{"id":26,"date":"2023-09-17T11:04:43","date_gmt":"2023-09-17T11:04:43","guid":{"rendered":"https:\/\/mathority.org\/id\/tingkat-perubahan-rata-rata-dan-seketika\/"},"modified":"2023-09-17T11:04:43","modified_gmt":"2023-09-17T11:04:43","slug":"tingkat-perubahan-rata-rata-dan-seketika","status":"publish","type":"post","link":"https:\/\/mathority.org\/id\/tingkat-perubahan-rata-rata-dan-seketika\/","title":{"rendered":"Tingkat perubahan rata-rata dan seketika"},"content":{"rendered":"<p>Di sini kami menjelaskan apa yang dimaksud dengan laju perubahan, laju perubahan rata-rata, dan laju perubahan sesaat. Anda akan dapat melihat beberapa contoh tentang cara menghitung laju perubahan dan, sebagai tambahan, Anda akan dapat berlatih dengan latihan langkah demi langkah yang telah diselesaikan mengenai laju perubahan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-la-tasa-de-variacion\"><\/span> Berapa tingkat perubahannya?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Dalam matematika, laju perubahan (TV) suatu fungsi adalah selisih nilai suatu fungsi pada dua titik yang berbeda.<\/strong> Oleh karena itu, untuk menghitung laju perubahan antara dua titik, nilai fungsi pada kedua titik tersebut harus dikurangi.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c33fec724dd0a5bf45bfec5a911f5bcb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[a,b]=f(b)-f(a)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"171\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Misalnya, jika dua bayangan suatu fungsi adalah f(2)=1 dan f(5)=7, laju perubahannya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8696c8ddc5db28bea4a9b14bc6dc0b9a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[2,5]=f(5)-f(2)=7-1=6\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"269\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Kita baru saja melihat arti matematis dari laju perubahan, namun dalam ilmu ekonomi konsep laju perubahan memiliki arti sebagai berikut:<\/p>\n<p> Dalam ilmu ekonomi, laju perubahan antara dua nilai adalah selisih keduanya yang dinyatakan dalam persentase, yaitu laju perubahan suatu variabel antara periode yang berbeda adalah perubahan relatifnya. Oleh karena itu, untuk menghitung laju perubahan, nilai kedua periode yang berbeda dikurangkan dan hasil yang diperoleh dibagi dengan nilai periode awal.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3a6392a6712643e5eeddbf7226523e42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[t,t+n]=\\cfrac{Y_{t+n}-Y_t}{Y_t}\\cdot 100\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"227\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<p> Misalnya, jika nilai saham tertentu meningkat dari \u20ac35 menjadi \u20ac50 dalam satu bulan, tingkat perubahannya adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-17a18b6b77c1e1b21cad5d1ffab56aca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[t,t+1]=\\cfrac{50-35}{35}\\cdot 100=42,86 \\ \\%\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"296\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Mengingat dua kemungkinan arti laju perubahan, dalam artikel ini kita akan fokus pada pemahaman definisi matematis laju perubahan. Dua jenis laju perubahan dapat dibedakan: laju perubahan rata-rata dan laju perubahan sesaat. Di bawah ini Anda memiliki penjelasan masing-masing jenisnya.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"tasa-de-variacion-media\"><\/span> Tingkat perubahan rata-rata<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Laju perubahan rata-rata (TVM) suatu fungsi dalam suatu interval adalah banyaknya satuan kenaikan (atau penurunan) fungsi tersebut untuk setiap satuan kenaikan variabel bebasnya.<\/strong> Oleh karena itu, laju perubahan rata-rata suatu fungsi dihitung dengan membagi pertumbuhan fungsi dalam suatu interval dengan amplitudo interval yang sama.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a08373207642a78dec20dd28a9dafc4b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM}[a,b]=\\cfrac{f(b)-f(a)}{b-a}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"191\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Agar Anda dapat melihat cara menghitung tingkat perubahan rata-rata, kami telah menyelesaikan contoh langkah demi langkah di bawah ini. