{"id":243,"date":"2023-07-10T14:58:48","date_gmt":"2023-07-10T14:58:48","guid":{"rendered":"https:\/\/mathority.org\/id\/persamaan-vektor-contoh-rumus-bidang\/"},"modified":"2023-07-10T14:58:48","modified_gmt":"2023-07-10T14:58:48","slug":"persamaan-vektor-contoh-rumus-bidang","status":"publish","type":"post","link":"https:\/\/mathority.org\/id\/persamaan-vektor-contoh-rumus-bidang\/","title":{"rendered":"Persamaan vektor bidang"},"content":{"rendered":"<p>Di halaman ini Anda akan menemukan persamaan (rumus) vektor bidang dan contoh perhitungannya. Selain itu, Anda akan dapat berlatih dengan latihan dan memecahkan masalah persamaan vektor bidang. <\/p>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-104\"><\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-la-ecuacion-vectorial-de-un-plano\"><\/span> Apa persamaan vektor suatu bidang? <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-105\"><\/div>\n<\/div>\n<p> Dalam geometri analitik, <strong>persamaan vektor suatu bidang<\/strong> adalah persamaan yang memungkinkan bidang apa pun dinyatakan secara matematis. Untuk mencari persamaan vektor suatu bidang, kita hanya memerlukan sebuah titik dan dua vektor bebas linier yang dimiliki bidang tersebut. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"formula-de-la-ecuacion-vectorial-del-plano\"><\/span> Rumus persamaan vektor bidang <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-106\"><\/div>\n<\/div>\n<div style=\"background-color:#FFCC8080;padding-top: 20px; padding-bottom: 0.5px; padding-right: 30px; padding-left: 30px; border: 2px solid #FFB74D; border-radius:20px;\">\n<p style=\"text-align:left\"> Perhatikan sebuah titik dan dua vektor arah pada sebuah bidang:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cf5d4130501bb01b15aa80f8f80caf1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{c} P(P_x,P_y,P_z) \\\\[2ex] \\vv{\\text{u}}=(\\text{u}_x,\\text{u}_y,\\text{u}_z)\\\\[2ex] \\vv{\\text{v}}=(\\text{v}_x,\\text{v}_y,\\text{v}_z)\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"95\" width=\"116\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p style=\"text-align:left\"> <strong>Rumus persamaan vektor suatu bidang<\/strong> adalah:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d80b8a9d79088c24cb1940b2abeb18bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=P+\\lambda \\vv{\\text{u}} + \\mu \\vv{\\text{v}}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"178\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-78b41d21b63c22ec05d3f93576a897e0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=(P_x,P_y,P_z)+\\lambda (\\text{u}_x,\\text{u}_y,\\text{u}_z) + \\mu (\\text{v}_x,\\text{v}_y,\\text{v}_z)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"398\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p style=\"text-align:left;\"> Emas<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2b5c45836864531b8e37025dabadd24a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lambda\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-461fe1a58a75801541487ddf10d32abd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"11\" style=\"vertical-align: -4px;\"><\/p>\n<p> adalah dua skalar, yaitu dua bilangan real.<\/p>\n<\/div>\n<p> Oleh karena itu, ini berarti bahwa setiap titik pada suatu bidang dapat dinyatakan sebagai kombinasi linier dari 1 titik dan 2 vektor. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/equations-planes.webp\" alt=\"persamaan vektor bidang xy online\" class=\"wp-image-2443\" width=\"404\" height=\"142\" srcset=\"\" sizes=\"auto, \"><\/figure>\n<\/div>\n<p> Selain itu, syarat yang diperlukan agar persamaan sebelumnya dapat berkorespondensi dengan suatu bidang adalah kedua vektor pada bidang tersebut mempunyai independensi linier, yaitu kedua vektor tersebut tidak boleh sejajar satu sama lain. lainnya.<\/p>\n<p> Di sisi lain, perlu diingat bahwa selain persamaan vektor, ada cara lain untuk menyatakan bidang secara analitis, seperti <a href=\"https:\/\/mathority.org\/id\/persamaan-parametrik-bidang\/\">persamaan parametrik bidang<\/a> dan <a href=\"https:\/\/mathority.org\/id\/persamaan-bidang-umum-atau-kartesius-implisit\/\">persamaan implisit bidang<\/a> . Anda dapat memeriksa setiap jenis persamaan di tautan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejemplo-de-como-hallar-la-ecuacion-vectorial-de-un-plano\"><\/span> Contoh cara mencari persamaan vektor suatu bidang <span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"adsb30\" style=\" margin:12px; text-align:center\">\n<div id=\"ezoic-pub-ad-placeholder-109\"><\/div>\n<\/div>\n<p> Setelah kita melihat penjelasan konsep persamaan vektor bidang, mari kita lihat cara menghitungnya melalui contoh:<\/p>\n<ul>\n<li> Tentukan persamaan vektor bidang yang melalui titik tersebut\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-66c1bcf32c114fa640cf6c3291ec42ac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(2,0,4)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"69\" style=\"vertical-align: -5px;\"><\/p>\n<p> dan berisi vektor<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-742e72027d137839ae3e565d098418f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{u}}=(1,3,-2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"103\" style=\"vertical-align: -5px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-85abe8a10ab167a3b72ce2048d480c5e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{v}}=(5,0,1).