una formula di matrice inversa leggermente diversa: prima traspongono la matrice A e poi calcolano la sua matrice aggiunta, invece di calcolare prima la matrice aggiunta e poi trasporla. In realt\u00e0 l&#8217;ordine non ha importanza perch\u00e9 il risultato \u00e8 esattamente lo stesso. Qui ti lasciamo la formula per invertire una matrice modificata nel caso in cui preferisci utilizzare questa: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-la-matrice-inverse-adjointe-de-transposee-3.webp\" alt=\"formula per la matrice inversa con la matrice aggiunta della trasposta\" class=\"wp-image-4372\" width=\"238\" height=\"239\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Vedremo poi <strong>come trovare l&#8217;inversa di una matrice<\/strong> risolvendo un esercizio a titolo di esempio:<\/p>\n<h3 class=\"wp-block-heading\"> Esempio di calcolo della matrice inversa utilizzando il metodo del determinante (o matrice aggiunta):<\/h3>\n<ul>\n<li> Calcolare l&#8217;inversa della seguente matrice:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c37ec4a7afd5b313bcf3c50d6ce26c6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 4 &amp; -2  \\\\[1.1ex] 3 &amp; -1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Per determinare l&#8217;inversa della matrice, dobbiamo applicare la seguente formula: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-la-matrice-inverse-avec-la-methode-par-determinants-ou-par-la-matrice-adjointe.webp\" alt=\"formula della matrice inversa con il metodo dei determinanti o della matrice aggiunta\" width=\"218\" height=\"59\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Ma se il determinante della matrice \u00e8 zero significa che la matrice non \u00e8 invertibile. La prima cosa da fare quindi \u00e8 calcolare il determinante della matrice e verificare che sia diverso da 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-710ccd4e4912dd492b496a742eaf7f56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\lvert A \\rvert  = \\begin{vmatrix}  4 &amp; -2  \\\\[1.1ex] 3 &amp; -1 \\end{vmatrix} = -4- (-6) = 2\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"240\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Il <strong>determinante non \u00e8 0<\/strong> , quindi <strong>la matrice \u00e8 invertibile<\/strong> .<\/p>\n<p> Pertanto, sostituendo nella formula il valore del determinante, l&#8217;inverso della matrice sar\u00e0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9be7ff27e83825750fc7b378f743412f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"161\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Dobbiamo ora calcolare la matrice sostitutiva di A. Per fare ci\u00f2, dobbiamo sostituire ogni elemento della matrice A con il suo sostitutivo. <\/p>\n<div style=\"background-color:#fffde7;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Ricordatevi che per calcolare il <strong>pignoramento<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> , cio\u00e8 dell&#8217;elemento riga<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> e la colonna<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> , deve essere applicata la seguente formula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dcce4b79a3549da03df7c78b678add31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } a_{ij} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"430\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p align=\"LEFT\"> Dove il minore complementare di<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e8 il determinante della matrice eliminando la riga<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> e la colonna<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> .<\/p>\n<\/div>\n<p> Pertanto i deputati degli elementi della matrice A sono: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c37ec4a7afd5b313bcf3c50d6ce26c6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 4 &amp; -2  \\\\[1.1ex] 3 &amp; -1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-981d47faf70cc1377c1abb515419a881_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} -1 \\end{vmatrix} = 1 \\cdot (-1) = \\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0f1e6a5a5c504b3b6d06e5d3d8e0862e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"336\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02a2bf190ba8788264d0326f38cb0a21_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -2 \\end{vmatrix} = -1 \\cdot (-2) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f01b7eb06a25b50bf15fbfd08e68cd13_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -1} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 4 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"309\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> <strong>Commento:<\/strong> non confondere il determinante 1\u00d71 con il valore assoluto, perch\u00e9 nel determinante 1\u00d71 il numero non viene convertito in positivo.<\/p>\n<p> Una volta calcolati i deputati, basta sostituire gli elementi di A con i loro deputati per trovare la <strong>matrice dei deputati di A<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-08fb7666b4518399c2a469ba445762be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} -1 &amp; -3  \\\\[1.1ex] 2 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"165\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> <strong>Commento:<\/strong> in certi punti la matrice aggiunta \u00e8 la trasposta della matrice aggiunta che qui definiamo.<\/p>\n<p> Pertanto, sostituiamo la matrice allegata nella formula della matrice inversa e diventa:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9be7ff27e83825750fc7b378f743412f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"161\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0abb4127db9c3c1d0a7b669fbc782605_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\begin{pmatrix} -1 &amp; -3  \\\\[1.1ex] 2 &amp; 4  \\end{pmatrix} ^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> L&#8217;espositore<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50d6971192a73f12b183dbddd7c75197_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> Questo ci dice che dobbiamo <strong>trasporre la matrice<\/strong> . E per trasporre una matrice devi <strong>cambiare le sue righe in colonne<\/strong> , vale a dire che la prima riga della matrice diventa la prima colonna della matrice, e la seconda riga diventa la seconda colonna:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-22965912cf8aee99610c81cf575c0ecd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\begin{pmatrix} -1 &amp; 2  \\\\[1.1ex] -3 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"151\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> E infine, moltiplichiamo ciascun termine della matrice per<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a7c03ba828b3d8aef58199ac2c95a47_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{1}{2} :\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"18\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-220748840151b429919c7ce6587b1bc0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\sfrac{-1}{2} &amp; \\sfrac{2}{2}  \\\\[1.1ex] \\sfrac{-3}{2} &amp; \\sfrac{4}{2}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/matrice-inverse-de-lexercice-resolu-par-les-determinants-22152.webp\" alt=\"esercizio risolto matrice inversa con determinanti 2x2\" width=\"188\" height=\"69\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h3 class=\"wp-block-heading\"> Esercizi risolti su matrici inverse con il metodo dei determinanti (o della matrice adiacente)<\/h3>\n<h4 class=\"wp-block-heading\"> Esercizio 1<\/h4>\n<p> Invertire la seguente matrice di dimensione 2\u00d72 utilizzando il metodo della matrice aggiunta: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bfb0807249e78845b375a402eb23a32b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 7  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La formula della matrice inversa \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Per prima cosa calcoliamo il determinante della matrice:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1c4e3bac90eb0da0361b4be1a2225146_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 7 \\end{vmatrix} = 7-6 = 1\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"187\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il determinante \u00e8 diverso da 0, quindi la matrice pu\u00f2 essere invertita.<\/p>\n<p class=\"has-text-align-left\"> Calcoliamo ora la matrice aggiunta di A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-34ac8739bfee66d594eee01b7a2b9205_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 7 \\end{vmatrix} = 1 \\cdot 7 = \\bm{7}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"303\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4021288fe5f1db07d81dbb43ce15e82a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 2\\end{vmatrix} = -1 \\cdot 2 = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"329\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-12783f7673a347fc5e0df04917332fa0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"330\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d48d00b2e8df51348f8f41c96b9197b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 7} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 \\end{vmatrix} = 1 \\cdot 1 = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"302\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3dea8fca2c025ff9b7d7673904344996_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 7 &amp; -2  \\\\[1.1ex] -3 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"165\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta calcolato il determinante della matrice e il suo aggiunto, sostituiamo i loro valori nella formula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9475e4162eff7e1ed9c08f363a8279ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{1} \\cdot \\begin{pmatrix} 7 &amp; -2 \\\\[1.1ex] -3 &amp; 1 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Trasponiamo la matrice allegata:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a5a6aaa8168e55c6eab1e3be1229a3da_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = 1 \\cdot \\begin{pmatrix} 7 &amp; -3 \\\\[1.1ex] -2 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"162\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice inversa di A \u00e8 quindi: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1236ad7262705dbbd9b0a094084ceac5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\bm{7} &amp; \\bm{-3} \\\\[1.1ex] \\bm{-2} &amp; \\bm{1} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 2<\/h4>\n<p> Invertire la seguente matrice quadrata utilizzando il metodo del determinante: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb735917d200ed35918cd44be6bd155b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} -3 &amp; -2 \\\\[1.1ex] 5 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La formula della matrice inversa \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Per prima cosa calcoliamo il determinante della matrice:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-49cd3daf7c50c811e78c29efe036bda4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} -3 &amp; -2 \\\\[1.1ex] 5 &amp; 4\\end{vmatrix} = -12+10 = -2\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"260\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il determinante \u00e8 diverso da 0, quindi la matrice pu\u00f2 essere invertita.