{"id":67,"date":"2023-09-17T05:59:45","date_gmt":"2023-09-17T05:59:45","guid":{"rendered":"https:\/\/mathority.org\/id\/matriks-terbalik\/"},"modified":"2023-09-17T05:59:45","modified_gmt":"2023-09-17T05:59:45","slug":"matriks-terbalik","status":"publish","type":"post","link":"https:\/\/mathority.org\/id\/matriks-terbalik\/","title":{"rendered":"Cara menghitung matriks invers"},"content":{"rendered":"<p>Di halaman ini Anda akan mempelajari apa itu dan bagaimana menghitung invers suatu matriks dengan metode determinan (atau matriks adjoin) dan metode Gauss. Anda juga akan melihat semua properti matriks invers, dan Anda juga akan menemukan contoh penyelesaian langkah demi langkah dan latihan untuk setiap metode sehingga Anda memahaminya sepenuhnya. Terakhir, kami menjelaskan rumus untuk membalikkan matriks 2&#215;2 dengan cepat dan bahkan kegunaan terbesar dari operasi matriks ini: menyelesaikan sistem persamaan linier.<\/p>\n<h2 class=\"wp-block-heading\"> Berapakah invers dari suatu matriks? <\/h2>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Menjadi<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> matriks persegi. <strong>Matriks terbalik<\/strong> dari<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> tertulis<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2b32875906f7ed9c10ffd1b09a6ed5e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"30\" style=\"vertical-align: 0px;\"><\/p>\n<p> , dan matriks inilah yang memenuhi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fd42c364eee57f5eada44b8ef06f254a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A \\cdot A^{-1} = I\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a003e1fd3042f8cd7ec7d3fe7f286f5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}\\cdot A  = I\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p align=\"LEFT\"> Emas<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-18b5e45cb4a1ee02e81b9a980f828db8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah matriks Identitas.<\/p>\n<\/div>\n<h2 class=\"wp-block-heading\"> Kapan Anda bisa membalikkan matriks dan kapan tidak?<\/h2>\n<p> Cara paling sederhana untuk menentukan invertibilitas suatu matriks adalah dengan menggunakan determinannya:<\/p>\n<ul>\n<li> Jika determinan matriks yang bersangkutan berbeda dengan 0, berarti matriks tersebut dapat dibalik. Dalam hal ini kita katakan bahwa ini adalah matriks biasa. Lebih jauh lagi, ini menyiratkan bahwa matriks tersebut memiliki peringkat maksimum.<\/li>\n<\/ul>\n<ul>\n<li> Sebaliknya, jika determinan matriks sama dengan 0, maka matriks tersebut tidak dapat dibalik. Dan, dalam hal ini, kita katakan bahwa ini adalah matriks tunggal atau matriks yang merosot.<\/li>\n<\/ul>\n<p> Pada dasarnya, ada dua metode untuk membalikkan matriks apa pun: metode determinan atau matriks adjoin dan metode Gauss. Di bawah ini Anda memiliki penjelasan yang pertama, tetapi Anda juga dapat berkonsultasi di bawah ini tentang cara membalikkan matriks dengan metode Gauss.<\/p>\n<h2 class=\"wp-block-heading\"> Membalikkan matriks menggunakan metode determinan (atau menggunakan matriks yang berdekatan) <\/h2>\n<div style=\"background-color:#dff6ff;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Untuk menghitung <strong>invers suatu matriks<\/strong> ,<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3017946e4911f6188e04dfdca6f050ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"30\" style=\"vertical-align: 0px;\"><\/p>\n<p> , rumus berikut harus diterapkan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p align=\"LEFT\" style=\"margin-bottom:8px\"> Emas:<\/p>\n<ul>\n<li style=\"margin-bottom:12px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a80d0312d139244060532c8c78fe6140_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix} A \\end{vmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"21\" style=\"vertical-align: -7px;\"><\/p>\n<p> adalah determinan matriks<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<\/li>\n<li style=\"margin-bottom:12px\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e87ef954487ce9371eac7dc25f234613_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adj}(A)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"55\" style=\"vertical-align: -5px;\"><\/p>\n<p> adalah matriks adjoin dari<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<\/li>\n<li> Peserta pameran\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50d6971192a73f12b183dbddd7c75197_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> menunjukkan transposisi matriks, yaitu matriks terlampir harus ditransposisi.<\/li>\n<\/ul>\n<\/div>\n<p> <strong>Komentar:<\/strong> Beberapa buku menggunakan rumus matriks invers yang sedikit berbeda: pertama-tama buku tersebut melakukan transposisi matriks A lalu menghitung matriks adjoinnya, alih-alih terlebih dahulu menghitung matriks adjoinnya lalu melakukan transposisi. Kenyataannya, urutannya tidak menjadi masalah karena hasilnya sama persis. Di sini kami memberikan rumus untuk membalikkan matriks yang dimodifikasi jika Anda lebih suka menggunakan yang ini: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-la-matrice-inverse-adjointe-de-transposee-3.webp\" alt=\"rumus matriks invers dengan matriks adjoint transposnya\" class=\"wp-image-4372\" width=\"238\" height=\"239\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Selanjutnya kita akan melihat <strong>cara mencari invers suatu matriks<\/strong> dengan menyelesaikan latihan sebagai contoh:<\/p>\n<h3 class=\"wp-block-heading\"> Contoh penghitungan matriks invers menggunakan metode determinan (atau matriks adjoint):<\/h3>\n<ul>\n<li> Hitung invers matriks berikut:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c37ec4a7afd5b313bcf3c50d6ce26c6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 4 &amp; -2  \\\\[1.1ex] 3 &amp; -1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Untuk menentukan invers matriks, kita harus menerapkan rumus berikut: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-la-matrice-inverse-avec-la-methode-par-determinants-ou-par-la-matrice-adjointe.webp\" alt=\"rumus matriks invers dengan metode determinan atau matriks adjoin\" width=\"218\" height=\"59\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Namun jika determinan matriksnya nol berarti matriks tersebut tidak dapat dibalik. Oleh karena itu, hal pertama yang harus dilakukan adalah menghitung determinan matriks dan memeriksa apakah determinannya berbeda dari 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-710ccd4e4912dd492b496a742eaf7f56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\lvert A \\rvert  = \\begin{vmatrix}  4 &amp; -2  \\\\[1.1ex] 3 &amp; -1 \\end{vmatrix} = -4- (-6) = 2\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"240\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> <strong>Penentunya bukan 0<\/strong> , sehingga <strong>matriksnya dapat dibalik<\/strong> .<\/p>\n<p> Oleh karena itu, dengan mensubstitusikan nilai determinan ke dalam rumus, invers matriksnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9be7ff27e83825750fc7b378f743412f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"161\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Sekarang kita harus menghitung wakil matriks A. Untuk melakukannya, kita harus mengganti setiap elemen matriks A dengan wakilnya. <\/p>\n<div style=\"background-color:#fffde7;padding-top: 20px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px\" class=\"has-background\">\n<p align=\"LEFT\"> Ingatlah bahwa untuk menghitung <strong>lampiran<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> , yaitu elemen baris<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> dan kolom<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> , rumus berikut harus diterapkan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dcce4b79a3549da03df7c78b678add31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de } a_{ij} = (-1)^{i+j} \\bm{\\cdot} \\text{Menor complementario de } a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"430\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p align=\"LEFT\"> Dimana minor komplementer dari<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41d4a89db3722950dc94351832a1bcd9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a_{ij}\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> adalah determinan matriks yang menghilangkan baris tersebut<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-695d9d59bd04859c6c99e7feb11daab6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"i\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> dan kolom<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-43c82d5bb00a7568d935a12e3bd969dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"j\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> .<\/p>\n<\/div>\n<p> Jadi, wakil elemen matriks A adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c37ec4a7afd5b313bcf3c50d6ce26c6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 4 &amp; -2  \\\\[1.1ex] 3 &amp; -1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-981d47faf70cc1377c1abb515419a881_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} -1 \\end{vmatrix} = 1 \\cdot (-1) = \\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0f1e6a5a5c504b3b6d06e5d3d8e0862e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"336\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02a2bf190ba8788264d0326f38cb0a21_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -2 \\end{vmatrix} = -1 \\cdot (-2) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f01b7eb06a25b50bf15fbfd08e68cd13_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -1} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 4 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"309\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> <strong>Komentar:<\/strong> Jangan bingung antara determinan 1\u00d71 dengan nilai absolut, karena pada determinan 1\u00d71 bilangan tersebut tidak diubah menjadi positif.<\/p>\n<p> Setelah deputi dihitung, cukup ganti elemen A dengan deputinya untuk mencari <strong>matriks deputi A<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-08fb7666b4518399c2a469ba445762be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} -1 &amp; -3  \\\\[1.1ex] 2 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"165\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> <strong>Komentar:<\/strong> di tempat tertentu matriks adjoint merupakan transpose dari matriks adjoint yang kita definisikan disini.