{"id":38,"date":"2023-09-17T10:59:38","date_gmt":"2023-09-17T10:59:38","guid":{"rendered":"https:\/\/mathority.org\/id\/diferensiasi-suatu-fungsi\/"},"modified":"2023-09-17T10:59:38","modified_gmt":"2023-09-17T10:59:38","slug":"diferensiasi-suatu-fungsi","status":"publish","type":"post","link":"https:\/\/mathority.org\/id\/diferensiasi-suatu-fungsi\/","title":{"rendered":"Diferensiabilitas suatu fungsi"},"content":{"rendered":"<p>Pada artikel ini Anda akan mempelajari cara mempelajari diferensiabilitas suatu fungsi, yaitu apakah suatu fungsi dapat terdiferensiasi atau tidak. Selain itu, kita akan melihat hubungan antara diferensiasi dan kontinuitas suatu fungsi. Dan terakhir, kita akan mempelajari diferensiasi fungsi sepotong-sepotong. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"derivabilidad-y-continuidad-de-una-funcion\"><\/span> Diferensiabilitas dan kontinuitas suatu fungsi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Kontinuitas dan diferensiabilitas<\/strong> suatu fungsi pada suatu titik berhubungan sebagai berikut:<\/p>\n<ul>\n<li> Jika suatu fungsi terdiferensiasi di suatu titik, maka fungsi tersebut kontinu di titik tersebut.<\/li>\n<li> Jika suatu fungsi tidak kontinu di suatu titik, maka fungsi tersebut juga tidak terdiferensiasi di titik tersebut.<\/li>\n<\/ul>\n<p> Namun kebalikan dari teorema ini salah: hanya karena suatu fungsi kontinu di suatu titik tidak berarti fungsi tersebut selalu terdiferensiasi di titik tersebut.<\/p>\n<p> Anda juga dapat melihat apakah suatu fungsi dapat terdiferensiasi pada suatu titik dari representasi grafisnya:<\/p>\n<ul>\n<li> Jika <strong>titik tersebut mulus,<\/strong> maka fungsinya terdiferensiasi pada titik tersebut.<\/li>\n<li> Jika suatu <strong>titik bersudut,<\/strong> maka fungsinya kontinu tetapi tidak terdiferensiasi pada titik tersebut. <\/li>\n<\/ul>\n<div class=\"wp-block-columns is-layout-flex wp-container-15\">\n<div class=\"wp-block-column is-vertically-aligned-center is-layout-flow\">\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/exercices-resolus-pour-representer-une-fonction-quadratique-incomplete.webp\" alt=\"\" class=\"wp-image-140\" width=\"250\" height=\"279\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"> <span style=\"color:#1976d2;\"><strong>Titik pemulusan<\/strong><\/span> di x=0:<br \/> fungsi kontinu dan terdiferensiasi pada tahap ini. <\/p>\n<\/div>\n<div class=\"wp-block-column is-layout-flow\">\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/comment-representer-graphiquement-une-fonction-avec-valeur-absolue.webp\" alt=\"\" class=\"wp-image-230\" width=\"286\" height=\"305\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p class=\"has-text-align-center\"> <span style=\"color:#1976d2;\"><strong>Titik sudut<\/strong><\/span> di x=2:<br \/> berfungsi kontinu tetapi tidak terdiferensiasi pada tahap ini. <\/p>\n<\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"derivabilidad-de-una-funcion-a-trozos\"><\/span> Diferensiabilitas fungsi sepotong-sepotong<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Setelah kita mengetahui hubungan antara kontinuitas dan diferensiabilitas suatu fungsi, kita akan mempelajari cara mempelajari diferensiabilitas suatu fungsi terdefinisi sedikit demi sedikit.<\/p>\n<p> Anda dapat mengetahui apakah suatu fungsi sepotong-sepotong dapat terdiferensiasi di suatu titik dengan menghitung <strong>turunan lateral<\/strong> di titik tersebut: <\/p>\n<div style=\"background-color:#FFF3E0; padding-top: 23px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 20px; border-radius:20px;\">\n<ul style=\"color:#64B5F6; font-weight: bold;\">\n<li> <span style=\"color:#000000;font-weight: normal;\">Jika turunan lateral di suatu titik tidak sama, maka fungsi tersebut tidak terdiferensiasi di titik tersebut:<\/span><\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-97c60c64dc01a7e0a9084313d15b0886_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(x_o^-) \\neq f'(x_o^+) \\ \\longrightarrow\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"163\" style=\"vertical-align: -5px;\"><\/p>\n<p> Itu tidak dapat dikurangkan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-67ab403a6241009b92035b251f86c88e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x_o\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"17\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<ul style=\"color:#64B5F6; font-weight: bold;\">\n<li> <span style=\"color:#000000;font-weight: normal;\">Jika