{"id":305,"date":"2023-07-06T14:52:33","date_gmt":"2023-07-06T14:52:33","guid":{"rendered":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/"},"modified":"2023-07-06T14:52:33","modified_gmt":"2023-07-06T14:52:33","slug":"teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti","status":"publish","type":"post","link":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/","title":{"rendered":"Teorema di rouche-fr\u00e9benius"},"content":{"rendered":"<p>In questa pagina scopriremo cos&#8217;\u00e8 il <strong>teorema di Rouch\u00e9 Frobenius<\/strong> e come con esso si calcola il rango di una matrice. Troverai anche esempi ed esercizi risolti passo passo con il teorema di Rouch\u00e9-Frobenius.<\/p>\n<h2 class=\"wp-block-heading\"> Cos&#8217;\u00e8 il teorema di Rouch\u00e9-Frobenius?<\/h2>\n<p> <strong>Il teorema di Rouch\u00e9-Frobenius \u00e8 un metodo per classificare sistemi di equazioni lineari.<\/strong> In altre parole, il teorema di Rouch\u00e9-Frobenius serve per scoprire quante soluzioni ha un sistema di equazioni senza doverlo risolvere.<\/p>\n<p> Esistono 3 tipi di sistemi di equazioni:<\/p>\n<ul>\n<li> <strong>Sistema compatibile determinato (SCD):<\/strong> il sistema ha una soluzione unica.<\/li>\n<li> <strong>Sistema compatibile indeterminato (ICS):<\/strong> il sistema ha infinite soluzioni.<\/li>\n<li> <strong>Sistema incompatibile (SI):<\/strong> il sistema non ha soluzione.<\/li>\n<\/ul>\n<p> Inoltre, il teorema di Rouch\u00e9-Frobenius consentir\u00e0 successivamente di <a href=\"https:\/\/mathority.org\/it\/esempi-di-regole-ed-esercizi-risolti-di-cramer\/\">risolvere i sistemi utilizzando la regola di Cramer<\/a> .<\/p>\n<h2 class=\"wp-block-heading\"> Enunciato del teorema di Rouch\u00e9-Frobenius<\/h2>\n<p> Lo dice il teorema di Rouch\u00e9-Frobenius<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bd767a13412c19de65e75a6826caee08_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A}\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 la matrice formata dai coefficienti delle incognite di un sistema di equazioni. e la pancia<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bf22ad0d457d763be692e97f3bcdf221_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A'}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"17\" style=\"vertical-align: 0px;\"><\/p>\n<p> , o <strong>matrice estesa<\/strong> , \u00e8 la matrice formata dai coefficienti delle incognite di un sistema di equazioni e dai termini indipendenti: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><\/figure>\n<\/div>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\" style=\"margin-bottom:20px\"> Il <strong>teorema di Rouch\u00e9-Frobenius<\/strong> ci permette di sapere con quale tipo di sistema di equazioni abbiamo a che fare a seconda del rango delle matrici A e A&#8217;:<\/p>\n<ul style=\"color:#E53935; font-weight: bold;\">\n<li style=\"margin-bottom:20px\"> <span style=\"color:#000000;font-weight: normal;\">Se rango(A) = rango(A&#8217;) = numero di incognite \u27f6 Sistema compatibile determinato (SCD)<\/span><\/li>\n<li style=\"margin-bottom:20px;\"> <span style=\"color:#000000;font-weight: normal;\">Se rango(A) = rango(A&#8217;) &lt; numero di incognite \u27f6 Sistema compatibile indeterminato (SCI)<\/span><\/li>\n<li> <span style=\"color:#000000;font-weight: normal;\">se intervallo(A)\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-be0e48d5500c7e73c450241ea2197789_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{\\neq}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"13\" style=\"vertical-align: -4px;\"><\/p>\n<p><\/span> intervallo (A&#8217;) \u27f6 Sistema incompatibile (SI)<\/li>\n<\/ul>\n<\/div>\n<p> Una volta che sappiamo cosa dice il teorema di Rouch\u00e9-Frobenius, vedremo come risolvere gli esercizi del teorema di Rouch\u00e9-Frobenius. Ecco 3 esempi: un esercizio risolto utilizzando il teorema di ogni tipo di sistema di equazioni.<\/p>\n<h2 class=\"wp-block-heading\"> Esempio di sistema compatibile determinato (SCD)<\/h2>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b6b2f93c6308c25e8df2fbb5da2af9a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{cases} 2x+y-3z=0 \\\\[1.5ex] x+2y-z= 1 \\\\[1.5ex] 4x-2y+z = 3\\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"135\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> La <strong>matrice A<\/strong> e la <strong>matrice estesa A&#8217;<\/strong> del sistema sono:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4597f5171b586bbcf0915d8512f7b89d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 2 &amp; 1 &amp; -3  \\\\[1.1ex] 1 &amp; 2 &amp; -1  \\\\[1.1ex] 4 &amp; -2 &amp; 1  \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 2 &amp; 1 &amp; -3 &amp; 0 \\\\[1.1ex] 1 &amp; 2 &amp; -1 &amp; 1  \\\\[1.1ex] 4 &amp; -2 &amp; 1 &amp; 3\\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Calcoliamo ora il rango della matrice A. Per fare ci\u00f2 controlliamo se il determinante dell&#8217;intera matrice \u00e8 diverso da 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c95b7158a2e6401cd16aeb708f128ff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 