<\/p>\n<p class=\"has-text-align-left\"> Calcoliamo ora la matrice aggiunta di A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8bff9fecfd83ca1edacba562d8714cbf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -3} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 4 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"309\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b558b2d47ccf4b3065ed8b26ab620502_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 5\\end{vmatrix} = -1 \\cdot 5 = \\bm{-5}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"335\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b6d0a26085435c08c6d60ab80f4fbb2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 5}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -2 \\end{vmatrix} = -1 \\cdot (-2) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-79a60c5e3003ea311503867a147c1500_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} -3 \\end{vmatrix} = 1 \\cdot (-3) = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"358\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-208ab7161076485ca6928bd1208f6714_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 4 &amp; -5  \\\\[1.1ex] 2 &amp; -3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"151\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta trovato il determinante della matrice e il suo aggiunto, sostituiamo i loro valori nella formula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-babecc87455bdc54006a77ba5369e540_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{-2} \\cdot \\begin{pmatrix} 4 &amp; -5 \\\\[1.1ex] 2 &amp; -3 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Trasponiamo la matrice allegata:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-17529597656a112a27d136ca212834d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{-2} \\cdot \\begin{pmatrix} 4 &amp; 2 \\\\[1.1ex] -5 &amp; -3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Moltiplichiamo ogni elemento per <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f70ecad488bad8503fe7f8427180e2e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{1}{-2} :\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"32\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-be52d2df839244cbb0b0ee00c9e45265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\cfrac{4}{-2} &amp; \\cfrac{2}{-2} \\\\[3ex] \\cfrac{-5}{-2} &amp; \\cfrac{-3}{-2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice inversa di A \u00e8 quindi: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-13e218c7d075daba3f875345f324d001_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\bm{-2} &amp; \\bm{-1} \\\\[2ex] \\cfrac{\\bm{5}}{\\bm{2}} &amp; \\cfrac{\\bm{3}}{\\bm{2}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"141\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 3<\/h4>\n<p> Invertire la seguente matrice di dimensione 3\u00d73 utilizzando il metodo delle matrici aggiunte: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d1b6a5f638281754d80983b5a50e15be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}2&amp;3&amp;-2\\\\[1.1ex] 1&amp;4&amp;1\\\\[1.1ex] 2&amp;1&amp;-3\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La formula della matrice inversa \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Risolviamo innanzitutto il determinante della matrice con la regola di Sarrus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fcac1cb3935b1000b6493a2866e8728a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 2&amp;3&amp;-2\\\\[1.1ex] 1&amp;4&amp;1\\\\[1.1ex] 2&amp;1&amp;-3 \\end{vmatrix} = -24+6-2+16-2+9 = 3\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"381\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il determinante \u00e8 diverso da 0, quindi la matrice pu\u00f2 essere invertita.<\/p>\n<p class=\"has-text-align-left\"> Risolto il determinante troviamo la matrice aggiunta di A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c510482ac77a8c5d511c095de600f1ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} = \\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 4&amp;1\\\\[1.1ex] 1&amp;-3 \\end{vmatrix} = 1 \\cdot (-13) = \\bm{-13}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"403\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fa99e03d34c925098c1ad3ed6f06c745_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} = \\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix}1&amp;1\\\\[1.1ex] 2&amp;-3\\end{vmatrix} = -1 \\cdot (-5) = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"384\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3bf9f8565b3e4a99ff254c7558699c13_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2}  = \\displaystyle (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} 1&amp;4\\\\[1.1ex] 2&amp;1 \\end{vmatrix} = 1\\cdot (-7) = \\bm{-7}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"377\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-99e2c3f55fbba7b5faa014758b60f4a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3&amp;-2 \\\\[1.1ex] 1&amp;-3 \\end{vmatrix} = -1 \\cdot (-7) = \\bm{7}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"385\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23326bccecf752508e7418cbbc8eacd3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} = \\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 2&amp;-2\\\\[1.1ex] 2&amp;-3 \\end{vmatrix} = 1 \\cdot (-2) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"384\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a9d056af07ce26751783152a67cdedb6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 2&amp;3\\\\[1.1ex] 2&amp;1\\end{vmatrix} = -1 \\cdot (-4) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"371\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bed501806c35c94e491ad2063b2d0653_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2}  = \\displaystyle (-1)^{3+1} \\bm{\\cdot} \\begin{vmatrix} 3&amp;-2\\\\[1.1ex] 4&amp;1\\end{vmatrix} = 1 \\cdot 11 = \\bm{11}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"360\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3f108a61eec662b9420708f6920060be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{3+2} \\bm{\\cdot} \\begin{vmatrix} 2&amp;-2\\\\[1.1ex] 1&amp;1\\end{vmatrix} = -1 \\cdot 4 = \\bm{-4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"371\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-77a152a00dbb5f1e0f8702dd9511095a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -3} = \\displaystyle (-1)^{3+3} \\bm{\\cdot} \\begin{vmatrix} 2&amp;3\\\\[1.1ex] 1&amp;4 \\end{vmatrix} = 1 \\cdot 5 = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"335\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4642a75697fd30286065cdb4063a7bd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} -13 &amp; 5 &amp; -7  \\\\[1.1ex] 7 &amp; -2 &amp; 4 \\\\[1.1ex] 11 &amp; -4 &amp; 5 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta calcolato il determinante della matrice e il suo aggiunto, sostituiamo i loro valori nella formula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fae003a07d40b69690566cde77857c3a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} -13 &amp; 5 &amp; -7 \\\\[1.1ex] 7 &amp; -2 &amp; 4 \\\\[1.1ex] 11 &amp; -4 &amp; 5 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"89\" width=\"224\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Trasponiamo la matrice allegata:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-55717407766afe98f50ca75f20536edc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} -13 &amp; 7 &amp; 11 \\\\[1.1ex] 5 &amp; -2 &amp; -4 \\\\[1.1ex] -7 &amp; 4 &amp; 5 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E la matrice invertita A \u00e8: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9835713a5b791ee959d6571d706180f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\sfrac{\\bm{-13}}{\\bm{3}} &amp; \\sfrac{\\bm{7}}{\\bm{3}} &amp; \\sfrac{\\bm{11}}{\\bm{3}} \\\\[1.1ex] \\sfrac{\\bm{5}}{\\bm{3}} &amp; \\sfrac{\\bm{-2}}{\\bm{3}} &amp; \\sfrac{\\bm{-4}}{\\bm{3}} \\\\[1.1ex] \\sfrac{\\bm{-7}}{\\bm{3}} &amp; \\sfrac{\\bm{4}}{\\bm{3}} &amp; \\sfrac{\\bm{5}}{\\bm{3}}\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"216\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 4<\/h4>\n<p> Invertire la seguente matrice di ordine 3 utilizzando il metodo della matrice aggiunta: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bf71320b51e9514d1c372389aeb3410a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}4&amp;5&amp;-1\\\\[1.1ex] -1&amp;3&amp;2\\\\[1.1ex] 3&amp;8&amp;1\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"150\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La formula della matrice inversa \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dobbiamo prima calcolare il determinante della matrice, perch\u00e9 se il determinante \u00e8 0, significa che la matrice non ha inversa.