turunan lateral di suatu titik berimpit, maka fungsi tersebut terdiferensiasi di titik tersebut:<\/span><\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3f9477828318b9e6392465762f831642_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(x_o^-) = f'(x_o^+) \\ \\longrightarrow\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"163\" style=\"vertical-align: -5px;\"><\/p>\n<p> Ya, itu bisa dibedakan <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-67ab403a6241009b92035b251f86c88e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x_o\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"17\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<\/div>\n<div style=\"background-color:#FFFDE7; padding-top: 23px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;\">\n<p style=\"text-align:left\"> <strong>Catatan:<\/strong> Agar suatu fungsi dapat terdiferensiasi di suatu titik, maka fungsi tersebut harus kontinu di titik tersebut. Oleh karena itu, sebelum menghitung turunan lateral, kita perlu memastikan bahwa fungsinya kontinu pada titik tersebut. Jika Anda belum mengetahui bagaimana kontinuitas dipelajari pada suatu titik, Anda dapat melihat caranya di tautan berikut:<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Lihat:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/id\/kontinuitas-fungsi-kontinuitas-suatu-fungsi\/\">kontinuitas suatu fungsi di suatu titik<\/a><\/span><\/p>\n<\/div>\n<p> Sekarang mari kita lihat contoh cara menghitung turunan suatu fungsi yang didefinisikan sepotong-sepotong di suatu titik:<\/p>\n<ul>\n<li> Pelajari kontinuitas dan diferensiasi fungsi berikut yang didefinisikan sepotong demi sepotong di titik x=2:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a98eee72521c68fd394eb6209a7d0a59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)=  \\left\\{ \\begin{array}{lcl} 3x^2-6x &amp; \\text{si} &amp;  x<2 \\\\[2ex] 6\\ln (x-1) &amp; \\text{si} &amp; x\\geq 2 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"249\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Fungsi kedua bagian tersebut kontinu pada intervalnya masing-masing, namun perlu diketahui apakah fungsi tersebut kontinu pada titik kritis x=2. Untuk melakukan ini, kita menyelesaikan batas lateral fungsi di titik:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dad5bcb0055431aa87a67068c04d2ce2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 2^-} f(x) = \\lim\\limits_{x\\to 2^-} \\bigl(3x^2-6x\\bigr) = 3\\cdot2^2-6\\cdot2=12-12=\\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"449\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-31e1ba2ea2c5fd9fa86e5cefed0e5535_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 2^+} f(x) = \\lim\\limits_{x\\to 2^+} 6\\ln (x-1) = 6\\ln (2-1)=6 \\ln 1=6 \\cdot 0= \\bm{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"28\" width=\"474\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p> Batas lateral pada titik kritis memberikan hasil yang sama, sehingga <strong>fungsinya kontinu di titik x=2.<\/strong><\/p>\n<p> Setelah kita mengetahui bahwa suatu fungsi kontinu di x=2, kita akan mempelajari diferensiasi fungsi tersebut di titik tersebut. Untuk melakukan ini, <strong>kita menghitung turunan lateral<\/strong> dari fungsi yang didefinisikan dalam potongan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3709995609d0f69f382ff651e397c00a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)= \\left\\{ \\begin{array}{lcl} 6x-6 &amp; \\text{si} &amp;  x<2 \\\\[2ex] \\cfrac{6}{x-1} &amp; \\text{si} &amp; x\\geq 2 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"76\" width=\"222\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Kami sekarang mengevaluasi setiap turunan lateral pada titik kritis:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ca27189960575c1151402d040bfa76f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(2^-)=6\\cdot2-6=12-6 = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"239\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-058310a16d7d545ea56e99517845842b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(2^+)=\\cfrac{6}{2-1} = \\cfrac{6}{1} = \\bm{6}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"181\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Kedua turunan lateralnya memberikan hasil yang sama, sehingga fungsinya terdiferensiasi di x=2 dan nilai turunannya adalah 6:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aadf046f27916c46f0a302d6e0c34113_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(2^-) = f'(2^+) = 6 \\ \\longrightarrow \\ \\bm{f'(2) = 6}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"275\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Sebaliknya, jika turunan lateral memberikan hasil yang berbeda, berarti fungsi tersebut tidak terdiferensiasi pada x=2. Dengan kata lain, turunannya tidak akan ada pada saat ini.