{"id":42,"date":"2023-09-17T10:57:01","date_gmt":"2023-09-17T10:57:01","guid":{"rendered":"https:\/\/mathority.org\/id\/masalah-optimasi\/"},"modified":"2023-09-17T10:57:01","modified_gmt":"2023-09-17T10:57:01","slug":"masalah-optimasi","status":"publish","type":"post","link":"https:\/\/mathority.org\/id\/masalah-optimasi\/","title":{"rendered":"Masalah optimasi"},"content":{"rendered":"<p>Di sini kami menjelaskan bagaimana masalah optimasi fungsi diselesaikan secara bertahap. Selain itu, Anda akan dapat berlatih dengan latihan yang diselesaikan pada masalah optimasi. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-son-los-problemas-de-optimizacion\"><\/span> Apa masalah optimasi?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Masalah optimasi<\/strong> adalah masalah dimana seseorang harus mencari maksimum atau minimum suatu fungsi. Misalnya, masalah optimasi akan melibatkan penghitungan fungsi maksimum yang menentukan keuntungan perusahaan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"como-resolver-los-problemas-de-optimizacion\"><\/span> Bagaimana mengatasi masalah optimasi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Langkah-langkah untuk mengatasi masalah pengoptimalan fungsi:<\/p>\n<ol>\n<li> <strong>Atur fungsi<\/strong> yang perlu dioptimalkan.<\/li>\n<li> <strong>Turunkan fungsi yang akan dioptimalkan.<\/strong><\/li>\n<li> Temukan <strong>titik kritis<\/strong> dari fungsi yang akan dioptimalkan. Untuk melakukan ini, Anda perlu mengatur turunan fungsi sama dengan nol dan menyelesaikan persamaan yang dihasilkan.<\/li>\n<li> Pelajari monotonisitas suatu fungsi dan <strong>tentukan maksimum atau minimum fungsi tersebut.<\/strong> <\/li>\n<\/ol>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-problema-de-optimizacion\"><\/span> Contoh masalah optimasi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dengan mempertimbangkan teori masalah optimasi, kita akan menyelesaikan masalah jenis ini langkah demi langkah sehingga Anda dapat melihat cara penyelesaiannya.<\/p>\n<ul>\n<li> Diantara semua segitiga siku-siku yang panjang kaki-kakinya 10 cm, hitunglah luas segitiga yang luas permukaannya maksimum.<\/li>\n<\/ul>\n<p> Untuk menyelesaikan soal ini, kita akan memanggil salah satu cabang segitiga <em>x<\/em> , dan cabang lainnya <em>y<\/em> : <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/triangle-optimisation-probleme.webp\" alt=\"masalah optimasi segitiga\" class=\"wp-image-2463\" width=\"172\" height=\"156\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> <u style=\"text-decoration-color:#FF9B28;\"><strong><span style=\"color:#1976d2;\">Langkah 1:<\/span><\/strong> Atur fungsi yang akan dioptimalkan.<\/u><\/p>\n<p> Kita ingin luas segitiganya maksimal, dan rumus luas segitiga adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d1fe72037bfa7f8a181f8f92fdeb5a93_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A = \\cfrac{b \\cdot h}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"70\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Dalam kasus kita, alas segitiga adalah <em>x<\/em> dan tingginya <em>adalah y<\/em> . Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fffb2f09f07fa450174fda22346dc38d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A = \\cfrac{x \\cdot y}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"72\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Kita sudah mempunyai fungsi untuk mengoptimalkannya, namun bergantung pada dua variabel sedangkan hanya dapat bergantung pada satu variabel. Namun, pernyataan tersebut memberitahu kita bahwa kedua kakinya harus berjumlah 10 cm. Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-97009913e60b18a66b47683b142eaa14_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x+ y = 10\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"83\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Kami menyelesaikan <em>y<\/em> dari persamaan ini:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9093174098ec3aeadce1fa9dd3724c27_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y = 10 -x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"82\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Dan kami mengganti ekspresi tersebut ke dalam fungsi:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d9ab3460a669f3a70a608b0a4c64f520_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A = \\cfrac{x \\cdot y}{2} \\ \\xrightarrow{ y \\  = \\ 10 -x } \\ A = \\cfrac{x(10-x)}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"278\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-28b512042d814bf88207c8fb0f9a5543_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x) = \\cfrac{10x-x^2}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"131\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Kita sekarang memiliki fungsi optimasi terencana dan itu hanya bergantung pada satu variabel, jadi kita bisa melanjutkan ke langkah berikutnya.<\/p>\n<p> <u style=\"text-decoration-color:#FF9B28;\"><strong><span style=\"color:#1976d2;\">Langkah 2:<\/span><\/strong> Hitung turunan dari fungsi yang akan dioptimalkan.<\/u><\/p>\n<p> Ini adalah fungsi rasional, jadi kami menerapkan rumus turunan pembagian untuk menurunkannya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0d555f298d7c31d09947787e4d294d59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x) = \\cfrac{10x-x^2}{2} \\ \\longrightarrow \\ A'(x) = \\cfrac{(10-2x) \\cdot 2 - (10x-x^2) \\cdot 0}{2^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"467\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-00979b72662361213ec4611a28e935a9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x) = \\cfrac{20-4x}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"126\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> <u style=\"text-decoration-color:#FF9B28;\"><strong><span style=\"color:#1976d2;\">Langkah 3:<\/span><\/strong> Temukan titik kritisnya.<\/u><\/p>\n<p> Untuk menemukan titik kritis suatu fungsi, kita perlu mengatur turunannya sama dengan nol dan menyelesaikan persamaan yang dihasilkan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-91e81f70cf7bd6388f6511629d203f7f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x) = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5753c4fdb7aaae61182eac6fd15e52d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{20-4x}{4} =0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"91\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Angka 4 membagi seluruh ruas kiri, sehingga kita dapat mengalikannya dengan mengalikan seluruh ruas kanan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23e63171262e022c8a63e717b31ed0b5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"20-4x=0 \\cdot 4\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"113\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8e9b9b9a13bafb9de785e9cf5b3e86ca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"20-4x=0\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"91\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e71409a99fca0883bc173a6df1b8c3af_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-4x=-20\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"87\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66b399752305ae60043d99032ba112d9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\cfrac{-20}{-4}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"76\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8ddab230605c435eb8b7408a736d3e77_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=5\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"42\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> <u style=\"text-decoration-color:#FF9B28;\"><span style=\"color:#1976d2;\"><strong>Langkah 4:<\/strong><\/span> Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/u><\/p>\n<p> Untuk mempelajari kemonotonan suatu fungsi, kita nyatakan titik kritis di sebelah kanan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-5.webp\" alt=\"\" class=\"wp-image-2466\" width=\"227\" height=\"88\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Dan