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb7dc647f4121450eeadf2f5b62b4475_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 4&amp;5&amp;-1\\\\[1.1ex] -1&amp;3&amp;2\\\\[1.1ex] 3&amp;8&amp;1 \\end{vmatrix} = 12+30+8+9-64+5 = \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"389\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il determinante di A \u00e8 0, <strong>quindi la matrice non pu\u00f2 essere invertita.<\/strong><\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\"> Esercizio 5<\/h4>\n<p> Invertire la seguente matrice quadrata 3 \u00d7 3 con il metodo della matrice determinante: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-92e56e0f8013b6b65c0894a139537cae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}1 &amp; 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 &amp; 0 \\\\[1.1ex] -1 &amp; -2 &amp; 2\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"164\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La formula della matrice inversa \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Innanzitutto risolviamo il determinante della matrice con la regola di Sarrus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-07f116ed906c31644ed0513667988e6f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\lvert A \\rvert = \\begin{vmatrix} 1 &amp; 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 &amp; 0 \\\\[1.1ex] -1 &amp; -2 &amp; 2 \\end{vmatrix} = 2+0-12-3-0+16 = 3\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"392\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il determinante \u00e8 diverso da 0, quindi la matrice pu\u00f2 essere invertita.<\/p>\n<p class=\"has-text-align-left\"> Risolto il determinante troviamo la matrice aggiunta di A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-20da2eac0d49b1134b39b1f5c95c5659_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 1} =  (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix}  1 &amp; 0 \\\\[1.1ex]  -2 &amp; 2 \\end{vmatrix} = 1 \\bm{\\cdot} (2-0) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"377\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c5b80624f0963dfb1a111d96b4e1ceae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 4} =  (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix}  -2 &amp;  0 \\\\[1.1ex] -1 &amp; 2 \\end{vmatrix} = -1 \\bm{\\cdot} (-4-0) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50dd371e77d1896adb197321b68efd1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -3} = (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} -2 &amp; 1 \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(4-(-1)\\bigr) = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"427\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-60b779f4366a3ef38ae522fcfca8e7d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -2} =  (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix}  4 &amp; -3  \\\\[1.1ex]  -2 &amp; 2 \\end{vmatrix} = -1 \\bm{\\cdot} (8-6) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"424\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51cb00c42e6932810a4220eb85c61acd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 1} = (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp;  -3  \\\\[1.1ex] -1 &amp;  2 \\end{vmatrix} = 1 \\bm{\\cdot} (2-3) = \\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3b26cbfa55d5567d2dae10c5dfbd158_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 0} =  (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 4  \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} = -1 \\bm{\\cdot} \\bigl(-2-(-4)\\bigr) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"462\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d9f1bf4f5e01df910cd59bd4b25f816_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -1} = (-1)^{3+1} \\bm{\\cdot} \\begin{vmatrix}  4 &amp; -3 \\\\[1.1ex]  1 &amp; 0  \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(0-(-3)\\bigr) = \\bm{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"414\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ce129b17734facf076e48fb1928d0e1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -2}   = (-1)^{3+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; -3 \\\\[1.1ex] -2 &amp; 0 \\end{vmatrix} = -1 \\cdot (0-6) = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3c8b319461dad7880bf2b9f20187b6fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 2} =  (-1)^{3+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 4 \\\\[1.1ex] -2 &amp; 1 \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(1-(-8)\\bigr) = \\bm{9}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"408\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-748fcb9d9d2a8326379da4d2bd08534a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 2 &amp; 4 &amp; 5 \\\\[1.1ex] -2 &amp; -1 &amp; -2 \\\\[1.1ex] 3 &amp; 6 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"206\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta calcolato il determinante della matrice e il suo aggiunto, sostituiamo i loro valori nella formula: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a0fc0e6effb520e22ff82c3034b4d4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} 2 &amp; 4 &amp; 5 \\\\[1.1ex] -2 &amp; -1 &amp; -2 \\\\[1.1ex] 3 &amp; 6 &amp; 9\\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"89\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Trasponiamo la matrice allegata:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bba6ddbc8ab9f2c64eb03cdb9fea530a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} 2 &amp; -2 &amp; 3 \\\\[1.1ex] 4 &amp; -1 &amp; 6 \\\\[1.1ex] 5 &amp; -2 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine, operiamo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41f999c23e7d5ce129b410b9f486983e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\sfrac{2}{3} &amp; \\sfrac{-2}{3} &amp; \\sfrac{3}{3} \\\\[1.1ex] \\sfrac{4}{3} &amp; \\sfrac{-1}{3} &amp; \\sfrac{6}{3} \\\\[1.1ex] \\sfrac{5}{3} &amp; \\sfrac{-2}{3} &amp; \\sfrac{9}{3} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"181\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-inverse-par-matrice-adjointe-33.webp\" alt=\"esercizio risolto passo passo della matrice inversa con il metodo della matrice aggiunta 3x3\" width=\"232\" height=\"104\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"> Invertire una matrice utilizzando il metodo di Gauss:<\/h2>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<p> Per <strong>calcolare l&#8217;inversa di una matrice con il metodo di Gauss<\/strong> , <strong>\u00e8 necessario eseguire delle operazioni sulle righe di una matrice<\/strong> (lo vedremo pi\u00f9 avanti). Quindi prima di vedere come utilizzare il metodo di Gauss, \u00e8 importante che tu conosca tutte le operazioni che si possono fare sulle righe delle matrici:<\/p>\n<h3 class=\"wp-block-heading\"> Trasformazioni di linea consentite nel metodo gaussiano<\/h3>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Cambia l&#8217;ordine<\/span><\/strong> delle righe della matrice.<\/li>\n<\/ul>\n<p> Ad esempio, possiamo cambiare l&#8217;ordine delle righe 2 e 3 di una matrice:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1d3f607625afb96bfb250168bd330818_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} 3 &amp; 5 &amp; -2 \\\\[2ex] -2 &amp; 4 &amp; -1  \\\\[2ex] 6 &amp; 1 &amp; -3 \\end{array} \\right)  \\begin{array}{c} \\\\[2ex] \\xrightarrow{ f_2 \\rightarrow f_3}} \\\\[2ex] \\xrightarrow{ f_3 \\rightarrow f_2}} \\end{array} \\left( \\begin{array}{ccc} 3 &amp; 5 &amp; -2  \\\\[2ex] 6 &amp; 1 &amp; -3  \\\\[2ex] -2 &amp; 4 &amp; -1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"331\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Moltiplica o dividi<\/span><\/strong> tutti i termini di una riga per un numero diverso da 0.<\/li>\n<\/ul>\n<p> Ad esempio, possiamo moltiplicare la riga 1 per 4 e dividere la riga 3 per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cca4df71c23b1f005068a0a93b77dfe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} 1 &amp; -2 &amp; 3 \\\\[2ex] 3 &amp; -1 &amp; 5  \\\\[2ex] 2 &amp; -4 &amp; -2  \\end{array} \\right) \\begin{array}{c}  \\xrightarrow{4  f_1} \\\\[2ex]  \\\\[2ex] \\xrightarrow{ f_3 \/ 2} \\end{array} \\left( \\begin{array}{ccc} 4 &amp; -8 &amp; 12 \\\\[2ex] 3 &amp; -1 &amp; 5  \\\\[2ex] 1 &amp; -2 &amp; -1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"103\" width=\"318\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Sostituisci una riga<\/span><\/strong> con la somma della stessa riga pi\u00f9 un&#8217;altra riga moltiplicata per un numero.<\/li>\n<\/ul>\n<p> Ad esempio, nella matrice seguente, aggiungiamo la riga 3 moltiplicata per 1 alla riga 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ca6644f015dd42ddbf4ab159bd10dec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} -1 &amp; -3 &amp; 4  \\\\[2ex] 2 &amp; 4 &amp; 1  \\\\[2ex] 1 &amp; -2 &amp; 3  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex]  \\xrightarrow{f_2 + 1\\cdot f_3}  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc} -1 &amp; -3 &amp; 4  \\\\[2ex] 3 &amp; 2 &amp; 4  \\\\[2ex] 1 &amp; -2 &amp; 3  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"339\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"> Esempio di calcolo della matrice inversa utilizzando il metodo di Gauss:<\/h3>\n<p> Vediamo con un esempio come applicare il <strong>metodo di Gauss<\/strong> per invertire una matrice:<\/p>\n<ul>\n<li> Calcolare l&#8217;inversa della seguente matrice:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-71553480cefa679dcb8eb98d97e0c717_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\left( \\begin{array}{ccc} 1 &amp; 0 &amp; 1 \\\\[2ex] 0 &amp; 2 &amp; 1 \\\\[2ex] 1 &amp; 5 &amp; 4 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> La prima cosa che dobbiamo fare \u00e8 combinare <strong>la matrice A e la matrice Identit\u00e0 in un&#8217;unica matrice<\/strong> . La matrice A a sinistra e la matrice Identit\u00e0 a destra: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d0650812fe7946f6da1e7973709dfde1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle   \\bigl( A \\  \\lvert \\ I \\bigr)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"51\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-inverse-par-la-methode-de-gauss-32153.webp\" alt=\"esercizio risolto passo passo della matrice inversa con il metodo 3x3 Gauss\" width=\"203\" height=\"120\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-background\" style=\"background-color:#dff6ff\"> Per calcolare la matrice inversa, dobbiamo <strong>convertire la matrice di sinistra in una matrice identit\u00e0.