{"id":43,"date":"2023-09-17T10:57:48","date_gmt":"2023-09-17T10:57:48","guid":{"rendered":"https:\/\/mathority.org\/de\/monotonie-einer-steigenden-und-fallenden-funktion\/"},"modified":"2023-09-17T10:57:48","modified_gmt":"2023-09-17T10:57:48","slug":"monotonie-einer-steigenden-und-fallenden-funktion","status":"publish","type":"post","link":"https:\/\/mathority.org\/de\/monotonie-einer-steigenden-und-fallenden-funktion\/","title":{"rendered":"Monotonie einer funktion: wachstum und verfall"},"content":{"rendered":"<p>In diesem Artikel erkl\u00e4ren wir, wie man die Monotonie einer Funktion erkennt, d. h. wie man die Anstiegs- und Abfallintervalle einer Funktion ermittelt. Dar\u00fcber hinaus k\u00f6nnen Sie mit Schritt-f\u00fcr-Schritt-\u00dcbungen das Wachstum und den R\u00fcckgang einer Funktion \u00fcben. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%c2%bfque-es-la-monotonia-de-una-funcion\"><\/span> Was ist die Monotonie einer Funktion?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Eine Funktion ist in einem Intervall monoton, wenn sie die gegebene Ordnung beibeh\u00e4lt. Es gibt f\u00fcnf Arten von Monotonie:<\/p>\n<ul style=\"color:#FF8A05; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Monoton wachsende Funktion:<\/strong> wenn der Wert der Funktion an einem Punkt immer gleich oder gr\u00f6\u00dfer als der Wert der Funktion an einem vorherigen Punkt ist.<\/span><\/li>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-3f5f07455dc1ffaaba45b1aa082e0b61_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)\\leq f(y) \\qquad x\n\n<li style=&quot;margin-bottom:8px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Fonction monotone d\u00e9croissante :<\/strong> lorsque la valeur de la fonction en un point est toujours \u00e9gale ou inf\u00e9rieure \u00e0 la valeur de la fonction en un point pr\u00e9c\u00e9dent.<\/span><\/li>\n<p>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;107&#8243; width=&#8220;899&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> f(x)\\geq f(y)\\qquad x<\/p>\n<li style=\"margin-bottom:8px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Streng monoton steigende Funktion:<\/strong> wenn der Wert der Funktion an einem Punkt immer gr\u00f6\u00dfer ist als der Wert der Funktion an einem vorherigen Punkt.<\/span><\/li>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ba961a7170cbd2542a5075800f74df42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)< f(y) \\qquad x\n\n<li style=&quot;margin-bottom:8px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Fonction d\u00e9croissante strictement monotone :<\/strong> lorsque la valeur de la fonction en un point est toujours inf\u00e9rieure \u00e0 la valeur de la fonction en un point pr\u00e9c\u00e9dent.<\/span><\/li>\n<p>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;107&#8243; width=&#8220;840&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> f(x)&gt;f(y) \\qquad x<\/p>\n<li style=\"margin-bottom:8px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Konstante Funktion<\/strong> , wenn der Wert der Funktion an einem Punkt immer gleich dem Wert der Funktion an einem vorherigen Punkt ist.<\/span><\/li>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c74a3ce038603a7e45c07b421bcaad10_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"f(x)=f(y) \\qquad x<\/ul>\n<p> Notez qu&#8217;une fonction constante est \u00e0 la fois une fonction monotone croissante et une fonction monotone d\u00e9croissante, car elle r\u00e9pond \u00e9galement \u00e0 leurs d\u00e9finitions. Ainsi, nous dirons qu&#8217;une <strong>fonction est monotone<\/strong> lorsqu&#8217;elle satisfait \u00e0 l&#8217;une des d\u00e9finitions ci-dessus dans tout son domaine. <\/p>\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/monotonicite-dune-fonction-croissante-et-decroissante.webp&quot; alt=&quot;monotonie d'une fonction graphique de croissance et de d\u00e9croissance&quot; class=&quot;wp-image-2431&quot; width=&quot;411&quot; height=&quot;419&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Comme vous pouvez le voir dans le graphique pr\u00e9c\u00e9dent, la fonction augmente lorsque sa repr\u00e9sentation \u00ab monte \u00bb, la fonction diminue lorsqu&#8217;elle \u00ab descend \u00bb et la fonction est constante lorsqu&#8217;elle reste la m\u00eame. En revanche, au point o\u00f9 la fonction passe de croissante \u00e0 d\u00e9croissante ou vice versa, on dit que ce point est un extr\u00eame relatif :<\/p>\n<ul>\n<li> Si la fonction passe de croissant \u00e0 d\u00e9croissant, le point est un <strong>maximum relatif<\/strong> .