{"id":231,"date":"2023-07-10T22:13:46","date_gmt":"2023-07-10T22:13:46","guid":{"rendered":"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/"},"modified":"2023-07-10T22:13:46","modified_gmt":"2023-07-10T22:13:46","slug":"angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore","status":"publish","type":"post","link":"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/","title":{"rendered":"Angolo tra due linee (formula)"},"content":{"rendered":"<p>In questa pagina troverai la spiegazione di come calcolare l&#8217;angolo tra due linee (formula). Potrai anche vedere diversi esempi e, inoltre, potrai esercitarti con esercizi risolti passo dopo passo. <\/p>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-104\"><\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-el-angulo-entre-dos-rectas\"><\/span> Qual \u00e8 l&#8217;angolo tra due linee? <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-105\"><\/div>\n<\/div>\n<p> <strong>L&#8217;angolo tra due linee \u00e8 l&#8217;angolo pi\u00f9 piccolo tra queste due linee.<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/angle-entre-deux-lignes-1.webp\" alt=\"angolo tra due linee\" class=\"wp-image-1637\" width=\"225\" height=\"206\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Nella pianta ci sono quattro tipi di linee a seconda dell&#8217;angolo che formano tra loro: linee che si intersecano (tra 0\u00ba e 90\u00ba), linee perpendicolari (90\u00ba), linee parallele (0\u00ba) e linee coincidenti (0\u00ba). <\/p>\n<div class=\"wp-block-columns is-layout-flex wp-container-143\">\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center has-text-color has-medium-font-size\" style=\"color:#ff6f00\"> <strong>linee che si intersecano<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/angles-droits-secants.webp\" alt=\"angolo tra due linee che si intersecano\" class=\"wp-image-1644\" width=\"205\" height=\"192\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Le linee che si intersecano si intersecano con un angolo acuto compreso tra 0\u00ba e 90\u00ba. <\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center has-text-color has-medium-font-size\" style=\"color:#ff6f00\"> <strong><strong>Rette perpendicolari<\/strong><\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/lignes-perpendiculaires-a-90-degres.webp\" alt=\"angolo tra due linee perpendicolari\" class=\"wp-image-1884\" width=\"181\" height=\"207\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Le linee perpendicolari si intersecano ad angolo retto di 90\u00ba. <\/p>\n<\/div>\n<\/div>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-105\"><\/div>\n<\/div>\n<div class=\"wp-block-columns is-layout-flex wp-container-146\">\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center has-text-color has-medium-font-size\" style=\"color:#ff6f00\"> <strong>Linee parallele<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droites-paralleles-a-langle.webp\" alt=\"\" class=\"wp-image-1643\" width=\"217\" height=\"195\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Le linee parallele non si toccano mai e formano tra loro un angolo di 0\u00ba. <\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center has-text-color has-medium-font-size\" style=\"color:#ff6f00\"> <strong>linee coincidenti<\/strong> <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/angle-coincident-lignes.webp\" alt=\"\" class=\"wp-image-1646\" width=\"189\" height=\"168\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Due rette coincidenti hanno tutti i punti in comune e quindi tra loro esiste sempre un angolo pari a 0\u00ba.<\/p>\n<\/div>\n<\/div>\n<p> In conclusione, il calcolo dell&#8217;angolo tra due rette parallele, coincidenti o perpendicolari \u00e8 immediato: le rette parallele e le rette coincidenti formano un angolo di 0 gradi poich\u00e9 hanno la stessa direzione, e le rette perpendicolari si intersecano con un angolo di 90 gradi . Per trovare invece l&#8217;angolo tra due rette che si intersecano \u00e8 necessario applicare una formula (la vedremo di seguito). <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfcomo-se-calcula-el-angulo-entre-dos-rectas\"><\/span> Come si calcola l&#8217;angolo tra due linee? <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-106\"><\/div>\n<\/div>\n<p> Esistono due modi per calcolare l&#8217;angolo tra due linee. Il primo metodo utilizza il <strong>vettore direzione<\/strong> di ciascuna linea e il secondo metodo si basa sulla <strong>pendenza<\/strong> di ciascuna linea.<\/p>\n<p> Nessuna procedura \u00e8 migliore dell&#8217;altra, infatti entrambe sono abbastanza semplici, ma a seconda di come sono espresse le linee un metodo o un altro \u00e8 pratico. Ti consigliamo quindi di sapere come utilizzare entrambi i metodi matematici. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"metodo-de-los-vectores-directores-de-las-rectas\"><\/span> Metodo di orientamento del vettore di linea<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> La formula per calcolare l&#8217;angolo tra due linee utilizzando i loro vettori di direzione \u00e8: <\/p>\n<div style=\"background-color:#FFCC8080;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px; border: 2px solid #FFB74D; border-radius:20px;\">\n<p style=\"text-align:left\"> Dati i vettori direzione di due linee diverse:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b626c82ac04d69ba3bcafb5fa87d7d00_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{u}} = (\\text{u}_x,\\text{u}_y)\\qquad \\vv{\\text{v}} = (\\text{v}_x,\\text{v}_y)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"216\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> L&#8217;angolo tra queste due linee pu\u00f2 essere calcolato con la seguente formula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-19eb97a6cf27fffc3ea832e388f924a0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert \\vv{\\text{u}} \\cdot \\vv{\\text{v}}\\rvert}{\\lvert \\vv{\\text{u}} \\rvert \\cdot \\lvert \\vv{\\text{v}} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"127\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> Oro<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4501274336c637b37c6332eae5c6c229_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lvert \\vv{\\text{u}} \\rvert\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"16\" style=\"vertical-align: -5px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9a59cd4f2581db3318d38a2a77340a64_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lvert \\vv{\\text{v}} \\rvert\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"15\" style=\"vertical-align: -5px;\"><\/p>\n<p> sono i moduli dei vettori<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cac24ae79c1e4cbc459f01ed5e4f824e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{u}}\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-391ac2e3ba0b7f327ba5a0edc1ba162d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{v}}\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> rispettivamente.<\/p>\n<\/div>\n<p> Ricorda che la formula per la grandezza di un vettore \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0761a6a31d273eefccceb4aad7556a6c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{\\text{v}} \\rvert = \\sqrt{ \\text{v}_x^2+\\text{v}_y^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"32\" width=\"117\" style=\"vertical-align: -11px;\"><\/p>\n<\/p>\n<p> Vediamo come trovare l&#8217;angolo tra due rette con un esempio:<\/p>\n<ul>\n<li> Calcola l&#8217;angolo tra le seguenti due linee: <\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a336a6cbbd7581f1fb6481561aef1efc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases} x=2-3t \\\\[2ex]y=1+4t \\end{cases} \\qquad s: \\ 2x-5y+7=0\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"334\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-109\"><\/div>\n<\/div>\n<p> Per calcolare l&#8217;angolo tra le due linee, devi prima trovare il vettore direzione di ciascuna linea.<\/p>\n<p> la destra<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 espressa sotto forma di <a href=\"https:\/\/mathority.org\/it\/formule-delle-equazioni-parametriche-di-una-retta\/\">equazione parametrica<\/a> , pertanto le componenti del vettore che ne segna la direzione sono:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5d3e98a6c4a49b9b38e463795eb44b82_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{r} = (-3,4)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"85\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> e la legge<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ea93feaa2c7157ec666d9a59c0f6a699_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  s\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 definito sotto forma di un&#8217;equazione implicita (o generale), quindi le coordinate del suo vettore direzione sono:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25fa1b333fb55fd35e2ff773a99aab2c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{s} = (-B,A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"94\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-59f221044ed855cbee5120d8936cc247_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{s} = (5,2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"71\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Ora che conosciamo il vettore direzione di ciascuna linea, possiamo usare la formula per l&#8217;angolo tra due linee:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p> Determiniamo quindi la grandezza dei due vettori:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5630e1894a54b931779a240cce2b3460_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{r} \\rvert = \\sqrt{(-3)^2+4^2}= 5\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"172\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3b8dca924b988372d9cc00e5a3e79041_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{s} \\rvert = \\sqrt{5^2+2^2}= \\sqrt{29}\" title=\"Rendered by QuickLaTeX.com\" height=\"24\" width=\"169\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Eseguiamo le operazioni vettoriali della formula dell&#8217;angolo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1f1810380fc6ddab753a49fb43d8d136_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert(-3,4) \\cdot (5,2)\\rvert}{5 \\cdot \\sqrt{29}}= \\cfrac{\\lvert-3 \\cdot 5 + 4\\cdot 2\\rvert}{26,93} = \\cfrac{7}{26,93} = 0,26\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"449\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p> E, infine, calcoliamo l&#8217;angolo formato dalle due rette con l&#8217;inverso del coseno:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-839ce1333f41e5392ef7d2127853aae2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\alpha= \\text{cos}^{-1}(0,26) = \\bm{74,93\u00ba}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"193\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Ricorda che puoi calcolare l&#8217;inverso del coseno utilizzando la calcolatrice con il tasto <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b70d14d21b828bcf46c4104f901c916_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\boxed{\\cos ^{-1}}.\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"57\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"metodo-de-las-pendientes\"><\/span> metodo della pendenza<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Ovviamente, per comprendere questo metodo, \u00e8 necessario conoscere la <a href=\"https:\/\/mathority.org\/it\/formula-della-pendenza-della-retta\/\">pendenza della retta<\/a> . Puoi rivedere questo concetto nel link, dove troverai una spiegazione dettagliata di cosa significa, come si calcola, esempi ed esercizi risolti sulla pendenza di una retta.