<\/strong> E, per farlo, dobbiamo applicare le trasformazioni alle righe finch\u00e9 non arriviamo l\u00ec.<\/p>\n<p> Procederemo per colonne, cio\u00e8 eseguiremo delle operazioni sulle righe per trasformare prima i numeri della prima colonna, poi quelli della seconda ed infine quelli della terza colonna. <\/p>\n<div class=\"wp-block-columns is-layout-flex wp-container-35\">\n<div class=\"wp-block-column is-layout-flow\" style=\"flex-basis:66.66%\">\n<p class=\"has-text-align-justify\"> Gli 1 e gli 0 nella prima colonna sono gi\u00e0 adatti, poich\u00e9 anche la matrice identit\u00e0 ha un 1 e uno 0 in queste posizioni. Pertanto, al momento non \u00e8 necessario applicare una trasformazione a queste righe. <\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\" style=\"flex-basis:33.33%\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7f51b3a869dde9c1697be9e57fce1548_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} \\color{blue}\\boxed{\\color{black}1} &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] \\color{blue}\\boxed{\\color{black}0} &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"101\" width=\"255\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<\/div>\n<\/div>\n<p> Tuttavia, la matrice identit\u00e0 ha uno 0 nell&#8217;ultimo elemento della prima colonna, dove ora abbiamo un 1. Quindi dobbiamo convertire 1 in 0. Per fare ci\u00f2, <strong>aggiungiamo la riga 1 moltiplicata per \u2013 alla riga 3.1 :<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-30b5442d5c5eac3e62aa7a7cae717e48_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rrr}  &amp; 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1  \\\\ + &amp; -1 &amp; 0 &amp; -1 &amp; -1 &amp; 0 &amp; 0  \\\\ \\hline  &amp; 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -f_1} \\\\ \\phantom{hline} \\\\ \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"68\" width=\"313\" style=\"vertical-align: -29px;\"><\/p>\n<\/p>\n<p> Quindi se facciamo questa somma otteniamo la seguente matrice:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-992a31603c2182a97d31ddf787df4f06_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c}   \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 - f_1} \\end{array} \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] \\color{blue}\\boxed{\\color{black}0} &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"520\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Siamo cos\u00ec riusciti a trasformare l&#8217;1 in 0.<\/p>\n<p> Passiamo ora alla seconda colonna della matrice di sinistra. Il primo elemento \u00e8 uno 0, il che \u00e8 positivo perch\u00e9 la matrice identit\u00e0 ha uno 0 nella stessa posizione. Tuttavia, invece del 2 dovrebbe esserci un 1, <strong>quindi dividiamo la seconda riga per 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a86b61ee601f9cd0ff9a70d1a280f887_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\xrightarrow{f_2\/2}\\\\[2ex] &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; \\color{blue}\\boxed{\\color{black}1} &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex] 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"527\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Inoltre, nella seconda colonna dobbiamo anche trasformare il 5 in 0. Bene, poich\u00e9 il 5 \u00e8 cinque volte pi\u00f9 grande dell&#8217;1 nella seconda riga, <strong>aggiungeremo la riga 2 moltiplicata per -5 alla riga 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66dd50ad7ec5e4c45f5011094a0c21b3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rrr}  &amp; 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\\\ + &amp; 0 &amp; -5 &amp; \\sfrac{-5}{2} &amp; 0 &amp; \\vphantom{\\Bigl(}\\sfrac{-5}{2} &amp; 0  \\\\ \\hline &amp; 0 &amp; 0 &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2} \\vphantom{\\Bigl(} &amp; 1  \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -5f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(}  \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"355\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p> Pertanto, eseguendo questa operazione, ci ritroveremo con la matrice con uno 0 nell&#8217;ultimo elemento della seconda colonna:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fcc790f05d73d308cb7d992841ab031a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex] 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\\\[2ex] \\xrightarrow{f_3 - 5f_2} \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; \\color{blue}\\boxed{\\color{black}0} &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2}  &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"590\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Infine trasformeremo l&#8217;ultima colonna della matrice a sinistra, ma questa volta dobbiamo iniziare dal basso. \u00c8 quindi necessario trasformare l&#8217;<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> in 1. Pertanto, <strong>moltiplichiamo l&#8217;ultima riga per 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-69614cae4dd388b6454ffd9b8d63c9a5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2}  &amp; 1  \\end{array} \\right)\\begin{array}{c}   \\\\[2ex] \\\\[2ex] \\xrightarrow{2f_3} \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  \\color{blue}\\boxed{\\color{black}1}  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"562\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Dobbiamo ora trasformare il<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> il resto dell&#8217;ultima colonna come 0. Tuttavia, questa volta non possiamo moltiplicare la riga per 2, perch\u00e9 convertiremo anche 1 in 2 (quando la matrice identit\u00e0 ha 1 in quella posizione). Pertanto, <strong>aggiungeremo la riga 3 divisa per -2 alla riga 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-881f9ea3ce2e52ddf332a13aba43bbcf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr}  &amp; 0 &amp; 1 &amp;  \\vphantom{\\Bigl(} \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\ + &amp; 0 &amp; 0 &amp;\\vphantom{\\Bigl(} -\\sfrac{1}{2}  &amp; 1 &amp; \\sfrac{5}{2}  &amp; -1  \\\\ \\hline &amp; 0 &amp; 1 &amp; 0\\phantom{0}  &amp; 1 &amp; 3 \\vphantom{\\Bigl(} &amp; -1  \\end{array} \\begin{array}{l}\\vphantom{\\Bigl(} \\color{blue}\\bm{\\leftarrow f_2} \\\\ \\color{blue}\\bm{\\leftarrow f_3\/(-2)}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(}  \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"357\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p> Quindi facendo questa operazione riusciamo a trasformare il<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> in uno 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-537958a51f67c7602ef121fa2c997ca8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\xrightarrow{f_2-f_3\/2} \\\\[2ex] &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\color{blue}\\boxed{\\color{black}0} &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"598\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Infine, dobbiamo solo trasformare l&#8217;1 nella prima riga della terza colonna in 0. Anche la terza riga ha un 1 in questa stessa colonna, <strong>quindi aggiungeremo la riga 3 moltiplicata per -1 alla riga 1:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8854a556147caefb16a2030e0e5e949a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr}  &amp; 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\ + &amp; 0 &amp; 0 &amp;  -1  &amp; 2 &amp; 5  &amp; -2  \\\\ \\hline &amp; 1 &amp; 0 &amp; 0  &amp; 3 &amp; 5 &amp; -2  \\end{array} \\begin{array}{l}\\color{blue}\\bm{\\leftarrow f_1} \\\\ \\color{blue}\\bm{\\leftarrow -f_3}\\\\ \\phantom{hline}   \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"68\" width=\"300\" style=\"vertical-align: -29px;\"><\/p>\n<\/p>\n<p> E facendo questa operazione riusciamo a convertire l&#8217;1 in uno 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ddd39df6bc92258ba163c65de4fd59f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\ \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp;0 &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1-f_3}  \\\\[2ex]  \\\\[2ex]  &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; \\color{blue}\\boxed{\\color{black}0}  &amp; 3 &amp; 5 &amp; -2  \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"99\" width=\"589\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Una volta che abbiamo convertito con successo la matrice sinistra in una matrice identit\u00e0, conosciamo anche la matrice inversa. Perch\u00e9 <strong>la matrice inversa \u00e8 la matrice che otteniamo sul lato destro convertendo la matrice sinistra in matrice identit\u00e0<\/strong> . L\u2019inversa della matrice \u00e8 quindi: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exemple-de-matrice-inverse-32153.webp\" alt=\"Esempio di matrice inversa 3x3\" width=\"251\" height=\"117\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h3 class=\"wp-block-heading\"> Esercizi risolti su matrici inverse con il metodo di Gauss <\/h3>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-118\"><\/div>\n<\/div>\n<h4 class=\"wp-block-heading\"> Esercizio 1<\/h4>\n<p> Invertire la seguente matrice tramite il metodo di Gauss: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36886e1ab1007f9a53bdc0dd71a0d15b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 2 \\\\[1.1ex] 1 &amp; 3  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La prima cosa che dobbiamo fare \u00e8 combinare la matrice A e la matrice Identit\u00e0 in un&#8217;unica matrice. La matrice A a sinistra e la matrice identit\u00e0 a destra: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-de-gauss-inverse-22152.webp\" alt=\"esercizio risolto di una matrice inversa con il metodo 2x2 Gauss\" width=\"143\" height=\"66\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Ora, per calcolare la matrice inversa, dobbiamo convertire la matrice del lato sinistro in matrice identit\u00e0. E, per farlo, dobbiamo applicare le trasformazioni alle righe finch\u00e9 non arriviamo l\u00ec.