\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"93\" style=\"vertical-align: -5px;\"><\/p>\n<\/li>\n<\/ul>\n<p> Untuk menentukan persamaan vektor bidang, cukup terapkan rumusnya:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d80b8a9d79088c24cb1940b2abeb18bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=P+\\lambda \\vv{\\text{u}} + \\mu \\vv{\\text{v}}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"178\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Dan sekarang kita substitusikan titik dan masing-masing vektor ke dalam persamaan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e966b1b217e19b857d5945de152312cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(x,y,z)=(2,0,4)+\\lambda (1,3,-2) + \\mu (5,0,1)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"326\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Seperti yang bisa Anda lihat pada contohnya, mencari persamaan vektor suatu bidang relatif mudah. Namun, soalnya bisa menjadi sedikit rumit, jadi di bawah ini Anda memiliki beberapa latihan yang diselesaikan dengan tingkat kesulitan berbeda sehingga Anda bisa berlatih. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"ejercicios-resueltos-de-la-ecuacion-vectorial-del-plano\"><\/span> Masalah Terpecahkan Persamaan Vektor Bidang<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Tentukan persamaan vektor bidang yang memuat vektor tersebut<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-967feca863a9a4d3f1e7f0267f5e75e7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{\\text{u}}=(0,-2,3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"103\" style=\"vertical-align: -5px;\"><\/p>\n<p> dan melewati dua poin berikut:<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b080bdb2f119700090341574b7bbf489_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(1,3,-1)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"83\" style=\"vertical-align: -5px;\"><\/p>\n<p> Dan <\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3ad5d13132fc818eac77b60b1ac15e13_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"B(2,-1,5).\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"89\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusi<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk mengetahui persamaan suatu bidang, diperlukan sebuah titik dan dua vektor dan dalam hal ini kita hanya mempunyai satu vektor, oleh karena itu kita harus mencari vektor pengarah bidang lainnya. Untuk melakukan ini, kita dapat menghitung vektor yang mendefinisikan dua titik pada bidang:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b85ba6303c469618bd0d69f560c11535_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{AB} = B - A = (2,-1,5) - (1,3,-1) = (1,-4,6)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"379\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita telah mengetahui dua vektor arah bidang dan sebuah titik, maka kita menggunakan rumus persamaan vektor bidang:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d80b8a9d79088c24cb1940b2abeb18bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=P+\\lambda \\vv{\\text{u}} + \\mu \\vv{\\text{v}}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"178\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kita substitusikan dua vektor dan salah satu dari dua titik pada bidang tersebut ke dalam persamaan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-941c8d43b51f4c2f838a0ef55b1f87fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(x,y,z)=(1,3,-1)+\\lambda (0,-2,3) + \\mu (1,-4,6)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"354\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Tentukan persamaan vektor bidang yang memuat tiga titik berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c61c59f12a57c3df9dcd45d35e601a65_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"A(2,-2,1) \\qquad B(1,0,4) \\qquad C(-1,3,-2)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"322\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusi<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk mencari persamaan vektor pada bidang tersebut, kita