<\/p>\n<p> La formula per calcolare l&#8217;angolo tra due linee dalle loro pendenze \u00e8: <\/p>\n<div style=\"background-color:#FFCC8080;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px; border: 2px solid #FFB74D; border-radius:20px;\">\n<p style=\"text-align:left\"> Oppure due linee distinte:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a9768adb30eaa8e08b67c58e5c4921df_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r_1 : \\ y=m_1 x+n_1 \\qquad r_2: \\ y=m_2 x+n_2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"321\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> L&#8217;angolo tra queste due linee pu\u00f2 essere determinato con la seguente formula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-82acfc9ae51ee3a469cfabc7024aa75c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{m_2-m_1}{1+m_1\\cdot m_2} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"166\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> Oro<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51921237944fd6e43f0640228a37376f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"22\" style=\"vertical-align: -3px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6dae86895dac0d4644151786b47c7ce_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_2\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"23\" style=\"vertical-align: -3px;\"><\/p>\n<p> sono le pendenze delle linee<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ce00e1b287bac058a29aa4a5cc2b715_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r_1\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"14\" style=\"vertical-align: -3px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-80681c4f8159fb897fed760530a2ef01_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r_2\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"15\" style=\"vertical-align: -3px;\"><\/p>\n<p> rispettivamente.<\/p>\n<\/div>\n<p> Vediamo come calcolare l&#8217;angolo tra due rette utilizzando le loro pendenze con un esempio:<\/p>\n<ul>\n<li> Trova l&#8217;angolo tra le due linee seguenti:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-37af9568ead27bf5cc0bedd4e23107b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ y=4x-2 \\qquad s: \\ y=-3x+1\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"272\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> La pendenza di ciascuna linea \u00e8 il numero prima della variabile <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-845f2902b8bebf60c3c7372a7fbe4d02_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x:\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"19\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6fd143f62c08661d4c17431b128bdcf9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_r = 4\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"56\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a6063973129bb0bac4b98714e474f8ed_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_s = -3\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"69\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Pertanto, l&#8217;angolo tra le due linee pu\u00f2 essere trovato applicando la formula della pendenza:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-551288f526b75201969ebf9117fc9b1f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{m_s-m_r}{1+m_r\\cdot m_s} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"165\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-639af21616a579864711c6c3466a5157_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{-3-4}{1+4\\cdot (-3)} \\end{vmatrix}=\\begin{vmatrix} \\cfrac{-7}{-11} \\end{vmatrix} = 0,64\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"294\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<p> E infine troviamo l&#8217;angolo con l&#8217;inverso della tangente:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-caed83d6028d223b06c41f639e5323e3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\alpha= \\text{tg}^{-1}(0,64) = \\bm{32,62\u00ba}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"184\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Ricorda che puoi calcolare l&#8217;inverso della tangente utilizzando la calcolatrice con il tasto<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2be52d0cf4b9ef4f831429feec90b416_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\boxed{\\tan ^{-1}}.\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"59\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p> Abbiamo appena visto un esempio con le pendenze di due rette espresse come un&#8217;equazione esplicita, ma se fossero sotto forma di <a href=\"https:\/\/mathority.org\/it\/formula-della-pendenza-della-retta-del-punto-di-equazione\/\">un&#8217;equazione di pendenza puntuale,<\/a> si dovrebbe usare questa stessa procedura. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-angulos-entre-dos-rectas\"><\/span> Risoluzione dei problemi relativi agli angoli tra due rette<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Esercizio 1<\/h3>\n<p> Determina l&#8217;angolo formato dalle due rette seguenti: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-975bcacc5eecede0a2288a39eeb27a73_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases} x=4+t \\\\[2ex]y=-3-2t \\end{cases} \\qquad s: \\ \\begin{cases} x=4t \\\\[2ex]y=-1-t \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"324\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> In questo caso utilizzeremo il metodo del vettore di direzione. Pertanto, dobbiamo prima trovare il vettore direzione di ciascuna linea. Entrambe le linee sono espresse come equazioni parametriche, quindi le componenti dei loro vettori di direzione sono i termini che precedono il parametro <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-40f8b062c79839dcf7f2885a9e1469e7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t:\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"15\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ac0191cf7cbec493c10a4fa8197e2a6b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{r} = (1,-2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"85\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-97225ee00d3957d5d85cdc93c8015ed4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{s} = (4,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"85\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ora che conosciamo il vettore direzione di ciascuna linea, possiamo usare la formula per l&#8217;angolo tra due linee:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Determiniamo quindi la grandezza dei due vettori: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2e501df610a9ae606c598ec472017f78_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{r} \\rvert = \\sqrt{1^2+(-2)^2}= \\sqrt{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"187\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b9e23805a7bdb58bd0b4893d4b6e586a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{s} \\rvert = \\sqrt{4^2+(-1)^2}= \\sqrt{17}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"196\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Risolviamo il prodotto scalare tra i due vettori del numeratore e la moltiplicazione dei moduli del denominatore: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e5d926125129db13c541515e1dd0beba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert(1,-2) \\cdot (4,-1)\\rvert}{\\sqrt{5} \\cdot \\sqrt{17}}= \\cfrac{\\lvert 1 \\cdot 4 + (-2)\\cdot (-1)\\rvert}{9,22} = \\cfrac{6}{9,22} = 0,65\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"494\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine troviamo l&#8217;angolo formato dalle due rette eseguendo l&#8217;inverso del coseno: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3ede88ebdcf81c8914fed546ba2a0d1b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\alpha= \\text{cos}^{-1}(0,65) = \\bm{49,40\u00ba}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"193\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 2<\/h3>\n<p> Trova l&#8217;angolo tra le due linee seguenti: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-818fae5a2074424ec782243f26c5708c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ -3x+4y+1=0 \\qquad s: \\ \\cfrac{x-1}{6} = \\cfrac{y+5}{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"337\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Risolveremo questo problema utilizzando il metodo del vettore di direzione, quindi prima dobbiamo trovare il vettore di direzione di ciascuna linea. la destra<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 espresso sotto forma di un&#8217;equazione generale (o implicita), tale che le componenti del vettore che ne segna la direzione sono: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-381327f58ef6c881ed34e78624c91b8d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{r} = (-B,A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"94\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-383a5264ab7ded87d5684560e6263e15_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{r} = (-4,-3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"99\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> e la legge<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ea93feaa2c7157ec666d9a59c0f6a699_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  s\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e8 definito sotto forma di un&#8217;equazione continua, quindi le coordinate cartesiane del suo vettore direzione sono i numeri dei denominatori:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4ba6fe3a3d80f3a44c2c3a0c8345ffa4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{s} = (6,3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"71\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Una volta conosciuto il vettore direzione di ciascuna linea, possiamo usare la formula per l&#8217;angolo tra due linee:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Determiniamo quindi i moduli dei due vettori: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-565377b63a2e28ce9613745bc0c0b756_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{r} \\rvert = \\sqrt{(-4)^2+(-3)^2}= 5\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-65100d7dbdf97aa72e9212379ff54de8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\lvert \\vv{s} \\rvert = \\sqrt{6^2+3^2}= \\sqrt{45}\" title=\"Rendered by QuickLaTeX.com\" height=\"24\" width=\"169\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Eseguiamo le operazioni tra i vettori della formula dell&#8217;angolo: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-790804eb21bd7b19771c5597b3cea577_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert\\vv{r} \\cdot \\vv{s}\\rvert}{\\lvert \\vv{r} \\rvert \\cdot \\lvert \\vv{s} \\rvert}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"125\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a36b58fc65b59f20656acc68016020ac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\cos(\\alpha) =\\cfrac{\\lvert(-4,-3) \\cdot (6,3)\\rvert}{5 \\cdot \\sqrt{45}}= \\cfrac{\\lvert -4 \\cdot 6 + (-3)\\cdot 3\\rvert}{33,54} = \\cfrac{33}{33,54} = 0,98\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"490\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E, infine, calcoliamo l&#8217;angolo formato dalle due rette con l&#8217;inverso del coseno: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-216ef184adb4e8e26ea4dba3a0d41a67_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\alpha= \\text{cos}^{-1}(0,98) = \\bm{10,30\u00ba}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"193\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 3<\/h3>\n<p> Qual \u00e8 l&#8217;angolo tra le due rette seguenti? <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a559370fd832ad2f4707782cf40cb37_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ y=-2x+9 \\qquad s: \\ y=5x-1\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"272\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> In questo caso utilizzeremo il metodo delle pendenze delle linee per scoprire l&#8217;angolo che formano, poich\u00e9 le linee hanno la forma di un&#8217;equazione esplicita.