<\/p>\n<p class=\"has-text-align-left\"> Il primo termine di tutti, 1, \u00e8 gi\u00e0 lo stesso della matrice identit\u00e0. Pertanto, in questo momento non \u00e8 necessario applicare una trasformazione alla prima riga.<\/p>\n<p class=\"has-text-align-left\"> Tuttavia, la matrice identit\u00e0 ha uno 0 nell&#8217;ultimo elemento della prima colonna, dove ora abbiamo un 1. Dobbiamo quindi convertire 1 in 0. Per fare ci\u00f2, sottraiamo la riga 1 dalla riga 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-247d8605795c43e79b5d7742854cfe6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{cc|cc}1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 1 &amp; 3 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\\\[1.5ex] \\xrightarrow{f_2 - f_1}  \\end{array} \\left( \\begin{array}{cc|cc} 1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1\\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"56\" width=\"332\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Passiamo alla seconda colonna: va bene la 1 sotto. Ma non i 2 sopra, poich\u00e9 la matrice identit\u00e0 ha uno 0 in quella posizione. Pertanto, per convertire il 2 in 0, dalla riga 1 sottraiamo la riga 2 moltiplicata per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-173a7bdb55ba058e5ae16d1fd8e91564_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{cc|cc} 1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1 \\end{array} \\right) \\begin{array}{c}  \\xrightarrow{f_1 - 2f_2} \\\\[1.5ex] &amp; \\end{array} \\left( \\begin{array}{cc|cc} 1 &amp; 0 &amp; 3 &amp; -2 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"367\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice inversa \u00e8 la matrice che otteniamo sul lato destro dopo aver convertito la matrice di sinistra in una matrice identit\u00e0. E ora abbiamo la matrice identit\u00e0 sul lato sinistro. La matrice inversa \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-98896d28465c9e1402e1c443375d93fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left(} \\begin{array}{cc}  \\bm{3} &amp; \\bm{-2} \\\\[1.5ex]  \\bm{-1} &amp; \\bm{1} \\end{array}\\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"157\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 2<\/h4>\n<p> Invertire la seguente matrice con la procedura gaussiana: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7ae5ba4a92a5ddc00ddf5b11775edafd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 1 &amp; -4 \\\\[1.1ex]  0 &amp; 3 &amp; 2 \\\\[1.1ex] 0 &amp; 1 &amp; 1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Innanzitutto, inseriamo la matrice A e la matrice Identit\u00e0 in un&#8217;unica matrice: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-81db2ef94d2db597cebb4c0c77685526_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 3 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"186\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora dobbiamo trasformare le righe fino a convertire la matrice di sinistra in una matrice identit\u00e0.<\/p>\n<p class=\"has-text-align-left\"> La prima colonna della matrice di sinistra \u00e8 gi\u00e0 uguale alla prima colonna della matrice identit\u00e0. Non \u00e8 quindi necessario modificare nessuno dei suoi numeri.<\/p>\n<p class=\"has-text-align-left\"> Tuttavia, la matrice identit\u00e0 ha un 1 nel secondo elemento della seconda colonna, dove ora c&#8217;\u00e8 un 3. Dobbiamo quindi convertire il 3 in un 1. Per fare ci\u00f2, dalla riga 2 sottraiamo la riga 3 moltiplicata per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bfd7cb4d4b81a75038807eb28393a83e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 3 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2 - 2f_3} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; 4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"458\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nell&#8217;ultimo elemento della seconda colonna, dove ora c&#8217;\u00e8 un 1. Dobbiamo quindi convertire l&#8217;1 in 0. Per fare ci\u00f2 sottraiamo la riga 2 dalla riga 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-932479e2f574c19ad7906d3d20e52ad0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 - f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"492\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nel primo elemento della seconda colonna, dove ora c&#8217;\u00e8 un 1. Dobbiamo quindi convertire 1 in 0. Per fare ci\u00f2, sottraiamo la riga 2 dalla riga 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-566e1453aab03f9792cb281e4c88a68c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 - f_2} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; -4 &amp; 1 &amp; -1 &amp; 2 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"506\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tutto quello che dobbiamo fare ora \u00e8 convertire -4 in 0. Per fare ci\u00f2, aggiungiamo la riga 3 moltiplicata per 4 alla riga 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f98a9cabeb101602dd11aa73516b998_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; -4 &amp; 1 &amp; -1 &amp; 2 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3\\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 + 4f_3} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 0 &amp; 1 &amp; -5 &amp; 14 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Abbiamo gi\u00e0 ottenuto la matrice identit\u00e0 dal lato sinistro. La matrice inversa \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e43ce6a7061f0339bd5d44b83afec07f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{1} &amp; \\bm{-5}  &amp; \\bm{14} \\\\[2ex]  \\bm{0} &amp; \\bm{1} &amp; \\bm{-2} \\\\[2ex] \\bm{0} &amp; \\bm{-1 }&amp; \\bm{3} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"185\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 3<\/h4>\n<p> Invertire la seguente matrice utilizzando il metodo gaussiano: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f02b0186690e68baaa9a630db2c870db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 2 &amp; 1 \\\\[1.1ex]  0 &amp; 1 &amp; 0 \\\\[1.1ex] 2 &amp; 0 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Prima di iniziare a operare, dobbiamo mettere la matrice A e la matrice Identit\u00e0 in un&#8217;unica matrice: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa6dc5af82076e22b1d0cf7ea16d748b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 2 &amp; 0 &amp; 3 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"172\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dobbiamo ora convertire la matrice di sinistra in una matrice identit\u00e0 operando sulle righe.<\/p>\n<p class=\"has-text-align-left\"> I primi due elementi della prima colonna sono gi\u00e0 uguali a quelli della matrice identit\u00e0. Non \u00e8 quindi necessario modificare tali cifre.<\/p>\n<p class=\"has-text-align-left\"> Ma la matrice identit\u00e0 ha uno 0 nel terzo elemento della prima colonna, dove ora c&#8217;\u00e8 un 2. Dobbiamo quindi convertire il 2 in uno 0. Per fare questo, dalla riga 3 sottraiamo la riga 1 moltiplicata per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-680a314b8cc900e01886291af12145e4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 2 &amp; 0 &amp; 3 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\\\[2ex] \\xrightarrow{f_3 - 2f_1}   \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"458\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nel primo elemento della seconda colonna, dove ora c&#8217;\u00e8 un 2. Dobbiamo quindi convertire il 2 in uno 0. Per fare questo, dalla riga 1 sottraiamo la riga 2 moltiplicata per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f87cbc594287f7ea4938091878562b4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 -2f_2} \\\\[2ex]  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nell&#8217;ultimo elemento della seconda colonna, dove ora c&#8217;\u00e8 un -4. Dobbiamo quindi convertire il -4 in 0. Per fare ci\u00f2 aggiungiamo la riga 2 moltiplicata per 4 alla riga 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b8cf2c3878d2d35656953a55bb3baf94_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 +4f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tutto quello che dobbiamo fare ora \u00e8 convertire il primo elemento della terza colonna in 0. Per fare ci\u00f2, aggiungiamo la riga 3 moltiplicata per -1 alla riga 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aac851b05c2dc25af3d7b9ecc622c9f6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 - f_3} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 0 &amp; 3 &amp; -6  &amp; -1\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"492\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Abbiamo gi\u00e0 capito che la matrice a sinistra \u00e8 la matrice identit\u00e0. Quindi l&#8217;inverso della matrice<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> Est:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-161fbe4a4d4dcc4fc503b6e3a9e0bfeb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{3} &amp; \\bm{-6}  &amp; \\bm{-1} \\\\[2ex]  \\bm{0} &amp; \\bm{1} &amp; \\bm{0} \\\\[2ex] \\bm{-2} &amp; \\bm{4}&amp; \\bm{1} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 4<\/h4>\n<p> Invertire la seguente matrice utilizzando il metodo gaussiano: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-47ad7ccd6aafab72255c96f2bc9148a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; -2 &amp; 0 \\\\[1.1ex]  1 &amp; 2 &amp; 2 \\\\[1.1ex] 0 &amp; 3 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> La prima cosa che dobbiamo fare \u00e8 unire la matrice A e la matrice Identit\u00e0 in un&#8217;unica matrice: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a832ceb9f09dfa88238c570b46b74d92_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 1 &amp; 2 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"186\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dobbiamo ora convertire la matrice a sinistra in una matrice identit\u00e0 applicando operazioni sulle righe.