sekarang kita evaluasi tanda turunannya pada setiap interval untuk mengetahui apakah fungsinya naik atau turun. Untuk melakukan ini, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-00979b72662361213ec4611a28e935a9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x) = \\cfrac{20-4x}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"126\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c9c9fbc0304871964748873af9e9918c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(0) = \\cfrac{20-4\\cdot0}{4} = \\cfrac{20}{4} = 5  \\  \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"264\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-05c98faeaeb88c5826a71a45b3e9c88a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(6) = \\cfrac{20-4\\cdot6}{4} = \\cfrac{20-24}{4} = \\cfrac{-4}{4} = -1   \\  \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"373\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-5-positif-negatif.webp\" alt=\"\" class=\"wp-image-2467\" width=\"227\" height=\"160\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Jika turunannya positif berarti fungsinya meningkat, dan jika turunannya negatif berarti fungsinya menurun. Oleh karena itu, interval kenaikan dan penurunan fungsi tersebut adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-188a50f6279237f5c478c7116a509d49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty, 5)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"60\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-743f877080ce04389168296915ca6795_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(5,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"61\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Pada x=5 fungsinya berubah dari naik ke turun, jadi <strong>x=5 adalah maksimum relatif<\/strong> dari fungsi yang akan dioptimalkan <strong>.<\/strong><\/p>\n<p> Jadi x=5 adalah nilai cabang segitiga yang mempunyai luas maksimum. Cukup hitung nilai kaki lainnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d396031e1a0eb65570a9f95d6701f9c1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y = 10 -x \\ \\xrightarrow{x \\ = \\ 5} \\ y = 10-5= \\bm{5}\" title=\"Rendered by QuickLaTeX.com\" height=\"23\" width=\"265\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Kesimpulannya, nilai maksimal luas maksimum segitiga adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-85b25208de94c730a3de04d6d428dc59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{x=5} \\ \\mathbf{cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"75\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e7e41736bd949777d18ec2a79b0beb93_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{y=5} \\ \\mathbf{cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"74\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"problemas-de-optimizacion-resueltos\"><\/span> Masalah optimasi teratasi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Masalah 1<\/h3>\n<p> Obatnya diberikan kepada orang sakit dan<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b4e3cbf5d4c5c6d9b702dd139f14c147_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> beberapa jam kemudian, konsentrasi bahan aktif dalam darah ditentukan oleh fungsinya<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-57f138f86e1400954205e4b91ed3103c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c(t) = te^{\u2212t\/2}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"84\" style=\"vertical-align: -5px;\"><\/p>\n<p> miligram per mililiter. Tentukan nilai maksimum dari<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c4be04707471a329c8bde249ab6cf526_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c(t)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"27\" style=\"vertical-align: -5px;\"><\/p>\n<p> dan menunjukkan kapan nilai tersebut tercapai. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Dalam soal ini, mereka sudah memberi kita fungsi yang diusulkan, yaitu<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-02fb8044e28a7e9ba53c1eb64bfec693_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle c(t) = t e^{-t\/2} .\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"100\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Fungsi tersebut terdiri dari hasil kali 2 fungsi. Oleh karena itu, untuk menghitung turunan suatu fungsi, kita harus menerapkan aturan turunan suatu produk: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1975d832fe40c4c12a2a4986244e3c24_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle c'(t)=1 \\cdot e^{-t\/2} + t \\cdot e^{-t\/2} \\cdot \\left( \\frac{-t}{2} \\right)'= e^{-t\/2} + t e^{-t\/2} \\cdot  \\frac{-1}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"46\" width=\"430\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d730042a2ff5df46d19bce35fe24392_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c'(t)=e^{-t\/2} + \\cfrac{-1}{2}t  e^{-t\/2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"193\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritisnya.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-626f673c4823e1bd527925bfe91d558f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c'(t)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-64818981c87104d6e0b400434ce53533_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c'(t)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"65\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6d9ebad9fa6bc78dc99b358f4786999f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle e^{-t\/2} + \\frac{-1}{2}t  e^{-t\/2}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"164\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengambil faktor persekutuan untuk menyelesaikan persamaan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-410004b26bf5de6dc03c12491bee91b9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle e^{-t\/2} \\left(1 - \\frac{1}{2}t \\right) = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"150\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agar perkaliannya sama dengan 0, salah satu dari dua unsur perkaliannya harus nol. Oleh karena itu, kami menetapkan setiap faktor sama dengan 0:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8390139724dbc4ad014db2a76e508290_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle e^{-t\/2}\\cdot \\left(1 - \\frac{1}{2}t \\right) = 0 \\longrightarrow \\begin{cases} e^{-t\/2}=0 \\ \\bm{\\times} \\\\[2ex]\\displaystyle 1 - \\frac{1}{2}t=0 \\ \\longrightarrow \\ 1= \\frac{1}{2}t \\ \\longrightarrow \\ \\bm{2=t} \\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"77\" width=\"486\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Suatu bilangan yang dipangkatkan ke bilangan lain tidak akan pernah menghasilkan 0, oleh karena itu,<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-10b6a1e4b24bf63d08aeff4da0374d25_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"e^{-t\/2}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"71\" style=\"vertical-align: 0px;\"><\/p>\n<p> Tidak ada solusi.