2 &amp; 1 &amp; -3  \\\\[1.1ex] 1 &amp; 2 &amp; -1  \\\\[1.1ex] 4 &amp; -2 &amp; 1  \\end{vmatrix} = 25 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"219\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Poich\u00e9 la matrice ha un determinante 3\u00d73 diverso da 0, <strong>la matrice A ha rango 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-842ae3b68df41813d9e409968f3ae946_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;, che sar\u00e0 almeno di rango 3 perch\u00e9 abbiamo appena visto che ha al suo interno un determinante di ordine 3 diverso da 0. Inoltre non pu\u00f2 essere di rango 4, poich\u00e9 non possiamo creare alcun determinante di ordine 4. Pertanto, <strong>anche la matrice A&#8217; \u00e8 di rango 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Pertanto, poich\u00e9 il rango della matrice A \u00e8 pari al rango della matrice A&#8217; e al numero di incognite del sistema (3), sappiamo dal teorema di Rouch\u00e9 Frobenius che si tratta di un <strong>Sistema Determinato Compatibile<\/strong> (SCD) :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-557185e16670c72d23eec5a3ea13b487_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 3 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = n = 3  \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCD}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"436\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"> Esempio di sistema compatibile indeterminato (ICS)<\/h2>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2360b9a47257f73cf3f5dea63fb24098_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{cases} x-y+2z=1 \\\\[1.5ex] 3x+2y+z= 5 \\\\[1.5ex] 2x+3y-z = 4\\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"135\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> La <strong>matrice A<\/strong> e la <strong>matrice estesa A&#8217;<\/strong> del sistema sono:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b281235e2702433b447e2586ae3092c9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 1 &amp; -1 &amp; 2  \\\\[1.1ex] 3 &amp; 2 &amp; 1  \\\\[1.1ex] 2 &amp; 3 &amp; -1  \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 1 &amp; -1 &amp; 2 &amp; 1 \\\\[1.1ex] 3 &amp; 2 &amp; 1 &amp; 5  \\\\[1.1ex] 2 &amp; 3 &amp; -1 &amp; 4 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Calcoliamo ora il rango della matrice A. Per fare ci\u00f2 controlliamo se il determinante dell&#8217;intera matrice \u00e8 diverso da 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-74cafc27ab41134696c3bf263132b98b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 1 &amp; -1 &amp; 2  \\\\[1.1ex] 3 &amp; 2 &amp; 1  \\\\[1.1ex] 2 &amp; 3 &amp; -1 \\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Il determinante dell&#8217;intera matrice A d\u00e0 0, quindi non \u00e8 di rango 3. Per vedere se \u00e8 di rango 2, dobbiamo trovare una sottomatrice in A il cui determinante \u00e8 diverso da 0. Ad esempio, quello dall&#8217;angolo in alto a sinistra :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-22b2487f7664a70c116593120de2743b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 1 &amp; -1  \\\\[1.1ex] 3 &amp; 2 \\end{vmatrix} = 5 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"123\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Poich\u00e9 la matrice ha un determinante 2\u00d72 diverso da 0, <strong>la matrice A ha rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Sappiamo gi\u00e0 che il determinante delle prime 3 colonne d\u00e0 0, quindi proviamo gli altri possibili determinanti 3\u00d73:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-17f264ad3859da88ffa6784be24e4143_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}1 &amp; -1 &amp;  1 \\\\[1.1ex] 3 &amp; 2 &amp; 5  \\\\[1.1ex] 2 &amp; 3 &amp; 4\\end{vmatrix} = 0 \\quad \\begin{vmatrix}1 &amp; 2 &amp; 1 \\\\[1.1ex] 3 &amp;  1 &amp; 5  \\\\[1.1ex] 2 &amp; -1 &amp; 4\\end{vmatrix} = 0 \\quad \\begin{vmatrix} -1 &amp; 2 &amp; 1 \\\\[1.1ex] 2 &amp; 1 &amp; 5  \\\\[1.1ex] 3 &amp; -1 &amp; 4\\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"404\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Tutti i determinanti 3\u00d73 della matrice A&#8217; sono 0, quindi neanche la matrice A&#8217; sar\u00e0 di rango 3. Tuttavia, al suo interno ha determinanti di ordine 2 diversi da 0. Ad esempio:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-22b2487f7664a70c116593120de2743b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 1 &amp; -1  \\\\[1.1ex] 3 &amp; 2 \\end{vmatrix} = 5 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"123\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Quindi <strong>la matrice A&#8217; sar\u00e0 di rango 2<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-80398cfd2fff647f81c0d4160f3b2f7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"81\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> L&#8217;estensione della matrice A \u00e8 uguale all&#8217;estensione della matrice A&#8217; ma queste sono inferiori al numero di incognite del