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-del-calculo-de-la-tasa-de-variacion-media-de-una-funcion\"><\/span> Contoh penghitungan rata-rata laju perubahan suatu fungsi<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li> Hitung laju perubahan rata-rata pada interval [2.5] dari fungsi berikut:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e583988ce73cdf54a12306a64c97cc42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x) = x^2-1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"106\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Pertama, kita menghitung nilai fungsi pada x=2 dan x=5:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-57a8756268ece6ee3543392da3aa5ee3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(5)= 5^2-1=25-1=24\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"217\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-7163ad8fbbfd700e474e6d40164c8cb9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2)=2^2-1=4-1=3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"200\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Dan kemudian kita menghitung laju rata-rata perubahan fungsi dalam interval hanya dengan menerapkan rumus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aca6688a94500231cb464ce5ca91685c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [a,b] = \\cfrac{f(b)-f(a)}{b-a}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"191\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-dba3fad93a4b7e04a5d6f1517eb6dc1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [2,5]=\\cfrac{f(5)-f(2)}{5-2} = \\cfrac{24 - 3}{5-2} = \\cfrac{21}{3} = \\bm{7}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"341\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Karena hasil TVM[2,5] positif, berarti fungsi tersebut bertambah pada interval [2,5]. Sebaliknya, jika hasilnya negatif, berarti fungsinya menurun pada interval tersebut. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"interpretacion-geometrica-de-la-tasa-de-variacion-media\"><\/span> Interpretasi geometris dari tingkat perubahan rata-rata<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Secara geometris, laju perubahan rata-rata suatu fungsi dalam suatu interval menyatakan kemiringan garis yang menghubungkan titik-titik ekstrem pada interval tersebut. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/taux-de-variation-moyen.webp\" alt=\"tingkat perubahan rata-rata\" class=\"wp-image-1678\" width=\"337\" height=\"378\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"tasa-de-variacion-instantanea\"><\/span>Tingkat perubahan seketika<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Laju perubahan sesaat (TVI) suatu fungsi pada suatu titik adalah batas kenaikan relatif fungsi tersebut pada suatu interval yang sangat kecil.<\/strong> Oleh karena itu, laju perubahan sesaat dihitung dengan menyelesaikan limit hasil bagi <em>f(a+h)-f(a)<\/em> <em>dengan<\/em> <em>h<\/em> mendekati nol.<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-605387fef74bd8fe7f7e8a3e75686a7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\text{TVI}(a)=\\lim_{h \\to 0}\\frac{f(a+h)-f(a)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Nilai laju perubahan sesaat dapat bernilai positif, negatif, atau nol, yang berarti fungsi pada titik tersebut masing-masing meningkat, menurun, atau tetap sama pada titik tersebut. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-del-calculo-de-la-tasa-de-variacion-instantanea-de-una-funcion\"><\/span> Contoh penghitungan laju perubahan sesaat suatu fungsi<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li> Hitung laju perubahan sesaat di titik x=2 dari fungsi berikut:<\/li>\n<\/ul>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a0f6973d1b2b1b370cb20764d5a954a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x) = x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"75\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Untuk menghitung laju perubahan sesaat, kita perlu menerapkan rumus:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef687e3c0bab81c2a8eaa578fcc41b9b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (a) = \\lim\\limits_{h \\to 0} \\cfrac{f(a+h)-f(a)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fd6499ec6074ceea794309155c7d788d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (2) = \\lim\\limits_{h \\to 0} \\cfrac{f(2+h)-f(2)}{h} =  \\lim\\limits_{h \\to 0} \\cfrac{(2+h)^2-2^2}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"390\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Kami menyelesaikan identitas penting:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-21ea1067eb0c47009dd7f9c214a16e4a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0}  \\cfrac{2^2+h^2+2\\cdot 2 \\cdot h -2^2}{h} = \\lim\\limits_{h \\to 0}  \\cfrac{4+h^2+4h -4}{h} = \\lim\\limits_{h \\to 0}  \\cfrac{h^2+4h}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"496\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#FF9B28;\">\u27a4<\/span> Jika Anda tidak ingat lagi <u style=\"text-decoration-color:#FF9B28;\">rumus identitas penting<\/u> , Anda akan menemukan semua rumus di situs kami yang mengkhususkan diri pada polinomial: <u style=\"text-decoration-color:#FF9B28;\">www.polinomios.org<\/u><\/p>\n<p> Sekarang mari kita coba menyelesaikan limitnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b380a5546aa95d74c4da1a81e0e4665b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0}  \\cfrac{h^2+4h}{h} = \\cfrac{0^2+4\\cdot 0}{0} =\\cfrac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"221\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Tapi kami menemukan nol ketidakpastian antara nol, oleh karena