<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk mempelajari kemonotonan suatu fungsi, kita nyatakan titik kritis di sebelah kanan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-2.webp\" alt=\"\" class=\"wp-image-2469\" width=\"204\" height=\"79\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-904d140578309f45e9c53d2a9a35e32d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle c'(0)=e^{-0\/2} + \\frac{-1}{2}\\cdot 0 \\cdot e^{-0\/2} = e^0 +\\frac{-1}{2}\\cdot 0 \\cdot e^{0} = 1 + 0 = 1 \\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"508\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ada4b79153afee560564a81df8d0c46f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle c'(3)=e^{-3\/2} + \\frac{-1}{2}(3)e^{-3\/2} = 0,22-0,33 = -0,11 \\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"449\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droite-numerique-deux-positif-negatif.webp\" alt=\"\" class=\"wp-image-2472\" width=\"202\" height=\"143\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya positif berarti fungsinya bertambah, sebaliknya jika turunannya negatif berarti fungsinya menurun. Dengan demikian interval pertumbuhan dan penurunan fungsi yang akan dioptimalkan adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3868632c123ece40100b3a40c266cc25_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty,2)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"60\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4c9901d11cc4672cab7e1e2a6de08ce4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(2,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"61\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsi tersebut berubah dari naik ke turun pada t=2, jadi <strong>t=2 adalah maksimum<\/strong> dari fungsi tersebut. Oleh karena itu, konsentrasi maksimum akan tercapai dalam <strong>t=2 jam.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Terakhir, kita substitusikan nilai terjadinya maksimum ke dalam fungsi aslinya, untuk mencari nilai konsentrasi maksimum: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dd8123e6fd3fe714d1784775375011f2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"c(2) = 2 \\cdot e^{-2\/2} = 2\\cdot e^{-1} = 2 \\cdot 0,37 = \\bm{0,74} \\ \\mathbf{mg\/ml}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"391\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Masalah 2<\/h3>\n<p> Sebuah toko berharap dapat menjual 40 skuter listrik dengan harga \u20ac1.000 per skuter. Namun menurut riset pasar, untuk setiap penurunan harga skuter sebesar \u20ac50, akan terjadi peningkatan penjualan 10 skuter terlaris.<\/p>\n<p> Pertama, tuliskan fungsi pendapatan toko berdasarkan berapa kali harga awal skuter sebesar $1.000 dikurangi sebesar $50. Selanjutnya menentukan harga skutik tersebut untuk mendapatkan keuntungan maksimal dan pendapatan yang diperoleh pada harga tersebut. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Pernyataan masalah memberi kita petunjuk, karena menyatakan bahwa fungsi tersebut harus bergantung pada berapa kali harga awal dikurangi sebesar $50. Oleh karena itu kita akan menyebutkan x berapa kali harga diturunkan sebesar \u20ac50:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d0357e75c58ab161e387dae18d3a6f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x= \\text{N\\'umero de veces que se rebaja el precio 50}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"368\" style=\"vertical-align: -4px;\"><\/p>\n<p> \u20ac<\/p>\n<p class=\"has-text-align-left\"> Fungsi pendapatan adalah jumlah skuter yang terjual dikalikan harga tiap skuter:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f04d6d19de5d7a7ad8dceadfbbdbdbe2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= \\text{N\\'umero patintetes vendidos} \\cdot \\text{Precio de cada patinete}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"470\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jumlah skuter yang terjual akan menjadi 40 ditambah 10 skuter untuk setiap pengurangan harga \u20ac50. Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-88b7464372c9683d065acbdbe2598cbe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{N\\'umero patintetes vendidos} = 40 + 10x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"308\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Harga setiap skuter akan menjadi \u20ac1000 pada awalnya, dan akan turun sebesar \u20ac50 dengan setiap penurunan harga. Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c22a7a64d350ea748ad2b4b3decd217_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Precio de cada patinete} = 1000 -50x\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"291\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, fungsi untuk mengoptimalkan masalah adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f04d6d19de5d7a7ad8dceadfbbdbdbe2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= \\text{N\\'umero patintetes vendidos} \\cdot \\text{Precio de cada patinete}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"470\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2cbffd131757d106f869b562d4e35c4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= (40 + 10x) \\cdot (1000-50x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"249\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0ae987678d7542e5d127fc02f8bf4daf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= 40000-2000x+10000x-500x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"310\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-902cc0a5c209ed48e3d93432b5550b1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= -500x^2+8000x+40000\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"249\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Karena fungsi polinomial, turunannya lebih mudah dihitung:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-acb8d705be4d3a30be83d2800f4d2403_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= -500x^2+8000x+40000\\ \\longrightarrow \\ I'(x)= -1000x+8000\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"477\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritis dari fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b55b4fb6ca5af90f829cb082893a5519_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I'(x)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"79\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b48142b0c92fea1f9dd87af211ada6b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I'(x)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"70\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5a0d58fd339d02e3f71b7fe031726cad_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-1000x+8000=0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"148\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a03bae4e019041d174c51fced30954ef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-1000x=-8000\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"132\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e67f8bf53c9c10c3384f729890f57b4d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\cfrac{-8000}{-1000} = 8\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk mempelajari monotonisitas suatu fungsi, kami mewakili titik kritis yang dihitung pada garis bilangan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-8.webp\" alt=\"\" class=\"wp-image-2481\" width=\"234\" height=\"91\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3cf47c71ae832d734c6e5f525efa05b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I'(0)= -1000\\cdot 0+8000=8000 \\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"300\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9df9f5fdff3d4ba6dcd7f17c68b16c2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I'(10)= -1000\\cdot 10+8000=-2000 \\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"331\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-8-positif-negatif.webp\" alt=\"\" class=\"wp-image-2482\" width=\"239\" height=\"169\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya positif berarti fungsinya meningkat, dan jika turunannya negatif berarti fungsinya menurun. Oleh karena itu, interval pertumbuhan dan penurunannya adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d85d36c78a812c7c5a8f127bb5145c42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty,8)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"60\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ba6980946255650ee8fe4dbc4c87c681_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(8,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"61\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsi tersebut berubah dari naik ke turun pada x=8, jadi <strong>x=8 adalah maksimum<\/strong> dari fungsi tersebut. Oleh karena itu, pendapatan maksimum akan diperoleh dengan melakukan <strong>pengurangan \u20ac50 sebanyak 8 kali.