<\/li>\n<li> Si la fonction passe de d\u00e9croissante \u00e0 croissante, le point est un <strong>minimum relatif<\/strong> . <\/li>\n<\/ul>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;como-estudiar-la-monotonia-de-una-funcion&quot;><\/span> Comment \u00e9tudier la monotonie d&#8217;une fonction<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<p> Pour \u00e9tudier la monotonie d&#8217;une fonction, c&#8217;est-\u00e0-dire les intervalles d&#8217;augmentation et de diminution d&#8217;une fonction, nous devons suivre les \u00e9tapes suivantes : <\/p>\n<div style=&quot;background-color:#FFF3E0; padding-top: 23px; padding-bottom: 0.5px; padding-right: 30px; padding-left: 10px; border-radius:30px;&quot;>\n<ol style=&quot;color:#64B5F6; font-weight: bold;&quot;>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Trouvez les <strong>points qui n&#8217;appartiennent pas au domaine<\/strong> de la fonction.<\/span><\/li>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Calculez la <strong>d\u00e9riv\u00e9e de la fonction.<\/strong><\/span><\/li>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Trouvez les <strong>racines de la d\u00e9riv\u00e9e<\/strong> , c&#8217;est-\u00e0-dire calculez les points qui annulent la d\u00e9riv\u00e9e en r\u00e9solvant <em>f'(x)=0<\/em> .<\/span><\/li>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Faites <strong>des intervalles<\/strong> avec les racines de la d\u00e9riv\u00e9e et les points qui n&#8217;appartiennent pas au domaine de la fonction.<\/span><\/li>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Calculez la valeur de la d\u00e9riv\u00e9e en un point de chaque intervalle.<\/span><\/li>\n<li style=&quot;margin-bottom:16px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Le signe de la d\u00e9riv\u00e9e<\/strong> d\u00e9termine la croissance ou la diminution de la fonction dans cet intervalle :<\/span>\n<ul style=&quot;color:#64B5F6; font-weight: bold; margin-top:8px; margin-left:8%&quot;>\n<li style=&quot;margin-bottom:8px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Si la d\u00e9riv\u00e9e de la fonction est positive, la fonction est <strong>croissante<\/strong> sur cet intervalle.<\/span><\/li>\n<li style=&quot;margin-bottom:8px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;>Si la d\u00e9riv\u00e9e de la fonction est n\u00e9gative, la fonction est <strong>d\u00e9croissante<\/strong> sur cet intervalle.<\/span> <\/li>\n<\/ul>\n<\/li>\n<\/ol>\n<\/div>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;ejemplo-de-como-hallar-la-monotonia-de-una-funcion&quot;><\/span> Exemple de comment trouver la monotonie d&#8217;une fonction<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<p> Apr\u00e8s avoir vu la th\u00e9orie de la monotonie d&#8217;une fonction, nous allons r\u00e9soudre ci-dessous un exemple \u00e9tape par \u00e9tape afin que vous compreniez parfaitement comment la monotonie d&#8217;une fonction est \u00e9tudi\u00e9e.<\/p>\n<ul>\n<li> Analysez la monotonie de la fonction rationnelle suivante :<\/li>\n<\/ul>\n<p>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;1031&#8243; width=&#8220;2440&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> f(x)=\\cfrac{3}{x^2-4}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-37223546dfa665d25d2a85146d1350fc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" La premi\u00e8re chose \u00e0 faire est de calculer le domaine de d\u00e9finition de la fonction. C'est une fonction rationnelle, il faut donc mettre le d\u00e9nominateur \u00e9gal \u00e0 0 pour voir quels nombres n'appartiennent pas au domaine de la fonction :\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"1659\" style=\"vertical-align: -4px;\"><\/p>\n<p> x^2-4=0x^2=4x=\\pm 2<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-881900f94943dd76064c9dc7966678d1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Ainsi, lorsque x vaut +2 ou -2, le d\u00e9nominateur sera 0. Et, par cons\u00e9quent, la fonction n'existera pas. Le domaine de la fonction est donc compos\u00e9 de tous les nombres sauf x=\u00b12.