perlu mencari dua vektor bebas linier yang terikat pada bidang tersebut. Dan untuk ini, kita dapat menghitung dua vektor yang ditentukan oleh 3 titik: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-fabb606f5950c8b864f9c2e67b4ba576_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{AB} = B - A = (1,0,4) - (2,-2,1) = (-1,2,3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"365\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1a4d8bb247e7d07e78d9db6229d7bb5a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{AC} = C - A = (-1,3,-2) - (2,-2,1) = (-3,5,-3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"406\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Koordinat kedua vektor yang ditemukan tidak proporsional, sehingga saling bebas linier.<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita telah mengetahui dua vektor arah dan sebuah titik pada bidang, maka kita terapkan rumus persamaan vektor pada bidang tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-d80b8a9d79088c24cb1940b2abeb18bb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=P+\\lambda \\vv{\\text{u}} + \\mu \\vv{\\text{v}}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"178\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan kita substitusikan dua vektor dan salah satu dari tiga titik pada bidang tersebut ke dalam persamaan: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-baa213bb98612c8fff5d3830141936a9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(x,y,z)=(2,-2,1)+\\lambda (-1,2,3) + \\mu (-3,5,-3)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"368\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Hitung 4 titik dalam ruang yang termasuk dalam bidang yang ditentukan oleh persamaan vektor berikut: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f741afbd4a2497d23e451858c85f24c2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=(0,2,1)+\\lambda (2,-1,4) + \\mu (-1,3,0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"340\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusi<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menghitung suatu titik pada bidang, cukup berikan nilai apa pun pada parameternya<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2b5c45836864531b8e37025dabadd24a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\lambda\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> Dan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f057d6a413d6aaa2ff88a679887b506d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu .\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"15\" style=\"vertical-align: -4px;\"><\/p>\n<p> Belum: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-132014e2e535396ec5fbd90f506d9d06_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{c} \\lambda =0 \\\\[2ex] \\mu =0 \\end{array} \\right\\} \\longrightarrow \\ (0,2,1)+0\\cdot (2,-1,4) + 0\\cdot  (-1,3,0)= \\bm{(0,2,1)}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"473\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-203c86c8c4e062be8c995bec8c3cfbd2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{c} \\lambda =1 \\\\[2ex] \\mu =0 \\end{array} \\right\\} \\longrightarrow \\ (0,2,1)+1\\cdot (2,-1,4) + 0\\cdot (-1,3,0)= \\bm{(2,1,5)}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"473\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6f4a371c0ec352adf59ee80a81086982_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{c} \\lambda =0 \\\\[2ex] \\mu =1 \\end{array} \\right\\} \\longrightarrow \\ (0,2,1)+0\\cdot (2,-1,4) + 1\\cdot (-1,3,0)= \\bm{(-1,5,1)}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"487\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-38353c40eec5b104be40c3e0a0c93d04_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left. \\begin{array}{c} \\lambda =1 \\\\[2ex] \\mu =1 \\end{array} \\right\\} \\longrightarrow \\ (0,2,1)+1\\cdot (2,-1,4) + 1\\cdot (-1,3,0)= \\bm{(1,4,5)}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"473\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 4<\/h3>\n<p> Temukan persamaan vektor bidang yang memuat garis<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> dan sejajar dengan kanan<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-23a7daa116b8874af1538c91f8d239de_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"s.