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Sekarang kita substitusikan nilai dimana pendapatan maksimum muncul ke dalam fungsi aslinya, untuk mencari nilai pendapatan maksimum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-902cc0a5c209ed48e3d93432b5550b1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(x)= -500x^2+8000x+40000\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"249\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fce0d14898ab44824c50e758de24099d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"I(8)= -500\\cdot 8^2+8000\\cdot 8+40000 = \\bm{72000}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"339\" style=\"vertical-align: -5px;\"><\/p>\n<p> <strong>\u20ac<\/strong><\/p>\n<p class=\"has-text-align-left\"> Dan harga setiap skuter setelah melakukan diskon \u20ac50 sebanyak 8 kali adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c22a7a64d350ea748ad2b4b3decd217_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Precio de cada patinete} = 1000 -50x\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"291\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a4646c3d785d36e70ba549b9672b697c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{Precio de cada patinete} = 1000 -50\\cdot 8=\\bm{600}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"353\" style=\"vertical-align: -4px;\"><\/p>\n<p> <strong>\u20ac<\/strong><\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Masalah 3<\/h3>\n<p> Fungsi biaya (dalam ribuan euro) suatu perusahaan dapat ditentukan dengan menggunakan ekspresi berikut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c84c0900acd506ad979886e5b5f10ff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=40-6x+x^2, \\quad x \\ge  0\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"224\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Emas<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ede05c264bba0eda080918aaa09c4658_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> mewakili ribuan unit yang diproduksi dari suatu barang tertentu.<\/p>\n<p> Tentukan berapa banyak yang harus diproduksi agar biayanya minimal, berapa biayanya, dan berapa biayanya jika barang-barang tersebut tidak diproduksi. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Pernyataan masalah sudah memberi kita fungsi yang akan dioptimalkan, yaitu<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6dc6eb92c2776f8026c348e7e5824d09_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)=40-6x+x^2 .\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"160\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5056826599d14c0ff8aa3ec134a68b0f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=40-6x+x^2 \\ \\longrightarrow \\ f'(x)=-6+2x\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"332\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritisnya.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-58dcd049349f740f082d583dfd9e364c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(x)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"80\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-36700780d306ccf4975387990b1949fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(x)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"72\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ecec21f50b0875af5ebb5c55ef5e2502_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-6+2x=0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"95\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d47687d0a8cb82ab26be7eadf0d7f3c8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2x=6\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"52\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f1ffe509b34b0d560397fbc1859cb64_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\cfrac{6}{2} = 3\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"77\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Kami mewakili titik kritis yang ditemukan di sebelah kanan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-3.webp\" alt=\"\" class=\"wp-image-2485\" width=\"231\" height=\"90\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2647164feab3d1bdc3e7cdb14c123294_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(0)=-6+2\\cdot 0=-6\\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"235\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7fe3f1add3273a0ba4d0418a3b9788a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(4)=-6+2\\cdot 4=-6+8=2\\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"298\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-3-negatif-positif.webp\" alt=\"\" class=\"wp-image-2486\" width=\"231\" height=\"163\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya lebih besar dari nol, maka fungsinya meningkat pada interval ini. Sebaliknya, jika turunannya kurang dari nol, maka fungsi tersebut menurun pada interval tersebut. Jadi, interval kenaikan dan penurunan fungsi tersebut adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fbc0e31e2b07080a4f83c2a34053c0f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(3,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"61\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a890e45091b2c4c9115051361c0a1a2c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty,3)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"60\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsi tersebut berubah dari menurun menjadi meningkat pada x=3, jadi <strong>x=3 adalah fungsi minimum<\/strong> . Oleh karena itu, biaya minimum akan dicapai dengan memproduksi <strong>3.000 unit.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Sekarang kita substitusikan nilai dimana biaya minimum tercapai ke dalam fungsi asli untuk mencari nilai biaya minimum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4a1c84d3c81fd4c7ebbecc922cc2288e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(3)=40-6\\cdot 3+3^2=\\bm{31}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"206\" style=\"vertical-align: -5px;\"><\/p>\n<p> jutaan euro.<\/p>\n<p class=\"has-text-align-left\"> Di sisi lain, mereka bertanya kepada kami berapa biayanya jika tidak ada produksi, yaitu kapan<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa5140cb12e100167e56a99c53750148_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x= 0 .\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"47\" style=\"vertical-align: 0px;\"><\/p>\n<p> Oleh karena itu perlu dilakukan perhitungan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8f92d7beea0ed3a053927c2d429d3450_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(0):\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"42\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a7051466b3981f72509f3e5e2aa1d2f7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(0)=40-6\\cdot 0+0^2=   \\bm{40}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"207\" style=\"vertical-align: -5px;\"><\/p>\n<p> jutaan euro.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Masalah 4<\/h3>\n<p> Kita ingin membuat rangka kayu berbentuk persegi panjang yang membatasi luas 2 m <sup>2<\/sup> . Kita tahu bahwa harga kayu adalah \u20ac7,5\/m untuk sisi horizontal dan \u20ac12,5\/m untuk sisi vertikal. Tentukan dimensi yang harus dimiliki persegi panjang tersebut sehingga total biaya rangka adalah seminimal mungkin dan biaya tersebut minimum. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menyelesaikan soal ini, kita beri nama sisi horizontal <em>x<\/em> , dan sisi vertikal <em>y<\/em> : <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/rectangle-fonction-optimisation-problemes.webp\" alt=\"masalah optimasi fungsi persegi panjang\" class=\"wp-image-2490\" width=\"166\" height=\"188\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Membeli sisi horizontal berharga \u20ac7,5 dan membeli sisi vertikal berharga \u20ac12,5. Selain itu, untuk setiap frame kita memerlukan dua sisi horizontal dan dua sisi vertikal. Oleh karena itu, biaya rangka dapat ditentukan dengan fungsi berikut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8485280ab046816dfbd587b192901fb9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C(x,y)= 7,5\\cdot 2x+12,5 \\cdot 2y = 15x +25y\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"323\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami sudah memiliki fungsi untuk mengoptimalkan. Tapi itu bergantung pada dua variabel, padahal hanya bisa bergantung pada satu variabel. Namun pernyataan tersebut memberitahu kita bahwa luas permukaan bingkai harus 2 m <sup>2<\/sup> . Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-13ea4da7e9b4674fdd1a733e0e3cd26e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x \\cdot y = 2\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"64\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami menghapus variabel <em>y<\/em> :<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e00a5c6da8de49964d27f2941dac8a4b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y =\\cfrac{2}{x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"46\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengganti ekspresi yang ditemukan dalam fungsi yang akan dioptimalkan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2cb9add65869ac746532ac4bf1537eb1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C(x,y)= 15x +25y\\ \\xrightarrow{y \\ = \\ \\frac{2}{x} } \\ C(x)= 15x+25\\left(\\cfrac{2}{x} \\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"396\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e232dbf6025d3b8d6593e4157cd09bff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C(x)= 15x+\\cfrac{50}{x} =15x +50x^{-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"249\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4ef3647de078c1f760dc37a5d3d6b68e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C(x)=15x +50x^{-1} \\ \\longrightarrow \\ C'(x)=15 -50x^{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"359\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritisnya.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-97f234a562c87b78e257fc7953dee7ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C'(x)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"84\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8732228827d41a41af6935b1f0bdc0d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C'(x)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"75\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cdaf71028a32e2818a7ec3376338df75_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"15 -50x^{-2}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"117\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8bf1bee39e8e6e8f54b838f7dc8810d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"15 =50x^{-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"86\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d4f9337813bfb8c7bf0d09f9889514c3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"15=\\cfrac{50}{x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"60\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0aea588515cc1c895b2ca5030cd55ffc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{15}{1}=\\cfrac{50}{x^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"61\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengalikan secara melintang untuk menyelesaikan persamaan dengan pecahan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-99a602636bc09eb630e637ec6454c8ce_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"15 \\cdot x^2 = 50 \\cdot 1\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"110\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dcdd7918a1af31e63925cb694da7d6be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x^2 = \\cfrac{50}{15}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"61\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e9090b3956470b16769ec2ae441f2d30_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x^2 = 3,33\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"76\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-92abf359db44a399822919b1bb62e7cf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sqrt{x^2} = \\sqrt{3,33}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"105\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b87ffa5999c0bbea78cc07d6a412460a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x = 1,83\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"69\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Kami mewakili titik kritis yang ditemukan untuk menganalisis fungsi monoton pada garis: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-183.webp\" alt=\"\" class=\"wp-image-2491\" width=\"206\" height=\"80\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-64f2221e9103ecdcb21609567e990135_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1)=15 -50\\cdot 1^{-2} = 15-50 = -35 \\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"347\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ad12501e06c6997d1555df684480d38b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(2)=15 -50\\cdot 2^{-2} = 15-12,5 = 2,5 \\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"358\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droite-numerique-183-negatif-positif.webp\" alt=\"\" class=\"wp-image-2493\" width=\"206\" height=\"146\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya positif berarti fungsinya meningkat, dan jika turunannya negatif berarti fungsinya menurun. Oleh karena itu, interval pertumbuhan dan penurunannya adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d8e4f82a46ac576b10134beda86f0bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(1,83,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"86\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-57f0911e594b424ad7908294a15f1b84_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty,1,83)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"86\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsinya berubah dari turun ke naik pada x=1,83, jadi <strong>x=1,83 adalah fungsi minimum<\/strong> .<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, x=1,83 adalah nilai sisi horizontal yang mewakili biaya minimum. Sekarang mari kita hitung nilai sisi vertikalnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-325134d449963e4d814cdd19a87bdfd4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y =\\cfrac{2}{x} \\ \\longrightarrow \\ y =\\cfrac{2}{1,83} = \\bm{1,09}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"223\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dengan demikian, nilai-nilai yang membentuk biaya kerangka minimum adalah:<\/p>\n<p class=\"has-text-align-center\"> sisi horisontal<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c8b9148690c3a5b5e441df6c02e23e85_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"= x = \\bm{1,83} \\ \\mathbf{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"110\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> sisi vertikal<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0ad15cb0e6023282190abbb21c5f8a47_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"= y = \\bm{1,09} \\ \\mathbf{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"109\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan biaya minimum yang dicapai dengan nilai tersebut adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bef42a21eacaeb4cd25b5e43c15e268b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"C= 15\\cdot 1,83+25\\cdot 1,09=\\bm{54,70}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"256\" style=\"vertical-align: -4px;\"><\/p>\n<p> <strong>\u20ac<\/strong><\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Masalah 5<\/h3>\n<p> Pintu katedral dibentuk oleh lengkungan setengah lingkaran yang ditopang oleh dua kolom, seperti terlihat pada gambar berikut: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/problemes-d-optimisation-de-la-geometrie.webp\" alt=\"masalah optimasi geometri\" class=\"wp-image-2500\" width=\"182\" height=\"268\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Jika keliling pintu adalah 20 m, tentukanlah pengukurannya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ede05c264bba0eda080918aaa09c4658_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0af556714940c351c933bba8cf840796_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> yang memaksimalkan luas permukaan seluruh pintu. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Luas lingkaran dihitung dengan rumus<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1ab0b6b8d454bae5631e7a82caed58d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\pi r^2.\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"31\" style=\"vertical-align: 0px;\"><\/p>\n<p> Jadi luas seluruh pintu adalah luas persegi panjang ditambah setengah luas kelilingnya: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-95c1f9b6152c4cbc623aeb8a0a5757b7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= x\\cdot y + \\cfrac{1}{2} \\left[ \\pi r ^2 \\right]\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"184\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-baa2e14b061cf14a657782db8fe91b92_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= x y + \\cfrac{1}{2} \\left[ \\pi \\left(\\cfrac{x}{2}\\right)^2 \\right]\" title=\"Rendered by QuickLaTeX.com\" height=\"64\" width=\"212\" style=\"vertical-align: -27px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9196d8284edebe6450d49aa5a0b6a3e1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= x y + \\cfrac{1}{2} \\left[ \\pi \\cdot \\cfrac{x^2}{4} \\right]\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"193\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b25e1d2c661585be998d1596d6650c01_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= x y +\\cfrac{1}{2} \\left[  \\cfrac{\\pi \\cdot x^2}{4} \\right]\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"193\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-64a0c7fa480320a1b564fec5f9ff8265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= xy +\\cfrac{\\pi x^2}{8}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"150\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami sudah memiliki fungsi untuk mengoptimalkan. Tapi itu bergantung pada dua variabel, padahal hanya bisa bergantung pada satu variabel.<\/p>\n<p class=\"has-text-align-left\"> Namun, rilis tersebut memberitahu kita bahwa keliling seluruh gerbang adalah 20m. Keliling lingkaran dihitung dengan rumus<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e815d233e188a7121eef89639e48fe75_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2 \\pi r.\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"31\" style=\"vertical-align: 0px;\"><\/p>\n<p> Oleh karena itu, keliling seluruh pintu adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7709d0c72bf84a17ac83bc46f5cce002_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P= x +2y +\\cfrac{1}{2} \\left[ 2 \\pi \\left( \\cfrac{x}{2}\\right) \\right] = x+2y + \\cfrac{2 \\pi x }{2 \\cdot 2} = x+2y + \\cfrac{ \\pi x }{2 }\" title=\"Rendered by QuickLaTeX.com\" height=\"54\" width=\"452\" style=\"vertical-align: -23px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kelilingnya harus 20 m. Oleh karena itu, kami menetapkan ekspresi sebelumnya sama dengan 20 untuk menemukan hubungan antara keduanya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ede05c264bba0eda080918aaa09c4658_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a70e6a4387a816f153e8597195143f54_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y :\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-282aa8aebdd04ba4989ba7466fdd694d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x+2y + \\cfrac{ \\pi x }{2 } = 20\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"136\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengalikan semua suku dengan 2 untuk menghilangkan pecahan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a185cfda7fb65f370636fa469b0de2c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2\\cdot x+2\\cdot 2y + 2 \\cdot \\cfrac{ \\pi x }{2 } = 2 \\cdot 20\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"223\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d67cd2fbdde0f884603e75bf270cb52c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2x+4y +  \\pi x = 40\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"143\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami membersihkan <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a70e6a4387a816f153e8597195143f54_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y :\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-740ff13a6824a3ee18cb1de0cbf52660_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"4y  = 40-2x- \\pi x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"143\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-db16e16a94223af02d63ea70eae3db7d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y   = \\cfrac{40-2x- \\pi x}{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"136\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengganti ekspresi yang ditemukan dalam fungsi yang akan dioptimalkan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-16c3b1d1a3ac443d4640ae2b72c164e6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x,y)= x y +\\cfrac{\\pi x^2}{8}\\ \\xrightarrow{y \\ = \\ \\frac{40-2x- \\pi x}{4} }\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"262\" style=\"vertical-align: -12px;\"><\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f463f9095e8028624678c06a08696a96_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x)= x \\cdot \\cfrac{40-2x- \\pi x}{4}+\\cfrac{\\pi x^2}{8}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"239\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-095586f92b592c3c9c50750f8a6eb7d4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(x)= \\cfrac{40x-2x^2-\\pi x^2}{4}+\\cfrac{\\pi x^2}{8}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"242\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong> <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42ce3330af662099ad431ee1187d26f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x)=\\cfrac{(40-4x-2\\pi x)\\cdot 4 +(40x-2x^2- \\pi x^2)\\cdot 0 }{4^2} +\\cfrac{2\\pi x \\cdot 8 + \\pi x^2 \\cdot 0}{8^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"544\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1a75cddf1efd4f17b6a3211093f2e0b5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x)=\\cfrac{160-16x-8\\pi x }{16} +\\cfrac{16\\pi x}{64}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"257\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritisnya.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a8f5a921f7e1978b553d11a76e0962c7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"83\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-424f3d5d91120e872bebd055792d71a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(x)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-89a04d2a2a532f36f15042d2d2c79d41_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\cfrac{160-16x-8\\pi x }{16} +\\cfrac{16\\pi x}{64} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"222\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ini adalah persamaan dengan pecahan, jadi kita mengalikan tiap suku dengan lcm penyebutnya untuk menghilangkan pecahannya: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-87d60f06d42276c79b3a4f33b00fdb7b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"64 \\cdot \\cfrac{160-16x-8\\pi x }{16} +64 \\cdot \\cfrac{16\\pi x}{64} = 0\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"285\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b2a7b3bbdad1ea1bf9f12861b1dbdf0a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"4\\cdot ( 160-16x-8\\pi x) +1\\cdot 16\\pi x= 0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"278\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-61a4622d4b65310580e066941ae13fac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"640-64x -32 \\pi x +16\\pi