<\/p>\n<p> Oleh karena itu, matriks terlampir kita substitusikan ke dalam rumus matriks invers sehingga menjadi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9be7ff27e83825750fc7b378f743412f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"161\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0abb4127db9c3c1d0a7b669fbc782605_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\begin{pmatrix} -1 &amp; -3  \\\\[1.1ex] 2 &amp; 4  \\end{pmatrix} ^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Peserta pameran<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50d6971192a73f12b183dbddd7c75197_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> Ini memberitahu kita bahwa kita perlu <strong>mengubah posisi matriks<\/strong> . Dan untuk mengubah urutan suatu matriks, Anda harus <strong>mengubah baris-barisnya menjadi kolom-kolom<\/strong> , artinya baris pertama matriks menjadi kolom pertama matriks, dan baris kedua menjadi kolom kedua:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-22965912cf8aee99610c81cf575c0ecd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{2} \\cdot \\begin{pmatrix} -1 &amp; 2  \\\\[1.1ex] -3 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"151\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Dan terakhir, kita mengalikan setiap suku matriks dengan<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a7c03ba828b3d8aef58199ac2c95a47_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{1}{2} :\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"18\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-220748840151b429919c7ce6587b1bc0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\sfrac{-1}{2} &amp; \\sfrac{2}{2}  \\\\[1.1ex] \\sfrac{-3}{2} &amp; \\sfrac{4}{2}  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"145\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/matrice-inverse-de-lexercice-resolu-par-les-determinants-22152.webp\" alt=\"latihan menyelesaikan matriks invers dengan determinan 2x2\" width=\"188\" height=\"69\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h3 class=\"wp-block-heading\"> Latihan soal matriks invers dengan metode determinan (atau matriks bersebelahan)<\/h3>\n<h4 class=\"wp-block-heading\"> Latihan 1<\/h4>\n<p> Balikkan matriks berdimensi 2\u00d72 berikut dengan menggunakan metode matriks adjoint: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bfb0807249e78845b375a402eb23a32b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 7  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Rumus matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertama-tama kita hitung determinan matriksnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1c4e3bac90eb0da0361b4be1a2225146_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 7 \\end{vmatrix} = 7-6 = 1\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"187\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Penentunya berbeda dengan 0, sehingga matriks dapat diinversi.<\/p>\n<p class=\"has-text-align-left\"> Sekarang mari kita hitung matriks adjoin dari A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-34ac8739bfee66d594eee01b7a2b9205_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 7 \\end{vmatrix} = 1 \\cdot 7 = \\bm{7}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"303\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4021288fe5f1db07d81dbb43ce15e82a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 2\\end{vmatrix} = -1 \\cdot 2 = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"329\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-12783f7673a347fc5e0df04917332fa0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3 \\end{vmatrix} = -1 \\cdot 3 = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"330\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d48d00b2e8df51348f8f41c96b9197b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 7} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 \\end{vmatrix} = 1 \\cdot 1 = \\bm{1}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"302\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3dea8fca2c025ff9b7d7673904344996_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 7 &amp; -2  \\\\[1.1ex] -3 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"165\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Setelah determinan matriks dan adjoinnya dihitung, kita substitusikan nilainya ke dalam rumus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9475e4162eff7e1ed9c08f363a8279ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{1} \\cdot \\begin{pmatrix} 7 &amp; -2 \\\\[1.1ex] -3 &amp; 1 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengubah urutan matriks terlampir:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a5a6aaa8168e55c6eab1e3be1229a3da_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = 1 \\cdot \\begin{pmatrix} 7 &amp; -3 \\\\[1.1ex] -2 &amp; 1 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"162\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, matriks invers dari A adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1236ad7262705dbbd9b0a094084ceac5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\bm{7} &amp; \\bm{-3} \\\\[1.1ex] \\bm{-2} &amp; \\bm{1} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 2<\/h4>\n<p> Balikkan matriks persegi berikut menggunakan metode determinan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb735917d200ed35918cd44be6bd155b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} -3 &amp; -2 \\\\[1.1ex] 5 &amp; 4  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Rumus matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertama-tama kita hitung determinan matriksnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-49cd3daf7c50c811e78c29efe036bda4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} -3 &amp; -2 \\\\[1.1ex] 5 &amp; 4\\end{vmatrix} = -12+10 = -2\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"260\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Penentunya berbeda dengan 0, sehingga matriks dapat diinversi.<\/p>\n<p class=\"has-text-align-left\"> Sekarang mari kita hitung matriks adjoin dari A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8bff9fecfd83ca1edacba562d8714cbf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -3} =\\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 4 \\end{vmatrix} = 1 \\cdot 4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"309\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b558b2d47ccf4b3065ed8b26ab620502_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2} =\\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix} 5\\end{vmatrix} = -1 \\cdot 5 = \\bm{-5}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"335\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b6d0a26085435c08c6d60ab80f4fbb2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 5}  =\\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} -2 \\end{vmatrix} = -1 \\cdot (-2) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"357\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-79a60c5e3003ea311503867a147c1500_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} =\\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} -3 \\end{vmatrix} = 1 \\cdot (-3) = \\bm{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"358\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-208ab7161076485ca6928bd1208f6714_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 4 &amp; -5  \\\\[1.1ex] 2 &amp; -3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"151\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Setelah determinan matriks dan adjoinnya ditemukan, kita substitusikan nilainya ke dalam rumus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-babecc87455bdc54006a77ba5369e540_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{-2} \\cdot \\begin{pmatrix} 4 &amp; -5 \\\\[1.1ex] 2 &amp; -3 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"173\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengubah urutan matriks terlampir:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-17529597656a112a27d136ca212834d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{-2} \\cdot \\begin{pmatrix} 4 &amp; 2 \\\\[1.1ex] -5 &amp; -3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengalikan setiap elemen dengan <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f70ecad488bad8503fe7f8427180e2e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{1}{-2} :\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"32\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-be52d2df839244cbb0b0ee00c9e45265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\cfrac{4}{-2} &amp; \\cfrac{2}{-2} \\\\[3ex] \\cfrac{-5}{-2} &amp; \\cfrac{-3}{-2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, matriks invers dari A adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-13e218c7d075daba3f875345f324d001_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\bm{-2} &amp; \\bm{-1} \\\\[2ex] \\cfrac{\\bm{5}}{\\bm{2}} &amp; \\cfrac{\\bm{3}}{\\bm{2}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"141\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 3<\/h4>\n<p> Balikkan matriks berdimensi 3\u00d73 berikut dengan menggunakan metode matriks adjoint: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d1b6a5f638281754d80983b5a50e15be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}2&amp;3&amp;-2\\\\[1.1ex] 1&amp;4&amp;1\\\\[1.1ex] 2&amp;1&amp;-3\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Rumus matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertama-tama kita selesaikan determinan matriks dengan aturan Sarrus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fcac1cb3935b1000b6493a2866e8728a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 2&amp;3&amp;-2\\\\[1.1ex] 1&amp;4&amp;1\\\\[1.1ex] 2&amp;1&amp;-3 \\end{vmatrix} = -24+6-2+16-2+9 = 3\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"381\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Penentunya berbeda dengan 0, sehingga matriks dapat diinversi.<\/p>\n<p class=\"has-text-align-left\"> Setelah determinannya terselesaikan, kita mencari matriks adjoint dari A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c510482ac77a8c5d511c095de600f1ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2} = \\displaystyle (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix} 4&amp;1\\\\[1.1ex] 1&amp;-3 \\end{vmatrix} = 1 \\cdot (-13) = \\bm{-13}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"403\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fa99e03d34c925098c1ad3ed6f06c745_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 3} = \\displaystyle (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix}1&amp;1\\\\[1.1ex] 2&amp;-3\\end{vmatrix} = -1 \\cdot (-5) = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"384\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3bf9f8565b3e4a99ff254c7558699c13_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -2}  = \\displaystyle (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} 1&amp;4\\\\[1.1ex] 2&amp;1 \\end{vmatrix} = 1\\cdot (-7) = \\bm{-7}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"377\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-99e2c3f55fbba7b5faa014758b60f4a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix} 3&amp;-2 \\\\[1.1ex] 1&amp;-3 \\end{vmatrix} = -1 \\cdot (-7) = \\bm{7}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"385\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23326bccecf752508e7418cbbc8eacd3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 4} = \\displaystyle (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 2&amp;-2\\\\[1.1ex] 2&amp;-3 \\end{vmatrix} = 1 \\cdot (-2) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"384\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a9d056af07ce26751783152a67cdedb6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 2&amp;3\\\\[1.1ex] 2&amp;1\\end{vmatrix} = -1 \\cdot (-4) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"371\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bed501806c35c94e491ad2063b2d0653_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 