itu:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ae32dac146777b5395b505ebf658af5f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0}  \\cfrac{h^2+4h}{h}= \\lim\\limits_{h \\to 0} \\cfrac{\\cancel{h}(h+4)}{\\cancel{h}} = \\lim\\limits_{h \\to 0} (h+4)\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"320\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Lihat:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/id\/nol-antara-nol-0-0-ketidakpastian\/\">cara menyelesaikan limit dengan ketidakpastian nol di antara nol<\/a><\/span><\/p>\n<p> Dan akhirnya kami memecahkan batasnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3b124f5a6537497e232294814f1d49b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} (h+4) = 0 +4 = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"27\" width=\"179\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p> Belum:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9504f8df3dcdd1c6954399b5a6aa0ef4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mathbf{TVI} \\bm{(2) = 4}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"93\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Karena hasil TVI(2) positif, berarti fungsinya bertambah pada x=2. Sebaliknya jika hasilnya negatif berarti fungsinya sedang menurun pada tahap ini. <\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"interpretacion-geometrica-de-la-tasa-de-variacion-instantanea\"><\/span> Interpretasi geometris dari laju perubahan sesaat<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Secara geometris, laju perubahan sesaat suatu fungsi di suatu titik menyatakan kemiringan garis singgung fungsi tersebut di titik yang sama. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/taux-de-changement-instantane.webp\" alt=\"tingkat perubahan seketika\" class=\"wp-image-1682\" width=\"336\" height=\"355\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<p> Jika dicermati, pengertian laju perubahan sesaat setara dengan <span style=\"text-decoration: underline;\"><a href=\"https:\/\/mathority.org\/id\/turunan\/\">konsep turunan suatu fungsi<\/a><\/span> . Jadi, laju perubahan sesaat juga digunakan untuk menghitung nilai turunan suatu fungsi di suatu titik. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-tasa-de-variacion\"><\/span> Latihan terpecahkan tentang tingkat perubahan<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Hitung nilai laju perubahan fungsi berikut pada interval [1,3]. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-52242e9edb560029e6861be262dc3418_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=x^2-5\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"106\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita tentukan nilai fungsi di ujung interval: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a68e7a97d5a6f45ee1d01481fe687da1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1)=1^2-5=1-5=-4\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"214\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a0d6343387ae4a98c94387008c73c791_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(3)=3^2-5=9-5=4\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"200\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan sekarang kita menerapkan rumus laju perubahan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c33fec724dd0a5bf45bfec5a911f5bcb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[a,b]=f(b)-f(a)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"171\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ab143c57ef36bb306946cbe760653ff_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TV}[1,3]=f(3)-f(1)=4-(-4)=4+4=\\bm{8}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"360\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Hitung laju perubahan rata-rata (TVM) dari fungsi berikut selama interval [1,4]: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b43717721aa2afd3fbc6d587213bbdef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=2x+1\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"107\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama kita hitung dulu gambaran fungsi di x=1 dan x=4. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0877ab6ef765a3944e138081718775cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(4)=2\\cdot4+1=9\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"151\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e2e61642cf8070ce3ae09b2eb3335c4a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1)=2\\cdot 1+1=3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"151\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami menerapkan rumus untuk tingkat perubahan rata-rata: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aca6688a94500231cb464ce5ca91685c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [a,b] = \\cfrac{f(b)-f(a)}{b-a}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"191\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-55ff356ed3f6444ca49c49e39dd46072_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [1,4] = \\cfrac{f(4)-f(1)}{4-1} = \\cfrac{9-3}{4-1}=\\cfrac{6}{3} = \\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"323\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Temukan