<\/p>\n<p> Terakhir, ingatlah bahwa prosedur ini juga berlaku untuk mempelajari diferensiasi suatu fungsi nilai absolut, karena fungsi nilai absolut juga dapat didefinisikan secara sepotong-sepotong. Anda dapat melihat cara mengonversi fungsi nilai absolut menjadi potongan di sini:<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Lihat:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/id\/fungsi-dengan-nilai-absolut\/\">cara mendefinisikan fungsi dengan nilai absolut sedikit demi sedikit<\/a><\/span> <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-derivabilidad-de-una-funcion\"><\/span> Latihan yang diselesaikan tentang diferensiasi suatu fungsi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Pelajarilah kontinuitas dan diferensiasi fungsi sepotong-sepotong berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3656065bb8de98bd07da153f26fd326e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\left\\{ \\begin{array}{lcl} x^3-4x^2 + 5 &amp; \\text{si} &amp;  x<1 \\\\[2ex] -x^2+3x &amp; \\text{si} &amp; x\\geq 1 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"265\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Fungsi kedua bagian tersebut kontinu, tetapi kita harus melihat apakah fungsi tersebut kontinu pada titik kritis x=1. Untuk melakukan ini, kita menyelesaikan batas lateral fungsi di titik tersebut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cf8ad0b4baa312a5ae1bb073e5c8ff8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 1^-} f(x) = \\lim\\limits_{x\\to 1^-} \\bigl(x^3-4x^2 + 5\\bigr)=1^3-4\\cdot 1^2 + 5=2\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"413\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f25bd83439fbb5cbd148b8be88f8770b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 1^+} f(x) = \\lim\\limits_{x\\to 1^+} \\bigl( -x^2+3x \\bigr)=-1^2+3\\cdot 1=2\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"364\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kedua batas lateral pada titik kritis memberikan hasil yang sama, sehingga fungsinya kontinu di x=1.<\/p>\n<p class=\"has-text-align-left\"> Setelah kita mengetahui bahwa fungsi tersebut kontinu pada titik kritisnya, kita akan mempelajari apakah fungsi tersebut terdiferensiasi pada titik yang sama. Oleh karena itu kami menghitung turunan lateral:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-42451fa799527167fe9a2e2259248870_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)= \\left\\{ \\begin{array}{lcl} 3x^2-8x  &amp; \\text{si} &amp;  x<1 \\\\[2ex] -2x+3 &amp; \\text{si} &amp; x\\geq 1 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"240\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengevaluasi dua turunan lateral di x=1; <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c9afcac5ff2f762d2b471725d4e755fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^-)=3\\cdot1^2-8\\cdot 1=3-8=-5\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"272\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dd2d9e21e09ecc434cafbf5fb0b5afaa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^+)=-2\\cdot 1+3=-2+3 =1\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"256\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Turunan lateralnya tidak berimpit di titik x=1 sehingga fungsinya tidak terdiferensiasi di titik tersebut. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-73b9cb3dada6f8aea03ffc1342d0f22f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^-) \\neq f'(1^+) \\ \\longrightarrow \\ \\cancel{\\exists} \\ f'(1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"225\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Analisislah diferensiasi dan kontinuitas fungsi berikut yang didefinisikan dalam beberapa bagian: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0d118e3904c810abd15e427e9c7d0504_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\left\\{ \\begin{array}{lcl} \\sqrt{4x} &amp; \\text{si} &amp;  x\\leq 1 \\\\[2ex] 2+\\ln x &amp; \\text{si} &amp; x> 1 \\end{array} \\right.