2}  = \\displaystyle (-1)^{3+1} \\bm{\\cdot} \\begin{vmatrix} 3&amp;-2\\\\[1.1ex] 4&amp;1\\end{vmatrix} = 1 \\cdot 11 = \\bm{11}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"360\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3f108a61eec662b9420708f6920060be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de 1} = \\displaystyle (-1)^{3+2} \\bm{\\cdot} \\begin{vmatrix} 2&amp;-2\\\\[1.1ex] 1&amp;1\\end{vmatrix} = -1 \\cdot 4 = \\bm{-4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"371\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-77a152a00dbb5f1e0f8702dd9511095a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Adjunto de -3} = \\displaystyle (-1)^{3+3} \\bm{\\cdot} \\begin{vmatrix} 2&amp;3\\\\[1.1ex] 1&amp;4 \\end{vmatrix} = 1 \\cdot 5 = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"335\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4642a75697fd30286065cdb4063a7bd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} -13 &amp; 5 &amp; -7  \\\\[1.1ex] 7 &amp; -2 &amp; 4 \\\\[1.1ex] 11 &amp; -4 &amp; 5 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Setelah kita menghitung determinan matriks dan adjoinnya, kita substitusikan nilainya ke dalam rumus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fae003a07d40b69690566cde77857c3a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} -13 &amp; 5 &amp; -7 \\\\[1.1ex] 7 &amp; -2 &amp; 4 \\\\[1.1ex] 11 &amp; -4 &amp; 5 \\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"89\" width=\"224\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengubah urutan matriks terlampir:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-55717407766afe98f50ca75f20536edc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} -13 &amp; 7 &amp; 11 \\\\[1.1ex] 5 &amp; -2 &amp; -4 \\\\[1.1ex] -7 &amp; 4 &amp; 5 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan matriks A yang terbalik adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9835713a5b791ee959d6571d706180f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{A^{-1} =} \\begin{pmatrix} \\sfrac{\\bm{-13}}{\\bm{3}} &amp; \\sfrac{\\bm{7}}{\\bm{3}} &amp; \\sfrac{\\bm{11}}{\\bm{3}} \\\\[1.1ex] \\sfrac{\\bm{5}}{\\bm{3}} &amp; \\sfrac{\\bm{-2}}{\\bm{3}} &amp; \\sfrac{\\bm{-4}}{\\bm{3}} \\\\[1.1ex] \\sfrac{\\bm{-7}}{\\bm{3}} &amp; \\sfrac{\\bm{4}}{\\bm{3}} &amp; \\sfrac{\\bm{5}}{\\bm{3}}\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"216\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 4<\/h4>\n<p> Balikkan matriks orde 3 berikut dengan menggunakan metode matriks adjoint: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bf71320b51e9514d1c372389aeb3410a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}4&amp;5&amp;-1\\\\[1.1ex] -1&amp;3&amp;2\\\\[1.1ex] 3&amp;8&amp;1\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"150\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Rumus matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita perlu menghitung determinan matriksnya terlebih dahulu, karena jika determinannya 0 berarti matriks tersebut tidak mempunyai invers.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eb7dc647f4121450eeadf2f5b62b4475_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{vmatrix}A\\end{vmatrix}=\\begin{vmatrix} 4&amp;5&amp;-1\\\\[1.1ex] -1&amp;3&amp;2\\\\[1.1ex] 3&amp;8&amp;1 \\end{vmatrix} = 12+30+8+9-64+5 = \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"389\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Penentu A adalah 0, <strong>sehingga matriksnya tidak dapat dibalik.<\/strong><\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\"> Latihan 5<\/h4>\n<p> Balikkan matriks persegi 3\u00d73 berikut dengan metode matriks determinan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-92e56e0f8013b6b65c0894a139537cae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix}1 &amp; 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 &amp; 0 \\\\[1.1ex] -1 &amp; -2 &amp; 2\\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"164\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Rumus matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Pertama-tama kita selesaikan determinan matriks dengan aturan Sarrus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-07f116ed906c31644ed0513667988e6f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\lvert A \\rvert = \\begin{vmatrix} 1 &amp; 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 &amp; 0 \\\\[1.1ex] -1 &amp; -2 &amp; 2 \\end{vmatrix} = 2+0-12-3-0+16 = 3\" title=\"Rendered by QuickLaTeX.com\" height=\"86\" width=\"392\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Penentunya berbeda dengan 0, sehingga matriks dapat diinversi.<\/p>\n<p class=\"has-text-align-left\"> Setelah determinannya terselesaikan, kita mencari matriks adjoint dari A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-20da2eac0d49b1134b39b1f5c95c5659_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 1} =  (-1)^{1+1} \\bm{\\cdot} \\begin{vmatrix}  1 &amp; 0 \\\\[1.1ex]  -2 &amp; 2 \\end{vmatrix} = 1 \\bm{\\cdot} (2-0) = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"377\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c5b80624f0963dfb1a111d96b4e1ceae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 4} =  (-1)^{1+2} \\bm{\\cdot} \\begin{vmatrix}  -2 &amp;  0 \\\\[1.1ex] -1 &amp; 2 \\end{vmatrix} = -1 \\bm{\\cdot} (-4-0) = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-50dd371e77d1896adb197321b68efd1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -3} = (-1)^{1+3} \\bm{\\cdot} \\begin{vmatrix} -2 &amp; 1 \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(4-(-1)\\bigr) = \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"427\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-60b779f4366a3ef38ae522fcfca8e7d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -2} =  (-1)^{2+1} \\bm{\\cdot} \\begin{vmatrix}  4 &amp; -3  \\\\[1.1ex]  -2 &amp; 2 \\end{vmatrix} = -1 \\bm{\\cdot} (8-6) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"424\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-51cb00c42e6932810a4220eb85c61acd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 1} = (-1)^{2+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp;  -3  \\\\[1.1ex] -1 &amp;  2 \\end{vmatrix} = 1 \\bm{\\cdot} (2-3) = \\bm{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"405\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3b26cbfa55d5567d2dae10c5dfbd158_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 0} =  (-1)^{2+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 4  \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} = -1 \\bm{\\cdot} \\bigl(-2-(-4)\\bigr) = \\bm{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"462\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d9f1bf4f5e01df910cd59bd4b25f816_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -1} = (-1)^{3+1} \\bm{\\cdot} \\begin{vmatrix}  4 &amp; -3 \\\\[1.1ex]  1 &amp; 0  \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(0-(-3)\\bigr) = \\bm{3}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"414\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ce129b17734facf076e48fb1928d0e1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de -2}   = (-1)^{3+2} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; -3 \\\\[1.1ex] -2 &amp; 0 \\end{vmatrix} = -1 \\cdot (0-6) = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"419\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3c8b319461dad7880bf2b9f20187b6fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\text{Adjunto de 2} =  (-1)^{3+3} \\bm{\\cdot} \\begin{vmatrix} 1 &amp; 4 \\\\[1.1ex] -2 &amp; 1 \\end{vmatrix} = 1 \\bm{\\cdot} \\bigl(1-(-8)\\bigr) = \\bm{9}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"408\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-748fcb9d9d2a8326379da4d2bd08534a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\displaystyle \\text{Adj}(A) = \\begin{pmatrix} 2 &amp; 4 &amp; 5 \\\\[1.1ex] -2 &amp; -1 &amp; -2 \\\\[1.1ex] 3 &amp; 6 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"206\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Setelah kita menghitung determinan matriks dan adjoinnya, kita substitusikan nilainya ke dalam rumus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1fe85ec6c4385daba7d2488b0d60ee2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{\\vert A \\vert } \\cdot \\Bigl( \\text{Adj}(A)\\Bigr)^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"175\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a0fc0e6effb520e22ff82c3034b4d4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} 2 &amp; 4 &amp; 5 \\\\[1.1ex] -2 &amp; -1 &amp; -2 \\\\[1.1ex] 3 &amp; 6 &amp; 9\\end{pmatrix}^{\\bm{t}}\" title=\"Rendered by QuickLaTeX.com\" height=\"89\" width=\"215\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengubah urutan matriks terlampir:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bba6ddbc8ab9f2c64eb03cdb9fea530a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\cfrac{1}{3} \\cdot \\begin{pmatrix} 2 &amp; -2 &amp; 3 \\\\[1.1ex] 4 &amp; -1 &amp; 6 \\\\[1.1ex] 5 &amp; -2 &amp; 9 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"178\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan akhirnya, kami mengoperasikan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41f999c23e7d5ce129b410b9f486983e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1} = \\begin{pmatrix} \\sfrac{2}{3} &amp; \\sfrac{-2}{3} &amp; \\sfrac{3}{3} \\\\[1.1ex] \\sfrac{4}{3} &amp; \\sfrac{-1}{3} &amp; \\sfrac{6}{3} \\\\[1.1ex] \\sfrac{5}{3} &amp; \\sfrac{-2}{3} &amp; \\sfrac{9}{3} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"181\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-inverse-par-matrice-adjointe-33.webp\" alt=\"latihan diselesaikan langkah demi langkah matriks invers dengan metode matriks adjoint 3x3\" width=\"232\" height=\"104\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"> Balikkan matriks menggunakan metode Gauss:<\/h2>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<p> Untuk <strong>menghitung invers suatu matriks dengan metode Gauss<\/strong> , <strong>Anda harus melakukan operasi pada baris-baris matriks<\/strong> (kita akan melihatnya nanti). Jadi sebelum melihat cara menggunakan metode Gauss, penting bagi Anda untuk mengetahui semua operasi yang dapat dilakukan pada baris matriks:<\/p>\n<h3 class=\"wp-block-heading\"> Transformasi garis diperbolehkan dalam metode Gaussian<\/h3>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Mengubah urutan<\/span><\/strong> baris matriks.<\/li>\n<\/ul>\n<p> Misalnya, kita dapat mengubah urutan baris 2 dan 3 suatu matriks:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1d3f607625afb96bfb250168bd330818_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} 3 &amp; 5 &amp; -2 \\\\[2ex] -2 &amp; 4 &amp; -1  \\\\[2ex] 6 &amp; 1 &amp; -3 \\end{array} \\right)  \\begin{array}{c} \\\\[2ex] \\xrightarrow{ f_2 \\rightarrow f_3}} \\\\[2ex] \\xrightarrow{ f_3 \\rightarrow f_2}} \\end{array} \\left( \\begin{array}{ccc} 3 &amp; 5 &amp; -2  \\\\[2ex] 6 &amp; 1 &amp; -3  \\\\[2ex] -2 &amp; 4 &amp; -1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"331\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Kalikan atau bagi<\/span><\/strong> semua suku dalam satu baris dengan angka selain 0.