\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"12\" style=\"vertical-align: 0px;\"><\/p>\n<p> menjadi garis: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5b06057454aa6047223c595fdb8d60f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle r: \\ \\begin{cases} x=4+2t \\\\[1.7ex] y=-1+t\\\\[1.7ex] z=5-4t \\end{cases} \\qquad \\qquad s: \\ \\frac{x-1}{2} = \\frac{y+2}{4}= \\frac{z+1}{-3}\" title=\"Rendered by QuickLaTeX.com\" height=\"107\" width=\"429\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E4F0FE\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#E4F0FE\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusi<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk mencari persamaan vektor bidang tersebut, kita perlu mengetahui dua vektor arah dan sebuah titik pada bidang tersebut. Instruksi memberitahu kita bahwa itu berisi garis<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> Oleh karena itu, kita dapat mengambil vektor arah dan sebuah titik pada garis ini untuk mendefinisikan bidang tersebut. Lebih lanjut pernyataan tersebut menyatakan bahwa bidang tersebut sejajar dengan garis<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4cc36ef269909ae645021a09d5e91016_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"s,\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"12\" style=\"vertical-align: -4px;\"><\/p>\n<p> jadi kita juga bisa menggunakan vektor arah garis ini untuk persamaan bidangnya.<\/p>\n<p class=\"has-text-align-left\"> hak<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c409433a9e2dfcdb83360a974d243f18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> dinyatakan dalam bentuk persamaan parametrik, sehingga komponen vektor arahnya adalah koefisien suku parameter<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-40f8b062c79839dcf7f2885a9e1469e7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t:\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"15\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e313a8b4e84e6b176488218f026cc17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{r} =(2,1,-4)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"102\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan koordinat Kartesius suatu titik pada garis yang sama adalah suku-suku bebas dari persamaan tersebut:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-610ad4575988feaea1215caf1913b014_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P(4,-1,5)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"83\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sebaliknya garis lurus<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ae1901659f469e6be883797bfd30f4f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"s\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> berbentuk persamaan kontinu sehingga komponen vektor arahnya adalah penyebut pecahan:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5fa0ec21ddcb8da0da4286a89b6e2232_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{s} =(2,4,-3)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"101\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, persamaan vektor bidang tersebut adalah: <\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f4e01864a3c82e5d4eec6142ac295d11_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"(x,y,z)=P+\\lambda \\vv{r} + \\mu \\vv{s}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"176\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a3f612d981cb579e43104dc679b36bc7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\bm{(x,y,z)=(4,-1,5)+\\lambda (2,1,-4) + \\mu (2,4,-3)}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"354\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Di halaman ini Anda akan menemukan persamaan (rumus) vektor bidang dan contoh perhitungannya. Selain itu, Anda akan dapat berlatih dengan latihan dan memecahkan masalah persamaan vektor bidang. Apa persamaan vektor suatu bidang? Dalam geometri analitik, persamaan vektor suatu bidang adalah persamaan yang memungkinkan bidang apa pun dinyatakan secara matematis. Untuk mencari persamaan vektor suatu bidang, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/id\/persamaan-vektor-contoh-rumus-bidang\/\"> <span class=\"screen-reader-text\">Persamaan vektor bidang<\/span> Selengkapnya &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[47],"tags":[],"class_list":["post-243","post","type-post","status-publish","format-standard","hentry","category-titik-garis-dan-bidang"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Persamaan vektor bidang - Mathority<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathority.org\/id\/persamaan-vektor-contoh-rumus-bidang\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Persamaan vektor bidang - Mathority\" \/>\n<meta property=\"og:description\" content=\"Di halaman ini Anda akan menemukan persamaan (rumus) vektor bidang dan contoh perhitungannya. Selain itu, Anda akan dapat berlatih dengan latihan dan memecahkan masalah persamaan vektor bidang. Apa persamaan vektor suatu bidang? Dalam geometri analitik, persamaan vektor suatu bidang adalah persamaan yang memungkinkan bidang apa pun dinyatakan secara matematis. 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