&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;65&#8243; width=&#8221;226&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Fungsi kedua bagian tersebut kontinu pada intervalnya, namun perlu juga diketahui apakah fungsi tersebut kontinu pada titik kritis perubahan definisi x=1. Oleh karena itu kami mendefinisikan batas lateral fungsi pada titik ini: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2c4fb7ef0ee9b3feeb5e15654528fc71_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 1^-} f(x) = \\lim\\limits_{x\\to 1^-} \\sqrt{4x} = \\sqrt{4\\cdot 1} = \\sqrt{4}=2\" title=\"Rendered by QuickLaTeX.com\" height=\"30\" width=\"323\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e509a70bd0e356f44ccac7ba6f075f8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 1^+} f(x) = \\lim\\limits_{x\\to 1^+} \\bigl( 2+\\ln x \\bigr) = 2 + \\ln (1) = 2+0 =2\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"399\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kedua batas lateral pada titik kritis memberikan hasil yang sama, sehingga fungsinya kontinu di x=1.<\/p>\n<p class=\"has-text-align-left\"> Dan sekarang kita mempelajari apakah fungsi tersebut terdiferensiasi pada titik ini dengan menghitung turunan lateral:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8261f3d268b47d9171710997c8cc70bd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)= \\left\\{ \\begin{array}{lcl} \\cfrac{4}{2\\sqrt{4x}}  &amp; \\text{si} &amp;  x<1 \\\\[4ex] \\cfrac{1}{x} &amp; \\text{si} &amp; x\\geq 1 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"108\" width=\"217\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami mengevaluasi dua turunan lateral di x=1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-de4ee71a175b34be07061d47470afe0d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^-)=\\cfrac{4}{2\\sqrt{4\\cdot1}}=\\cfrac{4}{2\\sqrt{4}}=\\cfrac{4}{2\\cdot 2}=\\cfrac{4}{4}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"309\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-594a8d05da432ab8962ff799d62d25a7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^+)=\\cfrac{1}{1}=1\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"115\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Turunan lateralnya sama, sehingga fungsinya terdiferensiasi di x=1 dan nilai turunannya adalah 1. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a58ba22b03193839f5070da4e2c1faf5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(1^-) = f'(1^+) = 1 \\ \\longrightarrow \\ \\bm{f'(1) = 1}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"274\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Tentukan apakah fungsi sepotong-sepotong berikut ini kontinu dan terdiferensiasi pada seluruh domainnya:<\/p>\n<pre class=\"ql-errors\"> *** QuickLaTeX cannot compile formula:\n\\displaystyle f(x)= \\left\\{ \\begin{array}{lcl} x^2+2x+1 &amp; \\text{si} &amp; x\\leq -1 \\\\[2ex] 2x+2 &amp; \\text{ si} &amp; -1&lt;div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria- expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\"&gt;&lt;div class=\"otfm-sp__title\"&gt; &lt;strong&gt;View solution&lt;\/strong&gt;&lt;\/div&gt;&lt; \/div&gt; The functions of all three parts are continuous, but we still need to check if the function is continuous at critical points. We therefore first check the continuity of the function at the point x=-1 by solving the lateral limits at this point:\n\n*** Error message:\nMissing $ inserted.\nleading text: \\displaystyle\nMissing { inserted.\nleading text: ...=\"wp-block-otfm-box-spoiler-start otfm-sp__\nMissing { inserted.\nleading text: ...ox-spoiler-start otfm-sp__wrapper otfm-sp__\nMissing { inserted.\nleading text: ...m-sp__wrapper otfm-sp__box js-otfm-sp-box__\nMissing { inserted.\nleading text: ...fm-sp__box js-otfm-sp-box__closed otfm-sp__\nYou can't use `macro parameter character #' in math mode.\nleading text: ...=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#\nMissing { inserted.\nleading text: ...e=\"text-align:center\"&gt;&lt;div class=\"otfm-sp__\nPlease use \\mathaccent for accents in math mode.\nleading text: ...g&gt;&lt;\/div&gt;&lt;\/div&gt; The functions of the three parts\nPlease use \\mathaccent for accents in math mode.