sistema (3). Pertanto, secondo il teorema di Rouch\u00e9-Frobenius, si tratta di un <strong>sistema compatibile indeterminato<\/strong> (ICS):<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-96868a2569ea0ab5ca99d8dc606d3dc9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=2 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = 2 \\ < \\ n =3  \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"475\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"> Esempio di sistema incompatibile (IS)<\/h2>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-30e1084dd637eb4371f6b2218af24136_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{cases} 2x+y-2z=3 \\\\[1.5ex] 3x-2y+z= 2 \\\\[1.5ex] x+4-5z = 3 \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"135\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p>La <strong>matrice A<\/strong> e la <strong>matrice estesa A&#8217;<\/strong> del sistema sono:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b435d86f1466af5748d91e6c9bd813e3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 2 &amp; 1 &amp; -2 \\\\[1.1ex] 3 &amp; -2 &amp; 1 \\\\[1.1ex] 1 &amp; 4 &amp; -5 \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 2 &amp; 1 &amp; -2 &amp; 3 \\\\[1.1ex] 3 &amp; -2 &amp; 1 &amp; 2  \\\\[1.1ex] 1 &amp; 4 &amp; -5 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Calcoliamo ora il rango della matrice A. Per fare ci\u00f2 controlliamo se il determinante dell&#8217;intera matrice \u00e8 diverso da 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-714538c91aa2620a6adb40581245f0e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 2 &amp; 1 &amp; -2 \\\\[1.1ex] 3 &amp; -2 &amp; 1 \\\\[1.1ex] 1 &amp; 4 &amp; -5 \\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Il determinante dell&#8217;intera matrice A d\u00e0 0, quindi non \u00e8 di rango 3. Per vedere se \u00e8 di rango 2, dobbiamo trovare una sottomatrice in A il cui determinante \u00e8 diverso da 0. Ad esempio, quello dall&#8217;angolo in alto a sinistra :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5a46decda8fd850d9c847922b0c896db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 2 &amp; 1  \\\\[1.1ex] 3 &amp; -2 \\end{vmatrix} = -7 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Poich\u00e9 la matrice ha un determinante di ordine 2 diverso da 0, <strong>la matrice A \u00e8 di rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Sappiamo gi\u00e0 che il determinante delle prime 3 colonne d\u00e0 0, quindi ora proviamo, ad esempio, con il determinante delle ultime 3 colonne:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-47aecdf801b92f21f2287fb96eaaa3f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 1 &amp; -2 &amp; 3 \\\\[1.1ex]  -2 &amp; 1 &amp; 2  \\\\[1.1ex]  4 &amp; -5 &amp; 3 \\end{vmatrix} = 3 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"161\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> D&#8217;altra parte, la matrice A&#8217; contiene un determinante il cui risultato \u00e8 diverso da 0, quindi <strong>la matrice A&#8217; avr\u00e0 rango 3<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Pertanto, poich\u00e9 il rango della matrice A \u00e8 minore del rango della matrice A&#8217;, deduciamo dal teorema di Rouch\u00e9-Frobenius che si tratta di un <strong>Sistema Incompatibile<\/strong> (SI) <strong>:<\/strong> <\/p>\n<p class=\"has-text-align-center\">\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c3da0513f318d25473e93ba88c51fb42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = 2 \\ \\neq \\ rg(A') = 3 \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"426\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\">Problemi risolti del teorema di Rouch\u00e9-Frobenius <\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-118\"><\/div>\n<\/div>\n<h3 class=\"estil_titol_H3 wp-block-heading\"> Esercizio 1<\/h3>\n<p> Determina il tipo del seguente sistema di equazioni a 3 incognite utilizzando il teorema di Rouch\u00e9-Frobenius: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-du-theoreme-de-rouche-8211-frebenius-1.webp\" alt=\"Esercizio risolto del teorema di Rouche - frobenius\" class=\"wp-image-3984\" width=\"193\" height=\"122\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Per prima cosa realizziamo la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-951ce5c1f0c606d4f060a1de58b60303_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 2 &amp; 1 &amp; -3 \\\\[1.1ex] 3 &amp; -1 &amp; -1 \\\\[1.1ex] -2 &amp; 4 &amp; 2 \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 2 &amp; 1 &amp; -3 &amp; 0 \\\\[1.1ex] 3 &amp; -1 &amp; -1 &amp; 2 \\\\[1.1ex] -2 &amp; 4 &amp; 2 &amp; 8 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"432\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dobbiamo ora trovare il rango della matrice A. Per fare ci\u00f2 controlliamo se il determinante della matrice \u00e8 diverso da 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-15cddb69f7590648d1d6ae61d942471e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 2 &amp; 1 &amp; -3 \\\\[1.1ex] 3 &amp; -1 &amp; -1 \\\\[1.1ex] -2 &amp; 4 &amp; 2 \\end{vmatrix} = -4+2-36+6+8-6=-30 \\bm{\\neq 0}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"450\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice avente un determinante del terzo ordine diverso da 0, <strong>la matrice A ha rango 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-842ae3b68df41813d9e409968f3ae946_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Questo sar\u00e0 almeno di rango 3, perch\u00e9 abbiamo appena visto che ha al suo interno un determinante di ordine 3 diverso da 0. Inoltre, non pu\u00f2 essere di rango 4, poich\u00e9 non possiamo non creare un determinante 4\u00d74. Pertanto <strong>anche la matrice A&#8217; \u00e8 di rango 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi, grazie al teorema di Rouch\u00e9-Frobenius, sappiamo che si tratta di un <strong>determinato sistema compatibile<\/strong> (SCD), perch\u00e9 l&#8217;intervallo di A \u00e8 uguale all&#8217;intervallo di A&#8217; e al numero di incognite. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-31b495a48a75d7af1f23e38818bf4eca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 3 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3 \\end{array}} \\\\ \\\\ \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = n = 3 \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCD}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"436\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 2<\/h3>\n<p> Classificare il seguente sistema di equazioni a 3 incognite utilizzando il teorema di Rouch\u00e9-Frobenius: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-du-theoreme-de-rouche-8211-frebenius-2.webp\" alt=\"Esercizio risolto del teorema di Rouche-Frobenius\" class=\"wp-image-3987\" width=\"190\" height=\"121\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Costruiamo innanzitutto la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-45e13aabe233ece927df7c9ba0bb3ec1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc}3 &amp; -1 &amp; 2  \\\\[1.1ex] 1 &amp; 2 &amp; -2  \\\\[1.1ex] 1 &amp; -5 &amp; 6 \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 3 &amp; -1 &amp; 2 &amp; 1 \\\\[1.1ex] 1 &amp; 2 &amp; -2 &amp; 5 \\\\[1.1ex] 1 &amp; -5 &amp; 6 &amp; -9 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora calcoliamo l&#8217;intervallo della matrice A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-87bc95df0033834bba0398b8421faac5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 3 &amp; -1 &amp; 2 \\\\[1.1ex] 1 &amp; 2 &amp; -2 \\\\[1.1ex] 1 &amp; -5 &amp; 6 \\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b9805283b75e2b89f67c7865a1263112_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 3 &amp; -1  \\\\[1.1ex] 1 &amp; 2 \\end{vmatrix} = 7 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"123\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi <strong>la matrice A ha rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Sappiamo gi\u00e0 che il determinante delle prime 3 colonne d\u00e0 0, quindi proviamo gli altri possibili determinanti 3\u00d73:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e6457fe3f03722b7f0d955191f318915_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}-1 &amp; 2 &amp; 1 \\\\[1.1ex] 2 &amp; -2 &amp; 5 \\\\[1.1ex] -5 &amp; 6 &amp; -9\\end{vmatrix} = 0 \\quad \\begin{vmatrix}3 &amp; 2 &amp; 1 \\\\[1.1ex] 1 &amp; -2 &amp; 5 \\\\[1.1ex] 1 &amp; 6 &amp; -9\\end{vmatrix} = 0 \\quad \\begin{vmatrix} 3 &amp; -1 &amp; 1 \\\\[1.1ex] 1 &amp; 2 &amp; 5 \\\\[1.1ex] 1 &amp; -5 &amp; -9\\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"446\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tutti i determinanti 3\u00d73 della matrice A&#8217; sono 0, quindi neanche la matrice A&#8217; sar\u00e0 di rango 3. Tuttavia al suo interno ha molti determinanti di ordine 2 diversi da 0. Ad esempio:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eafa4747802fae3f0c36350357abbeb2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} -1 &amp; 2  \\\\[1.1ex] 2 &amp; -2 \\end{vmatrix} = -2 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"150\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi <strong>la matrice A&#8217; sar\u00e0 di rango 2<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-80398cfd2fff647f81c0d4160f3b2f7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"81\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il rango della matrice A \u00e8 uguale al rango della matrice A&#8217; ma questi due sono inferiori al numero di incognite del sistema (3). Pertanto dal teorema di Rouch\u00e9-Frobenius sappiamo che si tratta di un <strong>sistema compatibile indeterminato<\/strong> (ICS): <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-96868a2569ea0ab5ca99d8dc606d3dc9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=2 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = 2 \\ < \\ n =3  \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"475\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 3<\/h3>\n<p> Determina quale tipo di sistema \u00e8 il seguente sistema di equazioni utilizzando