<\/p>\n<p class=\"has-text-align-left\"> Il primo elemento della prima colonna \u00e8 gi\u00e0 uguale a quello della matrice identit\u00e0. Non \u00e8 quindi necessario modificarlo.<\/p>\n<p class=\"has-text-align-left\"> Tuttavia, la matrice identit\u00e0 ha uno 0 nel secondo elemento della prima colonna, dove ora c&#8217;\u00e8 un 1. Dobbiamo quindi convertire l&#8217;1 in 0. Per fare ci\u00f2, sottraiamo la riga 1 dalla riga 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-83933b5a2315a4dcbc770bf92bf3831b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 1 &amp; 2 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2 - f_1} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 4 &amp; 2 &amp; -1 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"465\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Passiamo alla seconda colonna: trasformiamo prima il 4 in un 1 dividendo la seconda riga per 4:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-298984c72a249e2b5c98740cc0c1a11e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 4 &amp; 2 &amp; -1 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2\/4} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"495\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nel primo elemento della seconda colonna, dove ora c&#8217;\u00e8 un -2. Dobbiamo quindi convertire -2 in 0. Per fare ci\u00f2, aggiungiamo la riga 2 moltiplicata per 2 alla riga 1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ce876446d5d01a152e39480d69affd8c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr} &amp; 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\ + &amp; 0 &amp; 2 &amp; 1 &amp; \\vphantom{\\Bigl(}\\sfrac{-2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\ \\hline &amp; 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} \\vphantom{\\Bigl(}&amp; 0 \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_1} \\\\ \\color{blue}\\bm{\\leftarrow 2f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"313\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3dfcdcb586eed87861b3ac0ea46bea2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 +2f_2} \\\\[2ex]  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"525\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nell&#8217;ultimo elemento della seconda colonna, dove ora c&#8217;\u00e8 un 3. Dobbiamo quindi convertire il 3 in uno 0. Per fare questo, dalla riga 3 sottraiamo la riga 2 moltiplicata per 3: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-210ca8df473a00d9f205470ed2aa19a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|crr} &amp; 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0\\phantom{0} &amp; 1 \\\\ + &amp; 0 &amp; -3 &amp; \\vphantom{\\Bigl(}\\sfrac{-6}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 0 \\\\ \\hline &amp; 0 &amp; 0 &amp; \\vphantom{\\Bigl(}\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1 \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -3f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"350\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-94ed5a1b9cf1db0bfb99ce79d0a6d36b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 -3f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp;\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"525\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Passiamo alla terza colonna: dobbiamo trasformare l&#8217;ultima<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd7d08f65ca5dd13d94128372d3b6c95_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{2}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: 0px;\"><\/p>\n<p> in 1. Per fare ci\u00f2, moltiplichiamo la terza riga per 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a8134938726d3b48fe3d7d789260b128_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp;\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1   \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{2f_3 } \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"515\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice identit\u00e0 ha uno 0 nel secondo elemento dell&#8217;ultima colonna. \u00c8 quindi necessario convertire il<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd7d08f65ca5dd13d94128372d3b6c95_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{2}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: 0px;\"><\/p>\n<p> in uno 0. Per fare ci\u00f2, dalla riga 2 sottraiamo la riga 3 divisa per 2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc74ebe003751fd9ae3a5a77b2f589c8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|ccr} &amp; 0 &amp; 1 &amp; \\vphantom{\\Bigl(} \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\ + &amp; 0 &amp; 0 &amp; \\vphantom{\\Bigl(} \\sfrac{-1}{2} &amp; \\sfrac{-6}{8} &amp; \\sfrac{6}{8} &amp; -1  \\\\ \\hline &amp; 0 &amp; 1 &amp; 0\\phantom{0} &amp; -1 &amp; 1 &amp; -1\\vphantom{\\Bigl(} \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_2}\\vphantom{\\Bigl(}  \\\\ \\color{blue}\\bm{\\leftarrow -f_3\/2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"358\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b91b71183a50e41e9be5c7305f8cf3e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2-f_3\/2 } \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"542\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tutto quello che dobbiamo fare ora \u00e8 convertire il primo elemento della terza colonna in 0. Per fare ci\u00f2 sottraiamo la riga 3 dalla riga 1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-38796ed093a0fef52426fb5559931586_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr} &amp; 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\vphantom{\\Bigl(} \\\\ + &amp; 0 &amp; 0 &amp; -1 &amp; \\sfrac{-6}{4} &amp; \\sfrac{6}{4} &amp; -2 \\vphantom{\\Bigl(}  \\\\ \\hline &amp; 1 &amp; 0 &amp; 0 &amp; -1 &amp; 2 &amp; -2 \\vphantom{\\Bigl(} \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_1}\\vphantom{\\Bigl(}  \\\\ \\color{blue}\\bm{\\leftarrow -f_3}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"332\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2023374b9885dd33fe4d3c12e5a4de59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1-f_3 }  \\\\[2ex] \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 0 &amp; -1 &amp; 2 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"524\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice inversa \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0854e7cb80ba561b6e0c724a9a9b5fff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}= \\left(  \\begin{array}{ccc}  -1  &amp; 2 &amp; -2 \\\\[2ex]  -1 &amp; 1 &amp; -1 \\\\[2ex] \\sfrac{6}{4} &amp;\\sfrac{-6}{4} &amp; 2 \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"207\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Infine, le frazioni della matrice inversa possono essere semplificate:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c7ef6b6cdca2f4a808ed9457bde3b3f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{-1} &amp; \\bm{2}  &amp; \\bm{-2} \\\\[2ex]  \\bm{-1} &amp; \\bm{1} &amp; \\bm{-1} \\\\[2ex] \\sfrac{\\bm{3}}{\\bm{2}} &amp;\\sfrac{\\bm{-3}}{\\bm{2}} &amp; \\bm{2} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"207\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-119\"><\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"> Propriet\u00e0 della matrice inversa<\/h2>\n<p> La matrice inversa ha le seguenti caratteristiche:<\/p>\n<ul>\n<li> L&#8217;inversa di una matrice \u00e8 <span style=\"color:#1976d2;\"><strong>unica<\/strong><\/span> .<\/li>\n<\/ul>\n<ul>\n<li> L&#8217; <span style=\"color:#1976d2;\"><strong>inverso della matrice inversa<\/strong><\/span> \u00e8 la matrice originale:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-caac2cfeece17b627e46c7ec04020319_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A^{-1}\\right)^{-1} = A\" title=\"Rendered by QuickLaTeX.com\" height=\"26\" width=\"101\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> L&#8217; <span style=\"color:#1976d2;\"><strong>inverso della moltiplicazione<\/strong><\/span> di due matrici \u00e8 uguale al prodotto degli inversi delle matrici ma cambiando il loro ordine.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8f0dd4094bdc2faa4449008d1d8ee8c9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A \\cdot B)^{-1} = B^{-1} \\cdot A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"171\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> <span style=\"color:#1976d2;\"><strong>Trasporre una matrice<\/strong><\/span> e poi fare l&#8217;inverso della matrice \u00e8 come fare prima l&#8217;inversione della matrice e poi trasporla.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2dc6d83dd3d9b9dacec6e7806c9c0e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A^t\\right)^{-1} = \\left(A^{-1}\\right)^{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"26\" width=\"128\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> Per risolvere il <span style=\"color:#1976d2;\"><strong>determinante dell&#8217;inversa di una matrice<\/strong><\/span> possiamo calcolare il determinante della matrice e poi fare la sua inversa, poich\u00e9 le due operazioni danno lo stesso risultato.