\nleading text: ...are continuous, but we still need to see\n\n<\/pre>\n<p> \\lim\\limits_{x\\to -1^-} f(x) = \\lim\\limits_{x\\to -1^-} \\bigl(x^2+2x+1\\bigr) = (-1)^ 2+2(-1)+1 =0 \\lim\\limits_{x\\to -1^+} f(x) = \\lim\\limits_{x\\to -1^+} \\bigl(2x+2\\bigr ) = 2(-1)+2=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fadd0ce26a497a6a6c73bfaa7ed28f4e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Les deux limites lat\u00e9rales au point x=-1 donnent le m\u00eame r\u00e9sultat, donc la fonction est continue en x=-1. Nous allons maintenant v\u00e9rifier si la fonction est continue ou non au point x=2 : \" title=\"Rendered by QuickLaTeX.com\" height=\"56\" width=\"765\" style=\"vertical-align: 0px;\"><\/p>\n<p> \\lim\\limits_{x\\ke 2^-} f(x) = \\lim\\limits_{x\\ke 2^-} \\bigl(2x+2\\bigr) = 2\\cdot 2+2=4+2= 6 \\lim\\limits_{x\\to 2^+} f(x) = \\lim\\limits_{x\\to 2^+} \\bigl( -x^2+8x\\bigr) = -2^2+8\\ cdot 2 = -4+16=12<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c93f9d5e367031de798abaf833523710_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" En revanche, les limites lat\u00e9rales au point x=2 ne donnent pas le m\u00eame r\u00e9sultat, donc la fonction n'est pas continue en x=2. De plus, comme il n'est pas continu \u00e0 ce stade, il ne sera pas non plus d\u00e9rivable \u00e0 x=2. Une fois que l'on a \u00e9tudi\u00e9 la continuit\u00e9 de la fonction, on passe \u00e0 la diff\u00e9rentiabilit\u00e9. On calcule donc les d\u00e9riv\u00e9es lat\u00e9rales :\" title=\"Rendered by QuickLaTeX.com\" height=\"82\" width=\"908\" style=\"vertical-align: -4px;\"><\/p>\n<p> \\displaystyle f'(x)= \\kiri\\{ \\begin{array}{lcl} 2x+2 &amp; \\text{si} &amp; x\\leq -1 \\\\[2ex] 2 &amp; \\text{si} &amp; -1<\/p>\n<p class=\"has-text-align-left\"> Kita sudah mengetahui bahwa fungsi tersebut tidak terdiferensiasi pada x=2, jadi kita tinggal mempelajari apakah fungsi tersebut terdiferensiasi pada x=-1. Untuk melakukannya, kita evaluasi dua turunan lateral di titik: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cafb8bbe438865e050973664b6915fa9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(-1^-)=2(-1)+2 = -2+2=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"272\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5781d213b36777be5b2611a84ca95e96_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(-1^+)=2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"95\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Turunan lateralnya tidak berimpit di titik x=-1, sehingga fungsinya tidak terdiferensiasi di titik tersebut. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f3674d70c292d967d7074a0b4bee230e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(-1^-) \\neq f'(-1^+) \\ \\longrightarrow \\ \\cancel{\\exists} \\ f'(-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"267\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 4<\/h3>\n<p> Hitung nilai parameter a dan b sehingga fungsi sepotong-sepotong berikut ini kontinu dan terdiferensiasi di seluruh domainnya: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ce34d5d8a949fb3a0b904e9bf7d32f5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f(x)= \\left\\{ \\begin{array}{lcl} 2e^{x-3} + a &amp; \\text{si} &amp;  x< 3 \\\\[2ex](x-b)^2 &amp; \\text{si} &amp; x\\geq 3 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"243\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Berapa pun nilai yang tidak diketahui, fungsi tersebut kontinu dan terdiferensiasi di semua titik kecuali pada x=3, yang kontinuitas dan diferensiasinya harus diperiksa.<\/p>\n<p class=\"has-text-align-left\"> Agar suatu fungsi kontinu di suatu titik, kedua batas lateral pada titik tersebut harus berimpit. Oleh karena itu, kami memperkirakan batas lateral pada titik kritis: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21920afd0fe6c6a35983a39034b3f9f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 3^-} f(x) = \\lim\\limits_{x\\to 3^-} \\bigl(2e^{x-3}+a\\bigr) = 2e^{3-3}+a = 2 \\cdot e^0+a =2\\cdot 1 +a = 2+a\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"566\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f527d4602a1bdc26d763df1064b956d4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{x\\to 3^+} f(x) = \\lim\\limits_{x\\to 3^+} (x-b)^2 = (3-b)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"29\" width=\"282\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, kedua nilai yang diperoleh dari batas lateral harus sama agar fungsi tersebut kontinu:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3bec8303f39289b7f2cd7e6e439703c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2+a = (3-b)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"123\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita akan menganalisis diferensiasi pada titik x=3. Kami menemukan turunan lateral:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d542fc9488644f0c144059ae1403d961_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle f'(x)= \\left\\{ \\begin{array}{lcl} 2e^{x-3}  &amp; \\text{si} &amp;  x< 3 \\\\[2ex]2(x-b) &amp; \\text{si} &amp; x\\geq 3 \\end{array} \\right.