\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"1270\" style=\"vertical-align: 0px;\"><\/p>\n<p> \\text{Dom } f= \\mathbb{R}-\\{+2, -2 \\}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-4fb61132016e2973ef9e05038a294d30_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de d\u00e9finition de la fonction, nous devons \u00e9tudier \u00e0 quels points la d\u00e9riv\u00e9e premi\u00e8re de la fonction s'annule. Nous calculons donc d'abord la d\u00e9riv\u00e9e de la fonction en appliquant la formule de la d\u00e9riv\u00e9e d'une division : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"1866\" style=\"vertical-align: -4px;\"><\/p>\n<p> f(x)=\\cfrac{3}{x^2-4} \\ \\longrightarrow \\ f'(x)= \\cfrac{0\\cdot (x^2-4) \u2013 3\\cdot 2x}{\\left( x^2-4\\right)^2}f'(x)=\\cfrac{-6x}{\\left(x^2-4\\right)^2}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f1dc79f6d12f3b6e52d42dea9c466676_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Et maintenant, nous fixons la d\u00e9riv\u00e9e \u00e9gale \u00e0 0 et r\u00e9solvons l'\u00e9quation : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"523\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)=0\\cfrac{-6x}{\\left(x^2-4\\right)^2}=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-bdcc76fe8b915fd0c4e8594e2eb4aa74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Le terme\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"67\" style=\"vertical-align: 0px;\"><\/p>\n<p> \\left(x^2-4\\right)^2}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-e9046c0858171eb213c22710cd4ff1a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"Il s'agit de diviser tout le c\u00f4t\u00e9 gauche, nous pouvons donc le multiplier par tout le c\u00f4t\u00e9 droit : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"655\" style=\"vertical-align: -4px;\"><\/p>\n<p> -6x=0\\cdot \\left(x^2-4\\right)^2-6x=0x=\\cfrac{0}{-6}x=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-0cf21efdf92a2deb829cbe4d12ab51db_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de la fonction et\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"429\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)=0,<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9e6b4e8cd54219cdf05740695b33edf5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"Nous repr\u00e9sentons tous les points critiques trouv\u00e9s sur la ligne : \n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droite-numerique-2-0-2.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2399&quot; width=&quot;431&quot; height=&quot;84&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Et maintenant nous \u00e9valuons le signe de la d\u00e9riv\u00e9e dans chaque intervalle, pour savoir si la fonction augmente ou diminue dans chaque intervalle. Pour ce faire, nous prenons un point dans chaque intervalle (jamais les points critiques) et regardons quel signe la d\u00e9riv\u00e9e a \u00e0 ce point : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;149&#8243; width=&#8220;2048&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> f'(x)=\\cfrac{-6x}{\\left(x^2-4\\right)^2}f'(-3) = \\cfrac{-6\\cdot(-3)}{\\left( (-3)^2-4\\right)^2} = \\cfrac{+18}{+25} = +0,72 \\ \\rightarrow \\ \\bm{+}f'(-1) = \\cfrac{- 6\\ cdot(-1)}{\\left((-1)^2-4\\right)^2} = \\cfrac{+6}{+9} = +0,67 \\ \\rightarrow \\ \\bm{+ }f'( 1) = \\cfrac{-6\\cdot 1}{\\left(1^2-4\\right)^2} = \\cfrac{-6}{+9} = -0,67 \\ \\rightarrow \\ \\bm{-} f'(3) = \\cfrac{-6\\cdot3}{\\left(3^2-4\\right)^2} = \\cfrac{-18}{+25} = \u2013 0,72 \\ \\rightarrow \\ \\ bm{ -}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-53485b686e964fc859fc95e7b528e675_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/droite-numerique-2-0-2-positif-negatif.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2398&quot; width=&quot;430&quot; height=&quot;150&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Enfin, on en d\u00e9duit les intervalles de diminution et d&#8217;augmentation de la fonction. Si la d\u00e9riv\u00e9e est positive, cela signifie que la fonction augmente, et si la d\u00e9riv\u00e9e est n\u00e9gative, cela signifie que la fonction diminue. Ainsi les intervalles d&#8217;augmentation et de diminution de la fonction sont : <strong>Croissance:<\/strong>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;171&#8243; width=&#8220;2121&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(-\\infty, -2)\\cup (-2,0)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b37f8e12423d7bb7b377d9f5b7229269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" <strong>Diminuer:<\/strong> &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;19&#8243; width=&#8220;280&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(0,2)\\cup (2,+\\infty)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-512e85a725e7885e3a452ede011313b2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div style=&quot;background-color:#FFFDE7; padding-top: 23px; padding-bottom: 0.5px; padding-right: 40px; padding-left: 30px; border: 2.5px dashed #FFB74D; border-radius:20px;&quot;> <strong>Remarque :<\/strong> bien que l&#8217;intervalle (-\u221e,-2) ait le m\u00eame signe que l&#8217;intervalle (-2,0), les intervalles doivent \u00eatre exprim\u00e9s avec le signe U :&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;106&#8243; width=&#8220;894&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> (-\\infty, -2)\\cup (-2,0)<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-1cdcc3674c04430a0383ab9b6cb20c7e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\u2705 Et ne l'\u00e9crivez jamais comme ceci :\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"258\" style=\"vertical-align: -4px;\"><\/p>\n<p> (-\\infty,0)<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-a36d0e819b814b3e94191bd86cf9bd18_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\u274c. Parce que la fonction n'existe pas au point -2 et, par cons\u00e9quent, ce point ne doit pas \u00eatre inclus dans l'intervalle. <\/div>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;ejercicios-resueltos-de-la-monotonia-de-una-funcion&quot;><\/span> Exercices r\u00e9solus sur la monotonie d&#8217;une fonction<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<h3 class=&quot;wp-block-heading&quot;> Exercice 1<\/h3>\n<p> \u00c9tudiez la croissance et la diminution de la fonction polynomiale suivante : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;151&#8243; width=&#8220;841&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> \\displaystyle f(x)=x^3-6x^2+9x<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-19b707687763a67118de1be9601d0814_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF&quot; role=&quot;button&quot; tabindex=&quot;0&quot; aria-expanded=&quot;false&quot; data-otfm-spc=&quot;#E6F9EF&quot; style=&quot;text-align:center&quot;>\n<div class=&quot;otfm-sp__title&quot;> <strong>Voir la solution<\/strong><\/div>\n<\/div>\n<p> Il s&#8217;agit d&#8217;une fonction polynomiale, donc le domaine de la fonction est constitu\u00e9 de nombres r\u00e9els :&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;54&#8243; width=&#8220;1914&#8243; style=&#8220;vertical-align: -20px;&#8220;><\/p>\n<p> \\text{Dom } f= \\mathbb{R}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-308d536ecd0d3e2e0c01af48d5d6c4dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que l'on conna\u00eet le domaine de la fonction, il faut \u00e9tudier \u00e0 quels points elle est remplie.\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"691\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)=0.<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-2feb45238f8e3f2c4510c4bb19b82c7a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"On d\u00e9rive donc la fonction du troisi\u00e8me degr\u00e9 :\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"342\" style=\"vertical-align: -4px;\"><\/p>\n<p> f(x)=x^3-6x^2+9x \\ \\longrightarrow \\ f'(x)=3x^2-12x+9<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-6a72be17076f2e7ca4748680048acd08_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Et maintenant, nous fixons la d\u00e9riv\u00e9e \u00e9gale \u00e0 0 et r\u00e9solvons l'\u00e9quation quadratique en utilisant la formule g\u00e9n\u00e9rale : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"856\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)= 03x^2-12x+9=0\\begin{aligned}x &amp;=\\cfrac{-b \\pm \\sqrt{b^2-4ac}}{2a} = \\cfrac{-(- 12) \\pm \\sqrt{(-12)^2-4\\cdot 3 \\cdot 9}}{2\\cdot 3}=\\\\[2ex]&amp;= \\cfrac{+12 \\pm \\sqrt{144-108 }}{6} =\\cfrac{12 \\pm 6}{6}=\\begin{cases} \\cfrac{12 + 6}{6}= 3 \\\\[4ex] \\cfrac{12 \u2013 6}{6} =1 \\end{cases} \\end{aligned}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-5e25ab761c69282e23ff6ab98be35a6d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de la fonction et\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"429\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-9557564e681aef8adf938ba3e6e01ce3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\", nous repr\u00e9sentons tous les points singuliers trouv\u00e9s sur la droite num\u00e9rique : \n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-1-3.