<\/p>\n<p class=\"has-text-align-left\"> La pendenza di ciascuna linea \u00e8 il numero che accompagna la variabile indipendente <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-845f2902b8bebf60c3c7372a7fbe4d02_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x:\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"19\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42a36a89145f23919d8665908c3e2bc3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_r = -2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"69\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42de98336b7cbc2dc475ea3037bebc55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_s = 5\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"54\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertanto, l&#8217;angolo tra le due linee pu\u00f2 essere determinato applicando la formula della pendenza: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-551288f526b75201969ebf9117fc9b1f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{m_s-m_r}{1+m_r\\cdot m_s} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"165\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-172bd34124a3b9e86696158d992eebb8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{-2-5}{1+5\\cdot (-2)} \\end{vmatrix}=\\begin{vmatrix} \\cfrac{-7}{-9} \\end{vmatrix} = 0,78\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"293\" style=\"vertical-align: -19px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E infine troviamo l&#8217;angolo tra le due linee invertendo la tangente: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c84b4105875a851c576fb326e2ba6f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\alpha= \\text{tg}^{-1}(0,78) = \\bm{37,87\u00ba}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"185\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Esercizio 4<\/h3>\n<p> Trova l&#8217;equazione della retta che passa per il punto<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6958f848b3f39930bc315b56f627f888_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(5,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"66\" style=\"vertical-align: -5px;\"><\/p>\n<p> e forma con la linea un angolo di 45\u00ba<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa03a29f511592c1a1ecc8b306b0cf0d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r.\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"12\" style=\"vertical-align: 0px;\"><\/p>\n<p> Diciamo la riga: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-34edcc0a8f3b1c557be083882ab8b7e2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ y=2x+4\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"112\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>vedi soluzione<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Per risolvere il problema chiameremo<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ae1901659f469e6be883797bfd30f4f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"s\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> a destra che calcoleremo. Inoltre, utilizzeremo il metodo della pendenza perch\u00e9 conosciamo la pendenza della retta<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c5986f031932e6b3512dc564514c34b5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r:\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"17\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9edd8ad155030a560ef8313513b5ac14_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_r=2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"55\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dalla formula dell&#8217;angolo tra due rette (metodo della pendenza) si ottiene il valore della pendenza della retta <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-580a84fe09f12aa20c352a8336880e41_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"s:\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"17\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-551288f526b75201969ebf9117fc9b1f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(\\alpha) =\\begin{vmatrix} \\cfrac{m_s-m_r}{1+m_r\\cdot m_s} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"165\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sostituiamo i valori noti nella formula:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ace7fdfc7474a43a6fad81e0185d0050_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{tg}(45\u00ba) =\\begin{vmatrix} \\cfrac{m_s-2}{1+2\\cdot m_s} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"158\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E proviamo a risolvere l&#8217;equazione risultante:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0f2ea68d68e24c3e30df526dfb88873c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1 =\\begin{vmatrix} \\cfrac{m_s-2}{1+2m_s} \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"105\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Il valore assoluto dell&#8217;equazione la rende un po&#8217; difficile da risolvere, perch\u00e9 bisogna analizzare sia le opzioni positive che quelle negative: <\/p>\n<div class=\"wp-block-columns is-layout-flex wp-container-149\">\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7ad2ad90ee94f08746cea11db3a6917f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1 =+\\cfrac{m_s-2}{1+2m_s}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"110\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-56c4a065c3919fbe023153fe2ba9133c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1 \\cdot (1+2m_s)=m_s-2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"173\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d31fa5d4b608e062c0e15476b3f15e7f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1+2m_s=m_s-2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"137\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-870381f6e915e33b32ad147c9a4de5fc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 2m_s-m_s=-2-1\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"152\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1d7c13f0d7d21af8c407f7f535e0d994_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle m_s=-3\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"69\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b9e6f5eb952e8ea9758af5497ed8cf2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1 =-\\cfrac{m_s-2}{1+2m_s}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"110\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2b984c3bc74269597752a909f457c8ff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1 \\cdot (1+2m_s)=-(m_s-2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"200\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-df53d7b057ec0e6b6f7701fb5149cbe0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 1+2m_s=-m_s+2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"151\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9a96107cb59f52dcf9bb703e54c27757_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 2m_s+m_s=2-1\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"138\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-067dac6d6aea31f65caccf5ed9c30052_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle 3m_s=1\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"63\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9003dbf8679e5b0aaa8c10777f6d38fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle m_s=\\cfrac{1}{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"57\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Abbiamo quindi due possibili soluzioni: una linea con pendenza -3 e un&#8217;altra linea con pendenza un terzo.<\/p>\n<p class=\"has-text-align-left\"> La formula per l&#8217;equazione punto-pendenza di una linea \u00e8:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3441e1da8c7da5805b1133af77b14f60_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y-y_0=m(x-x_0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"149\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertanto, una volta conosciuta la pendenza delle due possibili rette, possiamo scrivere l&#8217;equazione punto-pendenza di ciascuna retta con il punto per il quale devono passare secondo l&#8217;enunciato, <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c8726fb72614f7e8f7e546f9ac6995cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(5,-1):\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0a69157a1cf6a00b750b804590e63524_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle s: \\ y+1=-3(x-5) \\qquad \\qquad s': \\ y+1=\\cfrac{1}{3}(x-5)\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"402\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>In questa pagina troverai la spiegazione di come calcolare l&#8217;angolo tra due linee (formula). Potrai anche vedere diversi esempi e, inoltre, potrai esercitarti con esercizi risolti passo dopo passo. Qual \u00e8 l&#8217;angolo tra due linee? L&#8217;angolo tra due linee \u00e8 l&#8217;angolo pi\u00f9 piccolo tra queste due linee. Nella pianta ci sono quattro tipi di linee &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\"> <span class=\"screen-reader-text\">Angolo tra due linee (formula)<\/span> Leggi altro &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[15],"tags":[],"class_list":["post-231","post","type-post","status-publish","format-standard","hentry","category-punti-rette-e-piani"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Angolo tra due linee (formula) - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\" \/>\n<meta property=\"og:locale\" content=\"it_IT\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Angolo tra due linee (formula) - Mathority\" \/>\n<meta property=\"og:description\" content=\"In questa pagina troverai la spiegazione di come calcolare l&#8217;angolo tra due linee (formula). Potrai anche vedere diversi esempi e, inoltre, potrai esercitarti con esercizi risolti passo dopo passo. Qual \u00e8 l&#8217;angolo tra due linee? L&#8217;angolo tra due linee \u00e8 l&#8217;angolo pi\u00f9 piccolo tra queste due linee. Nella pianta ci sono quattro tipi di linee &hellip; Angolo tra due linee (formula) Leggi altro &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-10T22:13:46+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/angle-entre-deux-lignes-1.webp\" \/>\n<meta name=\"author\" content=\"Squadra di Mathority\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Scritto da\" \/>\n\t<meta name=\"twitter:data1\" content=\"Squadra di Mathority\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tempo di lettura stimato\" \/>\n\t<meta name=\"twitter:data2\" content=\"5 minuti\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\"},\"author\":{\"name\":\"Squadra di Mathority\",\"@id\":\"https:\/\/mathority.org\/it\/#\/schema\/person\/8d6f69ffbe48aea8b43675a9a3ddb9c8\"},\"headline\":\"Angolo tra due linee (formula)\",\"datePublished\":\"2023-07-10T22:13:46+00:00\",\"dateModified\":\"2023-07-10T22:13:46+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\"},\"wordCount\":1145,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/mathority.org\/it\/#organization\"},\"articleSection\":[\"Punti, rette e piani\"],\"inLanguage\":\"it-IT\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\",\"url\":\"https:\/\/mathority.org\/it\/angolo-tra-due-linee-esempi-di-formule-esercizi-risolti-pendenze-vettore-direttore\/\",\"name\":\"Angolo tra due linee (formula) - 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