il teorema di Rouch\u00e9-Frobenius: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-du-theoreme-de-rouche-8211-frebenius-3.webp\" alt=\"esercizio risolto passo passo del teorema di rouche - frobenius\" class=\"wp-image-3990\" width=\"188\" height=\"122\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Per prima cosa realizziamo la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1820d31e4fd5c79804c9b6fa15abb469_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 1 &amp; 4 &amp; -2 \\\\[1.1ex] 3 &amp; -1 &amp; 3  \\\\[1.1ex] 5 &amp; 7 &amp; -1 \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 1 &amp; 4 &amp; -2 &amp; 3 \\\\[1.1ex] 3 &amp; -1 &amp; 3 &amp; -2 \\\\[1.1ex] 5 &amp; 7 &amp; -1 &amp; 0 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora calcoliamo l&#8217;intervallo della matrice A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4f998260ee4c96673085ea6fd4ca87ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 1 &amp; 4 &amp; -2 \\\\[1.1ex] 3 &amp; -1 &amp; 3 \\\\[1.1ex] 5 &amp; 7 &amp; -1\\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-159a1c58fdcd972b4b08e4795950e064_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 1 &amp; 4  \\\\[1.1ex] 3 &amp; -1 \\end{vmatrix} = -13 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi <strong>la matrice A ha rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Sappiamo gi\u00e0 che il determinante delle prime 3 colonne d\u00e0 0, ma non il determinante delle ultime 3 colonne:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c673a5bbbd41933208169fa3e08b7c62_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 4 &amp; -2 &amp; 3 \\\\[1.1ex]-1 &amp; 3 &amp; -2 \\\\[1.1ex] 7 &amp; -1 &amp; 0 \\end{vmatrix} = -40 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertanto <strong>la matrice A&#8217; ha rango 3<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il rango della matrice A \u00e8 minore del rango della matrice A&#8217;, possiamo quindi dedurre dal teorema di Rouch\u00e9-Frobenius che si tratta di un <strong>Sistema Incompatibile<\/strong> (SI) <strong>:<\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c3da0513f318d25473e93ba88c51fb42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = 2 \\ \\neq \\ rg(A') = 3 \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"426\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-119\"><\/div>\n<\/div>\n<h3 class=\"wp-block-heading\"> Esercizio 4<\/h3>\n<p> Determina il tipo del seguente sistema di equazioni a 3 incognite utilizzando il teorema di Rouch\u00e9-Frobenius: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-du-theoreme-de-rouche-8211-frobenius-3-inconnues-3-equations.webp\" alt=\"Rouche - Teorema di Frobenius esercizio risolto con 3 incognite e 3 equazioni\" class=\"wp-image-3991\" width=\"203\" height=\"122\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Per prima cosa realizziamo la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f8a0454c53a64f612c689ba1dae1196b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 5 &amp; -3 &amp; -2  \\\\[1.1ex] 1 &amp; 4 &amp; 1  \\\\[1.1ex]-3 &amp; 2 &amp; -2  \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 5 &amp; -3 &amp; -2 &amp; -2 \\\\[1.1ex] 1 &amp; 4 &amp; 1 &amp; 7 \\\\[1.1ex]-3 &amp; 2 &amp; -2 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"446\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dobbiamo ora calcolare il rango della matrice A. Per fare ci\u00f2 risolviamo il determinante della matrice con la regola di Sarrus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-420f0d1ee000f39cbfbce88bf122f413_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 5 &amp; -3 &amp; -2 \\\\[1.1ex] 1 &amp; 4 &amp; 1 \\\\[1.1ex]-3 &amp; 2 &amp; -2 \\end{vmatrix} = -40+9-4-24-10-6=-75 \\bm{\\neq 0}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"467\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> La matrice avente un determinante del terzo ordine diverso da 0, <strong>la matrice A ha rango 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-842ae3b68df41813d9e409968f3ae946_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertanto, <strong>anche la matrice A&#8217; \u00e8 di rango 3<\/strong> , poich\u00e9 \u00e8 sempre almeno di rango A e non pu\u00f2 essere di rango 4 perch\u00e9 non possiamo risolvere alcun determinante 4\u00d74.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi, grazie all&#8217;applicazione del teorema di Rouch\u00e9-Frobenius, sappiamo che il sistema \u00e8 un <strong>Sistema Determinato Compatibile<\/strong> (SCD), perch\u00e9 l&#8217;intervallo di A \u00e8 uguale all&#8217;intervallo di A&#8217; e al numero di incognite. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-31b495a48a75d7af1f23e38818bf4eca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 3 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3 \\end{array}} \\\\ \\\\ \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = n = 3 \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCD}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"436\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 5<\/h3>\n<p> Identifica quale tipo di sistema utilizza il seguente sistema di equazioni utilizzando il teorema di Rouch\u00e9-Frobenius: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exemple-du-theoreme-de-rouche-8211-frebenius.webp\" alt=\"esempio del teorema di Rouche - frobenius\" class=\"wp-image-3992\" width=\"205\" height=\"122\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Per prima cosa realizziamo la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3211e276b2b040969c38bc6c69eabd52_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 4 &amp; -1 &amp; 3 \\\\[1.1ex] -1 &amp; 7 &amp; 3 \\\\[1.1ex] -5 &amp; 8 &amp; 0 \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 4 &amp; -1 &amp; 3 &amp; 5 \\\\[1.1ex] -1 &amp; 7 &amp; 3 &amp; -3 \\\\[1.1ex] -5 &amp; 8 &amp; 0 &amp; 9 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora calcoliamo l&#8217;intervallo della matrice A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21004095a3a8ef3edfc15bed5c7853a4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 4 &amp; -1 &amp; 3 \\\\[1.1ex] -1 &amp; 7 &amp; 3 \\\\[1.1ex] -5 &amp; 8 &amp; 0\\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a58059046b56cf1f8d82c6c8939e44ca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 4 &amp; -1  \\\\[1.1ex]  -1 &amp; 7 \\end{vmatrix} = 27 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>La matrice A \u00e8 quindi di rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Il determinante delle prime 3 colonne che gi\u00e0 conosciamo d\u00e0 0, ma il determinante delle ultime 3 colonne non d\u00e0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-992718d3b50aedf77c80c262fad5845f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} -1 &amp; 3 &amp; 5 \\\\[1.1ex]  7 &amp; 3 &amp; -3 \\\\[1.1ex] 8 &amp; 0 &amp; 9\\end{vmatrix} = -408 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"193\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertanto <strong>la matrice A&#8217; ha rango 3<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-150bbc9c8e363db471c2d5bc4f33e1fd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E, infine, applichiamo il dominio al teorema di Rouch\u00e9-Frobenius: il dominio della matrice A \u00e8 pi\u00f9 piccolo del dominio della matrice A&#8217;, \u00e8 quindi un <strong>Sistema Incompatibile<\/strong> (SI) <strong>:<\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c3da0513f318d25473e93ba88c51fb42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=3 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = 2 \\ \\neq \\ rg(A') = 3 \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"426\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 6<\/h3>\n<p> Classificare il seguente sistema di equazioni di ordine 3 con il teorema di Rouch\u00e9-Frobenius: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d45e8bc425b08e403a98e01693201681_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{cases} 6x-2y+4z=1 \\\\[1.5ex] -2x+4y+3z= 7 \\\\[1.5ex] 8x-6y+z = -6\\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"158\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Costruiamo innanzitutto la matrice A e la matrice estesa A&#8217; del sistema:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8e779eca9135adc44e4a3a55f368560f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A= \\left( \\begin{array}{ccc} 6 &amp; -2 &amp; 4 \\\\[1.1ex] -2 &amp; 4 &amp; 3 \\\\[1.1ex] 8 &amp; -6 &amp; 1  \\end{array} \\right) \\qquad A'= \\left( \\begin{array}{ccc|c} 6 &amp; -2 &amp; 4 &amp; 1 \\\\[1.1ex] -2 &amp; 4 &amp; 3 &amp; 7 \\\\[1.1ex] 8 &amp; -6 &amp; 1 &amp; -6 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora calcoliamo l&#8217;intervallo della matrice A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c2f63f79858eae462547cf2f270fc780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix}A \\end{vmatrix}= \\begin{vmatrix} 6 &amp; -2 &amp; 4 \\\\[1.1ex] -2 &amp; 4 &amp; 3 \\\\[1.1ex] 8 &amp; -6 &amp; 1 \\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e5fa293b94b8c6acfd998f1e154abf7a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 6 &amp; -2  \\\\[1.1ex] -2 &amp; 4 \\end{vmatrix} = 20  \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi <strong>la matrice A ha rango 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eded270b78ab3d95ce827e3ea428efb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il rango di A, calcoliamo il rango di A&#8217;. Sappiamo gi\u00e0 che il determinante delle prime 3 colonne d\u00e0 0, quindi proviamo gli altri possibili determinanti 3\u00d73:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-98958f866454a1bf9f1ac078562065cd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} -2 &amp; 4 &amp; 1 \\\\[1.1ex]4 &amp; 3 &amp; 7 \\\\[1.1ex] -6 &amp; 1 &amp; -6\\end{vmatrix} = 0 \\quad \\begin{vmatrix}6 &amp; 4 &amp; 1 \\\\[1.1ex] -2 &amp; 3 &amp; 7 \\\\[1.1ex] 8 &amp;  1 &amp; -6\\end{vmatrix} = 0 \\quad \\begin{vmatrix} 6 &amp; -2 &amp; 1 \\\\[1.1ex] -2 &amp; 4 &amp; 7 \\\\[1.1ex] 8 &amp; -6 &amp; -6\\end{vmatrix} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"446\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tutti i determinanti 3\u00d73 della matrice A&#8217; sono 0, quindi neanche la matrice A&#8217; sar\u00e0 di rango 3. Tuttavia al suo interno sono presenti determinanti di ordine 2 diversi da 0. Ad esempio:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-58091f1a37a4ef81fdf56f01dd9531a3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{vmatrix} 6 &amp; -2 \\\\[1.1ex] -2 &amp; 4 \\end{vmatrix} = 20 \\neq 0\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Quindi <strong>la matrice A&#8217; sar\u00e0 di rango 2<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-80398cfd2fff647f81c0d4160f3b2f7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  rg(A')=2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"81\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Infine, applicando il teorema di Rouch\u00e9-Frobenius, sappiamo che si tratta di un <strong>Sistema Compatibile Indeterminato<\/strong> (ICS), perch\u00e9 l&#8217;intervallo della matrice A \u00e8 uguale all&#8217;intervallo della matrice A&#8217; ma questi due sono inferiori al numero di incognite presenti nella matrice sistema(3): <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-96868a2569ea0ab5ca99d8dc606d3dc9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{array}{c} \\begin{array}{c} \\color{black}rg(A) = 2 \\\\[1.3ex] \\color{black}rg(A')=2 \\\\[1.3ex] \\color{black}\\text{N\\'umero de inc\\'ognitas} = 3    \\end{array}} \\\\ \\\\  \\color{blue} \\boxed{ \\color{black}\\phantom{^9_9} rg(A) = rg(A') = 2 \\ < \\ n =3  \\color{blue} \\ \\bm{\\longrightarrow} \\ \\color{black} \\bm{SCI}\\phantom{^9_9}} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"138\" width=\"475\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>In questa pagina scopriremo cos&#8217;\u00e8 il teorema di Rouch\u00e9 Frobenius e come con esso si calcola il rango di una matrice. Troverai anche esempi ed esercizi risolti passo passo con il teorema di Rouch\u00e9-Frobenius. Cos&#8217;\u00e8 il teorema di Rouch\u00e9-Frobenius? Il teorema di Rouch\u00e9-Frobenius \u00e8 un metodo per classificare sistemi di equazioni lineari. In altre parole, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\"> <span class=\"screen-reader-text\">Teorema di rouche-fr\u00e9benius<\/span> Leggi altro &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[19],"tags":[],"class_list":["post-305","post","type-post","status-publish","format-standard","hentry","category-sistemi-educativi"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Teorema di Rouche-Fr\u00e9benius - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\" \/>\n<meta property=\"og:locale\" content=\"it_IT\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Teorema di Rouche-Fr\u00e9benius - Mathority\" \/>\n<meta property=\"og:description\" content=\"In questa pagina scopriremo cos&#8217;\u00e8 il teorema di Rouch\u00e9 Frobenius e come con esso si calcola il rango di una matrice. Troverai anche esempi ed esercizi risolti passo passo con il teorema di Rouch\u00e9-Frobenius. Cos&#8217;\u00e8 il teorema di Rouch\u00e9-Frobenius? Il teorema di Rouch\u00e9-Frobenius \u00e8 un metodo per classificare sistemi di equazioni lineari. In altre parole, &hellip; Teorema di rouche-fr\u00e9benius Leggi altro &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-06T14:52:33+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bd767a13412c19de65e75a6826caee08_l3.png\" \/>\n<meta name=\"author\" content=\"Squadra di Mathority\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Scritto da\" \/>\n\t<meta name=\"twitter:data1\" content=\"Squadra di Mathority\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tempo di lettura stimato\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minuti\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\"},\"author\":{\"name\":\"Squadra di Mathority\",\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8\"},\"headline\":\"Teorema di rouche-fr\u00e9benius\",\"datePublished\":\"2023-07-06T14:52:33+00:00\",\"dateModified\":\"2023-07-06T14:52:33+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\"},\"wordCount\":1547,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/mathority.org\/it\/#organization\"},\"articleSection\":[\"Sistemi educativi\"],\"inLanguage\":\"it-IT\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\",\"url\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\",\"name\":\"Teorema di Rouche-Fr\u00e9benius - Mathority\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/it\/#website\"},\"datePublished\":\"2023-07-06T14:52:33+00:00\",\"dateModified\":\"2023-07-06T14:52:33+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#breadcrumb\"},\"inLanguage\":\"it-IT\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mathority.org\/it\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Teorema di rouche-fr\u00e9benius\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mathority.org\/it\/#website\",\"url\":\"https:\/\/mathority.org\/it\/\",\"name\":\"Mathority\",\"description\":\"Dove la curiosit\u00e0 incontra il calcolo!