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2418&quot; width=&quot;320&quot; height=&quot;84&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Et enfin, on d\u00e9termine le signe de la d\u00e9riv\u00e9e sur chaque intervalle. Pour ce faire, nous prenons un point dans chaque intervalle et regardons quel signe la d\u00e9riv\u00e9e a \u00e0 ce point : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;148&#8243; width=&#8220;1253&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> f'(0)=3\\cdot 0^2-12\\cdot0+9 =+9 \\ \\rightarrow \\ \\bm{+}f'(2)=3\\cdot2^2-12\\cdot2+9 =-3 \\ \\rightarrow \\ \\bm{-}f'(4)=3\\cdot4^2-12\\cdot4+9 =+9 \\ \\rightarrow \\ \\bm{+}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-68263f376ecb46ffd16787b00e1d9ebf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-1-3-positif-negatif-positif.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2419&quot; width=&quot;320&quot; height=&quot;152&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> La fonction augmentera dans les intervalles o\u00f9 sa d\u00e9riv\u00e9e est positive et, inversement, la fonction diminuera dans les intervalles o\u00f9 sa d\u00e9riv\u00e9e est n\u00e9gative. Pourtant: <strong>Croissance:<\/strong>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;171&#8243; width=&#8220;1243&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(-\\infty, 1)\\cup (3,+\\infty)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b37f8e12423d7bb7b377d9f5b7229269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" <strong>Diminuer:<\/strong> &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;19&#8243; width=&#8220;280&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(1,3)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-52f7de32d14c9c541274ffc1c38bb6b9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-otfm-box-spoiler-end otfm-sp_end&quot;><\/div>\n<h3 class=&quot;wp-block-heading&quot;> Exercice 2<\/h3>\n<p> \u00c9tudiez la monotonie de la fonction rationnelle suivante : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;60&#8243; width=&#8220;582&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> \\displaystyle f(x)=\\frac{5}{x^2-9}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-cbfa529b8bc1836a9e88ebdba93db348_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF&quot; role=&quot;button&quot; tabindex=&quot;0&quot; aria-expanded=&quot;false&quot; data-otfm-spc=&quot;#E6F9EF&quot; style=&quot;text-align:center&quot;>\n<div class=&quot;otfm-sp__title&quot;> <strong>Voir la solution<\/strong><\/div>\n<\/div>\n<p> Tout d&#8217;abord, il faut trouver le domaine de la fonction. Nous fixons donc le d\u00e9nominateur \u00e9gal \u00e0 z\u00e9ro et r\u00e9solvons l&#8217;\u00e9quation quadratique r\u00e9sultante : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;54&#8243; width=&#8220;2169&#8243; style=&#8220;vertical-align: -20px;&#8220;><\/p>\n<p> x^2-9 = 0 x^2 = 9 x = \\pm 3<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-217f2f83b04dcc31aa31167cdd7ec397_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Ainsi, lorsque x est \u00e9gal \u00e0 +3 ou -3, le d\u00e9nominateur sera 0 et la fonction n'existera pas.\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"651\" style=\"vertical-align: -4px;\"><\/p>\n<p> \\text{Dom } f= \\mathbb{R}-\\{+3, -3 \\}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-aa5b9dca6173f0247b02e18e4be259af_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de d\u00e9finition de la fonction, nous devons \u00e9tudier en quels points la d\u00e9riv\u00e9e est nulle. On d\u00e9rive donc la fonction : \" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"1124\" style=\"vertical-align: -4px;\"><\/p>\n<p> f(x)=\\cfrac{5}{x^2-9} \\ \\longrightarrow \\ f'(x)= \\cfrac{0\\cdot (x^2-9) \u2013 5\\cdot (2x)}{\\ left(x^2-9\\right)^2}f'(x)= \\cfrac{-10x}{\\left(x^2-9\\right)^2}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-105289e7db130092c4705b04680bb007_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Maintenant, nous fixons la d\u00e9riv\u00e9e \u00e9gale \u00e0 0 et r\u00e9solvons l'\u00e9quation : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"506\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)= 0\\cfrac{-10x}{\\left(x^2-9\\right)^2}=0 -10x=0\\cdot \\left(x^2-9\\right)^2 &#8211; 10x= 0 x= \\cfrac{0}{-10} x=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-44d702fddee2b48037776117f05465af_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Ensuite, on repr\u00e9sente tous les points singuliers trouv\u00e9s sur la droite : \n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/ligne-numerique-3-0-3.