x= 0\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"229\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-94c6efd66ea5f2f1c68ab09d59fb5432_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-64x -32 \\pi x +16\\pi x= -640\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"226\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bdaf73c6d74c3d4f605b5aea3cdeb1ad_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-64x -16 \\pi x = -640\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"166\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4bfe710d37882f664daed4de23f2eb7a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(-64 -16 \\pi) x = -640\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"169\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b551560fd86665e639dbc88aeb88a2bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\cfrac{-640}{-64 -16 \\pi}  = 5,6\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"167\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk mempelajari kemonotonan suatu fungsi, kita nyatakan titik kritis di sebelah kanan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-56.webp\" alt=\"\" class=\"wp-image-2501\" width=\"214\" height=\"83\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e8b0c6b03e591be56505c8853595dd0a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(0)=\\cfrac{160-16\\cdot 0-8\\pi \\cdot 0 }{16} +\\cfrac{16\\pi \\cdot 0}{64} = 10 +0 = 10 \\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"456\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-91c7e9012e4937dad79ec792910df916_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A'(6)=\\cfrac{160-16\\cdot 6-8\\pi \\cdot 6 }{16} +\\cfrac{16\\pi \\cdot 6}{64} = -5,42 +4,71 = -0,71 \\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"543\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droite-numerique-56-positif-negatif.webp\" alt=\"\" class=\"wp-image-2503\" width=\"218\" height=\"155\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya positif berarti fungsinya meningkat, dan jika turunannya negatif berarti fungsinya menurun. Oleh karena itu, interval pertumbuhan dan penurunannya adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-375f15fd5182721ee68f606765b66e89_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty , 5,6)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ce3629c3ea3fa84fd3413a15913976f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(5,6,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsinya berubah dari naik ke turun pada x=5,6, jadi <strong>x=5,6 adalah maksimum<\/strong> dari fungsi tersebut.<\/p>\n<p class=\"has-text-align-left\"> Belum,<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c0d40793b19725cb50b88536bdaf3239_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=5,6\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"60\" style=\"vertical-align: -4px;\"><\/p>\n<p> adalah nilai yang membuat permukaan maksimum. Sekarang kita menghitung nilai<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a70e6a4387a816f153e8597195143f54_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y :\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"18\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-af3ff0bf06cb82b6661c9ead44cabaa6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"y = \\cfrac{40-2\\cdot 5,6- \\pi \\cdot 5,6}{4} = 2,80\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"251\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi, nilai permukaan maksimum adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-25cd4efdc51c2a6fb453056df61536fa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{x = 5,60} \\ \\mathbf{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"91\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9b69c85499698e995f01f60b2b78ef20_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{y = 2,80} \\ \\mathbf{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"90\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Masalah 6<\/h3>\n<p> Kami ingin membangun tangki berbentuk silinder dengan luas 54 cm <sup>2<\/sup> . Tentukan jari-jari alas dan tinggi silinder agar volumenya maksimum. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> <strong>Langkah 1: Atur fungsi yang akan dioptimalkan.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Volume silinder dihitung dengan rumus berikut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fbe33001d54c8245539894746beb9eac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V= A_{base}\\cdot h\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"101\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Luas alasnya adalah lingkaran, jadi rumusnya adalah<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fc935e01b9c94505406438dea94cf121_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A_{\\text{base}}=\\pi r^2\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<p> . Oleh karena itu, rumus volume silinder adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-df6ffff5ee54af4f7b10424871d1af92_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V= \\pi r^2 \\cdot h\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"88\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami sudah memiliki fungsi untuk mengoptimalkan. Tapi itu tergantung pada dua variabel (<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-14b463d0ecd5b350ced6cf1d6a12eef3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> ) sementara itu hanya dapat bergantung pada satu. Namun pernyataan tersebut menyatakan bahwa luas silinder harus 54 cm <sup>2<\/sup> , jadi kita akan memanfaatkan kondisi ini untuk mencari hubungan antara<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f0bf134a8aafe0dfaa4d711f78b8b1f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h .\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Untuk menghitung luas silinder Anda harus menjumlahkan luas lateralnya dengan luas kedua alasnya: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/problemes-optimisation-des-fonctions-verins.webp\" alt=\"masalah optimasi fungsi silinder.png\" class=\"wp-image-2507\" width=\"557\" height=\"271\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-edd9578a95d32143e6eaf0830db3854b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A_{cilindro} = A_{lateral}+2A_{base} = 2\\pi r h + 2\\pi r^2\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"330\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Luas silinder harus 54 cm <sup>2<\/sup> , jadi kita atur ekspresi sebelumnya sama dengan 54 untuk mendapatkan hubungan antara<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6868abdfd034048aa59644d2ac62353_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h :\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"19\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0ef4f7f8554876495f8907d4f71e1152_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A_{cilindro} =2\\pi r h + 2\\pi r^2 = 54\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"223\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami membersihkan <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f6868abdfd034048aa59644d2ac62353_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h :\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"19\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dd73c08d458b0ab2061031782d125ab9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2\\pi r h = 54 - 2\\pi r^2\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-abf53b37d2a3ae4784079bfd67d3007f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h = \\cfrac{54 - 2\\pi r^2}{2\\pi r}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"112\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengganti ekspresi yang ditemukan dalam fungsi yang akan dioptimalkan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2c47f99ce14b444ed73661b2b568e8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V=  \\pi r^2 \\cdot h \\xrightarrow{h \\ = \\ \\frac{54 - 2\\pi r^2}{2\\pi r} } V = \\pi r^2 \\cdot \\cfrac{54 - 2\\pi r^2}{2\\pi r}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"346\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-81d564fcd7cdf880066ed3eb6eb9a18a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V = \\cancel{\\pi}  r^{\\cancel{2}} \\cdot \\cfrac{54 - 2\\pi r^2}{2 \\cancel{\\pi} \\cancel{r}} =r \\cdot \\cfrac{54 - 2\\pi r^2}{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"278\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f95e7e1fc6088ba84a7b3885fe929d58_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V(r) = r \\cdot (27 - \\pi r^2)= 27r - \\pi r^3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"259\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 2: Hitung turunan dari fungsi yang akan dioptimalkan.