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e32fcd8a6c25d8c863947e6cc31efdc6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle det\\left(A^{-1}\\right) =\\bigl( det(A) \\bigr) ^{-1} = \\cfrac{1}{det(A)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"261\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"> Formula per calcolare rapidamente l&#8217;inversa di una matrice 2&#215;2<\/h2>\n<p> Come abbiamo visto, qualsiasi matrice pu\u00f2 essere invertita mediante il metodo dei determinanti o mediante il metodo di Gauss. Ma, separatamente, esiste anche una <strong>formula per trovare molto rapidamente l\u2019inverso di una matrice 2\u00d72<\/strong> : <\/p>\n<div class=\"wp-block-image estil_requadre_foto\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-matrice-inverse-22152.webp\" alt=\"formula per trovare l'inversa di una matrice 2x2, formula della matrice inversa 2x2\" class=\"wp-image-673\" width=\"475\" height=\"75\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Come puoi vedere, invertire una matrice 2&#215;2 \u00e8 semplice: basta risolvere il determinante della matrice<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3c046b53b17b87e9ca0f447d664754ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(|A|)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"35\" style=\"vertical-align: -5px;\"><\/p>\n<p> , alterna la posizione degli elementi della diagonale principale e cambia il segno degli elementi della diagonale secondaria.<\/p>\n<h3 class=\"wp-block-heading\"> Esempio di come ottenere una matrice inversa 2\u00d72 con la formula<\/h3>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<p> Calcola l&#8217;inversa della seguente matrice quadrata 2 \u00d7 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-599baee27c05b5610a8714363e1260eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Il determinante della matrice A \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ab99f7b87d01c670a8598df6364ab58f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{vmatrix} &amp; = 3 \\cdot (-4)- (-2) \\cdot 5 \\\\ &amp; = -12-(-10) \\\\[2ex] &amp; =-12+10\\\\[2ex] &amp;=-2\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"281\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Ora applichiamo <strong>la formula della matrice inversa<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-68fd6e830b576af8abf55be1e11fbafb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{-2} \\begin{pmatrix} -4 &amp; -5 \\\\[1.1ex] 2 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"333\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> E moltiplichiamo la matrice per la frazione:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41da8ef6bef1d339337717ed4ad86ae5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} =\\begin{pmatrix} \\cfrac{-4}{-2} &amp; \\cfrac{-5}{-2} \\\\[3ex] \\cfrac{2}{-2} &amp; \\cfrac{3}{-2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> La matrice invertita A \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-29da2a64f6da927857de112ca8363ba5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{2} &amp; \\cfrac{\\bm{5}}{\\bm{2}} \\\\[3ex] \\bm{-1} &amp; \\bm{-}\\cfrac{\\bm{3}}{\\bm{2}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"143\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Come puoi vedere, invertire una matrice con questa formula \u00e8 molto pi\u00f9 veloce, ma pu\u00f2 essere utilizzata solo su matrici di dimensione 2&#215;2.<\/p>\n<h3 class=\"wp-block-heading\"> Esercizi risolti di matrici inverse 2\u00d72 con la formula<\/h3>\n<h4 class=\"wp-block-heading\"> Esercizio 1<\/h4>\n<p> Invertiamo la seguente matrice di dimensione 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc06e21fc1c3c54f9b3fc0dcd4912a8f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Il determinante della matrice A \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1b0ae510ea7a336cbe5ea56a554da719_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{vmatrix} &amp; = 2 \\cdot 3- 1 \\cdot 5 \\\\ &amp; = 6-5 \\\\[2ex] &amp; =1\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"118\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora applichiamo la formula per trovare la matrice inversa: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b8f18178c829fd38360a04a947d52017_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{1} \\begin{pmatrix} 3 &amp; -5 \\\\[1.1ex] -1 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"292\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> L\u2019inversa della matrice A \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-237fe82cd91972f667f6751fa4735534_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{3} &amp; \\bm{-5} \\\\[1.1ex] \\bm{-1} &amp; \\bm{2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 2<\/h4>\n<p> Calcolare l&#8217;inversa della seguente matrice di ordine 2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2289d1c5c9aeb87016f719305d900a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Il determinante della matrice A \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3fef2cc00702131123994cc588bf7ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} &amp; = 2 \\cdot (-2)- (-1) \\cdot 6 \\\\ &amp; = -4-(-6) \\\\[2ex] &amp; =-4+6 \\\\[2ex] &amp; =2\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"282\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Applichiamo ora la formula per risolvere la matrice inversa di dimensione 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2de7166a0cf59e0f8c5b7750e1947f04_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{2} \\begin{pmatrix} -2 &amp; -6 \\\\[1.1ex] 1 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"319\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine facciamo la moltiplicazione: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6a5973078468914beb4bd4d85a40331_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{-2}{2} &amp; \\cfrac{-6}{2} \\\\[3ex] \\cfrac{1}{2} &amp; \\cfrac{2}{2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a540a077ee9a24da96fa988410aef429_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{-1} &amp; \\bm{-3} \\\\[2ex] \\cfrac{\\bm{1}}{\\bm{2}} &amp; \\bm{1} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"141\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 3<\/h4>\n<p> Invertiamo la seguente matrice 2&#215;2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36e230a808c42411a9cfd2d9eb44543d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Il determinante della matrice A \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e7a6c5ef316ae51b43c90863c6245780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2\\end{vmatrix} &amp; = 4 \\cdot 2 - 5 \\cdot 1 \\\\ &amp; = 8-5 \\\\[2ex] &amp;  =3\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"118\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Applichiamo ora la formula per calcolare la matrice inversa di dimensione 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2f359bd166c295b869a8cf04d927097_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{3} \\begin{pmatrix} 2 &amp; -1 \\\\[1.1ex] -5 &amp; 4 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"292\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine, facciamo il prodotto tra la frazione e la matrice:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6a02ea2e547dcc21081ae80df407a4e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{\\bm{2}}{\\bm{3}} &amp; \\bm{-}\\cfrac{\\bm{1}}{\\bm{3}} \\\\[3ex] \\bm{-}\\cfrac{\\bm{5}}{\\bm{3}} &amp; \\cfrac{\\bm{4}}{\\bm{3}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"147\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Esercizio 4<\/h4>\n<p> Trovare l&#8217;inversa della seguente matrice del secondo ordine: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-422fcd6f391a2682e4b546c9e9c05b55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"117\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Vedi la soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Il determinante della matrice A \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e9997751e16d3b976454be828cb914d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10\\end{vmatrix} &amp; = (-2) \\cdot 10- (-3) \\cdot 5 \\\\ &amp; = -20-(-15) \\\\[2ex] &amp; =-20+15 \\\\[2ex] &amp; =-5\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"285\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora applichiamo la formula per creare la matrice inversa di dimensione 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7c0c614039614bd9125b2920da8698eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10\\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{-5} \\begin{pmatrix} 10 &amp; -5 \\\\[1.1ex] 3 &amp; -2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"323\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine facciamo la moltiplicazione: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-edb1dfc870b3045eaefc1716a80e2ca2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{10}{-5} &amp; \\cfrac{-5}{-5} \\\\[3ex] \\cfrac{3}{-5} &amp; \\cfrac{-2}{-5} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"155\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c49e161c701254cfbe20353c11980eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{-2} &amp; \\bm{1} \\\\[2ex] \\bm{-}\\cfrac{\\bm{3}}{\\bm{5}} &amp; \\cfrac{\\bm{2}}{\\bm{5}} \\ \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"137\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\">Risolvere un sistema di equazioni con la matrice inversa<\/h2>\n<p> \u00c8 difficile apprezzare le reali applicazioni dell&#8217;inverso di una matrice. Infatti, probabilmente ti starai chiedendo&#8230; a cosa serve la matrice inversa? Serve davvero a qualcosa?<\/p>\n<p> Ebbene, uno degli usi della matrice inversa \u00e8 <strong>risolvere sistemi di equazioni lineari<\/strong> . E s\u00ec, anche se possono sembrare due concetti molto diversi, \u00e8 possibile trovare la soluzione di un sistema di equazioni invertendo una matrice.