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2408&quot; width=&quot;420&quot; height=&quot;82&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Et maintenant nous \u00e9valuons le signe de la d\u00e9riv\u00e9e dans chaque intervalle, pour savoir si la fonction augmente ou diminue. Nous prenons donc un point dans chaque intervalle (jamais les points singuliers) et regardons quel signe la d\u00e9riv\u00e9e a \u00e0 ce point : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;171&#8243; width=&#8220;1823&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> f'(-4)= \\cfrac{-10(-4)}{\\left((-4)^2-9\\right)^2}= \\cfrac{+40}{+49} =+0, 82 \\ \\rightarrow \\ \\bm{+}f'(-1)= \\cfrac{-10(-1)}{\\left((-1)^2-9\\right)^2}= \\cfrac{+ 10}{+64} = +0,16 \\ \\rightarrow \\ \\bm{+}f'(1)= \\cfrac{-10\\cdot 1}{\\left(1^2-9\\right)^2} = \\ cfrac{-10}{+64} = -0,16 \\ \\rightarrow \\ \\bm{-}f'(4)= \\cfrac{-10\\cdot 4}{\\left(4^2-9\\ right)^2 }= \\cfrac{-40}{+7} =-0,82 \\ \\rightarrow \\ \\bm{-}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-44a60ba151439d1b550bcc38840fc7aa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/carre-du-binome-d-une-soustraction.jpg&quot; alt=&quot;&quot; class=&quot;wp-image-2409&quot; width=&quot;421&quot; height=&quot;149&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Si la d\u00e9riv\u00e9e est positive, cela signifie que la fonction augmente, cependant, si la d\u00e9riv\u00e9e est n\u00e9gative, cela signifie que la fonction diminue. Par cons\u00e9quent, les intervalles de croissance et de diminution de la fonction rationnelle sont : <strong>Croissance:<\/strong>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;171&#8243; width=&#8220;1732&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(-\\infty, -3)\\cup (-3,0)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b37f8e12423d7bb7b377d9f5b7229269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" <strong>Diminuer:<\/strong> &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;19&#8243; width=&#8220;280&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(0,3)\\cup (3,+\\infty)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-969cb14f7199ed721f03d1b2fb30b7fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-otfm-box-spoiler-end otfm-sp_end&quot;><\/div>\n<h3 class=&quot;wp-block-heading&quot;> Exercice 3<\/h3>\n<p> Calculez la monotonie de la fonction logarithmique suivante : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;60&#8243; width=&#8220;582&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> \\displaystyle f(x)=\\ln\\left(x^2+1\\right)<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-f648aae4d37a3c35a78a0f22239b6805_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__E6F9EF&quot; role=&quot;button&quot; tabindex=&quot;0&quot; aria-expanded=&quot;false&quot; data-otfm-spc=&quot;#E6F9EF&quot; style=&quot;text-align:center&quot;>\n<div class=&quot;otfm-sp__title&quot;> <strong>Voir la solution<\/strong><\/div>\n<\/div>\n<p> Nous devons d&#8217;abord \u00e9tudier le domaine de la fonction logarithmique. \u00c9tant un logarithme, il faut regarder quand son argument est sup\u00e9rieur \u00e0 0, puisqu&#8217;il n&#8217;existe pas de logarithme naturel d&#8217;un nombre n\u00e9gatif ou 0 :&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;55&#8243; width=&#8220;2513&#8243; style=&#8220;vertical-align: -21px;&#8220;><\/p>\n<p> x^2+1&gt; 0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-eae5e5a0c07e63019e262a35dea4c602_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Dans ce cas, la fonction quadratique x <sup>2<\/sup> +1 sera toujours positive, car le carr\u00e9 d&#8217;un nombre sera toujours positif. Par cons\u00e9quent, le domaine de la fonction sera compos\u00e9 uniquement de nombres r\u00e9els :&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;40&#8243; width=&#8220;1172&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> \\text{Dom } f= \\mathbb{R}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-18c712971043b768411821848dfbc237_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de d\u00e9finition de la fonction, nous devons calculer les z\u00e9ros (ou racines) de