<\/li>\n<\/ul>\n<p> Misalnya, kita mengalikan baris 1 dengan 4 dan membagi baris 3 dengan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cca4df71c23b1f005068a0a93b77dfe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} 1 &amp; -2 &amp; 3 \\\\[2ex] 3 &amp; -1 &amp; 5  \\\\[2ex] 2 &amp; -4 &amp; -2  \\end{array} \\right) \\begin{array}{c}  \\xrightarrow{4  f_1} \\\\[2ex]  \\\\[2ex] \\xrightarrow{ f_3 \/ 2} \\end{array} \\left( \\begin{array}{ccc} 4 &amp; -8 &amp; 12 \\\\[2ex] 3 &amp; -1 &amp; 5  \\\\[2ex] 1 &amp; -2 &amp; -1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"103\" width=\"318\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong><span style=\"color:#1976d2;\">Ganti sebuah baris<\/span><\/strong> dengan jumlah baris yang sama ditambah baris lainnya dikalikan dengan sebuah angka.<\/li>\n<\/ul>\n<p> Misalnya, pada matriks berikut, kita menambahkan baris 3 dikalikan 1 ke baris 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ca6644f015dd42ddbf4ab159bd10dec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc} -1 &amp; -3 &amp; 4  \\\\[2ex] 2 &amp; 4 &amp; 1  \\\\[2ex] 1 &amp; -2 &amp; 3  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex]  \\xrightarrow{f_2 + 1\\cdot f_3}  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc} -1 &amp; -3 &amp; 4  \\\\[2ex] 3 &amp; 2 &amp; 4  \\\\[2ex] 1 &amp; -2 &amp; 3  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"339\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"> Contoh penghitungan matriks invers menggunakan metode Gauss:<\/h3>\n<p> Mari kita lihat dengan contoh bagaimana menerapkan <strong>metode Gauss<\/strong> untuk membalikkan matriks:<\/p>\n<ul>\n<li> Hitung invers matriks berikut:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-71553480cefa679dcb8eb98d97e0c717_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\left( \\begin{array}{ccc} 1 &amp; 0 &amp; 1 \\\\[2ex] 0 &amp; 2 &amp; 1 \\\\[2ex] 1 &amp; 5 &amp; 4 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Hal pertama yang perlu kita lakukan adalah menggabungkan <strong>matriks A dan matriks Identitas menjadi satu matriks<\/strong> . Matriks A di sebelah kiri dan matriks Identitas di sebelah kanan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d0650812fe7946f6da1e7973709dfde1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle   \\bigl( A \\  \\lvert \\ I \\bigr)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"51\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-inverse-par-la-methode-de-gauss-32153.webp\" alt=\"latihan diselesaikan langkah demi langkah matriks invers dengan metode 3x3 Gauss\" width=\"203\" height=\"120\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-background\" style=\"background-color:#dff6ff\"> Untuk menghitung matriks invers, kita perlu <strong>mengubah matriks kiri menjadi matriks identitas.<\/strong> Dan, untuk melakukan itu, kita perlu menerapkan transformasi pada baris hingga kita mencapainya.<\/p>\n<p> Kita akan melanjutkan per kolom, artinya kita akan melakukan operasi pada baris untuk terlebih dahulu mengubah angka-angka di kolom pertama, lalu angka-angka di kolom kedua, dan terakhir angka-angka di kolom ketiga. <\/p>\n<div class=\"wp-block-columns is-layout-flex wp-container-35\">\n<div class=\"wp-block-column is-layout-flow\" style=\"flex-basis:66.66%\">\n<p class=\"has-text-align-justify\"> Angka 1 dan 0 pada kolom pertama sudah sesuai, karena matriks identitas juga mempunyai angka 1 dan 0 pada posisi tersebut. Oleh karena itu, transformasi pada baris ini tidak perlu diterapkan saat ini. <\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\" style=\"flex-basis:33.33%\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7f51b3a869dde9c1697be9e57fce1548_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} \\color{blue}\\boxed{\\color{black}1} &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] \\color{blue}\\boxed{\\color{black}0} &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"101\" width=\"255\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<\/div>\n<\/div>\n<p> Namun, matriks identitas mempunyai 0 pada elemen terakhir kolom pertama, dimana kita sekarang mempunyai 1. Jadi kita perlu mengubah 1 menjadi 0. Untuk melakukannya, <strong>kita menambahkan baris 1 dikalikan \u2013 ke baris 3.1 :<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-30b5442d5c5eac3e62aa7a7cae717e48_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rrr}  &amp; 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1  \\\\ + &amp; -1 &amp; 0 &amp; -1 &amp; -1 &amp; 0 &amp; 0  \\\\ \\hline  &amp; 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -f_1} \\\\ \\phantom{hline} \\\\ \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"68\" width=\"313\" style=\"vertical-align: -29px;\"><\/p>\n<\/p>\n<p> Jadi jika kita melakukan penjumlahan ini, kita akan mendapatkan matriks berikut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-992a31603c2182a97d31ddf787df4f06_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c}   \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 - f_1} \\end{array} \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] \\color{blue}\\boxed{\\color{black}0} &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"520\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Kami telah berhasil mengubah 1 menjadi 0.<\/p>\n<p> Sekarang mari kita beralih ke kolom kedua dari matriks kiri. Elemen pertama adalah 0, yang bagus karena matriks identitas memiliki 0 pada posisi yang sama. Namun, bukannya 2 yang seharusnya ada adalah 1, <strong>jadi kita bagi baris kedua dengan 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a86b61ee601f9cd0ff9a70d1a280f887_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 2 &amp; 1 &amp; 0 &amp; 1 &amp; 0  \\\\[2ex] 1 &amp; 5 &amp; 4 &amp;0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\xrightarrow{f_2\/2}\\\\[2ex] &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; \\color{blue}\\boxed{\\color{black}1} &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex] 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"527\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Selain itu, pada kolom kedua kita juga perlu mengubah angka 5 menjadi 0. Nah, karena angka 5 lima kali lebih besar dari angka 1 pada baris kedua, <strong>kita akan menambahkan baris 2 dikalikan -5 ke baris 3:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66dd50ad7ec5e4c45f5011094a0c21b3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rrr}  &amp; 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\\\ + &amp; 0 &amp; -5 &amp; \\sfrac{-5}{2} &amp; 0 &amp; \\vphantom{\\Bigl(}\\sfrac{-5}{2} &amp; 0  \\\\ \\hline &amp; 0 &amp; 0 &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2} \\vphantom{\\Bigl(} &amp; 1  \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -5f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(}  \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"355\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p> Oleh karena itu, dengan melakukan operasi ini, kita mendapatkan matriks dengan 0 pada elemen terakhir kolom kedua:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fcc790f05d73d308cb7d992841ab031a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex] 0 &amp; 5 &amp; 3 &amp; -1 &amp; 0 &amp; 1  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\\\[2ex] \\xrightarrow{f_3 - 5f_2} \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; \\color{blue}\\boxed{\\color{black}0} &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2}  &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"590\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Terakhir, kita akan mengubah kolom terakhir matriks ke kiri, namun kali ini kita harus memulai dari bawah. Oleh karena itu perlu adanya transformasi<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> menjadi 1. Oleh karena itu, <strong>baris terakhir kita kalikan dengan 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-69614cae4dd388b6454ffd9b8d63c9a5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  \\sfrac{1}{2}  &amp; -1 &amp; \\sfrac{-5}{2}  &amp; 1  \\end{array} \\right)\\begin{array}{c}   \\\\[2ex] \\\\[2ex] \\xrightarrow{2f_3} \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  \\color{blue}\\boxed{\\color{black}1}  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"562\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Kita sekarang harus mentransformasikannya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> sisa kolom terakhir adalah 0. Namun, kali ini kita tidak dapat mengalikan baris tersebut dengan 2, karena kita juga akan mengubah 1 menjadi 2 (bila matriks identitas mempunyai angka 1 pada posisi tersebut). Oleh karena itu, <strong>kami akan menambahkan baris 3 dibagi -2 ke baris 2:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-881f9ea3ce2e52ddf332a13aba43bbcf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr}  &amp; 0 &amp; 1 &amp;  \\vphantom{\\Bigl(} \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\ + &amp; 0 &amp; 0 &amp;\\vphantom{\\Bigl(} -\\sfrac{1}{2}  &amp; 1 &amp; \\sfrac{5}{2}  &amp; -1  \\\\ \\hline &amp; 0 &amp; 1 &amp; 0\\phantom{0}  &amp; 1 &amp; 3 \\vphantom{\\Bigl(} &amp; -1  \\end{array} \\begin{array}{l}\\vphantom{\\Bigl(} \\color{blue}\\bm{\\leftarrow f_2} \\\\ \\color{blue}\\bm{\\leftarrow f_3\/(-2)}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(}  \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"357\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p> Jadi dengan melakukan operasi ini kami berhasil mengubah<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b05f3ca9cc1227bdfe634ccc9f60935_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> dalam 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-537958a51f67c7602ef121fa2c997ca8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{1}{2} &amp; 0 &amp; \\sfrac{1}{2} &amp; 0  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right) \\begin{array}{c}   \\\\[2ex] \\xrightarrow{f_2-f_3\/2} \\\\[2ex] &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\color{blue}\\boxed{\\color{black}0} &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"100\" width=\"598\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Terakhir, kita hanya perlu mengubah angka 1 di baris pertama kolom ketiga menjadi 0. Baris ketiga juga memiliki angka 1 di kolom yang sama, <strong>jadi kita akan menambahkan baris 3 dikalikan -1 ke baris 1:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8854a556147caefb16a2030e0e5e949a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr}  &amp; 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\ + &amp; 0 &amp; 0 &amp;  -1  &amp; 2 &amp; 5  &amp; -2  \\\\ \\hline &amp; 1 &amp; 0 &amp; 0  &amp; 3 &amp; 5 &amp; -2  \\end{array} \\begin{array}{l}\\color{blue}\\bm{\\leftarrow f_1} \\\\ \\color{blue}\\bm{\\leftarrow -f_3}\\\\ \\phantom{hline}   \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"68\" width=\"300\" style=\"vertical-align: -29px;\"><\/p>\n<\/p>\n<p> Dan dengan melakukan operasi ini kami berhasil mengubah angka 1 menjadi 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ddd39df6bc92258ba163c65de4fd59f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\ \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp;0 &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1-f_3}  \\\\[2ex]  \\\\[2ex]  &amp; \\end{array}  \\left(  \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; \\color{blue}\\boxed{\\color{black}0}  &amp; 3 &amp; 5 &amp; -2  \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; 1 &amp; 3  &amp; -1  \\\\[2ex]  0 &amp; 0 &amp;  1  &amp; -2 &amp; -5  &amp; 2  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"99\" width=\"589\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Setelah kita berhasil mengubah matriks kiri menjadi matriks identitas, kita juga mengetahui matriks inversnya. Karena <strong>invers matriks adalah matriks yang kita peroleh di ruas kanan dengan cara mengubah matriks kiri menjadi matriks identitas<\/strong> . Oleh karena itu, kebalikan dari matriks tersebut adalah: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exemple-de-matrice-inverse-32153.webp\" alt=\"Contoh matriks invers 3x3\" width=\"251\" height=\"117\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h3 class=\"wp-block-heading\"> Menyelesaikan latihan matriks invers dengan metode Gauss <\/h3>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-118\"><\/div>\n<\/div>\n<h4 class=\"wp-block-heading\"> Latihan 1<\/h4>\n<p> Balikkan matriks berikut melalui metode Gauss: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36886e1ab1007f9a53bdc0dd71a0d15b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 2 \\\\[1.1ex] 1 &amp; 3  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Hal pertama yang perlu kita lakukan adalah menggabungkan matriks A dan matriks Identitas menjadi satu matriks. Matriks A di sebelah kiri dan matriks identitas di sebelah kanan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercice-resolu-matrice-de-gauss-inverse-22152.webp\" alt=\"menyelesaikan latihan matriks invers dengan metode 2x2 Gauss\" width=\"143\" height=\"66\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Sekarang, untuk menghitung matriks invers, kita perlu mengubah matriks sisi kiri menjadi matriks identitas. Dan, untuk melakukan itu, kita perlu menerapkan transformasi pada baris hingga kita mencapainya.<\/p>\n<p class=\"has-text-align-left\"> Suku pertama semuanya, 1, sudah sama dengan matriks identitas. Oleh karena itu, saat ini tidak perlu menerapkan transformasi pada baris pertama.<\/p>\n<p class=\"has-text-align-left\"> Akan tetapi, matriks identitasnya mempunyai angka 0 pada elemen terakhir kolom pertama, dimana sekarang kita mempunyai angka 1. Oleh karena itu, kita perlu mengubah angka 1 menjadi 0. Untuk melakukannya, kita kurangi baris 1 dari baris 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-247d8605795c43e79b5d7742854cfe6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{cc|cc}1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 1 &amp; 3 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\\\[1.5ex] \\xrightarrow{f_2 - f_1}  \\end{array} \\left( \\begin{array}{cc|cc} 1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1\\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"56\" width=\"332\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita beralih ke kolom kedua: 1 di bawah sudah bagus. Namun tidak dengan angka 2 di atas, karena matriks identitas mempunyai angka 0 pada posisi tersebut. Oleh karena itu, untuk mengubah 2 menjadi 0, dari baris 1 kita kurangi baris 2 dikalikan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-173a7bdb55ba058e5ae16d1fd8e91564_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{cc|cc} 1 &amp; 2 &amp; 1 &amp; 0 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1 \\end{array} \\right) \\begin{array}{c}  \\xrightarrow{f_1 - 2f_2} \\\\[1.5ex] &amp; \\end{array} \\left( \\begin{array}{cc|cc} 1 &amp; 0 &amp; 3 &amp; -2 \\\\[1.5ex] 0 &amp; 1 &amp; -1 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"57\" width=\"367\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks invers adalah matriks yang kita peroleh di ruas kanan setelah mengubah matriks di sebelah kiri menjadi matriks identitas. Dan sekarang kita mendapatkan matriks identitas di sisi kiri. Oleh karena itu, matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-98896d28465c9e1402e1c443375d93fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left(} \\begin{array}{cc}  \\bm{3} &amp; \\bm{-2} \\\\[1.5ex]  \\bm{-1} &amp; \\bm{1} \\end{array}\\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"157\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 2<\/h4>\n<p> Balikkan matriks berikut dengan prosedur Gaussian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7ae5ba4a92a5ddc00ddf5b11775edafd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 1 &amp; -4 \\\\[1.1ex]  0 &amp; 3 &amp; 2 \\\\[1.1ex] 0 &amp; 1 &amp; 1  \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita letakkan matriks A dan matriks Identitas ke dalam satu matriks: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-81db2ef94d2db597cebb4c0c77685526_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 3 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"186\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita perlu mentransformasikan baris-baris tersebut sampai kita mengubah matriks kiri menjadi matriks identitas.<\/p>\n<p class=\"has-text-align-left\"> Kolom pertama matriks kiri sudah sama dengan kolom pertama matriks identitas. Oleh karena itu, tidak perlu mengubah nomor apa pun.<\/p>\n<p class=\"has-text-align-left\"> Akan tetapi, matriks identitas mempunyai angka 1 pada elemen kedua kolom kedua, dimana sekarang terdapat angka 3. Oleh karena itu, kita harus mengubah angka 3 menjadi angka 1. Untuk melakukannya, dari baris 2 kita kurangi baris 3 dikalikan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bfd7cb4d4b81a75038807eb28393a83e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 3 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2 - 2f_3} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; 4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"458\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai angka 0 pada elemen terakhir kolom kedua, dimana sekarang terdapat angka 1. Oleh karena itu, kita harus mengubah angka 1 menjadi 0. Untuk melakukannya, kita kurangi baris 2 dari baris 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-932479e2f574c19ad7906d3d20e52ad0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 1 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 - f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"492\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai 0 pada elemen pertama kolom kedua, dimana sekarang terdapat 1. Oleh karena itu, kita harus mengubah 1 menjadi 0. Untuk melakukannya, kita kurangi baris 2 dari baris 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-566e1453aab03f9792cb281e4c88a68c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 1 &amp; -4 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 - f_2} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; -4 &amp; 1 &amp; -1 &amp; 2 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"506\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Yang harus kita lakukan sekarang adalah mengubah -4 menjadi 0. Untuk melakukannya, kita menambahkan baris 3 dikalikan 4 ke baris 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f98a9cabeb101602dd11aa73516b998_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; -4 &amp; 1 &amp; -1 &amp; 2 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3\\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 + 4f_3} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 0 &amp; 1 &amp; -5 &amp; 14 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; -2 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; 0 &amp; -1 &amp; 3 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita telah memperoleh matriks identitas dari sisi kiri. Oleh karena itu, matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e43ce6a7061f0339bd5d44b83afec07f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{1} &amp; \\bm{-5}  &amp; \\bm{14} \\\\[2ex]  \\bm{0} &amp; \\bm{1} &amp; \\bm{-2} \\\\[2ex] \\bm{0} &amp; \\bm{-1 }&amp; \\bm{3} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"185\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 3<\/h4>\n<p> Balikkan matriks berikut menggunakan metode Gaussian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f02b0186690e68baaa9a630db2c870db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; 2 &amp; 1 \\\\[1.1ex]  0 &amp; 1 &amp; 0 \\\\[1.1ex] 2 &amp; 0 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Sebelum kita mulai beroperasi, kita perlu meletakkan matriks A dan matriks Identitas ke dalam satu matriks: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa6dc5af82076e22b1d0cf7ea16d748b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 2 &amp; 0 &amp; 3 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"172\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita harus mengubah matriks kiri menjadi matriks identitas dengan mengoperasikan baris-barisnya.<\/p>\n<p class=\"has-text-align-left\"> Dua elemen pertama pada kolom pertama sudah sama dengan matriks identitas. Oleh karena itu, angka-angka ini tidak perlu diubah.<\/p>\n<p class=\"has-text-align-left\"> Namun matriks identitas mempunyai angka 0 pada elemen ketiga kolom pertama, dimana sekarang terdapat angka 2. Oleh karena itu, kita harus mengubah angka 2 menjadi angka 0. Untuk melakukannya, dari baris 3 kita kurangi baris 1 dikalikan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-680a314b8cc900e01886291af12145e4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 2 &amp; 0 &amp; 3 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\\\[2ex] \\xrightarrow{f_3 - 2f_1}   \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"458\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai 0 pada elemen pertama kolom kedua, dimana sekarang terdapat 2. Oleh karena itu, kita harus mengubah 2 menjadi 0. Untuk melakukannya, dari baris 1 kita kurangi baris 2 dikalikan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f87cbc594287f7ea4938091878562b4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 2 &amp; 1 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 -2f_2} \\\\[2ex]  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai angka 0 pada elemen terakhir kolom kedua, yang sekarang menjadi -4. Oleh karena itu kita harus mengubah -4 menjadi 0. Untuk melakukannya, kita menambahkan baris 2 dikalikan 4 ke baris 3:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b8cf2c3878d2d35656953a55bb3baf94_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; -4 &amp; 1 &amp; -2 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 +4f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"499\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Yang harus kita lakukan sekarang adalah mengubah elemen pertama kolom ketiga menjadi 0. Untuk melakukannya, kita menambahkan baris 3 dikalikan -1 ke baris 1:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aac851b05c2dc25af3d7b9ecc622c9f6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 1 &amp; 1 &amp; -2 &amp; 0\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 - f_3} \\\\[2ex]  \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 0 &amp; 3 &amp; -6  &amp; -1\\\\[2ex]  0 &amp; 1 &amp; 0 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; -2 &amp; 4 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"492\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita telah menyadari bahwa matriks di sebelah kiri adalah matriks identitas. Jadi kebalikan dari matriks tersebut<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> Timur:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-161fbe4a4d4dcc4fc503b6e3a9e0bfeb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{3} &amp; \\bm{-6}  &amp; \\bm{-1} \\\\[2ex]  \\bm{0} &amp; \\bm{1} &amp; \\bm{0} \\\\[2ex] \\bm{-2} &amp; \\bm{4}&amp; \\bm{1} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 4<\/h4>\n<p> Balikkan matriks berikut menggunakan metode Gaussian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-47ad7ccd6aafab72255c96f2bc9148a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 1 &amp; -2 &amp; 0 \\\\[1.1ex]  1 &amp; 2 &amp; 2 \\\\[1.1ex] 0 &amp; 3 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"85\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Hal pertama yang perlu kita lakukan adalah menggabungkan matriks A dan matriks Identitas menjadi satu matriks: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cbeb2e5edb9eaf9e47efc4cc74b1333_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\left( A \\ | \\ I \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"51\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a832ceb9f09dfa88238c570b46b74d92_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 1 &amp; 2 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"186\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita harus mengubah matriks di sisi kiri menjadi matriks identitas dengan menerapkan operasi baris.<\/p>\n<p class=\"has-text-align-left\"> Elemen pertama kolom pertama sudah sama dengan matriks identitas. Oleh karena itu, tidak perlu mengubahnya.<\/p>\n<p class=\"has-text-align-left\"> Namun, matriks identitas memiliki 0 pada elemen kedua kolom pertama, yang sekarang terdapat 1. Oleh karena itu, kita harus mengubah 1 menjadi 0. Untuk melakukannya, kita kurangi baris 1 dari baris 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-83933b5a2315a4dcbc770bf92bf3831b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 1 &amp; 2 &amp; 2 &amp; 0 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2 - f_1} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 4 &amp; 2 &amp; -1 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"465\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita beralih ke kolom kedua: pertama-tama kita ubah angka 4 menjadi angka 1 dengan membagi baris kedua dengan 4:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-298984c72a249e2b5c98740cc0c1a11e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 4 &amp; 2 &amp; -1 &amp; 1 &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2\/4} \\\\[2ex] &amp;  \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"495\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai angka 0 pada elemen pertama kolom kedua, yang sekarang menjadi -2. Oleh karena itu kita harus mengubah -2 menjadi 0. Untuk melakukannya, kita menambahkan baris 2 dikalikan 2 ke baris 1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ce876446d5d01a152e39480d69affd8c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr} &amp; 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\ + &amp; 0 &amp; 2 &amp; 1 &amp; \\vphantom{\\Bigl(}\\sfrac{-2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\ \\hline &amp; 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} \\vphantom{\\Bigl(}&amp; 0 \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_1} \\\\ \\color{blue}\\bm{\\leftarrow 2f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"313\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3dfcdcb586eed87861b3ac0ea46bea2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; -2 &amp; 0 &amp; 1 &amp; 0 &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1\\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1 +2f_2} \\\\[2ex]  \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"525\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai angka 0 pada elemen terakhir kolom kedua, dimana sekarang terdapat angka 3. Oleh karena itu, kita harus mengubah angka 3 menjadi angka 0. Untuk melakukannya, dari baris 3 kita kurangi baris 2 dikalikan 3: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-210ca8df473a00d9f205470ed2aa19a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|crr} &amp; 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0\\phantom{0} &amp; 1 \\\\ + &amp; 0 &amp; -3 &amp; \\vphantom{\\Bigl(}\\sfrac{-6}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 0 \\\\ \\hline &amp; 0 &amp; 0 &amp; \\vphantom{\\Bigl(}\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1 \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_3} \\\\ \\color{blue}\\bm{\\leftarrow -3f_2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"88\" width=\"350\" style=\"vertical-align: -39px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-94ed5a1b9cf1db0bfb99ce79d0a6d36b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 3 &amp; 2 &amp; 0 &amp; 0 &amp; 1 \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{f_3 -3f_2} \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp;\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1  \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"525\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita beralih ke kolom ketiga: kita harus mengubah kolom terakhir<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd7d08f65ca5dd13d94128372d3b6c95_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{2}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: 0px;\"><\/p>\n<p> menjadi 1. Untuk melakukannya, kita kalikan baris ketiga dengan 2:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a8134938726d3b48fe3d7d789260b128_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp;\\sfrac{2}{4} &amp; \\sfrac{3}{4} &amp; \\sfrac{-3}{4} &amp; 1   \\end{array} \\right) \\begin{array}{c} \\\\[2ex]  \\\\[2ex] \\xrightarrow{2f_3 } \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"515\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Matriks identitas mempunyai angka 0 pada elemen kedua kolom terakhir. Oleh karena itu, perlu dilakukan konversi<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cd7d08f65ca5dd13d94128372d3b6c95_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sfrac{2}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: 0px;\"><\/p>\n<p> menjadi 0. Untuk melakukan ini, dari baris 2 kita kurangi baris 3 dibagi 2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc74ebe003751fd9ae3a5a77b2f589c8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|ccr} &amp; 0 &amp; 1 &amp; \\vphantom{\\Bigl(} \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\ + &amp; 0 &amp; 0 &amp; \\vphantom{\\Bigl(} \\sfrac{-1}{2} &amp; \\sfrac{-6}{8} &amp; \\sfrac{6}{8} &amp; -1  \\\\ \\hline &amp; 0 &amp; 1 &amp; 0\\phantom{0} &amp; -1 &amp; 1 &amp; -1\\vphantom{\\Bigl(} \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_2}\\vphantom{\\Bigl(}  \\\\ \\color{blue}\\bm{\\leftarrow -f_3\/2}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"358\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b91b71183a50e41e9be5c7305f8cf3e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{-1}{4} &amp; \\sfrac{1}{4} &amp; 0 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2 \\end{array} \\right) \\begin{array}{c} \\\\[2ex] \\xrightarrow{f_2-f_3\/2 } \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"542\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Yang harus kita lakukan sekarang adalah mengubah elemen pertama kolom ketiga menjadi 0. Untuk melakukannya, kita kurangi baris 3 dari baris 1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-38796ed093a0fef52426fb5559931586_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{lrrr|rcr} &amp; 1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\vphantom{\\Bigl(} \\\\ + &amp; 0 &amp; 0 &amp; -1 &amp; \\sfrac{-6}{4} &amp; \\sfrac{6}{4} &amp; -2 \\vphantom{\\Bigl(}  \\\\ \\hline &amp; 1 &amp; 0 &amp; 0 &amp; -1 &amp; 2 &amp; -2 \\vphantom{\\Bigl(} \\end{array} \\begin{array}{l} \\color{blue}\\bm{\\leftarrow f_1}\\vphantom{\\Bigl(}  \\\\ \\color{blue}\\bm{\\leftarrow -f_3}\\vphantom{\\Bigl(} \\\\ \\phantom{hline} \\vphantom{\\Bigl(} \\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"332\" style=\"vertical-align: -44px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2023374b9885dd33fe4d3c12e5a4de59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left( \\begin{array}{ccc|ccc}1 &amp; 0 &amp; 1 &amp; \\sfrac{2}{4} &amp; \\sfrac{2}{4} &amp; 0 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2 \\end{array} \\right) \\begin{array}{c} \\xrightarrow{f_1-f_3 }  \\\\[2ex] \\\\[2ex] &amp; \\end{array} \\left( \\begin{array}{ccc|ccc} 1 &amp; 0 &amp; 0 &amp; -1 &amp; 2 &amp; -2 \\\\[2ex] 0 &amp; 1 &amp; 0 &amp; -1 &amp; 1 &amp; -1 \\\\[2ex] 0 &amp; 0 &amp; 1 &amp; \\sfrac{6}{4} &amp; \\sfrac{-6}{4} &amp; 2   \\end{array} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"98\" width=\"524\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, matriks inversnya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0854e7cb80ba561b6e0c724a9a9b5fff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A^{-1}= \\left(  \\begin{array}{ccc}  -1  &amp; 2 &amp; -2 \\\\[2ex]  -1 &amp; 1 &amp; -1 \\\\[2ex] \\sfrac{6}{4} &amp;\\sfrac{-6}{4} &amp; 2 \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"207\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Akhirnya, pecahan dari matriks invers dapat disederhanakan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6c7ef6b6cdca2f4a808ed9457bde3b3f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{A^{-1}= \\left( } \\begin{array}{ccc}  \\bm{-1} &amp; \\bm{2}  &amp; \\bm{-2} \\\\[2ex]  \\bm{-1} &amp; \\bm{1} &amp; \\bm{-1} \\\\[2ex] \\sfrac{\\bm{3}}{\\bm{2}} &amp;\\sfrac{\\bm{-3}}{\\bm{2}} &amp; \\bm{2} \\end{array} \\bm{ \\right)}\" title=\"Rendered by QuickLaTeX.com\" height=\"96\" width=\"207\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-119\"><\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"> Properti Matriks Terbalik<\/h2>\n<p> Matriks invers mempunyai ciri-ciri sebagai berikut:<\/p>\n<ul>\n<li> Kebalikan suatu matriks adalah <span style=\"color:#1976d2;\"><strong>unik<\/strong><\/span> .<\/li>\n<\/ul>\n<ul>\n<li> <span style=\"color:#1976d2;\"><strong>Invers matriks invers<\/strong><\/span> adalah matriks asal:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-caac2cfeece17b627e46c7ec04020319_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A^{-1}\\right)^{-1} = A\" title=\"Rendered by QuickLaTeX.com\" height=\"26\" width=\"101\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> <span style=\"color:#1976d2;\"><strong>Invers perkalian<\/strong><\/span> dua matriks sama dengan hasil kali invers matriks-matriks tersebut, tetapi ordenya berubah.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8f0dd4094bdc2faa4449008d1d8ee8c9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A \\cdot B)^{-1} = B^{-1} \\cdot A^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"171\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> <span style=\"color:#1976d2;\"><strong>Transposisi suatu matriks<\/strong><\/span> kemudian melakukan invers matriks sama seperti melakukan inversi matriks terlebih dahulu kemudian melakukan transposisi.