\",\"publisher\":{\"@id\":\"https:\/\/mathority.org\/it\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mathority.org\/it\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"it-IT\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/mathority.org\/it\/#organization\",\"name\":\"Mathority\",\"url\":\"https:\/\/mathority.org\/it\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"it-IT\",\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png\",\"contentUrl\":\"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png\",\"width\":703,\"height\":151,\"caption\":\"Mathority\"},\"image\":{\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8\",\"name\":\"Squadra di Mathority\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"it-IT\",\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"caption\":\"Squadra di Mathority\"},\"sameAs\":[\"http:\/\/mathority.org\/it\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Teorema di Rouche-Fr\u00e9benius - Mathority","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/","og_locale":"it_IT","og_type":"article","og_title":"Teorema di Rouche-Fr\u00e9benius - Mathority","og_description":"In questa pagina scopriremo cos&#8217;\u00e8 il teorema di Rouch\u00e9 Frobenius e come con esso si calcola il rango di una matrice. Troverai anche esempi ed esercizi risolti passo passo con il teorema di Rouch\u00e9-Frobenius. Cos&#8217;\u00e8 il teorema di Rouch\u00e9-Frobenius? Il teorema di Rouch\u00e9-Frobenius \u00e8 un metodo per classificare sistemi di equazioni lineari. In altre parole, &hellip; Teorema di rouche-fr\u00e9benius Leggi altro &raquo;","og_url":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/","article_published_time":"2023-07-06T14:52:33+00:00","og_image":[{"url":"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bd767a13412c19de65e75a6826caee08_l3.png"}],"author":"Squadra di Mathority","twitter_card":"summary_large_image","twitter_misc":{"Scritto da":"Squadra di Mathority","Tempo di lettura stimato":"8 minuti"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#article","isPartOf":{"@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/"},"author":{"name":"Squadra di Mathority","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8"},"headline":"Teorema di rouche-fr\u00e9benius","datePublished":"2023-07-06T14:52:33+00:00","dateModified":"2023-07-06T14:52:33+00:00","mainEntityOfPage":{"@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/"},"wordCount":1547,"commentCount":0,"publisher":{"@id":"https:\/\/mathority.org\/it\/#organization"},"articleSection":["Sistemi educativi"],"inLanguage":"it-IT","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/","url":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/","name":"Teorema di Rouche-Fr\u00e9benius - Mathority","isPartOf":{"@id":"https:\/\/mathority.org\/it\/#website"},"datePublished":"2023-07-06T14:52:33+00:00","dateModified":"2023-07-06T14:52:33+00:00","breadcrumb":{"@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#breadcrumb"},"inLanguage":"it-IT","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/mathority.org\/it\/teorema-di-de-rouche-frobenius-con-esempi-ed-esercizi-risolti\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mathority.org\/it\/"},{"@type":"ListItem","position":2,"name":"Teorema di rouche-fr\u00e9benius"}]},{"@type":"WebSite","@id":"https:\/\/mathority.org\/it\/#website","url":"https:\/\/mathority.org\/it\/","name":"Mathority","description":"Dove la curiosit\u00e0 incontra il calcolo!","publisher":{"@id":"https:\/\/mathority.org\/it\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mathority.org\/it\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"it-IT"},{"@type":"Organization","@id":"https:\/\/mathority.org\/it\/#organization","name":"Mathority","url":"https:\/\/mathority.org\/it\/","logo":{"@type":"ImageObject","inLanguage":"it-IT","@id":"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/","url":"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png","contentUrl":"https:\/\/mathority.org\/it\/wp-content\/uploads\/2023\/10\/mathority-logo.png","width":703,"height":151,"caption":"Mathority"},"image":{"@id":"https:\/\/mathority.org\/it\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8","name":"Squadra di Mathority","image":{"@type":"ImageObject","inLanguage":"it-IT","@id":"https:\/\/mathority.org\/it\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g","caption":"Squadra di Mathority"},"sameAs":["http:\/\/mathority.org\/it"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts\/305","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/comments?post=305"}],"version-history":[{"count":0,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/posts\/305\/revisions"}],"wp:attachment":[{"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/media?parent=305"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/categories?post=305"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mathority.org\/it\/wp-json\/wp\/v2\/tags?post=305"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}