la d\u00e9riv\u00e9e de la fonction. On calcule donc la d\u00e9riv\u00e9e de la fonction : \" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"1329\" style=\"vertical-align: -5px;\"><\/p>\n<p> f(x)=\\ln \\bigl(x^2+1 \\bigr) \\ \\longrightarrow \\ f'(x)=\\cfrac{1}{x^2+1 } \\cdot (2x)f'(x) = \\cfrac{2x}{x^2+1}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-105289e7db130092c4705b04680bb007_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Maintenant, nous fixons la d\u00e9riv\u00e9e \u00e9gale \u00e0 0 et r\u00e9solvons l'\u00e9quation : \" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"506\" style=\"vertical-align: -4px;\"><\/p>\n<p> f'(x)= 0\\cfrac{2x}{x^2+1}=0 2x=0\\cdot \\left(x^2+1\\right) 2x= 0 x= \\cfrac{0}{2} x=0<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-ecba1ea1339010b5cb7ae51bc20941e7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" Une fois que nous avons calcul\u00e9 le domaine de d\u00e9finition de la fonction et les racines de la d\u00e9riv\u00e9e premi\u00e8re de la fonction, nous repr\u00e9sentons tous les points critiques trouv\u00e9s sur la droite, qui dans ce cas n'est que z\u00e9ro : \n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/nombre-ligne-0.webp&quot; alt=&quot;&quot; class=&quot;wp-image-2426&quot; width=&quot;217&quot; height=&quot;84&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> On \u00e9value le signe de la d\u00e9riv\u00e9e dans chaque intervalle pour savoir si la fonction augmente ou diminue : &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;151&#8243; width=&#8220;1581&#8243; style=&#8220;vertical-align: -4px;&#8220;><\/p>\n<p> f'(-1)= \\cfrac{2\\cdot(-1)}{(-1)^2+1}= \\cfrac{-2}{+2} = -1 \\ \\rightarrow \\ \\bm{- }f'(1)= \\cfrac{2\\cdot1}{1^2+1}= \\cfrac{+2}{+2} = +1 \\ \\rightarrow \\ \\bm{+}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-c95fabc58609786ea56e5c82a69d4045_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\n\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-large is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;http:\/\/mathority.org\/wp-content\/uploads\/2023\/07\/interpretation-geometrique-du-carre-de-la-difference.jpg&quot; alt=&quot;&quot; class=&quot;wp-image-2427&quot; width=&quot;218&quot; height=&quot;155&quot; srcset=&quot;&quot; sizes=&quot;&quot; data-src=&quot;&quot;><\/figure>\n<\/div>\n<p> Si la d\u00e9riv\u00e9e est positive, cela signifie que la fonction augmente, mais si la d\u00e9riv\u00e9e est n\u00e9gative, cela signifie que la fonction diminue. En conclusion, les intervalles de croissance et de d\u00e9croissance de la fonction sont : <strong>Croissance:<\/strong>&#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;171&#8243; width=&#8220;1597&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(0,+\\infty)}<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/mathority.org\/wp-content\/ql-cache\/quicklatex.com-b37f8e12423d7bb7b377d9f5b7229269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" <strong>Diminuer:<\/strong> &#8220; title=&#8220;Rendered by QuickLaTeX.com&#8220; height=&#8220;19&#8243; width=&#8220;280&#8243; style=&#8220;vertical-align: -5px;&#8220;><\/p>\n<p> \\bm{(-\\infty,0)}$<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>In diesem Artikel erkl\u00e4ren wir, wie man die Monotonie einer Funktion erkennt, d. h. wie man die Anstiegs- und Abfallintervalle einer Funktion ermittelt. Dar\u00fcber hinaus k\u00f6nnen Sie mit Schritt-f\u00fcr-Schritt-\u00dcbungen das Wachstum und den R\u00fcckgang einer Funktion \u00fcben. Was ist die Monotonie einer Funktion? Eine Funktion ist in einem Intervall monoton, wenn sie die gegebene Ordnung &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathority.org\/de\/monotonie-einer-steigenden-und-fallenden-funktion\/\"> <span class=\"screen-reader-text\">Monotonie einer funktion: wachstum und verfall<\/span> Weiterlesen &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[6],"tags":[],"class_list":["post-43","post","type-post","status-publish","format-standard","hentry","category-derivate"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.2 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Monotonie einer Funktion (Zunahme und Abnahme)<\/title>\n<meta name=\"description\" content=\"Wie man die Monotonie einer Funktion untersucht, das hei\u00dft, wie man die Intervalle der Zunahme und Abnahme einer Funktion kennt. 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