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2dc6d83dd3d9b9dacec6e7806c9c0e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left(A^t\\right)^{-1} = \\left(A^{-1}\\right)^{t}\" title=\"Rendered by QuickLaTeX.com\" height=\"26\" width=\"128\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<ul>\n<li> Untuk menyelesaikan <span style=\"color:#1976d2;\"><strong>determinan invers suatu matriks<\/strong><\/span> kita dapat menghitung determinan matriks tersebut kemudian melakukan inversnya, karena kedua operasi tersebut memberikan hasil yang sama.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e32fcd8a6c25d8c863947e6cc31efdc6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle det\\left(A^{-1}\\right) =\\bigl( det(A) \\bigr) ^{-1} = \\cfrac{1}{det(A)}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"261\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"> Rumus untuk menghitung invers matriks 2&#215;2 dengan cepat<\/h2>\n<p> Seperti yang telah kita lihat, matriks apa pun dapat dibalik dengan metode determinan atau metode Gauss. Namun secara terpisah, ada juga <strong>rumus untuk mencari invers matriks 2\u00d72 dengan sangat cepat<\/strong> : <\/p>\n<div class=\"wp-block-image estil_requadre_foto\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/formule-de-matrice-inverse-22152.webp\" alt=\"rumus mencari invers matriks 2x2, rumus invers matriks 2x2\" class=\"wp-image-673\" width=\"475\" height=\"75\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Seperti yang Anda lihat, membalikkan matriks 2&#215;2 itu sederhana: cukup selesaikan determinan matriksnya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3c046b53b17b87e9ca0f447d664754ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(|A|)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"35\" style=\"vertical-align: -5px;\"><\/p>\n<p> , mengganti posisi elemen-elemen diagonal utama, dan mengubah tanda elemen-elemen diagonal sekunder.<\/p>\n<h3 class=\"wp-block-heading\"> Contoh cara mendapatkan matriks invers 2\u00d72 dengan rumusnya<\/h3>\n<div class=\"adsb30\" style=\" margin:px; text-align:\"><\/div>\n<p> Hitung invers matriks persegi 2 \u00d7 2 berikut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-599baee27c05b5610a8714363e1260eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A = \\begin{pmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Penentu matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ab99f7b87d01c670a8598df6364ab58f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{vmatrix} &amp; = 3 \\cdot (-4)- (-2) \\cdot 5 \\\\ &amp; = -12-(-10) \\\\[2ex] &amp; =-12+10\\\\[2ex] &amp;=-2\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"281\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Sekarang kita terapkan <strong>rumus matriks invers<\/strong> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-68fd6e830b576af8abf55be1e11fbafb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} 3 &amp; 5 \\\\[1.1ex] -2 &amp; -4 \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{-2} \\begin{pmatrix} -4 &amp; -5 \\\\[1.1ex] 2 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"333\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Dan kita mengalikan matriks dengan pecahan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-41da8ef6bef1d339337717ed4ad86ae5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} =\\begin{pmatrix} \\cfrac{-4}{-2} &amp; \\cfrac{-5}{-2} \\\\[3ex] \\cfrac{2}{-2} &amp; \\cfrac{3}{-2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Oleh karena itu, matriks A yang terbalik adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-29da2a64f6da927857de112ca8363ba5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{2} &amp; \\cfrac{\\bm{5}}{\\bm{2}} \\\\[3ex] \\bm{-1} &amp; \\bm{-}\\cfrac{\\bm{3}}{\\bm{2}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"143\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Seperti yang Anda lihat, membalikkan matriks dengan rumus ini jauh lebih cepat, tetapi hanya dapat digunakan pada matriks berdimensi 2&#215;2.<\/p>\n<h3 class=\"wp-block-heading\"> Soal soal matriks invers 2\u00d72 dengan rumus<\/h3>\n<h4 class=\"wp-block-heading\"> Latihan 1<\/h4>\n<p> Balikkan matriks berdimensi 2\u00d72 berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dc06e21fc1c3c54f9b3fc0dcd4912a8f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Penentu matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1b0ae510ea7a336cbe5ea56a554da719_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{vmatrix} &amp; = 2 \\cdot 3- 1 \\cdot 5 \\\\ &amp; = 6-5 \\\\[2ex] &amp; =1\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"118\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita terapkan rumus untuk mencari matriks invers: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b8f18178c829fd38360a04a947d52017_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 2 &amp; 5 \\\\[1.1ex] 1 &amp; 3 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{1} \\begin{pmatrix} 3 &amp; -5 \\\\[1.1ex] -1 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"292\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, invers matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-237fe82cd91972f667f6751fa4735534_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{3} &amp; \\bm{-5} \\\\[1.1ex] \\bm{-1} &amp; \\bm{2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"139\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 2<\/h4>\n<p> Hitung invers matriks orde 2 berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f2289d1c5c9aeb87016f719305d900a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"122\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Penentu matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3fef2cc00702131123994cc588bf7ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{vmatrix} &amp; = 2 \\cdot (-2)- (-1) \\cdot 6 \\\\ &amp; = -4-(-6) \\\\[2ex] &amp; =-4+6 \\\\[2ex] &amp; =2\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"282\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita terapkan rumus untuk menyelesaikan matriks invers berdimensi 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2de7166a0cf59e0f8c5b7750e1947f04_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 2 &amp; 6 \\\\[1.1ex] -1 &amp; -2 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{2} \\begin{pmatrix} -2 &amp; -6 \\\\[1.1ex] 1 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"319\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kita melakukan perkalian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6a5973078468914beb4bd4d85a40331_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{-2}{2} &amp; \\cfrac{-6}{2} \\\\[3ex] \\cfrac{1}{2} &amp; \\cfrac{2}{2} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"163\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a540a077ee9a24da96fa988410aef429_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{-1} &amp; \\bm{-3} \\\\[2ex] \\cfrac{\\bm{1}}{\\bm{2}} &amp; \\bm{1} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"141\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 3<\/h4>\n<p> Balikkan matriks 2&#215;2 berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36e230a808c42411a9cfd2d9eb44543d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"95\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Penentu matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e7a6c5ef316ae51b43c90863c6245780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2\\end{vmatrix} &amp; = 4 \\cdot 2 - 5 \\cdot 1 \\\\ &amp; = 8-5 \\\\[2ex] &amp;  =3\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"118\" width=\"198\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita terapkan rumus untuk menghitung invers matriks berdimensi 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2f359bd166c295b869a8cf04d927097_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} 4 &amp; 1 \\\\[1.1ex] 5 &amp; 2 \\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{3} \\begin{pmatrix} 2 &amp; -1 \\\\[1.1ex] -5 &amp; 4 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"292\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kita mengerjakan perkalian antara pecahan dan matriks:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6a02ea2e547dcc21081ae80df407a4e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{\\bm{2}}{\\bm{3}} &amp; \\bm{-}\\cfrac{\\bm{1}}{\\bm{3}} \\\\[3ex] \\bm{-}\\cfrac{\\bm{5}}{\\bm{3}} &amp; \\cfrac{\\bm{4}}{\\bm{3}} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"147\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h4 class=\"wp-block-heading\">Latihan 4<\/h4>\n<p> Temukan invers dari matriks orde kedua berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-422fcd6f391a2682e4b546c9e9c05b55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A=\\begin{pmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"117\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E3F2FD boto_ver_solucion\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E3F2FD\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Penentu matriks A adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e9997751e16d3b976454be828cb914d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\begin{aligned}\\begin{vmatrix}A\\end{vmatrix} = \\begin{vmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10\\end{vmatrix} &amp; = (-2) \\cdot 10- (-3) \\cdot 5 \\\\ &amp; = -20-(-15) \\\\[2ex] &amp; =-20+15 \\\\[2ex] &amp; =-5\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"285\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita terapkan rumus untuk membuat matriks invers berdimensi 2\u00d72: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d5308484309da4485a3d9b92af86e7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A = \\begin{pmatrix} a &amp; b \\\\[1.1ex] c &amp; d \\end{pmatrix}\\longrightarrow A^{-1} = \\cfrac{1}{|A|} \\begin{pmatrix} d &amp; -b \\\\[1.1ex] -c &amp; a \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"305\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7c0c614039614bd9125b2920da8698eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A=\\begin{pmatrix} -2 &amp; 5 \\\\[1.1ex] -3 &amp; 10\\end{pmatrix} \\longrightarrow A^{-1} = \\cfrac{1}{-5} \\begin{pmatrix} 10 &amp; -5 \\\\[1.1ex] 3 &amp; -2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"323\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kita melakukan perkalian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-edb1dfc870b3045eaefc1716a80e2ca2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  A^{-1} = \\begin{pmatrix} \\cfrac{10}{-5} &amp; \\cfrac{-5}{-5} \\\\[3ex] \\cfrac{3}{-5} &amp; \\cfrac{-2}{-5} \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"97\" width=\"155\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c49e161c701254cfbe20353c11980eb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle  \\bm{A^{-1} =}\\begin{pmatrix} \\bm{-2} &amp; \\bm{1} \\\\[2ex] \\bm{-}\\cfrac{\\bm{3}}{\\bm{5}} &amp; \\cfrac{\\bm{2}}{\\bm{5}} \\ \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"137\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\">Selesaikan sistem persamaan dengan matriks invers<\/h2>\n<p> Sulit untuk mengapresiasi penerapan nyata invers suatu matriks. Bahkan, Anda mungkin bertanya-tanya&#8230; untuk apa matriks invers itu digunakan? Apakah itu benar-benar digunakan untuk apa pun?