laju rata-rata perubahan fungsi berikut dalam interval [-1.3]: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a04612aafb771e8771b2810a18e18475_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=(x+1)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"120\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menentukan laju perubahan rata-rata, pertama-tama kita perlu menghitung f(-1) dan f(3): <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3da577fe4ac481741007375057aa116e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(3)=(3+1)^2=(4)^2=16\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"213\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-8b7269aaa1c01fb9a5e218a0a627483b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(-1)=((-1)+1)^2=(0)^2=0\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"246\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami sekarang menggunakan rumus untuk tingkat perubahan rata-rata: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aca6688a94500231cb464ce5ca91685c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [a,b] = \\cfrac{f(b)-f(a)}{b-a}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"191\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-080aef07d76e5d8823128118052fb808_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [-1,3] = \\cfrac{f(3)-f(-1)}{3-(-1)} = \\cfrac{16-0}{3+1}=\\cfrac{16}{4} = \\bm{4}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"369\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 4<\/h3>\n<p> Hitung rata-rata laju perubahan pada interval [2,4] dari fungsi yang ditunjukkan pada grafik berikut: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/representation-d-une-fonction-quadratique-ou-parabole.webp\" alt=\"\" class=\"wp-image-137\" width=\"290\" height=\"328\" srcset=\"\" sizes=\"auto, \" data-src=\"\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Kami menerapkan rumus untuk tingkat perubahan rata-rata: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aca6688a94500231cb464ce5ca91685c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [a,b] = \\cfrac{f(b)-f(a)}{b-a}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"191\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-436fb10e74beb8c2ede9c9ac586d96c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM} [2,4]=\\cfrac{f(4)-f(2)}{4-2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"192\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Seperti yang kita lihat di rumus, kita perlu mencari nilai f(4) dan f(2). Dan ini dapat dengan mudah dilakukan dengan melihat representasi grafis dari fungsi tersebut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fad0fc656e95d7bc9517693b55a15540_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(4)=5\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"65\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e7d13ebd46205da0aa8ff41e5133ba3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2)=1\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"65\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan sekarang setelah kita mengetahui nilai fungsinya, kita substitusikan ke dalam rumus: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9a84929c02a38e91b072239affa6d9f0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVM}[2,4]=\\cfrac{f(4)-f(2)}{4-2}=\\cfrac{5-1}{4-2}=\\cfrac{4}{2}=\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"323\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 5<\/h3>\n<p> Hitung laju perubahan sesaat fungsi berikut di titik x=2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9de7457ac9ec3e1599c6f986c5ba57ee_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=3x\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"77\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menentukan laju perubahan fungsi sesaat di titik x=2 kita menerapkan rumus yang sesuai: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a66c321e96cb1e871b9c7debfee1f4bc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI}(a)=\\lim\\limits_{h \\to 0} \\cfrac{f(a+h)-f(a)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-73ee822823f921f75014cb9b50e47f51_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}\\text{TVI}(2)=\\lim\\limits_{h \\to 0} \\cfrac{f(2+h)-f(2)}{h}=\\\\[4ex]=\\lim\\limits_{h \\to 0} \\cfrac{3(2+h)-3\\cdot 2}{h} =\\\\[4ex]=\\lim\\limits_{h \\to 0} \\cfrac{6+3h-6}{h}= \\lim\\limits_{h \\to 0} \\cfrac{3h}{h} =\\\\[4ex]=\\lim\\limits_{h \\to 0} \\cfrac{3\\cancel{h}}{\\cancel{h}}=\\lim\\limits_{h \\to 0} 3 = \\bm{3}\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"239\" width=\"250\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 6<\/h3>\n<p> Tentukan laju perubahan sesaat (TVI) dari fungsi berikut di