\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"236\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengevaluasi dua turunan lateral pada titik kritis: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0fb3afef2352f0f5f96302b987a5de9c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(3^-)= 2e^{3-3} =  2e^0 = 2\\cdot 1 = 2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"250\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-360474b477f347569ad1e3b64b63cc79_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f'(3^+)=2(3-b) = 6 - 2b\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"205\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, agar suatu fungsi dapat terdiferensiasi pada x=3, nilai yang diperoleh dari turunan lateralnya harus sama:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8a98a45230845ad86846cd7db486af0b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2=6-2b\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"80\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan dengan menyelesaikan persamaan ini kita dapat mencari nilai b: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7f53d30cae8270029d25ea28322b6986_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2b=6-2\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"79\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c263311ac7433ce2b417bb7ad0ef449b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2b=4\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"49\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7dd2f0fd5e5207a815bf5789ada67541_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"b=\\cfrac{4}{2} =\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"74\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Terakhir, setelah kita mengetahui nilai parameter b, kita dapat menghitung nilai parameter a dengan menyelesaikan persamaan yang kita peroleh sebelumnya pada batas lateral: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3bec8303f39289b7f2cd7e6e439703c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2+a = (3-b)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"123\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6468721c373f078ad3e97a290c2d86f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2+a = (3-2)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"124\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d1cc01602cd205cae7b9c9b8ba391760_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"2+a =1\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"72\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ce22cc1bba3ee9612a7f8cb2624d2483_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a =1-2\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"72\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-be5f9e4b074e8b3ba5d0e96f8ae4e2cd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{a =-1}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"55\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Pada artikel ini Anda akan mempelajari cara mempelajari diferensiabilitas suatu fungsi, yaitu apakah suatu fungsi dapat terdiferensiasi atau tidak. Selain itu, kita akan melihat hubungan antara diferensiasi dan kontinuitas suatu fungsi. Dan terakhir, kita akan mempelajari diferensiasi fungsi sepotong-sepotong. Diferensiabilitas dan kontinuitas suatu fungsi Kontinuitas dan diferensiabilitas suatu fungsi pada suatu titik berhubungan sebagai berikut: &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/id\/diferensiasi-suatu-fungsi\/\"> <span class=\"screen-reader-text\">Diferensiabilitas suatu fungsi<\/span> Selengkapnya &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[38],"tags":[],"class_list":["post-38","post","type-post","status-publish","format-standard","hentry","category-derivatif"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Diferensiabilitas suatu fungsi (teori dan latihan yang diselesaikan)<\/title>\n<meta name=\"description\" content=\"Bagaimana mempelajari diferensiasi suatu fungsi dan mengetahui apakah suatu fungsi dapat terdiferensiasi atau tidak. 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