<\/p>\n<p> Nah, salah satu kegunaan matriks invers adalah <strong>untuk menyelesaikan sistem persamaan linear<\/strong> . Dan ya, meskipun keduanya tampak seperti dua konsep yang sangat berbeda, solusi sistem persamaan dapat ditemukan dengan membalikkan matriks.<\/p>\n<p> Mari kita lihat dengan contoh bagaimana hal ini dilakukan:<\/p>\n<ul>\n<li> Hitung penyelesaian sistem persamaan berikut dengan matriks invers:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-200c0f994f86752e7d650621a0d4100f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{r} x+3y=5 \\\\[2ex] 2x+4y=6 \\end{array} \\right\\}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"112\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Pertama-tama, harus diperhatikan bahwa sistem persamaan dapat dinyatakan dalam bentuk matriks:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4b9c9f181fc16a501799145c516a9747_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 4 \\end{pmatrix}\\begin{pmatrix} x \\\\[1.1ex]y \\end{pmatrix} = \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"156\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Kita dapat memverifikasi bahwa bentuk matriks sistem ini setara dengan ekspresi persamaan: jika kita mengalikan matriks, kita akan melihat bahwa kita memperoleh dua persamaan sistem.<\/p>\n<p> Sekarang, untuk menyederhanakan langkah selanjutnya, kami akan menelepon<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> ke matriks yang memiliki koefisien yang tidak diketahui,<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> ke kolom matriks dengan yang tidak diketahui, dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-770fd1447ccf2fc229801b486b0d8f8a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"B\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> ke matriks kolom dengan suku-suku bebas:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ec1e9c04147230526534e694fb54f316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle AX=B\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"67\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Jadi matriksnya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah persamaan matriks yang tidak diketahui.<\/p>\n<p> Untuk menyelesaikan persamaan matriks ini, Anda harus mengikuti prosedur yang tidak akan kami jelaskan secara detail di sini. Jika Anda ingin memahaminya secara menyeluruh, Anda dapat melihat cara menyelesaikan <a href=\"https:\/\/mathority.org\/id\/cara-menyelesaikan-contoh-persamaan-matriks-dan-latihan-penyelesaian-matriks-2x2-dan-3x3\/\">persamaan dengan matriks<\/a> , di mana kami menjelaskan keseluruhan prosesnya langkah demi langkah.<\/p>\n<p> Prosedur ini didasarkan pada sifat matriks invers: setiap matriks dikalikan dengan inversnya sama dengan matriks Identitas (atau Unit). Oleh karena itu, matriks yang tidak diketahui dapat diselesaikan dengan mudah<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> dengan mengalikan kedua ruas persamaan dengan invers matriks A: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ec1e9c04147230526534e694fb54f316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle AX=B\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"67\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e20a8dfa638cb0fa47765a784dc47a61_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle A^{-1}\\cdot AX=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"156\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-218f48c32d9bfd298c1e9559e8059a82_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle IX=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"107\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-acfded1a5d11f4b183ac34c85df906fc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=A^{-1}\\cdot B\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"98\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Dan setelah kita mengisolasi matriksnya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4ee28752517d6062a3ca0314890342d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"X\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> , kami menghitung kebalikan dari<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"13\" style=\"vertical-align: 0px;\"><\/p>\n<p> dan kita menyelesaikan perkalian matriks: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9a1290e37a9e3f56fc6b288bc7686d66_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=\\left.\\begin{pmatrix} 1 &amp; 3 \\\\[1.1ex] 2 &amp; 4 \\end{pmatrix}\\right.^{-1}\\cdot \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"58\" width=\"170\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21471fc8a4c04aac3121519e8ef874e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X=\\cfrac{1}{-2} \\begin{pmatrix} 4 &amp; -3 \\\\[1.1ex] -2 &amp; 1 \\end{pmatrix}\\cdot \\begin{pmatrix} 5 \\\\[1.1ex] 6 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"202\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b9457fedf68c4bdfea898922e465eeb8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle X= \\begin{pmatrix} -1 \\\\[1.1ex] 2 \\end{pmatrix}\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"86\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Oleh karena itu, penyelesaian sistem persamaan tersebut adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c2748b49f967580a0871d8739ee0d4f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\bm{x=-1} \\qquad \\bm{y=2}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"133\" style=\"vertical-align: -4px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Di halaman ini Anda akan mempelajari apa itu dan bagaimana menghitung invers suatu matriks dengan metode determinan (atau matriks adjoin) dan metode Gauss. Anda juga akan melihat semua properti matriks invers, dan Anda juga akan menemukan contoh penyelesaian langkah demi langkah dan latihan untuk setiap metode sehingga Anda memahaminya sepenuhnya. Terakhir, kami menjelaskan rumus untuk &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/id\/matriks-terbalik\/\"> <span class=\"screen-reader-text\">Cara menghitung matriks invers<\/span> Selengkapnya &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[39],"tags":[],"class_list":["post-67","post","type-post","status-publish","format-standard","hentry","category-penentu-suatu-matriks"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Cara menghitung matriks invers -<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/id\/matriks-terbalik\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Cara menghitung matriks invers -\" \/>\n<meta property=\"og:description\" content=\"Di halaman ini Anda akan mempelajari apa itu dan bagaimana menghitung invers suatu matriks dengan metode determinan (atau matriks adjoin) dan metode Gauss. 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Terakhir, kami menjelaskan rumus untuk &hellip; Cara menghitung matriks invers Selengkapnya &raquo;\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mathority.org\/id\/matriks-terbalik\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-17T05:59:45+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25b206f25506e6d6f46be832f7119ffa_l3.png\" \/>\n<meta name=\"author\" content=\"Tim Mathority\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Ditulis oleh\" \/>\n\t<meta name=\"twitter:data1\" content=\"Tim Mathority\" \/>\n\t<meta name=\"twitter:label2\" content=\"Estimasi waktu membaca\" \/>\n\t<meta name=\"twitter:data2\" content=\"14 menit\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/\"},\"author\":{\"name\":\"Tim Mathority\",\"@id\":\"https:\/\/mathority.org\/id\/#\/schema\/person\/ea4523caf53a07e2ebf32e306a925b38\"},\"headline\":\"Cara menghitung matriks invers\",\"datePublished\":\"2023-09-17T05:59:45+00:00\",\"dateModified\":\"2023-09-17T05:59:45+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/\"},\"wordCount\":2716,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/mathority.org\/id\/#organization\"},\"articleSection\":[\"Penentu suatu matriks\"],\"inLanguage\":\"id\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/mathority.org\/id\/matriks-terbalik\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/\",\"url\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/\",\"name\":\"Cara menghitung matriks invers -\",\"isPartOf\":{\"@id\":\"https:\/\/mathority.org\/id\/#website\"},\"datePublished\":\"2023-09-17T05:59:45+00:00\",\"dateModified\":\"2023-09-17T05:59:45+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/#breadcrumb\"},\"inLanguage\":\"id\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mathority.org\/id\/matriks-terbalik\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mathority.org\/id\/matriks-terbalik\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mathority.org\/id\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Cara menghitung matriks invers\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mathority.org\/id\/#website\",\"url\":\"https:\/\/mathority.org\/id\/\",\"name\":\"Mathority\",\"description\":\"Di mana rasa ingin tahu bertemu dengan perhitungan!\",\"publisher\":{\"@id\":\"https:\/\/mathority.org\/id\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mathority.org\/id\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"id\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/mathority.org\/id\/#organization\",\"name\":\"Mathority\",\"url\":\"https:\/\/mathority.org\/id\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"id\",\"@id\":\"https:\/\/mathority.org\/id\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/mathority.org\/id\/wp-content\/uploads\/2023\/09\/mathority-logo.png\",\"contentUrl\":\"https:\/\/mathority.org\/id\/wp-content\/uploads\/2023\/09\/mathority-logo.png\",\"width\":703,\"height\":151,\"caption\":\"Mathority\"},\"image\":{\"@id\":\"https:\/\/mathority.org\/id\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/mathority.org\/id\/#\/schema\/person\/ea4523caf53a07e2ebf32e306a925b38\",\"name\":\"Tim Mathority\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"id\",\"@id\":\"https:\/\/mathority.org\/id\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/8a35e4c8616d1c34c03ca02862b580f4372c5650665668489db53a09579bbc4f?s=96&d=mm&r=g\",\"caption\":\"Tim Mathority\"},\"sameAs\":[\"http:\/\/mathority.org\/id\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Cara menghitung matriks invers -","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mathority.org\/id\/matriks-terbalik\/","og_locale":"id_ID","og_type":"article","og_title":"Cara menghitung matriks invers -","og_description":"Di halaman ini Anda akan mempelajari apa itu dan bagaimana menghitung invers suatu matriks dengan metode determinan (atau matriks adjoin) dan metode Gauss. Anda juga akan melihat semua properti matriks invers, dan Anda juga akan menemukan contoh penyelesaian langkah demi langkah dan latihan untuk setiap metode sehingga Anda memahaminya sepenuhnya. 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