<\/p>\n<p> Vediamo con un esempio come si realizza:<\/p>\n<ul>\n<li> Calcola la soluzione del seguente sistema di equazioni con la matrice inversa:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-200c0f994f86752e7d650621a0d4100f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{r} x+3y=5 \\\\[2ex] 2x+4y=6 \\end{array} \\right\\}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"112\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Innanzitutto va osservato che un sistema di equazioni pu\u00f2 essere espresso sotto forma di matrici:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b9c9f181fc16a501799145c516a9747_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 4 \\end{pmatrix}\\begin{pmatrix} x \\\\[1.1ex]y \\end{pmatrix} = \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"156\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Possiamo verificare che questa forma matriciale del sistema equivale all&#8217;espressione con equazioni: se moltiplichiamo le matrici vedremo che otteniamo le due equazioni del sistema.<\/p>\n<p> Ora, per semplificare i passaggi successivi, chiameremo<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> alla matrice che ha i coefficienti delle incognite,<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> alle colonne della matrice con le incognite, e<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-770fd1447ccf2fc229801b486b0d8f8a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"B\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> alla matrice colonna con termini indipendenti:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ec1e9c04147230526534e694fb54f316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle AX=B\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"67\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Quindi la matrice<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 l&#8217;incognita dell&#8217;equazione della matrice.<\/p>\n<p> Per risolvere questa equazione di matrice, \u00e8 necessario seguire una procedura che non spiegheremo in modo cos\u00ec dettagliato qui. Se vuoi capirlo completamente, puoi dare un&#8217;occhiata a come risolvere <a href=\"https:\/\/mathority.org\/it\/come-risolvere-esempi-di-equazioni-di-matrici-ed-esercizi-risolti-di-matrici-2x2-e-3x3\/\">le equazioni con le matrici<\/a> , dove spieghiamo l&#8217;intero processo passo dopo passo.<\/p>\n<p> Questa procedura si basa su una propriet\u00e0 delle matrici inverse: qualsiasi matrice moltiplicata per la sua inversa \u00e8 uguale alla matrice Identit\u00e0 (o Unit\u00e0). Pertanto, la matrice sconosciuta pu\u00f2 essere facilmente risolta<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> moltiplicando entrambi i membri dell&#8217;equazione per l&#8217;inverso della matrice A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ec1e9c04147230526534e694fb54f316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle AX=B\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"67\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e20a8dfa638cb0fa47765a784dc47a61_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1}\\cdot AX=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"156\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-218f48c32d9bfd298c1e9559e8059a82_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle IX=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"107\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-acfded1a5d11f4b183ac34c85df906fc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"98\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> E una volta che abbiamo isolato la matrice<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> , calcoliamo l&#8217;inverso di<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> e risolviamo il prodotto di matrici: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9a1290e37a9e3f56fc6b288bc7686d66_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=\\left.\\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 4 \\end{pmatrix}\\right.^{-1}\\cdot \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"58\" width=\"170\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21471fc8a4c04aac3121519e8ef874e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=\\cfrac{1}{-2} \\begin{pmatrix} 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 \\end{pmatrix}\\cdot \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"202\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b9457fedf68c4bdfea898922e465eeb8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X= \\begin{pmatrix} -1 \\\\[1.1ex] 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"86\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> La soluzione del sistema di equazioni \u00e8 quindi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c2748b49f967580a0871d8739ee0d4f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{x=-1} \\qquad \\bm{y=2}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"133\" style=\"vertical-align: -4px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>In questa pagina imparerai cos&#8217;\u00e8 e come calcolare l&#8217;inversa di una matrice con il metodo dei determinanti (o matrice aggiunta) e con il metodo di Gauss. Vedrai anche tutte le propriet\u00e0 della matrice inversa e troverai anche esempi ed esercizi risolti passo dopo passo per ciascun metodo in modo da comprenderli completamente. Infine, spieghiamo una &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/it\/matrice-inversa\/\"> <span class=\"screen-reader-text\">Come calcolare la matrice inversa<\/span> Leggi altro &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[7],"tags":[],"class_list":["post-70","post","type-post","status-publish","format-standard","hentry","category-determinante-di-una-matrice"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Come calcolare la matrice inversa -<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/it\/matrice-inversa\/\" \/>\n<meta property=\"og:locale\" content=\"it_IT\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Come calcolare la matrice inversa -\" \/>\n<meta property=\"og:description\" content=\"In questa pagina imparerai cos&#8217;\u00e8 e come calcolare l&#8217;inversa di una matrice con il metodo dei determinanti (o matrice aggiunta) e con il metodo di Gauss. 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l&#8217;inversa di una matrice con il metodo dei determinanti (o matrice aggiunta) e con il metodo di Gauss. Vedrai anche tutte le propriet\u00e0 della matrice inversa e troverai anche esempi ed esercizi risolti passo dopo passo per ciascun metodo in modo da comprenderli completamente. Infine, spieghiamo una &hellip; Come calcolare la matrice inversa Leggi altro &raquo;","og_url":"https:\/\/mathority.org\/it\/matrice-inversa\/","article_published_time":"2023-09-17T05:59:45+00:00","og_image":[{"url":"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png"}],"author":"Squadra di Mathority","twitter_card":"summary_large_image","twitter_misc":{"Scritto da":"Squadra di Mathority","Tempo di lettura stimato":"15 minuti"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/mathority.org\/it\/matrice-inversa\/#article","isPartOf":{"@id":"https:\/\/mathority.org\/it\/matrice-inversa\/"},"author":{"name":"Squadra di Mathority","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8"},"headline":"Come calcolare la matrice inversa","datePublished":"2023-09-17T05:59:45+00:00","dateModified":"2023-09-17T05:59:45+00:00","mainEntityOfPage":{"@id":"https:\/\/mathority.org\/it\/matrice-inversa\/"},"wordCount":3045,"commentCount":0,"publisher":{"@id":"https:\/\/mathority.org\/it\/#organization"},"articleSection":["Determinante di una matrice"],"inLanguage":"it-IT","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/mathority.org\/it\/matrice-inversa\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/mathority.org\/it\/matrice-inversa\/","url":"https:\/\/mathority.org\/it\/matrice-inversa\/","name":"Come calcolare la matrice inversa -","isPartOf":{"@id":"https:\/\/mathority.org\/it\/#website"},"datePublished":"2023-09-17T05:59:45+00:00","dateModified":"2023-09-17T05:59:45+00:00","breadcrumb":{"@id":"https:\/\/mathority.org\/it\/matrice-inversa\/#breadcrumb"},"inLanguage":"it-IT","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mathority.org\/it\/matrice-inversa\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/mathority.org\/it\/matrice-inversa\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mathority.org\/it\/"},{"@type":"ListItem","position":2,"name":"Come calcolare la matrice inversa"}]},{"@type":"WebSite","@id":"https:\/\/mathority.org\/it\/#website","url":"https:\/\/mathority.org\/it\/","name":"Mathority","description":"Dove la curiosit\u00e0 incontra il calcolo!","publisher":{"@id":"https:\/\/mathority.org\/it\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mathority.org\/it\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"it-IT"},{"@type":"Organization","@id":"https:\/\/mathority.org\/it\/#organization","name":"Mathority","url":"https:\/\/mathority.org\/it\/","logo":{"@type":"ImageObject","inLanguage":"it-IT","@id":"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/","url":"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png","contentUrl":"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png","width":703,"height":151,"caption":"Mathority"},"image":{"@id":"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8","name":"Squadra di Mathority","image":{"@type":"ImageObject","inLanguage":"it-IT","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","caption":"Squadra di Mathority"},"sameAs":["http:\/\/mathority.org\/it"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts\/70","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/comments?post=70"}],"version-history":[{"count":0,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts\/70\/revisions"}],"wp:attachment":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/media?parent=70"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/categories?post=70"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/tags?post=70"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}