<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-58e3403f2812564067058ece1bcd83ec_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V(r)=27r - \\pi r^3\\ \\longrightarrow \\ V'(r)= 27-3 \\pi r^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"324\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 3: Temukan titik kritisnya.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk menemukan titik kritis dari fungsi tersebut, kita menyelesaikannya <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e868c9ed52907fbe13197b00c29b7d21_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V'(r)=0:\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"83\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d3de17aa96e46530402559cf14e8db4d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V'(r)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"74\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-10638a98b4a67b085c0854f95c86a65b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"27-3 \\pi r^2=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"108\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8e31d335383816f692cd02cb2ca8f55b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-3 \\pi r^2=-27\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"104\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ff57ef2a3aa07b3c9f9f76a9cb00f484_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r^2=\\cfrac{-27}{-3\\pi }\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"82\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7d9e55eb22dc67a402b53bbb9ca17298_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r^2=2,86\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"75\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8c7c4c4acf5b028e2dbba11dfc83d20b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sqrt{r^2}=\\sqrt{2,86}\" title=\"Rendered by QuickLaTeX.com\" height=\"21\" width=\"103\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-01af3fa2bc910bd2da923aa2c83e1d7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r=1,69\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"67\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <strong>Langkah 4: Pelajari monotonisitas suatu fungsi dan tentukan maksimum atau minimum fungsi tersebut.<\/strong><\/p>\n<p class=\"has-text-align-left\"> Untuk mempelajari monotonisitas suatu fungsi, kita nyatakan titik kritis yang terdapat pada garis bilangan: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-169.webp\" alt=\"\" class=\"wp-image-2508\" width=\"232\" height=\"90\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Dan sekarang kita evaluasi tanda turunannya pada setiap interval, untuk mengetahui apakah fungsinya naik atau turun. Oleh karena itu, kita mengambil sebuah titik di setiap interval (bukan titik kritisnya) dan melihat tanda apa yang dimiliki turunannya pada titik tersebut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8d2aa45b6cfc986ec1e33cdd5e9266e3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V'(0)= 27-3 \\pi\\cdot 0^2 = 27-0 = +27 \\ \\rightarrow \\ \\bm{+}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"333\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2c599118454ccdcc0e318f01ac61b84d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V'(2)= 27-3 \\pi \\cdot 2^2 = 27-37,70 = -10,70 \\ \\rightarrow \\ \\bm{-}\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"393\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-169-positif-negatif.webp\" alt=\"\" class=\"wp-image-2509\" width=\"249\" height=\"176\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Jika turunannya positif berarti fungsinya meningkat, dan jika turunannya negatif berarti fungsinya menurun. Oleh karena itu, interval pertumbuhan dan penurunannya adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Pertumbuhan:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b5e2776182fc7c0a5138adfee1aafaaf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(-\\infty,1,69)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"86\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Mengurangi:<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f4ac44f6269498e03069a77e1989c8be_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(1,69,+\\infty)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"86\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Fungsinya berubah dari naik ke turun pada r=1,69, jadi <strong>r=1,69 cm adalah fungsi maksimumnya<\/strong> .<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, r=1,69 adalah nilai jari-jari yang menghasilkan volume maksimum. Sekarang kita menghitung tingginya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-381f3c5eb279572f486e28e68f0c5af2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"h = \\cfrac{54 - 2\\pi \\cdot 1,69^2}{2\\pi \\cdot1,69} = \\cfrac{54 - 17,94}{10,62} = 3,39\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"316\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi nilai yang menjadikan volume maksimum adalah:<\/p>\n<p class=\"has-text-align-center\"> <strong>Radio<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5c99f9d93c8a300be7afef76dfb71379_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{= r = 1,69} \\ \\mathbf{cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"117\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"> <strong>Tinggi<\/strong><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5ee2564c5e4b2a4e4409c392e5d01627_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{= h = 3,39} \\ \\mathbf{cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"119\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Di sini kami menjelaskan bagaimana masalah optimasi fungsi diselesaikan secara bertahap. Selain itu, Anda akan dapat berlatih dengan latihan yang diselesaikan pada masalah optimasi. Apa masalah optimasi? Masalah optimasi adalah masalah dimana seseorang harus mencari maksimum atau minimum suatu fungsi. Misalnya, masalah optimasi akan melibatkan penghitungan fungsi maksimum yang menentukan keuntungan perusahaan. Bagaimana mengatasi masalah &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/id\/masalah-optimasi\/\"> <span class=\"screen-reader-text\">Masalah optimasi<\/span> Selengkapnya &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[49],"tags":[],"class_list":["post-42","post","type-post","status-publish","format-standard","hentry","category-representasi-fungsi"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Masalah optimasi -<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/id\/masalah-optimasi\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Masalah optimasi -\" \/>\n<meta property=\"og:description\" content=\"Di sini kami menjelaskan bagaimana masalah optimasi fungsi diselesaikan secara bertahap. Selain itu, Anda akan dapat berlatih dengan latihan yang diselesaikan pada masalah optimasi. Apa masalah optimasi? Masalah optimasi adalah masalah dimana seseorang harus mencari maksimum atau minimum suatu fungsi. Misalnya, masalah optimasi akan melibatkan penghitungan fungsi maksimum yang menentukan keuntungan perusahaan. 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