titik x=1: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a64e895ef4284c9ac73729d092f47767_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=x^2+1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"106\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Kami menerapkan rumus untuk laju perubahan sesaat: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef687e3c0bab81c2a8eaa578fcc41b9b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (a) = \\lim\\limits_{h \\to 0} \\cfrac{f(a+h)-f(a)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9aae03d6907f804a3015daa4ecca1e9f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (1) = \\lim\\limits_{h \\to 0} \\cfrac{f(1+h)-f(1)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"233\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Lalu, kami menghitung<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-59ab22db5134b4e8bc6bbed7ab09bd5f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1+h)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"64\" style=\"vertical-align: -5px;\"><\/p>\n<p> Dan <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-32045357853caad8774629c95963835d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1):\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"42\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bcec545e7bbd1d55ba069ac58c7862ed_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1+h) = (1+h)^2+1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"181\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c5f418d9c95675368ebe7525ad0354ef_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(1)=1^2+1=1+1=2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengganti nilai yang ditemukan dalam batasnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-89bedae84e1ece0933ddf522e449e005_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (1) = \\lim\\limits_{h \\to 0} \\cfrac{f(1+h)-f(1)}{h}= \\lim\\limits_{h \\to 0} \\cfrac{(1+h)^2+1-2}{h} =\\lim\\limits_{h \\to 0} \\cfrac{(1+h)^2-1}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"563\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami memecahkan produk penting:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef36f072cd7bee2d30936dc5a18bdf7a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{1^2+h^2+2\\cdot 1 \\cdot h-1}{h}=\\lim\\limits_{h \\to 0} \\cfrac{1+h^2+2h-1}{h}=\\lim\\limits_{h \\to 0} \\cfrac{h^2+2h}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"488\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang mari kita coba menyelesaikan limitnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eada4220b55e8f3f27f6e565244fa430_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{h^2+2h}{h}=\\cfrac{0^2+2\\cdot 0}{0} = \\cfrac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"221\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Tapi kita menemukan bentuk tak tentu nol dibagi nol, jadi kita memfaktorkan polinomial pembilang pecahan dan menyederhanakannya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-89248fe68bc38749f3ad45e65d902840_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{h^2+2h}{h}=\\lim\\limits_{h \\to 0} \\cfrac{h(h+2)}{h} = \\lim\\limits_{h \\to 0} \\cfrac{\\cancel{h}(h+2)}{\\cancel{h}}= \\lim\\limits_{h \\to 0}(h+2)\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"442\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> <span style=\"color:#FF9B28;\">\u27a4<\/span> Jika anda belum mengetahui <u style=\"text-decoration-color:#FF9B28;\">cara menyelesaikan zero indeterminacy between zero<\/u> , penjelasan selengkapnya dapat anda lihat pada link diatas tentang <u style=\"text-decoration-color:#FF9B28;\">cara menyelesaikan limit dengan zero indeterminacy antara nol.<\/u><\/p>\n<p class=\"has-text-align-left\"> Dan akhirnya, kami menyelesaikan batasannya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5467af069ca6192116dee3e32de90ea7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0}(h+2) = 0+2 =\\bm{2}\" title=\"Rendered by QuickLaTeX.com\" height=\"27\" width=\"178\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ringkasnya, laju perubahan fungsi sesaat di titik x=1 sama dengan 2. <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fbcab0fecbbbe2fbefd80027e8748bda_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mathbf{TVI} \\bm{(1) = 2}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"92\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 7<\/h3>\n<p> Tentukan laju perubahan sesaat fungsi berikut di titik x=2: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1b3e71aa0e6f65532f0324d35e827180_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=4x^2-x+3\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"147\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E6F9EF\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama-tama kita menggunakan rumus laju perubahan sesaat: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ef687e3c0bab81c2a8eaa578fcc41b9b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (a) = \\lim\\limits_{h \\to 0} \\cfrac{f(a+h)-f(a)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a6a7c9ceda50eea0255d09898ff47cbb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (2) = \\lim\\limits_{h \\to 0} \\cfrac{f(2+h)-f(2)}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"233\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami menghitung<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bd34e7bfca2688fc7047d0cbe546068d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2+h)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"64\" style=\"vertical-align: -5px;\"><\/p>\n<p> Dan <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f026e401162db03299777455b748b308_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2):\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"42\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-79281afbca1e53d72c77a132af8593a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2+h) = 4(2+h)^2-(2+h)+3=4(2+h)^2-h+1\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"423\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9260dd17b5ceca44c7ff2d860f0354c3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(2) =4\\cdot 2^2-2+3=4\\cdot 4-2+3 =17\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"313\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kami mengganti nilai yang ditemukan dalam batasnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6ad59f5f751af139656a471bf2a41801_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{TVI} (2) = \\lim\\limits_{h \\to 0} \\cfrac{f(2+h)-f(2)}{h}=\\\\[4ex]=\\lim\\limits_{h \\to 0} \\cfrac{4(2+h)^2-h+1-17}{h}=\\\\[4ex]= \\lim\\limits_{h \\to 0} \\cfrac{4(2+h)^2-h-16}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"190\" width=\"286\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami menghitung persamaan penting:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e358be77d34e9ec7c27433743001162c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{4(2^2+h^2+2\\cdot 2 \\cdot h)-h-16}{h}=\\lim\\limits_{h \\to 0} \\cfrac{4(4+h^2+4h)-h-16}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"500\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami beroperasi pada pembilang:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e7c2b63592b070fa6046376f878d45bc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{16+4h^2+16h-h-16}{h}=\\lim\\limits_{h \\to 0} \\cfrac{4h^2+15h}{h}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"355\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang mari kita coba menyelesaikan limitnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b9dda4d5e5c5eab8c018f1b46a3da45e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{4h^2+15h}{h}=\\cfrac{4\\cdot0^2+15\\cdot 0}{0} = \\cfrac{0}{0}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"269\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Namun kita memperoleh ketidakpastian nol dibagi nol, jadi kita memfaktorkan polinomialnya dan menyederhanakannya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e0d1213a45968f3137f0c39272cd70dc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0} \\cfrac{4h^2+15h}{h}=\\lim\\limits_{h \\to 0} \\cfrac{h(4h+15)}{h}=\\lim\\limits_{h \\to 0} \\cfrac{\\cancel{h}(4h+15)}{\\cancel{h}}= \\lim\\limits_{h \\to 0}(4h+15)\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"513\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan akhirnya, kami menyelesaikan batasannya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5eb4579d04c151866059162480d4c816_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lim\\limits_{h \\to 0}(4h+15)=4\\cdot 0+15 =\\bm{15}\" title=\"Rendered by QuickLaTeX.com\" height=\"27\" width=\"235\" style=\"vertical-align: -13px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Belum: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9181cbd259448ba47e80eb081625ee2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mathbf{TVI} \\bm{(2) = 15}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"101\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Di sini kami menjelaskan apa yang dimaksud dengan laju perubahan, laju perubahan rata-rata, dan laju perubahan sesaat. Anda akan dapat melihat beberapa contoh tentang cara menghitung laju perubahan dan, sebagai tambahan, Anda akan dapat berlatih dengan latihan langkah demi langkah yang telah diselesaikan mengenai laju perubahan. Berapa tingkat perubahannya? Dalam matematika, laju perubahan (TV) suatu &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/id\/tingkat-perubahan-rata-rata-dan-seketika\/\"> <span class=\"screen-reader-text\">Tingkat perubahan rata-rata dan seketika<\/span> Selengkapnya &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[38],"tags":[],"class_list":["post-26","post","type-post","status-publish","format-standard","hentry","category-derivatif"],"yoast_head":"<!-- This site is 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